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Possible disk emission in the BLR of AGN Edi Bon Astronomical Observatory Belgrade, Serbia...
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Transcript of Possible disk emission in the BLR of AGN Edi Bon Astronomical Observatory Belgrade, Serbia...
Possible disk emission in the BLR of AGN
Edi BonAstronomical Observatory Belgrade, Serbia
L. Č. Popović1 , D. Ilić2 1- Astronomical Observatory Belgrade, Serbia
2- University of Belgrade, Faculty of Mathematics Department of Astronomy
Intro:I – Here we investigated the structure of broad emission profiles
(Hα, Hβ…)II – To explain the structure of these profiles we simplified the
things using “two-component model”, with assumption that the wings of the lines originated in the disk, and a spherical region that surrounds the disk contributes to the core of the lines.
III – we applied this model to the profiles of 14 single-peaked AGN (that we observed at INT), that already had a proof of the disk existence in X domain of spectra
IV – the fitting to this model allowed as to do only ruff estimation of parameters, because of luck of shoulders or bumps and the large number of parameters of our model
V – in order to determine better fit, we simulated our model for different parameters so we could estimate influence of the disk flux in the profiles
Unification Scheme of AGN
BLR
BAL
Torus
masers
Emmering, Blandford & Shlosman 1992
• Torus – samo oblast u vetru akrecionog diska
I()=IAD()+IG()Where:
IAD() the emissions of the relativistic accretion disk
IG() the emissions of the spherical region around the disk
The whole line profile can be described by the relation:
•The disk is contributing to the wings of the lines,•a spherical medium arround the disk to the core of the lines.
Two-component model
Sl. 1: Dekompozicija Hβ linije posmatrana na INT-u. Isprekidana linija pretstavlja posmatranja,dok puna linija pretstavlja najbolji fit. Na dnu su gausove komponente i isprekidana linija koja pretstavlja doprinos Fe II multipleksa
Sl. 2: Isto kao Sl. 1, samo za Hα liniju. Pored uske Hα centralne komponente, prisutne su dve slabe uske [NII] linije: na 7136 Å i 7174 Å
Fit
a) the comparison of all line profiles (dashed lines) with an averaged one (solid line); b) fit of the averaged line profile. c),d),e),f) represent fit of Lyα, Mg II, Hβ and H α lines, resp.
IIIZw2
MODEL IIIZw2
zdisk – shift of the disk komponent
s – width of Gaussianin the disk
Rinn inner radius Rout outer radius zG shift of the Gaussian
WG width of the Gaussian
< AV > averaged prfile FD/FG flux ratio
Two fits of 3C 273 with the two-component model the disk parameters are: a) i=14°, Rinn=400 Rg, Rout=1420 Rg, Wd=1620 km/s, p=3.0 (WG=1350 km/s); b) i=29°, Rinn=1250 Rg, Rout=15000 Rg, Wd=700 km/s, p=2.8 (WG=1380 km/s)
The random velocities of a spherical region (ILR) as a function of the local random disk velocities. The dashed line represents the function VILR = VDisk [km s−1].
Ratio of FWHM & width @ 10-40% of hight in function of inclination.
over 25% disk is weak
Fluks gausijana dva putamanji od fluksa diska
0
2
4
6
8
10
12
0 20 40 60 80inklinacija
Wx/
W50
10
20
30
40
Gaussian flux = 1/2 disk flux
Ratio of FWHM & width @ 5-45% of hight in function of inclination.
over 40% disk is weak
Fluks gausijana tri puta manji od fluksa diska
0
2
4
6
8
10
12
0 10 20 30 40 50 60 70
inklinacija diska
Wx/
W50
5
10
15
20
25
30
35
40
45
Gaussian flux = 1/3 disk flux
Ratio of FWHM & width @ 2-30% of hight in function of inclination.
over 10% disk is weak
Fluks gausijana tri puta veci odfluksa diska
0
2
4
6
8
10
12
0 10 20 30 40 50 60 70
inklinacija diska
Wx/
W50
2
3
4
5
6
7
8
9
10
15
20
25
30
Gaussian flux = 3 x disk flux
Ratio of FWHM & width @ 5-35% of hight in function of inclination.
over 10-15% disk is not detectable.
ww1xg2
0
1
2
3
4
5
6
7
8
9
10
0 20 40 60 80inclination
Wx/
W50
5
10
15
20
25
30
35
Gaussian flux = 2 x disk flux
Ratio of FWHM & width @ 3-30%.
w11
0
2
4
6
8
10
12
0 20 40 60 80inklinacija diska
Wx/
W50
3
6
10
15
20
25
30
Gaussian flux = disk flux
Gaussian flux = disk flux, for inclination i=30, Fixed ring, width 800, Rinn from 200 to 1200
za i=30 , Rout-Rinn=800 new1-11-zai30
0
1
2
3
4
5
6
7
8
9
0 500 1000 1500Rinn
Wx
/W5
0
5
10
20
30
40
50
Gaussian flux = disk flux, for inclination i=30, Weith response to emisivity
za i=30 po emisivnosti qnew12-18-i30
0
1
2
3
4
5
6
7
0 1 2 3 4q
Wx
/W5
0
5
10
15
20
20
Gaussian flux = disk flux, for inclination i=20, Fixed ring, width 800, Rinn from 200 to 1200
za i=20, Rout-Rinn 800
0
1
2
3
4
5
6
0 500 1000 1500Rinn
Wx/
W50
5
10
15
20
25
30
3c12010 %: 2.867891 20 %: 1.915054
na 10% for i=20 2.9 => Rinn=600na 20% for i=20 1.9 => Rinn=1000---------------------------------------------------------------
Flux of Gaussian = 1/2 fluks of disk10% 2.9 => i=2020% 2 => i=25
Flux of Gaussian = 1/3 fluks of disk10% 2.9 => i=2620% 1.9 => i=25
Flux of Gaussian = 3 x fluks of disk10% 3 => i=1520% 1.65 => i=15 max
Flux of Gaussian = fluks of disk10% 2.8 => i=1520% 1.9 => i=12
Flux of Gaussian = 2 x fluks of disk10% 2.6 => i=1520% 1.75 => i=20 max
Fixed ring for i=10
0
0.5
1
1.5
2
2.5
3
0 500 1000 1500
Rinn
Wx/
W50 10%
20%
30%
Fixed ring for i=12
0
0.5
1
1.5
2
2.5
3
3.5
0 500 1000 1500
Rinn
Wx
/W1
0 10%
20%
30%
Fixed ring for i=15
0
0.5
1
1.5
2
2.5
3
3.5
4
0 200 400 600 800 1000 1200 1400
Rinn
Wx/
W50
10%
20%
30%
na 10% za i=10 2.9=> Rinn=170na 20% za i=10 1.9=> Rinn=230
na 10% za i=12 2.9=> Rinn=200na 20% za i=12 1.9=> Rinn=250
na 10% za i=15 2.9=> Rinn=320na 20% za i=15 1.9=> Rinn=600