Pile CAP Design Example + 2 piles
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Transcript of Pile CAP Design Example + 2 piles
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Project Job Ref.
Section Sheet no./rev.
1
Calc. by
CDate
3/25/2015Chk'd by Date App'd by Date
RC PILE CAP DESIGN (BS8110:PART1:1997)TEDDS calculation version 2.0.02
b
P1 P2
s
L
e
Loaded width - x
ex
ex
2 Pile Cap, height h
Pile Cap Design Truss Method
Design Input - 2 Piles - No EccentricityNumber of piles; N = 2ULS axial load; Fuls = 31500.0 kNThe ultimate load per pile; Fuls_pile = Fuls/2 = 15750.0 kNCharacteristic axial load; Fchar = 21500.0 kNThe characteristic load per pile; Fchar_pile = Fchar/2 = 10750.0 kNPile diameter; = 1800 mmPile spacing; s = 4500 mmPile cap overhang ; e = 200 mmOverall length of pile cap; L = s + + 2 e = 6700 mmOverall width of pile cap; b = + 2 e = 2200 mmOverall height of pile cap; h = 3000 mmDimension of loaded area; x = 1500 mm; (parallel to pile cap)
CoverConcrete grade; fcu = 40.0 N/mm2
Nominal cover; cnom = 100 mmTension bar diameter; Dt = 32 mmLink bar diameter; Ldia = 10 mmDepth to tension steel; d = h cnom - Ldia - Dt/2 = 2874 mm
Pile Cap ForcesCompression within pile cap; Fc = Fuls/(2 sin()) = 20002.5 kNTension within pile cap; Ft = Fc cos() = 12330.4 kNCompression In Pile Cap - Suggested Additional Check
Check compression diagonal as an unreinforced column, using a core equivalent to pile diameter
Compressive force in pile cap; Pc = 0.4 fcu 2/4 = 40715.0 kNPASS Compression
Cl. 3.8.4.3
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Project Job Ref.
Section Sheet no./rev.
2
Calc. by
CDate
3/25/2015Chk'd by Date App'd by Date
Tension In One Truss MemberCharacteristic strength of reinforcement; fy = 500 N/mm2
Partial safety factor for strength of steel; ms = 1.15Required area of reinforcement; As_req = Ft /(1/ms fy) =28360 mm2Provided area of reinforcement; As_prov = Ast = 33778 mm2
Tension in truss member; Pt = (1/ms fy) As_prov = 14686.3 kNPASS Tension
Cl. 3.11.4.2
Max / Min Areas Of ReinforcementMinimum area of tension steel; Ast_min = kt Ac = 8580 mm2Maximum area of tension steel; Ast_max = 4 % Ac = 264000 mm2
Area of tension steel provided OKCl. 3.12.6 & Table 3.25
Shear
Applied shear stressAplied Shear stress; V = Fuls / 2 = 15750.0 kNWidth of pile cap shear plane; bv = min( b, 3 ) = 2200 mmDesign shear stress; v = V / (bv d) = 2.49 N/mm2Allowable shear stress; vallowable = min ((0.8 N1/2/mm) (fcu ), 5 N/mm2 ) = 5.00 N/mm2
Shear stress - OKCl. 3.4.5.2
Design concrete shear strengthDetermine concrete shear strength on the section at distance / 5 inside face of pile:
Cl. 3.11.4.3 & fig. 3.23
Shear stress - Table 3.8;vc_25 = 0.79 r1/3 max(0.67, (400 mm/d)1/4) 1.0 N/mm2 / 1.25 = 0.34 N/mm2
Shear stress - Cl. 3.4.5.8 & fig. 3.5; vc = vc_25 ( min( fcu, 40 N/mm2 ) / 25 N/mm2 )1/3 = 0.40 N/mm2Spacing; av = min( 2 d, max( ( s / 2 - / 2 + / 5 - x / 2 ), 0.1 mm )) = 960 mmEnhanced shear stress; vc_enh = min( vallowable , 2 d vc / av) = 2.41 N/mm2
Concrete shear strength - NOT OK, provide MINIMUM links
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Project Job Ref.
Section Sheet no./rev.
3
Calc. by
CDate
3/25/2015Chk'd by Date App'd by Date
Deflection Check (Cl 3.4.6)Redistribution ratio; b = 1.0Design service stress in tension reinforcement; fs = 2 fy As_req /(3 As_prov b) = 279.9 N/mm2Modification for tension reinforcement;
factortens = min( 2, 0.55 + (477 N/mm2 - fs)/(120 (0.9 N/mm2 + Ft /(bd )))) = 1.126Modified span to depth ratio; modfspan_depth = factortens basicspan_depth = 22.5Span of pile cap for deflection check; Ls = 4500 mmActual span to depth ratio; actualspan_depth = Ls /d = 1.57
PASS - Deflection