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Q 9 : Topic Form 4: Knowledge (1m): Understanding (4m)

: Conceptualize (5m): Problem Solving (10m)

Q 10 : Topic Form 5: Knowledge (1m): Understanding (4m)

: Conceptualize (5m): Problem Solving (10m)

Section B :ESSAY (Choose One)30 minutes

Q11 : Topic Form 4 : Knowledge (1m)

: Understanding (4m) : Application (Quantitative) (5m)

: Decision Making (10m)

Q12 : Topic Form 5 : Knowledge (1m)

: Understanding (4m) : Application (Quantitative) (5m)

: Decision Making (10m)

SECTION C: ESSAY( Choose One)

30 minutes

18/5/08 …12 Jamadilawal 1429Hhro,SmscMuzaffarSyah,Melaka HRO

The ability to reason by identifying and analysing common characteristics or variables involve, and synthesis the common characteristic or relation with variables to create a physics concept..

CONCEPTUALISATION ELEMENT

Construct: Conceptualize 1. Make and state the observation

- Observation skill & critical thinking

2. Make comparison - State the similarities and

differences 3. State the relationship

- from the similarities and differences or state the

principle/law involved.

1 ) State the identical characteristic shown in the diagrams below and relate the relationship between their focal lengths and the curvature of mirrors

SPM 2004

5 marks

Curved mirror J Curved mirror K

Diagram 1.1 Diagram 1.2

CONSTRUCT: Conceptualization Skill Paper 2 - Section B

(Question 9 / Question 10)

- mirror K is more curve / K is more concave

- Reflection rays is focused at a

point /F

- The light focus point in mirror K is closer then mirror J

- Focal length is distance between F and P

- Curvature increase focal length

decrease // / inversely propotional

5 marks

Suggested answer

Problem Solving - Quantitative Section C: Q11/12)

Write all the information again. Use symbols.

Choose the formula. Make substitution Final answer with correct unit

1.The specification of a frying pan is 240V 1000W. Calculate the time taken for the frying pan to heat up 1000 cm3 cooking oil from the temperature 30 oC to 120 oC.Assume that all the electrical energy was used to increase the temperature of the oil only and no heat loss to the surrounding.[Specific heat capacity of oil is 2000 J kg–1 oC–1,

Density of oil is 800 kg m-3] [5

marks]

Problem Solving - Quantitative (Paper 2 Section B: Q9/10)

Model Answer

Given: P = 1000W V = 240 VVolume = 1000 cm3 = 1000 x 10-6 m3

θ = 120 – 30 = 90 oC.c of oil = 2000 J kg–1 oC–1, Density of oil = 800 kg m-3

Mass,m = 800 x 1000 x10-6

= 8 x 10-1 kgt = ?Solution: Heat supplied by heater = heat received by the oil By using formula:

pt = mcθ 1000(t) = (8 x10-1) x 2000 x 90 t = 144 s

Problem Solving- Qualitative (Paper 2 Section B: Q9/10) 1. Diagram below shows a saloon car.

Ahmad want to modify the car to be a safety racing car. State the modifications to be done by Ahmad and give a suitable physics concept for every of the aspect below:(i) Safety (ii) Shape(iii) Power (iv) Stability (v) Mass

[10 marks]

Suggestion Rationale1 The front shape is

long // The steering of the car is elastic

2 To lengthen the time of impact // impulsive force is

reduce

 Any 5 correct

3 ShapeAerodynamic // The frame of the car is hard and stiff

4 To reduce the air resistance // stiff / hard to bend

5 PowerHigh engine power

6 Produce high acceleration // Bigger force

7 StabilityWide tyre // Lower the car’s body // fix spoiler to the car

8 Low center Of Gravity

9 MassLow density material but stiff and strong // no added material

10 Maximum acceleration/speed

TOTAL 10

OR:

DECISION MAKING STEPS1. Distinguish the characteristics given 2. Explain the properties of every

chosen characteristics and give the reason.

3. Distinguish the most suitable material based on the characteristics stated.

4. Give reasons why the material chosen.

DON’T WRITE THE CRITERIA FOR ALL THE CHOICE GIVEN IN THE QUESTION

DON’T STATE VALUE

DON’T COMPARE BETWEEN THE CRITERIA

Section C : DECISION MAKING NOTE

DO WRITE EACH CRITERIA FOR THE CHOSEN SUBJECT

DO STATE THE CHARACTERISTIC AS HIGH / LOW /LARGE /SMALL

DO THE JUSTIFICATION BY REPEATING ALL THE CHARACTERICS OF THE CHOSEN SUBJECT.

Section C : DECISION MAKING NOTE

Decision Making Skill(P2-Section A: Q 8; Section C: Q 11/12)

For every metal properties in the table above, explain the suitability of the properties tobe used as a material to make a frying pan. Hence determine the most suitable metal to make the frying pan. Give the justification for your choice.

[10 marks]

Metal Spec. heat

capacity /J kg–1 oC–1

Melting point /

oC

Density/kg m-3

Rate ofRusting

P 450 1540 7873 HighR 880 660 2698 HighS 510 1620 7800 Do not Rust T 398 961 10500 MediumU 377 978 8400 Do not rust

Q 1) As a researcher you are assign to investigate the properties of the metal in the table to be used as the material to make a quality frying pan.

Properties Explanation

Low specific heat capacity

Easily to be hot

High melting point Can sustain high temperature

Low density lighter

Low rate or rusty

S is chosen

So that it do not rust

Because of low specific heat capacity, high melting point, low density and low rate of rusty.

OR:

Good Luck for your SPM 2010 & Thank You