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  • HS - 1/3Your Target is to secure Good Rank in Pre-Medical 201401CM313230

    1. NCERT (XII) (E) Page No. # 166, 169

    11. NCERT (XII) (E) Page No. # 169

    21. NCERT (XII) (E) Page No. # 169

    31. NCERT (XII) (E) Page No. # 167, 168

    41. NCERT (XII) (E) Page No. # 168, 169

    51. NCERT (XII) (E) Page No. # 167

    93. log x

    m = log k +

    1

    n log p

    log x

    m = .3010 + 1 log .5

    log x

    m = log 2 + log .5

    log x

    m = log 2 .5

    (Slope = tan = 1

    n = tan 45 = 1)

    x

    m = 2 .5 = 1 atm

    HINT SHEET

    DATE : 05 - 04 - 2014 AIPMT

    TARGET : PRE-MEDICAL 2014

    LEADER COURSE(Phase : MLP, MLQ, MLR, MLS, MLT & MLU)

    DATE : 10 - 01 - 2010MAJOR TEST # 04

    ANSWER KEY

    SYLLABUS - 04

    94. NCERT Page No. # 149

    97. For spontaneity, Ecell

    > 0

    0cellE = 0 for concentration cell.

    (i) Anode : H2 Zn+ + 2e

    2H + 2e H + 2

    H /anode 2 H /cathode2

    Cathode

    0cellE =

    0.0591

    2log

    2

    2

    H / cathode

    H / anode

    = 0.0591

    2log

    2

    1

    P

    P = +ve

    98. NCERT Page No. # 216

    103. NCERT Page No. # 247

    106. Fact

    Que. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

    Ans. 2 2 3 4 2 1 2 2 4 1 3 4 2 3 4 1 3 3 1 1

    Que. 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40

    Ans. 1 2 3 2 4 2 4 2 3 1 3 1 2 3 3 4 1 4 3 3

    Que. 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

    Ans. 3 4 1 4 2 4 3 4 3 1 2 4 4 2 2 2 4 2 2 2

    Que. 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80

    Ans. 3 4 3 3 3 3 2 2 4 3 4 4 3 2 1 4 2 1 3 2

    Que. 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100

    Ans. 2 1 2 3 4 2 2 3 4 3 1 3 3 3 2 3 1 3 1 3

    Que. 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120

    Ans. 3 1 3 2 4 2 2 3 2 2 3 4 3 4 1 1 2 4 1 4

    Que. 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140

    Ans. 1 2 4 2 4 4 2 4 4 4 3 2 2 1 3 4 4 3 1 3

    Que. 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160

    Ans. 3 1 2 4 1 1 3 1 3 4 1 4 1 2 2 1 4 4 2 1

    Que. 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180

    Ans. 1 2 3 3 2 4 3 1 4 3 3 3 4 3 2 3 3 2 2 4

  • 05042014TARGET : PRE-MEDICAL 2014

    HS - 2/3 Your Target is to secure Good Rank in Pre-Medical 2014 01CM313230

    MAJOR TEST

    107. H2O 2e H2 +

    1

    2O2

    2 96500 C 22.4 1000 cm3 H2

    2 96500 224

    22.4 1000

    C 224 cm3 H2

    = 1930 C.

    108. NCERT Page No. # 254

    111.B c3 dC 7 dC

    2 dt 5 dt

    3 3cdC 3 5 152 10 10dt 2 7 7

    113. NCERT Page No. # 240

    118. NCERT Page No. # 250

    122. 0eq Ba(OH)2 = 0

    Ba2+ + 0

    eq, OH

    eq BaCl2= 0

    eq Ba2+ + 0 eq, Cl

    eq NH4Cl = 0

    eq NH

    4+ + 0

    eq, Cl

    eq, NH4OH = 0

    eq, NH

    4+ + 0

    eq, OH

    I + III + II

    eq, NH4OH = (228.8 + 129.8) 120.3

    = 238.33 cm2eq1

    eq, NH4OH =

    144.766 10 1000

    0.2

    = 2.383

    = 4

    4

    eq,NH OH

    eq,NH OH

    = 102

    126. Ecell = 0cellE

    0.0591

    2 log

    2

    2

    [Zn ]

    [Ag ]

    = 0.8 (0.14) 0.0591

    2 log 2

    1

    1= 0.94 V.

    127. 200 ml of solution requires = 0.73 gm HCl

    Moles of HCl = 0.73

    36.5 = 0.02 mole = 20m mole

    Therefore 1000 ml of solution will require

    = 20

    1000 100m mole HCl200

    132. 50 ml of gold solution = 0.05 mg gelatin

    10 ml of gold solution = 0.05

    1050

    Gold no. = 0.01

    138. The focal length of combination of two thin lenses

    placed in contact is given by

    1

    F =

    1

    1

    f + 2

    1

    f

    In every combination, lenses are in contact.

    Hence, the focal length of combination in each

    case is

    1

    F =

    1

    f +

    1

    f F =

    f

    2

    Hence, the required ratio is 1 : 1 : 1

    142. i2 = 2 20

    2

    i t

    T

    2i =

    T T T2 2 22 20 0

    2 3

    0 0 0

    i t i1 1i dt dt t dt

    T T T T

    =

    T2 23 30 03 3

    0

    i it T

    3 3T T

    22 0 0

    rms

    i ii i

    3 3

    143. m = f0

    ef =

    200

    4 = 50

    147. v = 2vm = 2 2 = 4 m/s

    148. d = 0.0344 mm

    = 600 nm

    3

    9

    0.0344 10rad.

    d 600 10

    or

    = 1

  • 05042014PRE-MEDICAL : LEADER COURSE (MLP, MLQ, MLR, MLS, MLT & MLU)

    HS - 3/3Your Target is to secure Good Rank in Pre-Medical 201401CM313230

    MAJOR TEST

    157. Given, magnification m = I

    O =

    v

    u = p

    or v = upUsing mirror's formula,

    1

    v +

    1

    u =

    1

    f

    Here the image of the real object is also real

    therefore v, u and f all are on the negative side.

    Hence,1

    up + 1

    u =

    1

    f

    1

    u

    11

    p

    =

    1

    f

    u = p 1

    P

    f

    158.s X

    d D or

    9 d

    2d 2D

    2d

    9D

    162. For the virtual image,

    C F O I

    u

    Virtual

    f

    +v

    m = + v

    u = +2

    v = 2u

    Using mirror's formula,

    1

    v +

    1

    u =

    1

    f

    1

    2u +

    1

    u =

    1

    f

    or 2u = f = 40

    u = 20cm

    166. e .(B V)

    167. = 1

    1

    sin i

    sin r = 2

    2

    sin i

    sin r

    172. When the observer is in the denser medium and

    object is in rarer medium,

    w

    a =

    a w

    1

    = 1

    4 /3 =

    3

    4 =

    Real depth

    Apparent depth

    Real depth = 3

    4 apparent depth

    = 3

    4 20cm = 15cm

    173. = tan ip

    = tan 60 = 3 1.732

    177. Given,

    =

    i

    g = 1.6 , w = 1.2

    Then,w

    g =

    g

    w

    =

    1.6

    1.2

    For the total ineternal reflection, the angle of

    incidence i must be greater than the critical angle

    C.

    i.e., i = > C

    But sin C = w g

    1

    or C = sin1 w

    g

    = sin1 12

    16

    C = sin1 3

    4

    Hence, > sin1 3

    4