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    EXPERT SYSTEMS AND SOLUTIONS

    Email: [email protected]

    [email protected]

    Cell: 9952749533www.researchprojects.info

    PAIYANOOR, OMR, CHENNAI

    Call For Research Projects Final

    year students of B.E in EEE, ECE, EI,

    M.E (Power Systems), M.E (Applied

    Electronics), M.E (Power Electronics)

    Ph.D Electrical and Electronics.

    Students can assemble their hardware in our

    Research labs. Experts will be guiding theprojects.

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    Electrical Transients in Power System

    January 2009

    Mehdi Vakilian

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    Text Books:

    1-Transients in Power Systems

    by: Lou van der Slius, 2001

    2- Electrical Transients in Power Systemby: Allan Greenwood, 1991

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    COURSE OUTLINE

    Fundamental Notions About Electrical Transients

    Basic Concepts and Simple Switching Transients

    Damping Effect on Switching Transients

    Abnormal Switching Transients

    Testing ofCircuit Breakers

    Transient Analysis of3Ph Power Systems

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    Course Outline ..continued

    Transient Analysis of3Ph Power Systems

    Traveling Waves and OtherTransients on

    Transmission Line

    Modeling PowerEquipments forTransients

    Numerical Simulation ofElec. Transients

    Lightning and its Induced Transients

    Insulation Coordination

    Protection Against Over Voltages

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    Evaluation System

    Assignments 10%

    Mid Term One (items 1 to 4) : 10%

    Mid Term Two (items 5 to 7) : 10% Final : 60%

    Class Project : 10%

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    Chapter One : Fundemental Notions

    about Electrical Transients Time Scale in Power System Studies:

    planning, Load Flow, Dynamic Stability

    Switching, external disturbancesFrequency Content

    Differential Equations Solution

    Distributed and Lumped ParametersCalculatable,Controllable, Preventable

    Tools for Study

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    CCT Parameters

    In Steady State and

    Transient

    Mathematical

    Presentation & Physical

    Interpretation

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    Simple RCCircuit, Closing Ideal Sw.

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    Equations ofRCCircuit

    1dQ dV I C

    dt dt

    ! !

    11

    dVV RC V

    dt

    !

    1

    1

    dV dt

    V V RC

    !

    1V IR Idt

    C

    !

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    RCCircuit Response

    /1

    t RCV V Ae

    !

    /1 1[ (0)] t RCV V V V e!

    .)ln( 1 ConsRC

    tVV !

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    RCCircuit Discharge

    11 0

    dV RC V

    dt !

    /1 1(0) t RCV V e!

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    Capacitor Voltage ofRCCCT

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    Simple Circuits Characteristic

    (th

    umbprint)RC , RL , LC Circuits

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    Thumbprints:

    RC CCT: Time

    Constant ; RC

    RL CCT : Time

    Constant ; L/R LC CCT : Period of

    Oscillation ;

    2 LCT

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    Principle of Superposition

    Ifstimulus s1 produces R1

    & s2 produces R2

    applying s1+ s2 simultaneouslyresponds R1+R2 in Linear System

    Linear System: responseproportional to :

    stimulus

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    S.P. Application in Switching

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    CCT Detail I1: Pre-opening current

    I2: Superposed currentto simulate current cease

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    S.P. application in Closing switch

    V1 : voltage across contacts pre-closing

    Therefore:

    -V1fictitious stimulus superposedsimulating the closing action

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    The LaplaceTransform Method

    0

    , 0

    ( ) ( )

    lim ( )

    st

    st

    a

    F t F t e dt

    F t e dtX

    ^

    g

    pg p

    !

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    Laplace Transform Continued

    1 2 1 2

    ( ) ( )

    ( ) ( )

    ( ) ( )

    [ ( ) ( )] ( ) ( )

    s j

    t f s

    I t i s

    V t v s

    t t t t

    W [

    ^

    ^

    ^

    ^ ^ ^

    !

    !

    !

    !

    !

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    Transform of Simple Functions

    00 0

    '

    '' ' '

    2

    0 0

    .

    ( )

    st

    st st

    st st

    consV

    e VV V e dt V e dt Vs s

    I t I t

    II t I t e dt I t e dts

    ^

    ^

    ! ! ! !

    !

    ! ! !

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    Laplace Transform continued

    sin2

    j t j t e et

    j

    [ [

    [

    !

    2 2

    1 1 1sin ( )

    2t j s j s j s

    [

    ^ [ [ [ [! !

    2 2cos st s^ [

    [

    !

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    Laplace Transform Application

    ' ( ) ( ) (0)F t s F t F ^ ^!

