pi.math.cornell.edu - Paper folding geometry: how origami beat … · 2013. 4. 1. · Postulates:...
Transcript of pi.math.cornell.edu - Paper folding geometry: how origami beat … · 2013. 4. 1. · Postulates:...
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Paper folding geometry:how origami beat Euclid
Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Double the altar
1
Sunday, March 3, 13
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Double the altar
1
Sunday, March 3, 13
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Double the cube
1
Sunday, March 3, 13
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Double the cube
Sunday, March 3, 13
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2
Double the cube
Sunday, March 3, 13
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Double the cube?
Sunday, March 3, 13
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22
2
Double the cube?
Sunday, March 3, 13
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22
2
Double the cube?No, octuple the cube!
Sunday, March 3, 13
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Double the cube
Volume of the cube = (edge)
3= 2
) edge = 3p2 ' 1.25992105...
Sunday, March 3, 13
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1
Double the cube
Vol=1
Volume of the cube = (edge)
3= 2
) edge = 3p2 ' 1.25992105...
Sunday, March 3, 13
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Vol=2
Double the cube
3p2
Volume of the cube = (edge)
3= 2
) edge = 3p2 ' 1.25992105...
Sunday, March 3, 13
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Double the square
Sunday, March 3, 13
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Double the square
1
Sunday, March 3, 13
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Double the square
1
Sunday, March 3, 13
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Double the square
1
Sunday, March 3, 13
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Double the square
1
Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
4. All right angles are equal.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
4. All right angles are equal.5. If two straight lines meet a third straight line so as to make the two interior angles on the same side less than two right angles, then those two lines will meet if extended indefinitely on the side on which the angles are less than two right angles.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
4. All right angles are equal.5. If two straight lines meet a third straight line so as to make the two interior angles on the same side less than two right angles, then those two lines will meet if extended indefinitely on the side on which the angles are less than two right angles.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
4. All right angles are equal.5. If two straight lines meet a third straight line so as to make the two interior angles on the same side less than two right angles, then those two lines will meet if extended indefinitely on the side on which the angles are less than two right angles.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
4. All right angles are equal.5. If two straight lines meet a third straight line so as to make the two interior angles on the same side less than two right angles, then those two lines will meet if extended indefinitely on the side on which the angles are less than two right angles.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
4. All right angles are equal.5. Given a straight line and a point not on that line, there exists exactly one line through that point that is parallel to the given line.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
4. All right angles are equal.5. Given a straight line and a point not on that line, there exists exactly one line through that point that is parallel to the given line.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
4. All right angles are equal.5. Given a straight line and a point not on that line, there exists exactly one line through that point that is parallel to the given line.
Sunday, March 3, 13
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Postulates:1. Let it be granted that a straight line may be drawn from any one point to any other point.2. Let it be granted that a finite straight line may be produced to any length in a straight line.3. Let it be granted that a circle may be described with any center at any distance from that center.
4. All right angles are equal.5. Given a straight line and a point not on that line, there exists exactly one line through that point that is parallel to the given line.
Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Proposition 1: To construct an equilateral triangle on a given finite straight line.
Sunday, March 3, 13
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Proposition 1: To construct an equilateral triangle on a given finite straight line.
Sunday, March 3, 13
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Proposition 1: To construct an equilateral triangle on a given finite straight line.
Sunday, March 3, 13
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Proposition 1: To construct an equilateral triangle on a given finite straight line.
Sunday, March 3, 13
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Proposition 9: To bisect a given rectilinear angle.
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Proposition 9: To bisect a given rectilinear angle.
Sunday, March 3, 13
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Proposition 9: To bisect a given rectilinear angle.
Sunday, March 3, 13
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Proposition 9: To bisect a given rectilinear angle.
Sunday, March 3, 13
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Proposition 9: To bisect a given rectilinear angle.
Sunday, March 3, 13
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Proposition 10: To bisect a given finite straight line.
Sunday, March 3, 13
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Proposition 10: To bisect a given finite straight line.
Sunday, March 3, 13
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Proposition 10: To bisect a given finite straight line.
Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Vol=2
3p2
Double the cube
Volume of the cube = (edge)
3= 2
) edge = 3p2 ' 1.25992105...
Sunday, March 3, 13
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What points can we construct?
Sunday, March 3, 13
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What points can we construct?
