8/11/2019 Pile Capacity Check

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Daimeter of pile (D) = 1.20 m

Effective pile length from bottom of pile cap = 28.00 m

Height of GL from bottom of pile cap = 2.30 m

Depth of water table from GL = 2.30 m

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 2.3 m 0.00 Dry density 1.60 t/m^3

2.3 - 15 m 12.70 Submerged density 0.60 t/m^315 - 30.3 m 15.30 Submerged density 0.60 t/m^3

Total = 28.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 2.3 m 0.00 f 0.0 degrees

2.3 - 15 m 12.70 f 24.0 degrees

15 - 30.3 m 15.30 f 24.0 degrees

Total = 28.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 2.3 m 0.00 c 0 t/m^2

2.3 - 15 m 12.70 c 0.328 t/m^2

15 - 30.3 m 15.30 c 0.328 t/m^2

Total = 28.00

Qu(ultimate) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + Sum (K i to d * Pdi * tan * Asi) +

Ap * (c * Nc) + * Ci * Asi

Cross sectional area of pile (Ap) = 1.1304 m^2

Unit weight of soil above water table = 1.6 t/m^3

Effective unit weight at soil at pile toe = 0.6 t/m^3

Cohesion at pile toe = 0.33 t/m^2

For f= 24 degrees Nc = 9 Nq = 10.66 Ng= 10.88

Overburden pressure at bottom of pile cap (Pd0) = 3.68 t/m^2

Overburden pressure (Pd1) = 3.68 t/m^2

Overburden pressure (Pd2) = 16.80 t/m^2

Total overburden pressure (Pd) = 20.48 t/m^2

Point resistant (Rb) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + 254.55 tAp * (c * Nc)

Adopt value of K = 1.00 & d= f tan d= 0.445

a= 0.40 Average Ci = 0.328 t/m^2

As1 = 0.00 m^2

As2 = 105.56 m^2

As = As1 + As2 105.56 m^2

Average overburden pressure for upper part of pile = 3.68 t/m^2

Average overburden pressure for lower part of pile = 12.08 t/m^2

Skin friction resistant (fs1) = 0.00 t

Skin friction resistant (fs2) = 567.73 t

Total skin friction resistant (Rs) = a* Ci * Asi + 581.58 t

Sum (K i to d * Pdi * tand * Asi)

Total bearing resistant (Rb + Rs) = 836.13 t (A)

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Ratio=Rs/Rb 2.2847

Allowable bearing resistant Qu(allow.) = FOS = 2.5 334.45 t

Limiting the overburden pressure upto 20 times of dia. of pile, i.e. 24.00 m

Actual length of pile provided = 28.00 m

and assuming water table reach the GL, Hence gsubmerged = 0.6 t/m^3

Maximum overburden pressure = 14.4 t/m^2

Adopt value of K = 1.00 & d= f tan d= 0.445As = 105.56 m^2

Total skin friction resistant (Rs) = a* Ci * Asi + 352.23 t

Sum (K i to d * Pdi * tand * Asi)

Total bearing resistant (Rb + Rs) = 606.78 t (B)

Ratio=Rs/Rb 1.3837

Allowable bearing resistant Qu(allow.) = FOS = 2.5 242.71 t

Also ignoring the Ngeffect in point bearing, Rb = 173.52 t

Total bearing resistant (Rb + Rs) = 525.75 t (C )

Ratio=Rs/Rb 2.0299

Allowable bearing resistant Qu(allow.) = FOS = 2.5 210.30 t

Uplift resistant = Skin resistant of pile/2 FOS = 2.5 -70.45 t

8/11/2019 Pile Capacity Check

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Daimeter of pile (D) = 1.20 m

Effective pile length from bottom of pile cap = 28.00 m

Height of GL from bottom of pile cap = 2.30 m

Depth of water table from GL = 2.30 m

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 2.3 m 0.00 Dry density 1.60 t/m^3

2.3 - 15 m 12.70 Submerged density 0.60 t/m^315 - 30.3 m 15.30 Submerged density 0.60 t/m^3

Total = 28.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 2.3 m 0.00 f 0.0 degrees

2.3 - 15 m 12.70 f 23.0 degrees

15 - 30.3 m 15.30 f 23.0 degrees

Total = 28.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 2.3 m 0.00 c 0 t/m^2

2.3 - 15 m 12.70 c 0.315 t/m^2

15 - 30.3 m 15.30 c 0.315 t/m^2

Total = 28.00

Qu(ultimate) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + Sum (K i to d * Pdi * tan * Asi) +

Ap * (c * Nc) + * Ci * Asi

Cross sectional area of pile (Ap) = 1.1304 m^2

Unit weight of soil above water table = 1.6 t/m^3

Effective unit weight at soil at pile toe = 0.6 t/m^3

Cohesion at pile toe = 0.32 t/m^2

For f= 23 degrees Nc = 9 Nq = 8.53 Ng= 8.13

Overburden pressure at bottom of pile cap (Pd0) = 3.68 t/m^2

Overburden pressure (Pd1) = 3.68 t/m^2

Overburden pressure (Pd2) = 16.80 t/m^2

Total overburden pressure (Pd) = 20.48 t/m^2

Point resistant (Rb) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + 203.99 tAp * (c * Nc)

