PROBLEM 1A closed cylindrical tank filled with water has a hemispherical dome and is connected to an inverted piping system as shown. The liquid in the top part of the piping system has a specific gravity of 0.8, and the remaining parts of the system are filled with water. If the pressure gage reading at A is 60 kPa, determine

(a) The pressure in pipe B, and (b) The pressure head, in millimetres of mercury, at the top of the dome (point C).

PROBLEM 2

1

hemispherical dome

PA = 60 kPa

A

B

C

water

SG = 0.84 m

3 m

2 mwater

3 m

A U-tube mercury manometer is connected to a closed pressurized tank as illustrated. If the air pressure is 2 psi, determine the differential reading h. The specific weight of the air is negligible.

PROBLEM 3

2

Mercury (SG = 13.6)

Pair = 2 psi

2 ft

2 ft

2 ft

h

air

water

An inverted open tank is held in place by a force R as shown. If the specific gravity of the manometer fluid is 2.5, determine the value of h.

PROBLEM 4

3

1-in.-diameter tube

3 ft

air

2 ft

h

1 ft

2-ft-diameter tank

water

R

The mercury manometer indicates a differential reading of 0.30 m when the pressure in pipe A is 30-mm Hg vacuum. Determine the pressure in pipe B.

PROBLEM 5

4

0.50 m

0.15 m

0.30 m

water

oilA B

Mercury (SG = 13.6)

Compartments A and B of the tank shown are closed and filled with air and a liquid with a specific gravity equal to 0.6. Determine the manometer reading h if the barometric pressure is 14.7 psi and the pressure gage reads 0.5 psi. The effect of the weight of the air is negligible.

PROBLEM 6

5

0.5 psi

air

water

Liquid (SG = 0.6)

0.1 ft

h

mercury (SG = 13.6)

open

A B

Water, oil, and salt water fill a tube as shown in the figure. Determine the pressure at point 1 (inside the closed tube).

PROBLEM 7

6

3 ft

2 ft

4 ftwater

Oil density = 1.20 slugs/ft3 Salt water (SG = 1.20)

1

Determine the elevation difference, h, between the water levels in the two open tanks shown.

7

0.4 m

h

1 mwater

water

SG = 0.90