Sunday, March 3, 13
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What points can we construct?
Sunday, March 3, 13
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What points can we construct?
Sunday, March 3, 13
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What points can we construct?
Sunday, March 3, 13
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What points can we construct?
Sunday, March 3, 13
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What points can we construct?
Sunday, March 3, 13
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What numbers can we construct?
Sunday, March 3, 13
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What numbers can we construct?
0
Sunday, March 3, 13
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What numbers can we construct?
0 1
Sunday, March 3, 13
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2
What numbers can we construct?
0 1
Sunday, March 3, 13
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2
What numbers can we construct?
0 112
Sunday, March 3, 13
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32
What numbers can we construct?
0 112
Sunday, March 3, 13
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32
What numbers can we construct?
0 112
14
Sunday, March 3, 13
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32
What numbers can we construct?
0 112
14
34
Sunday, March 3, 13
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32
What numbers can we construct?
0 112
14
34
32
Sunday, March 3, 13
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32
What numbers can we construct?
0 112
14
34
32
18
Sunday, March 3, 13
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2k.All integers and all fractions with denominator
32
What numbers can we construct?
0 112
14
34
32
18
Sunday, March 3, 13
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2k.All integers and all fractions with denominator
32
What numbers can we construct?
0 112
14
34
32
18
And what else?Sunday, March 3, 13
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Thales’ theorem (intercept theorem):
Sunday, March 3, 13
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Thales’ theorem (intercept theorem):
Sunday, March 3, 13
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Thales’ theorem (intercept theorem):
Sunday, March 3, 13
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ab
c d
Thales’ theorem (intercept theorem):
Sunday, March 3, 13
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ab
c d
b
a=
d
c
Thales’ theorem (intercept theorem):
Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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A = B = height of Thales
Sunday, March 3, 13
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C = 32m+ 230m2 = 147m
A = B = height of Thales
Sunday, March 3, 13
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C = 32m+ 230m2 = 147m
D
A=
C
B
A = B = height of Thales
Sunday, March 3, 13
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C = 32m+ 230m2 = 147m
D
A=
C
B
A = B = height of Thales
D = 147m
Sunday, March 3, 13
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ab
c d
b
a=
d
c
Thales’ theorem (intercept theorem):
Sunday, March 3, 13
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ab
1 ?
b
a=
?
1
Sunday, March 3, 13
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ab
1 ba
b
a=
?
1
Sunday, March 3, 13
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ab
1 ba
b
a=
?
1
We can construct all fractions!
Sunday, March 3, 13
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ab
1 ba
b
a=
?
1
We can construct all fractions!
÷a
Sunday, March 3, 13
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a
1
?
d
?a =
d1
Sunday, March 3, 13
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a
1 d
?a =
d1
a⇥ d
Sunday, March 3, 13
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a
1 d
⇥a ?a =
d1
a⇥ d
Sunday, March 3, 13
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a
1 d
⇥a ?a =
d1
a⇥ d
We can multiply, divide, add and subtract.
Sunday, March 3, 13
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a
1 d
⇥a ?a =
d1
a⇥ d
We can multiply, divide, add and subtract.
And what else?
Sunday, March 3, 13
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1
Sunday, March 3, 13
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1
p2
Sunday, March 3, 13
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All square roots!
Sunday, March 3, 13
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All square roots!
p2
1
1
Sunday, March 3, 13
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All square roots! 1
p2
1
1
Sunday, March 3, 13
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All square roots! 1
12 +p22=?2
p2
1
1
Sunday, March 3, 13
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All square roots! 1
12 +p22=?2
p3
p2
1
1
Sunday, March 3, 13
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All square roots! 1
12 +p22=?2
1
p3
p2
1
1
Sunday, March 3, 13
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All square roots! 1
12 +p22=?2
1
12 +p32=?2
p3
p2
1
1
Sunday, March 3, 13
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All square roots! 1
12 +p22=?2
1
12 +p32=?2
p4p
3p2
1
1
Sunday, March 3, 13
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All square roots!
Sunday, March 3, 13
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All square roots! Ver no quadro que produz todas as \sqrt{k}Espiral de Teodoro (até \sqrt{17}. Em 1958, E. Teuffel provou que duas hipotenusas da espiral nunca colidem.
