8/14/2019 Pile capacity check.xlsx

1/7

Daimeter of pile (D) = 1.20 m

Effective pile length from bottom of pile cap = 15.00 m

Height of GL from bottom of pile cap = 2.30 m

Depth of water table from GL = 2.30 m

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 0 m 0.00 Dry density 1.87 t/m^3

0 - 15 m 15.00 Submerged density 0.87 t/m^3Total = 15.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 0 m 0.00 f 35.0 degrees

0 - 15 m 15.00 f 35.0 degrees

Total = 15.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 0 m 0.00 c 0 t/m^2

0 - 15 m 15.00 c 2 t/m^2

Total = 15.00

Qu(ultimate) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + Sum (K i to d * Pdi * tan * Asi) +Ap * (c * Nc) + * Ci * Asi

Cross sectional area of pile (Ap) = 1.1304 m^2

Unit weight of soil above water table = 1.87 t/m^3

Effective unit weight at soil at pile toe = 0.87 t/m^3

Cohesion at pile toe = 2.00 t/m^2

For f= 35 degrees Nc = 9 Nq = 33.3 Ng= 48.03

Overburden pressure at bottom of pile cap (Pd0) = 4.301 t/m^2

Overburden pressure (Pd1) = 4.30 t/m^2

Overburden pressure (Pd2) = 13.05 t/m^2

Total overburden pressure (Pd) = 17.35 t/m^2

Point resistant (Rb) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + 701.82 t

Ap * (c * Nc)

Adopt value of K = 1.00 & d= f tan d= 0.700a= 0.40 Average Ci = 2.00 t/m^2

As1 = 0.00 m^2

As2 = 56.55 m^2

As = As1 + As2 56.55 m^2

Average overburden pressure for upper part of pile = 4.30 t/m^2

Average overburden pressure for lower part of pile = 10.83 t/m^2

Skin friction resistant (fs1) = 0.00 t

Skin friction resistant (fs2) = 428.66 t

Total skin friction resistant (Rs) = a* Ci * Asi + 473.90 t

Sum (K i to d * Pdi * tand * Asi)

Total bearing resistant (Rb + Rs) = 1175.72 t (A)

Ratio=Rs/Rb 0.6752

Allowable bearing resistant Qu(allow.) = FOS = 2.5 470.29 t

8/14/2019 Pile capacity check.xlsx

2/7

Limiting the overburden pressure upto 20 times of dia. of pile, i.e. 15.00 m

Actual length of pile provided = 15.00 m

and assuming water table reach the GL, Hence gsubmerged = 0.87 t/m^3

Maximum overburden pressure = 13.05 t/m^2

Adopt value of K = 1.00 & d= f tan d= 0.700

As = 56.55 m^2

Total skin friction resistant (Rs) = a* Ci * Asi + 303.60 t

Sum (K i to d * Pdi * tand * Asi)Total bearing resistant (Rb + Rs) = 1005.42 t (B)

Ratio=Rs/Rb 0.4326

Allowable bearing resistant Qu(allow.) = FOS = 2.5 402.17 t

Also ignoring the Ngeffect in point bearing, Rb = 491.23 t

Total bearing resistant (Rb + Rs) = 794.83 t (C )

Ratio=Rs/Rb 0.6180

Allowable bearing resistant Qu(allow.) = FOS = 2.5 317.93 t

Uplift resistant = Skin resistant of pile/2 FOS = 2.5 -60.72 t

8/14/2019 Pile capacity check.xlsx

3/7

Daimeter of pile (D) = 1.20 m

Effective pile length from bottom of pile cap = 20.00 m

Height of GL from bottom of pile cap = 2.30 m

Depth of water table from GL = 2.30 m

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 0 m 0.00 Dry density 1.87 t/m^3

0 - 20 m 20.00 Submerged density 0.87 t/m^3Total = 20.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 0 m 0.00 f 33.0 degrees

0 - 20 m 20.00 f 33.0 degrees

Total = 20.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 0 m 0.00 c 0 t/m^2

0 - 20 m 20.00 c 2 t/m^2

Total = 20.00

Qu(ultimate) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + Sum (K i to d * Pdi * tan * Asi) +Ap * (c * Nc) + * Ci * Asi

Cross sectional area of pile (Ap) = 1.1304 m^2

Unit weight of soil above water table = 1.87 t/m^3

Effective unit weight at soil at pile toe = 0.87 t/m^3

Cohesion at pile toe = 2.00 t/m^2

For f= 33 degrees Nc = 9 Nq = 27.34 Ng= 37.77

Overburden pressure at bottom of pile cap (Pd0) = 4.301 t/m^2

Overburden pressure (Pd1) = 4.30 t/m^2

Overburden pressure (Pd2) = 17.40 t/m^2

Total overburden pressure (Pd) = 21.70 t/m^2

Point resistant (Rb) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + 713.31 t

Ap * (c * Nc)

