Pre-CalculusLesson 1.1 Linear Functions Points and Lines Point A position in space. Has no size...
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Transcript of Pre-CalculusLesson 1.1 Linear Functions Points and Lines Point A position in space. Has no size...
![Page 1: Pre-CalculusLesson 1.1 Linear Functions Points and Lines Point A position in space. Has no size Coordinate An ordered pair of numbers which describe a.](https://reader035.fdocuments.in/reader035/viewer/2022072006/56649cf75503460f949c7bb2/html5/thumbnails/1.jpg)
Pre-Calculus Lesson 1.1 Linear Functions
Points and Lines
Point A position in space. Has no size
Coordinate An ordered pair of numbers which describe a point’s position in the x-y plane (x,y) 2nd 1st
X-axis The horizontal axis. Quadrant Quadrant
Y-axis The vertical axis 3rd 4th
quadrant Quadrant
Origin The point of intersection of the x- and y axis. Identified as (0,0)
Quadrants One of 4 areas the x-y axes divide a coordinate plane into.
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Linear Equations
• General Form Ax + By = C
• Solution Any ordered pair (x,y) that
makes the equation true
Example 1 Sketch the graph of the equation
3x + 2y = 18.
Method 1 Find the x- and y-intercepts of the graph.
(To find the x-intercept, let y = 0. To find the y-intercept, let x = 0)
Substituting 0 in for y yields: Substituting 0 in for x yields:
3x + 2(0) = 18 3(0) + 2y = 18
3x = 18 2y = 18
x = 6 y = 9
Now plot the points (6,0) and (0,9) and draw your line.
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The graph of 3x + 2y = 18:
Slope-intercept method: y = (m)x + (b)
Here the equation is solved for y. Once the equation is solved forY, (m) -- the coefficient of x -- will always identify the slope of the line. (b) – the constant term will always identify the point where the line crosses the y-axis (y-intercept)
Graph the equation: 3x - 2y = 61st : solve for y -3x - 3x - 2y = - 3x + 6 - 2 - 2 y = (3/2)x - 3
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Since the equation is solved for y: y = (3/2)x – 3 (we align under the equation y = (m)x + (b)
So we can identify values for m = (3/2), & b = - 3
(Knowing m = slope rise & b y-intercept run
We go to our graph and place a point at: - 3 on the y – axisThen from there we move:Up 3 spaces and right 2 spaces
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Special cases from the General form: Ax + By = C
a) If C = 0, the line will always pass through the origin. 3x + 2y = 0 (blue line) b) If A = 0, (no x-term) The line will always be horizontal: 0x + 2y = 6 or 2y = 6 or y = 3 (red line) c) If B = 0, (no y term) the line will always be vertical: 3x + 2(0) = 6 or 3x = 6 or x = 2
![Page 6: Pre-CalculusLesson 1.1 Linear Functions Points and Lines Point A position in space. Has no size Coordinate An ordered pair of numbers which describe a.](https://reader035.fdocuments.in/reader035/viewer/2022072006/56649cf75503460f949c7bb2/html5/thumbnails/6.jpg)
When working with 2 lines at the same time (called a system of equations) one of ‘3’ things can happen:
a) Parallel lines (no solutions occur) y = (2/3) x - 3 2x – 3y = 9
a) Intersecting lines (one solution occurs) y = (-2/3) x + 2 5x – 4y = 8
a) Same line (Concurrent, Or coincident lines) (infinite number of solutions) y = (-5/2)x + 4 5x + 2y = 8
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Solving a system of equations: 1st : Remember there are three different methods:i) Graphing
ii) substitutioniii) Addition-subtraction
(Elimination method)
Example 2 Solve this system: 3x – y = 9 7x – 5y = 25
(Grapher’s can be used to check the algebra process only!!!!!!) (I expect to see pencil/paper detailed processes at all times!!!!!!)
Use your method of choice
(Check the solution process for example 2 in the book)
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Two synonymous terms are: Length and Distance
To find the length of a line segment we need to calculateThe distance between two points: (x1,y1), (x2,y2)
Remember the Distance Formula---Oh you better!
To find the ‘midpoint’ of a line segment, we find the ‘average’ between the two endpoints!
Remember the Midpoint Formula-- it is so suite!
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Example 3:
If A = (-1,9) and B = (4,-3), find:
a) The length of AB (check the solution process in the book)
b) The coordinates of the midpoint of AB(check the solution process in the book)