Sunday, March 3, 13
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All square roots! Ver no quadro que produz todas as \sqrt{k}Espiral de Teodoro (até \sqrt{17}. Em 1958, E. Teuffel provou que duas hipotenusas da espiral nunca colidem.
Sunday, March 3, 13
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All square roots! Ver no quadro que produz todas as \sqrt{k}Espiral de Teodoro (até \sqrt{17}. Em 1958, E. Teuffel provou que duas hipotenusas da espiral nunca colidem.
Sunday, March 3, 13
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We can construct
Sunday, March 3, 13
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We can constructp2
Sunday, March 3, 13
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We can constructp2p3
Sunday, March 3, 13
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We can constructp2p3
p53
Sunday, March 3, 13
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We can constructp2p3
p53
6p7
Sunday, March 3, 13
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We can constructp2p3
p53
6p7
1 + 6p7
Sunday, March 3, 13
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We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
Sunday, March 3, 13
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We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
Sunday, March 3, 13
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We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
Sunday, March 3, 13
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We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
56
p3� 2
q107
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
56
p3� 2
q107
Sunday, March 3, 13
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We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
56
p3� 2
q107
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
56
p3� 2
q107
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
56
p3� 2
q107
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
etc.
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
And what about ?p
1 + 3p2
etc.
Sunday, March 3, 13
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1
a
?
?
a? =
?1
All square roots?
⇥?
Sunday, March 3, 13
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1
a
?
?
a? =
?1
? =pa
All square roots?
⇥?
Sunday, March 3, 13
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All square roots!
1 a
Sunday, March 3, 13
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All square roots!
1 a
Sunday, March 3, 13
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All square roots!
1 a
Sunday, March 3, 13
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All square roots!
1 a
Sunday, March 3, 13
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All square roots!
1 a
pa
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
etc.
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
p1 + 3
p2
etc.
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
p1 + 3
p2
2 +q
67� 3 59p12
etc.
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
p1 + 3
p2
2 +q
67� 3 59p12 q
5+p7
7+p5
etc.
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
p1 + 3
p2
2 +q
67� 3 59p12
rp3457 � 2
q91�
pp5 + 33p
2+p3
q5+
p7
7+p5
etc.
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
p1 + 3
p2
2 +q
67� 3 59p12
rp3457 � 2
q91�
pp5 + 33p
2+p3
q5+
p7
7+p5
etc.
8p47
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
p1 + 3
p2
2 +q
67� 3 59p12
rp3457 � 2
q91�
pp5 + 33p
2+p3
q5+
p7
7+p5
etc.
etc.
8p47
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
p1 + 3
p2
2 +q
67� 3 59p12
rp3457 � 2
q91�
pp5 + 33p
2+p3
q5+
p7
7+p5
And what else?
etc.
etc.
8p47
Sunday, March 3, 13
-
We can constructp2p3
p53
6p7
1 + 6p7
23 + 5
p11
4�2p15
22
� 913 +137
p10
8p5
p2p3
q2341
�4 + 12q
1992
3�p22
�22+ 45p67
56
p3� 2
q107
p21100
20 �525
p26 + 43p
7+ 3883
p99
p1 + 3
p2
2 +q
67� 3 59p12
rp3457 � 2
q91�
pp5 + 33p
2+p3
q5+
p7
7+p5
And what else? Nothing else!
etc.
etc.
8p47
Sunday, March 3, 13
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Sunday, March 3, 13
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In general, it’s impossible to trisect an angle with ruler and compass.✓
Sunday, March 3, 13
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In general, it’s impossible to trisect an angle with ruler and compass.
In general, the number cos is not constructible with ruler and compass.
✓
✓3
Sunday, March 3, 13
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In general, it’s impossible to trisect an angle with ruler and compass.
In general, the number cos is not constructible with ruler and compass.
✓
1
✓3
Sunday, March 3, 13
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In general, it’s impossible to trisect an angle with ruler and compass.
In general, the number cos is not constructible with ruler and compass.
✓
1
✓3
↵cos ↵
Sunday, March 3, 13
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In general, it’s impossible to trisect an angle with ruler and compass.
In general, the number cos is not constructible with ruler and compass.
✓
1cos ✓ = 4(cos ✓3 )
3 � 3(cos ✓3 )
✓3
↵cos ↵
Sunday, March 3, 13
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In general, it’s impossible to trisect an angle with ruler and compass.