Adopt value of K = 1.00 & d= f tan d= 0.424

a= 0.40 Average Ci = 0.315 t/m^2

As1 = 0.00 m^2

As2 = 105.56 m^2

As = As1 + As2 105.56 m^2

Average overburden pressure for upper part of pile = 3.68 t/m^2

Average overburden pressure for lower part of pile = 12.08 t/m^2

Skin friction resistant (fs1) = 0.00 t

Skin friction resistant (fs2) = 541.26 t

Total skin friction resistant (Rs) = a* Ci * Asi + 554.56 t

Sum (K i to d * Pdi * tand * Asi)

Total bearing resistant (Rb + Rs) = 758.55 t (A)

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Ratio=Rs/Rb 2.7186

Allowable bearing resistant Qu(allow.) = FOS = 2.5 303.42 t

Limiting the overburden pressure upto 20 times of dia. of pile, i.e. 24.00 m

Actual length of pile provided = 28.00 m

and assuming water table reach the GL, Hence gsubmerged = 0.6 t/m^3

Maximum overburden pressure = 14.4 t/m^2

Adopt value of K = 1.00 & d= f tan d= 0.424As = 105.56 m^2

Total skin friction resistant (Rs) = a* Ci * Asi + 335.91 t

Sum (K i to d * Pdi * tand * Asi)

Total bearing resistant (Rb + Rs) = 539.89 t (B)

Ratio=Rs/Rb 1.6467

Allowable bearing resistant Qu(allow.) = FOS = 2.5 215.96 t

Also ignoring the Ngeffect in point bearing, Rb = 138.85 t

Total bearing resistant (Rb + Rs) = 474.76 t (C )

Ratio=Rs/Rb 2.4192

Allowable bearing resistant Qu(allow.) = FOS = 2.5 189.90 t

Uplift resistant = Skin resistant of pile/2 FOS = 2.5 -67.18 t

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Daimeter of pile (D) = 1.20 m

Effective pile length from bottom of pile cap = 28.00 m

Height of GL from bottom of pile cap = 2.30 m

Depth of water table from GL = 2.30 m

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 2.3 m 0.00 Dry density 1.60 t/m^3

2.3 - 15 m 12.70 Submerged density 0.60 t/m^315 - 30.3 m 15.30 Submerged density 0.60 t/m^3

Total = 28.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 2.3 m 0.00 f 0.0 degrees

2.3 - 15 m 12.70 f 23.0 degrees

15 - 30.3 m 15.30 f 23.0 degrees

Total = 28.00

Depth Length BH-01 BH-02 BH-03 BH-04 Average

0 - 2.3 m 0.00 c 0 t/m^2

2.3 - 15 m 12.70 c 0.323 t/m^2

15 - 30.3 m 15.30 c 0.323 t/m^2

Total = 28.00

Qu(ultimate) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + Sum (K i to d * Pdi * tan * Asi) +

Ap * (c * Nc) + * Ci * Asi

Cross sectional area of pile (Ap) = 1.1304 m^2

Unit weight of soil above water table = 1.6 t/m^3

Effective unit weight at soil at pile toe = 0.6 t/m^3

Cohesion at pile toe = 0.32 t/m^2

For f= 23 degrees Nc = 9 Nq = 8.53 Ng= 8.13

Overburden pressure at bottom of pile cap (Pd0) = 3.68 t/m^2

Overburden pressure (Pd1) = 3.68 t/m^2

Overburden pressure (Pd2) = 16.80 t/m^2

Total overburden pressure (Pd) = 20.48 t/m^2

Point resistant (Rb) = Ap*(0.5 * D * g* Ng+ Pd * Nq) + 204.07 tAp * (c * Nc)

Adopt value of K = 1.00 & d= f tan d= 0.424

a= 0.40 Average Ci = 0.323 t/m^2

As1 = 0.00 m^2

As2 = 105.56 m^2

As = As1 + As2 105.56 m^2

Average overburden pressure for upper part of pile = 3.68 t/m^2

Average overburden pressure for lower part of pile = 12.08 t/m^2

Skin friction resistant (fs1) = 0.00 t

Skin friction resistant (fs2) = 541.26 t

Total skin friction resistant (Rs) = a* Ci * Asi + 554.90 t

Sum (K i to d * Pdi * tand * Asi)

Total bearing resistant (Rb + Rs) = 758.97 t (A)

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Ratio=Rs/Rb 2.7192

Allowable bearing resistant Qu(allow.) = FOS = 2.5 303.59 t

Limiting the overburden pressure upto 20 times of dia. of pile, i.e. 24.00 m

Actual length of pile provided = 28.00 m

and assuming water table reach the GL, Hence gsubmerged = 0.6 t/m^3

Maximum overburden pressure = 14.4 t/m^2

Adopt value of K = 1.00 & d= f tan d= 0.424As = 105.56 m^2

Total skin friction resistant (Rs) = a* Ci * Asi + 336.24 t

Sum (K i to d * Pdi * tand * Asi)

Total bearing resistant (Rb + Rs) = 540.31 t (B)

Ratio=Rs/Rb 1.6477

Allowable bearing resistant Qu(allow.) = FOS = 2.5 216.13 t

Also ignoring the Ngeffect in point bearing, Rb = 138.85 t

Total bearing resistant (Rb + Rs) = 475.09 t (C )

Ratio=Rs/Rb 2.4217

Allowable bearing resistant Qu(allow.) = FOS = 2.5 190.04 t

Uplift resistant = Skin resistant of pile/2 FOS = 2.5 -67.25 t

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