Powerpoint Templates Page 1 Powerpoint Templates Quantum Chemistry Revisited.
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Transcript of Powerpoint Templates Page 1 Powerpoint Templates Quantum Chemistry Revisited.
Powerpoint TemplatesPage 1
Powerpoint Templates
Quantum Chemistry
Revisited
Powerpoint TemplatesPage 2
Wave Equation
Non Relativistic Limit
β2π = ࡬ππΰ΅°2 π2πππ‘2
παΊπ₯,π¦,π§,π‘α»= παΊπ₯,π¦,π§α».παΊπ‘α» Possible solution: Plane wavesπαΊπ‘α»= πππβπππ‘
Powerpoint TemplatesPage 3
β2π = β࡬2ππΰ΅°
2 π
Ξ»= βπ
β2π = β࡬2ππβ ΰ΅°
2 π
πΈ= π+ π= π22π+ π
Powerpoint TemplatesPage 4
π= ΰΆ₯2π(πΈβ π)
β2π = β࡬2πβΰ΅°
2 2π(πΈβ π)π
(β β28π2πβ2 + π)π = πΈπ
Time Independent SchrΓΆdinger Equation
Powerpoint TemplatesPage 5
πΈ= βΞ½= β π2π
παΊπ‘α»= πππβπππ‘
ππαΊπ‘α»ππ‘ = βπ2ππΈβ πππβπππ‘
π β2ππππ‘παΊπ‘α»= πΈπαΊπ‘α» Time dependent SchrΓΆdinger Equation
Powerpoint TemplatesPage 6
αβ β28π2πβ2 + παπ(π₯,π¦,π§)π(π‘) = π β2ππππ‘π(π₯,π¦,π§)π(π‘)
Lousy relativistic equation
2nd derivative in space
1st derivative in time
Many fathers equation
(Klein, Fock, SchrΓΆdinger, de Broglie, ...)
Klein-Gordon Equation (1926)
Powerpoint TemplatesPage 7
(E β V)2 = p2c2 + m2c4
β2π24π2 πΏ2π(π)πΏπ2 +αΎαΊπΈβ πα»2 β ππ2π4αΏπαΊπα»= 0
β2π24π2 πΏ2παΊπ,π‘α»πΏπ2 β β24π2 πΏ2παΊπ,π‘α»πΏπ‘2 β πβππ πΏπ(π,π‘)πΏπ‘ + αΊπ2 β ππ2π4α»π(π,π‘) = 0
Free Electron (V = 0)
β2π24π2 πΏ2παΊπ,π‘α»πΏπ2 β β24π2 πΏ2παΊπ,π‘α»πΏπ‘2 β ππ2π4 π(π,π‘) = 0
Powerpoint TemplatesPage 8
Klein-Gordon Equations
Eigen values for E2
Β± E solutions
Matter
Antimatter
Carl Anderson discovers the positron in 1932
KG works well for bosons (integer spin particles)
Powerpoint TemplatesPage 9
(ππ»+ πππ πππ‘)2 = π2π»2 β π2 1π2 πππ‘2
a = b = 1
ab + ba = 0
π = α1 00 β1α π = α0 11 0α ππ π = α0 βππ 0α
Powerpoint TemplatesPage 10
πΌ1 = 0 00 0 0 11 00 11 0 0 00 0 πΌ2 = 0 00 0 0 βππ 00 βππ 0 0 00 0
πΌ3 = 0 00 0 1 00 β11 00 β1 0 00 0 π½ = 1 00 1 0 00 00 00 0 β1 00 β1
3 dimensions and time
Powerpoint TemplatesPage 11
ΰ΅β πΌπ πβπ2π πΏπΏπ3
π=1 + π½ππ2π4ΰ΅±π(π,π‘) = πβ2ππΏπαΊπ,π‘α»πΏπ‘
Dirac Equation
2 positive solutions
2 negative solutions
Matter / Antimatter
Spin Β± Β½
Powerpoint TemplatesPage 12
π1 = α1 00 β1α π2 = α0 11 0α π3 = α0 βππ 0α Pauli Matrices
π= βπ β2πββ πππ΄
π.π= π.(βπ β2πββ πππ΄)
Powerpoint TemplatesPage 13
π»= 12π(π.π)2 + π
π.π π.π= π2πΌ+ ππ.(ππ₯π)
β2π(βπ β2πββ πππ΄)2 + πβ πβ4ππππ1.π΅ΰ΅¨πΉ= ππ1 β2ππππ‘πΉ
πΉ= α10απ πΉ= α01απ
Powerpoint TemplatesPage 14
αβ β28π2π πΏ2πΏπ2 + παπαΊπ,π‘α»= π β2π πΏπ(π,π‘)πΏπ‘
αβ β28π2π πΏ2πΏπ2 + παπβαΊπ,π‘α»= β π β2π πΏπβ(π,π‘)πΏπ‘
πβαβ β28π2π πΏ2πΏπ2 + παπ = πβπ β2π πΏππΏπ‘
παβ β28π2π πΏ2πΏπ2 + παπβ= β ππ β2π πΏπβπΏπ‘
Powerpoint TemplatesPage 15
π β2π πΏαΎππβαΏπΏπ‘ = β β28π2ππβ πΏ2πΏπ2 π+ β28π2ππ πΏ2πΏπ2 πβ
πΏππΏπ‘ = β β4πππ πΏπΏππβ πΏπΏπ πβ π πΏπΏπ πβࡨ
π½= β4πππ απβ πΏπΏπ πβ π πΏπΏπ πβα πΏππΏπ‘ + βπ½= 0
ππαΊπ‘α»+ ΰΆ± π½π .πα¬Τ¦ππ= 0
Powerpoint TemplatesPage 16
There cant be flow in pure real and pure imaginary wave
functions.
In stationary states the flow is either zero or constant.
div D = Ο implies that stationary states create static
electric fields.
rot H = J + D/t implies that stationary states with Jβ 0
create static magnetic fields.
Static magnetic fields induce currents J which create
induced magnetic fields.
Time dependent magnetic fields induce time dependent
electric fields (rot E = - B/t), which means time
dependent charge densities to which correspond non
stationary states.