In general, the number cos is not constructible with ruler and compass.
✓
1cos ✓ = 4(cos ✓3 )
3 � 3(cos ✓3 )12 = 4x
3 � 3x=)
✓3
↵cos ↵
Sunday, March 3, 13
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Sunday, March 3, 13
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Given a circle, build a square with the same area.
Sunday, March 3, 13
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Given a circle, build a square with the same area.
Sunday, March 3, 13
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Given a circle, build a square with the same area.
r
area of the circle = ⇡r2
Sunday, March 3, 13
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Given a circle, build a square with the same area.
r
area of the circle = ⇡r2
area of the square = (edge)
2
Sunday, March 3, 13
-
Given a circle, build a square with the same area.
r
area of the circle = ⇡r2
area of the square = (edge)
2
edge =p⇡r
Sunday, March 3, 13
-
Given a circle, build a square with the same area.
r
Is constructible with ruler and compass?
p⇡
area of the circle = ⇡r2
area of the square = (edge)
2
edge =p⇡r
Sunday, March 3, 13
-
Given a circle, build a square with the same area.
r
Is constructible with ruler and compass?
⇡
area of the circle = ⇡r2
area of the square = (edge)
2
edge =p⇡r
Sunday, March 3, 13
-
Given a circle, build a square with the same area.
r
Is constructible with ruler and compass? No.
⇡
area of the circle = ⇡r2
area of the square = (edge)
2
edge =p⇡r
Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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n = 2k ⇥ product of distinct Fermat primes
Sunday, March 3, 13
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Fn = 22n + 1
n = 2k ⇥ product of distinct Fermat primes
Sunday, March 3, 13
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Fn = 22n + 1
n = 2k ⇥ product of distinct Fermat primes
F0 = 3, F1 = 5, F2 = 17, F3 = 257, F4 = 65537, F5 is not prime, . . .
Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Dividing into thirdsDarren Scotthttp://[email protected]
2/3
1/3
2
3
1
3
2
3
Sunday, March 3, 13
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Dividing into thirdsDarren Scotthttp://[email protected]
2/3
1/3
2
3
1
3
2
3
Sunday, March 3, 13
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Dividing into thirdsDarren Scotthttp://[email protected]
2/3
1/3
2
3
1
3
2
3
Sunday, March 3, 13
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Dividing into thirdsDarren Scotthttp://[email protected]
2/3
1/3
2
3
1
3
2
3
Sunday, March 3, 13
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Dividing into thirdsDarren Scotthttp://[email protected]
2/3
1/3
2
3
1
3
2
3
12
x
1� x
Sunday, March 3, 13
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Dividing into thirdsDarren Scotthttp://[email protected]
2/3
1/3
2
3
1
3
2
3
12
x
1� x38
12
Sunday, March 3, 13
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Dividing into thirdsDarren Scotthttp://[email protected]
2/3
1/3
2
3
1
3
2
3
12
x
1� x38
12
12
Sunday, March 3, 13
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Axiom 1:
Sunday, March 3, 13
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Axiom 1:
Sunday, March 3, 13