Adopt value of K = 1.00 & d= f tan d= 0.649a= 0.40 Average Ci = 2.00 t/m^2

As1 = 0.00 m^2

As2 = 75.40 m^2

As = As1 + As2 75.40 m^2

Average overburden pressure for upper part of pile = 4.30 t/m^2

Average overburden pressure for lower part of pile = 13.00 t/m^2

Skin friction resistant (fs1) = 0.00 t

Skin friction resistant (fs2) = 636.58 t

Total skin friction resistant (Rs) = a* Ci * Asi + 696.90 t

Sum (K i to d * Pdi * tand * Asi)

Total bearing resistant (Rb + Rs) = 1410.21 t (A)

Ratio=Rs/Rb 0.9770

Allowable bearing resistant Qu(allow.) = FOS = 2.5 564.08 t

8/14/2019 Pile capacity check.xlsx

4/7

Limiting the overburden pressure upto 20 times of dia. of pile, i.e. 20.00 m

Actual length of pile provided = 20.00 m

and assuming water table reach the GL, Hence gsubmerged = 0.87 t/m^3

Maximum overburden pressure = 17.4 t/m^2

Adopt value of K = 1.00 & d= f tan d= 0.649

As = 75.40 m^2

Total skin friction resistant (Rs) = a* Ci * Asi + 486.31 t

Sum (K i to d * Pdi * tand * Asi)Total bearing resistant (Rb + Rs) = 1199.61 t (B)

Ratio=Rs/Rb 0.6818

Allowable bearing resistant Qu(allow.) = FOS = 2.5 479.85 t

Also ignoring the Ngeffect in point bearing, Rb = 537.75 t

Total bearing resistant (Rb + Rs) = 1024.06 t (C )

Ratio=Rs/Rb 0.9043

Allowable bearing resistant Qu(allow.) = FOS = 2.5 409.62 t

Uplift resistant = Skin resistant of pile/2 FOS = 2.5 -97.26 t

8/14/2019 Pile capacity check.xlsx

5/7

Daimeter of pile (D) = 1.20 m

Effective pile length from bottom of pile cap = 25.00 m

Height of GL from bottom of pile cap = 2.30 m

Depth of water table from GL = 2.30 m

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 0 m 0.00 Dry density 1.87 t/m^3

0 - 25 m 25.00 Submerged density 0.87 t/m^3Total = 25.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 0 m 0.00 f 33.0 degrees

0 - 25 m 25.00 f 33.0 degrees

Total = 25.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 0 m 0.00 c 0 t/m^2

0 - 25 m 25.00 c 2 t/m^2

Total = 25.00

Qu(ultimate) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + Sum (K i to d * Pdi * tan * Asi) +Ap * (c * Nc) + * Ci * Asi

Cross sectional area of pile (Ap) = 1.1304 m^2

Unit weight of soil above water table = 1.87 t/m^3

Effective unit weight at soil at pile toe = 0.87 t/m^3

Cohesion at pile toe = 2.00 t/m^2

For f= 33 degrees Nc = 9 Nq = 27.34 Ng= 37.77

Overburden pressure at bottom of pile cap (Pd0) = 4.301 t/m^2

Overburden pressure (Pd1) = 4.30 t/m^2

Overburden pressure (Pd2) = 21.75 t/m^2

Total overburden pressure (Pd) = 26.05 t/m^2

Point resistant (Rb) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + 847.74 t

Ap * (c * Nc)

Adopt value of K = 1.00 & d= f tan d= 0.649a= 0.40 Average Ci = 2.00 t/m^2

As1 = 0.00 m^2

As2 = 94.25 m^2

As = As1 + As2 94.25 m^2

Average overburden pressure for upper part of pile = 4.30 t/m^2

Average overburden pressure for lower part of pile = 15.18 t/m^2

Skin friction resistant (fs1) = 0.00 t

Skin friction resistant (fs2) = 928.85 t

Total skin friction resistant (Rs) = a* Ci * Asi + 1004.25 t

Sum (K i to d * Pdi * tand * Asi)

Total bearing resistant (Rb + Rs) = 1851.99 t (A)

Ratio=Rs/Rb 1.1846

Allowable bearing resistant Qu(allow.) = FOS = 2.5 740.80 t

8/14/2019 Pile capacity check.xlsx

6/7

Limiting the overburden pressure upto 20 times of dia. of pile, i.e. 25.00 m

Actual length of pile provided = 25.00 m

and assuming water table reach the GL, Hence gsubmerged = 0.87 t/m^3

Maximum overburden pressure = 21.75 t/m^2

Adopt value of K = 1.00 & d= f tan d= 0.649

As = 94.25 m^2

Total skin friction resistant (Rs) = a* Ci * Asi + 741.01 t

Sum (K i to d * Pdi * tand * Asi)Total bearing resistant (Rb + Rs) = 1588.75 t (B)

Ratio=Rs/Rb 0.8741

Allowable bearing resistant Qu(allow.) = FOS = 2.5 635.50 t

Also ignoring the Ngeffect in point bearing, Rb = 672.19 t

Total bearing resistant (Rb + Rs) = 1413.19 t (C )

Ratio=Rs/Rb 1.1024

Allowable bearing resistant Qu(allow.) = FOS = 2.5 565.28 t

Uplift resistant = Skin resistant of pile/2 FOS = 2.5 -148.20 t

8/14/2019 Pile capacity check.xlsx

7/7

3