    '' 2 '( ) ( ) (0) (0) F t s F t sF F ^ ^!

    ( ) 1 2 ' 1( ) ( ) (0) (0) ... (0)n n n n nF t s F t s F s F F ^ ^ !

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    Laplace Transform Continued

    01 1

    [ ( ) ] ( ) ( )

    t

    t dt t d s s

    ^ ^ X X

    !

    0

    1 1[ ( ) ] ( ) ( ) ( )

    t

    I t dt I t I t dt ts s

    ^ ^ ^g g

    ! !

    ( ) (0)[ ( ) ] ( )

    t

    i sI t dt q ss s

    ^g

    ! !

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    SolvingRC problem with Lap. Trans.

    In terms of I in the

    CCT:

    Applying L.P. :

    0d I I

    d t R C !

    ( )( ) (0) 0

    i s si s I

    RC

    !

    (0 )(0 ) c

    V VI

    R

    !

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    ContinuingRC CCT solution

    The L.T. solution:

    The time solution:

    ( 0 ) 1( )

    1cV Vi s

    R sR C

    !

    (0)( ) [ ]

    t

    c RC

    V VI t eR

    !

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    RL CCT excited by Battery V

    Solving for I in CCT

    The L.T. ofEq.:

    The response:

    dIRI L V

    dt !

    ( ) ( ) (0)V

    Ri s L si s LIs

    !

    1( ) ........ (0) 0

    [ ]

    Vi s I

    RL s sL

    ! !

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    RL Time solution

    1 1 1 1[ ]( ) s s s sE E E

    !

    1 1 1 [1 ]

    ( )

    te

    s s

    E^

    E E

    !

    ( ) [1 ]R t

    LV

    I t eR

    !

    (0) 0, : (0)tR

    L I add I e

    {

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    Example: 377 MVA Gen field winding

    L=0.638H, Exciter noload:1.2 MW(480V) Energy stored in F.W.:

    6

    1.2 10 2500480

    I Av! !

    2 2 61 10.638 2.5 10 1.994

    2 2E L I ! ! v v v !

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    How must the exciter voltage be changed

    to reduce the field current to zero in 5 Sec

    . .

    4 8 00 .1 9 2

    2 5 0 0f WR ! ! ;

    0.638

    3.3230.192

    L

    sRX ! ! !

    53.323(5) 2500 (1 ) 0( )

    0.192

    exciter

    VI e V V

    ! ! !

    617......V Volts( !

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    Example on LCCC T Transient

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    Two energy stored elements

    Second order O.D.E.

    c

    d IL V V

    d t !

    1d IL Id t V d t C

    !

    (0)( )( ) (0) c

    Qi s VL si s LI

    sC sC s !

    (0 ): (0 )c c

    Qw h e r e V

    C!

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    LCCCT solution Ass. I(0)=0

    2 2

    (0) 1( ) (0)1 1( ) (

    )

    cV V si s IL s s

    LC LC

    !

    12 020 2 2

    0

    1(0) 0, ( ) ( )cCV i s V

    LC L s

    [

    [

    [

    ! ! p !

    12

    0( ) ( ) sinC

    I t V t L[!

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    LCCCT cont. solving for Vc

    Surge Imp. 12

    0 ( )L

    ZC

    !

    2

    2 2

    0 02c c

    d VV V

    dt[ [ !

    2

    2 2 '0

    0

    ( ) ( ) (0) (0)c c c

    V s v s sV V

    s

    [[ !

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    If I(0)=0 then: V`c(0)=0 and Vc(0)

    2

    0

    2 2 2 2

    0 0

    (0)

    ( ) ( )

    c

    c

    V sV

    v s s s s

    [

    [ [!

    2

    1 002 2

    0

    1 cos( )

    ts s

    [^ [[

    !

    0 0 0( ) (1 cos ) (0)cos [ (0)]cosc c cV t V t V t V V V t[ [ [! !

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    Vc characteristic

    Vc Osc. Amp depend on V-Vc(0)

    Vc starts at Vc(0) as expected

    Response for :

    1-Vc(0)=-V

    2-Vc(0)=0

    3-Vc(0)=+V/2

    Voltage and Current Relation

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    Solution of an RL CCT Stimulated

    by an Exp. Drive (Ass. I(0)=0)

    ( ) tU t V e E!

    ( ) ( ) (0)

    VR

    i s Lsi s LI s E !

    ( )( )( )

    Vi s

    R Ls s E!

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    Exp. Stimulated RL CCT, Cont.

    If /R LP !

    1 1( ) ( )( )

    Vi s L s sE E

    !

    ( ) ( )( )

    t tV

    I te e

    L

    P E

    E P

    !