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Axiom 1:
Axiom 2:
Sunday, March 3, 13
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Axiom 1: Axiom 2:
Sunday, March 3, 13
-
Axiom 1: Axiom 2:
Axiom 3:
Sunday, March 3, 13
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Axiom 1: Axiom 2: Axiom 3:
Sunday, March 3, 13
-
Axiom 1: Axiom 2: Axiom 3:
Axiom 4:
Sunday, March 3, 13
-
Axiom 1: Axiom 2: Axiom 3:
Axiom 4:
Sunday, March 3, 13
-
Axiom 1: Axiom 2: Axiom 3:
Axiom 4:
Axiom 5:
Sunday, March 3, 13
-
Axiom 1: Axiom 2: Axiom 3:
Axiom 4: Axiom 5:
Sunday, March 3, 13
-
Axiom 1: Axiom 2: Axiom 3:
Axiom 4: Axiom 5:
Axiom 6:
Sunday, March 3, 13
-
Axiom 1: Axiom 2: Axiom 3:
Axiom 4: Axiom 5: Axiom 6:
Sunday, March 3, 13
-
Axiom 1: Axiom 2: Axiom 3:
Axiom 4: Axiom 5: Axiom 6:
Axiom 7:
Sunday, March 3, 13
-
Axiom 1: Axiom 2: Axiom 3:
Axiom 4: Axiom 5: Axiom 6:
Axiom 7:
Sunday, March 3, 13
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Peter Messer’s construction of :3p2
A
B
Sunday, March 3, 13
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Peter Messer’s construction of :3p2
P
A
B
A
B
Sunday, March 3, 13
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Peter Messer’s construction of :3p2
P
A
B
A
B
BP = 3p2 AP
Sunday, March 3, 13
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P
A
B
r
3p2 r
Sunday, March 3, 13
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P
A
B
P
A
B
r
3p2 r
r
3p2 r
Sunday, March 3, 13
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P
A
B
P
A
B3p2
1
r
3p2 r
r
3p2 r
Sunday, March 3, 13
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P
A
B
P
A
B3p2
1
r
3p2 r
r
3p2 r
3p2 r
Sunday, March 3, 13
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A B
C
Angle trisection:
Sunday, March 3, 13
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A B
C
A B
C
D
A
Angle trisection:
Sunday, March 3, 13
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A B
C
A B
C
D
A
Angle trisection:
BÂD = 13 BÂC
Sunday, March 3, 13
-
A B
C
A B
C
D
A
Angle trisection:
BÂD = 13 BÂC
Sunday, March 3, 13
-
A B
C
A B
C
D
A
Angle trisection:
BÂD = 13 BÂC
Sunday, March 3, 13
-
A B
C
A B
C
D
A
Angle trisection:
BÂD = 13 BÂC
Sunday, March 3, 13
-
And...?
Sunday, March 3, 13
-
And...?
Sunday, March 3, 13
-
No.
And...?
Sunday, March 3, 13
-
Fn = 22n + 1
n = 2k ⇥ product of distinct Fermat primes
F0 = 3, F1 = 5, F2 = 17, F3 = 257, F4 = 65537, F5 is not prime, . . .Sunday, March 3, 13
-
Fn = 22n + 1
n = 2k ⇥ product of distinct Fermat primes
F0 = 3, F1 = 5, F2 = 17, F3 = 257, F4 = 65537, F5 is not prime, . . .Sunday, March 3, 13
-
Fn = 22n + 1
n = 2k ⇥ product of distinct Fermat primes
F0 = 3, F1 = 5, F2 = 17, F3 = 257, F4 = 65537, F5 is not prime, . . .Sunday, March 3, 13
-
Fn = 22n + 1
F0 = 3, F1 = 5, F2 = 17, F3 = 257, F4 = 65537, F5 is not prime, . . .
n = 2k3l ⇥ product of distinct Pierpont primes
Sunday, March 3, 13
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2u3v + 1
F0 = 3, F1 = 5, F2 = 17, F3 = 257, F4 = 65537, F5 is not prime, . . .
n = 2k3l ⇥ product of distinct Pierpont primes
Sunday, March 3, 13
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2u3v + 1
2, 3, 5, 7, 13, 17, 19, 37, 73, 97, 109, 163, 193, 257, . . .
