Planck’s hypothesis, and Einstein’s photon theory. Contents: Hubris at the turn of the century
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Transcript of Planck’s hypothesis, and Einstein’s photon theory. Contents: Hubris at the turn of the century
Planck’s hypothesis, and Einstein’s photon theory.
Contents:•Hubris at the turn of the century•Black Body radiation•The problem with black body radiation•Planck’s hypothesis•Einstein’s corpuscular light theory•Photons : Example 1 | Example 2
•Whiteboards
Hubris
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•1900 +/- 10.•The end of physics•Tricky bits
•Motion of the earth with respect to “ether”•(Einsteinian relativity)
•Black body radiation•(Quantum mechanics)
Black Body radiation
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Radiation given off by hot stuff
Black Body radiation
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The problem
fig 27-5
Black Body radiation
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Planck’s solution
Planck proposes a quantum hypothesisEmin = hf
h = Planck’s constant = 6.626 x 10-34 Jsf = frequency of oscillations (Hz, s-1)
E = nhf, n = 1,2,3,...Hypothesis fits data exactly.Planck thinks it’s just math, not reality
Einstein’s photon theory
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Einstein:Reality is quantumRadiation is also quantizedPhotons = corpuscular theory
E = hf v = fE = Photon energy (Joules)v = c = speed of light = 3.00 x 108 m/sf = frequency (Hz) = wavelength (m)
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E = hf v = fE = Photon energy (Joules)v = c = speed of light = 3.00 x 108 m/sf = frequency (Hz) = wavelength (m)
Example 1: What is the energy of a 460 nm photon?v = f, c = f, f = c/E = hf = hc/
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E = hf v = fE = Photon energy (Joules)v = c = speed of light = 3.00 x 108 m/sf = frequency (Hz) = wavelength (m)Example 2: A photon has an energy of 13 eV. What is its wavelength? (Remember V = W/q, and 1 eV is one electron moved through 1 volt)E (in Joules) = (13 eV)(1.602 x 10-19 J/eV)c = f, = c/fE = hf, f = E/h = c/f = hc/E
Whiteboards: Photons
1 | 2 | 3 | 4
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4.36 x 10-19 J W
E = hf = (6.626 x 10-34 Js)(6.58 x 1014 s-1) = 4.36 x 10-19 J
What is the energy of a photon with a frequency of 6.58 x 1014 Hz?
8.23 x 1015 Hz, 36.5 nm W
E = hf f = E/h = (5.45 x 10-18 J)/(6.626 x 10-34 Js) = 8.23 x 1015 Hzv = f, = v/f = (3.00 x 108 m/s)/(8.23 x 1015 Hz) = 36.5 nm
What is the frequency of a photon with an energy of 5.45 x 10-18 J?What is its wavelength?
6.33 x 10-19 J, 3.95 eV W
E = hf = hc/1eV = 1.602 x 10-19 JE = hc/= (6.626 x 10-34 Js)(3.00 x 108 m/s)/(3.14 x 10-9 m) = 6.33 x 10-19 J
E = (6.33 x 10-19 J)/(1.602 x 10-19 J/eV) = 3.95 eV
What is the energy in Joules of a 314 nm photon? What is that energy in eV? (2)
206 nm W
E = hf = hc/1eV = 1.602 x 10-19 JE = (6.02 eV)(1.602 x 10-19 J/eV) = 9.64 x 10-19 JE = hc/, = hc/E= (6.626 x 10-34 Js)(3.00 x 108 m/s)/(9.64 x 10-19 J) = 2.06 x 10-7 m = 206 nm (nm = 1 x 10-9 m)
A photon has an energy of 6.02 eV. What is its wavelength?(answer in nm) (2)
9.36 x 1017 photons/sec W
E = hf = hc/In one second, a 300 mW laser emits photons with a total energy of .300 JE = hc/,= (6.626 x 10-34 Js)(3.00 x 108 m/s)/(620. x 10-9 m) = 3.20613 x 10-19 J (per photon) # photons = (.300 J/s)/(3.20613 x 10-19 J/photon) = 9.36 x 1017 photons/secHey, that’s a lot!
How many photons per second stream from a 620. nm, 300. mW laser? (2)
Waves Photons
Color
Brightness
Energy per photon changesE = hfX-Rays, UV, Gamma
Wavelength Changes
Amplitude Changes # of photons changesmany = brightfew = dimCCD Devices, High speed film
big = red
small = blue
small = dim
big = bright
Light