n = 2k3l ⇥ product of distinct Pierpont primes
Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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= {points at the same distance from the point O and the line l}
Sunday, March 3, 13
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Axiom 6:
Sunday, March 3, 13
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y
2=� 4x
focus: (�1, 0)directrix: x = 1
directrix: y = �1/2focus: (0, 1/2)
x
2=2y
Sunday, March 3, 13
-
y
2=� 4x
focus: (�1, 0)directrix: x = 1
directrix: y = �1/2focus: (0, 1/2)
x
2=2y
Sunday, March 3, 13
-
y
2 = �4x 2y dydx
= �4 y = �2m
(x, y) = (�1m
2,
�2m
)
x
2 = 2y 2x = 2dydx
x = m (x, y) = (m, m2
2)
Sunday, March 3, 13
-
y
2 = �4x 2y dydx
= �4 y = �2m
(x, y) = (�1m
2,
�2m
)
x
2 = 2y 2x = 2dydx
x = m (x, y) = (m, m2
2)
Sunday, March 3, 13
-
y
2 = �4x 2y dydx
= �4 y = �2m
(x, y) = (�1m
2,
�2m
)
x
2 = 2y 2x = 2dydx
x = m (x, y) = (m, m2
2)
Sunday, March 3, 13
-
y
2 = �4x 2y dydx
= �4 y = �2m
(x, y) = (�1m
2,
�2m
)
x
2 = 2y 2x = 2dydx
x = m (x, y) = (m, m2
2)
y = mx+ b
Sunday, March 3, 13
-
y
2 = �4x 2y dydx
= �4 y = �2m
(x, y) = (�1m
2,
�2m
)
x
2 = 2y 2x = 2dydx
x = m (x, y) = (m, m2
2)
y = mx+ b m
2
2= mm+ b
�2m
= m�1m2
+ b
Sunday, March 3, 13
-
y
2 = �4x 2y dydx
= �4 y = �2m
(x, y) = (�1m
2,
�2m
)
x
2 = 2y 2x = 2dydx
x = m (x, y) = (m, m2
2)
y = mx+ b m
2
2= mm+ b
�2m
= m�1m2
+ b b = �m
2
2= � 1
m
Sunday, March 3, 13
-
y
2 = �4x 2y dydx
= �4 y = �2m
(x, y) = (�1m
2,
�2m
)
x
2 = 2y 2x = 2dydx
x = m (x, y) = (m, m2
2)
y = mx+ b m
2
2= mm+ b
�2m
= m�1m2
+ b b = �m
2
2= � 1
m
m3 = 2
Sunday, March 3, 13
-
y
2 = �4x 2y dydx
= �4 y = �2m
(x, y) = (�1m
2,
�2m
)
x
2 = 2y 2x = 2dydx
x = m (x, y) = (m, m2
2)
y = mx+ b m
2
2= mm+ b
�2m
= m�1m2
+ b b = �m
2
2= � 1
m
m3 = 2 m = 3p2
Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
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Sunday, March 3, 13
-
References:
•Euclid’s elements: http://aleph0.clarku.edu/~djoyce/java/elements/elements.html (with explanations of the proofs and a geometry applet) and http://www.math.ubc.ca/~cass/Euclid/byrne.html (“in which coloured diagrams and symbols are used instead of letters for the greater ease of learners”)
• Wikipedia page about the origami axioms: http://en.wikipedia.org/wiki/Huzita%E2%80%93Hatori_axioms
• Wikipedia page about origami math results: http://en.wikipedia.org/wiki/Mathematics_of_paper_folding
• Robert Lang’s webpage has loads of materials (including many of the photos of fancy origami): http://www.langorigami.com/ . In particular, this paper has a lot a information: http://www.langorigami.com/science/math/hja/origami_constructions.pdf
• A TED talk about origami math things, but not quite the same content as this talk: http://www.ted.com/talks/robert_lang_folds_way_new_origami.html
• Folding a regular heptagon! http://www.math.sjsu.edu/~alperin/TotallyRealHeptagon.pdf
Sunday, March 3, 13
http://aleph0.clarku.edu/~djoyce/java/elements/elements.htmlhttp://aleph0.clarku.edu/~djoyce/java/elements/elements.htmlhttp://www.math.ubc.ca/~cass/Euclid/byrne.htmlhttp://www.math.ubc.ca/~cass/Euclid/byrne.htmlhttp://www.math.ubc.ca/~cass/Euclid/byrne.htmlhttp://www.math.ubc.ca/~cass/Euclid/byrne.htmlhttp://en.wikipedia.org/wiki/Huzita%E2%80%93Hatori_axiomshttp://en.wikipedia.org/wiki/Huzita%E2%80%93Hatori_axiomshttp://en.wikipedia.org/wiki/Mathematics_of_paper_foldinghttp://en.wikipedia.org/wiki/Mathematics_of_paper_foldinghttp://www.langorigami.com/http://www.langorigami.com/http://www.langorigami.com/science/math/hja/origami_constructions.pdfhttp://www.langorigami.com/science/math/hja/origami_constructions.pdfhttp://www.ted.com/talks/robert_lang_folds_way_new_origami.htmlhttp://www.ted.com/talks/robert_lang_folds_way_new_origami.htmlhttp://www.math.sjsu.edu/~alperin/TotallyRealHeptagon.pdfhttp://www.math.sjsu.edu/~alperin/TotallyRealHeptagon.pdf