Physics 2 for Electrical Engineering

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Physics 2 for Electrical Engineering Ben Gurion University of the Negev www.bgu.ac.il/atomchip , www.bgu.ac.il/nanocenter Lecturers: Daniel Rohrlich , Ron Folman Teaching Assistants: Ben Yellin, Yoav Etzioni Grader: Gady Afek Week 8. Faraday’s law – Magnetism in matter • Faraday’s law of induction • Lenz’s law • “motional emf” • towards Maxwell’s equations Sources: Halliday, Resnick and Krane, 5 th Edition, Chaps. 34-35.

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Ben Gurion University of the Negev. www.bgu.ac.il/atomchip , www.bgu.ac.il/nanocenter. Physics 2 for Electrical Engineering. Lecturers: Daniel Rohrlich , Ron Folman Teaching Assistants: Ben Yellin, Yoav Etzioni Grader: Gady Afek. - PowerPoint PPT Presentation

Transcript of Physics 2 for Electrical Engineering

Page 1: Physics 2 for Electrical Engineering

Physics 2 for Electrical EngineeringPhysics 2 for Electrical Engineering

Ben Gurion University of the Negevwww.bgu.ac.il/atomchip, www.bgu.ac.il/nanocenter

Lecturers: Daniel Rohrlich , Ron Folman Teaching Assistants: Ben Yellin, Yoav Etzioni

Grader: Gady Afek

Week 8. Faraday’s law – Magnetism in matter • Faraday’s law of induction • Lenz’s law • “motional emf” • towards Maxwell’s equationsSources: Halliday, Resnick and Krane, 5th Edition, Chaps. 34-35.

Page 2: Physics 2 for Electrical Engineering

Magnetism in matter

We classify materials as diamagnetic, paramagnetic or ferromagnetic according to their magnetic properties.

These three classes of materials differ in their behavior in a magnetic field.

Page 3: Physics 2 for Electrical Engineering

Magnetism in matter

We classify materials as diamagnetic, paramagnetic or ferromagnetic according to their magnetic properties.

These three classes of materials differ in their behavior in a magnetic field.

When a diamagnetic material is placed in a magnetic field, it generates a weak field in the opposite direction. In this sense, its behavior is analogous to a dielectric material.

When a paramagnetic material is placed in a magnetic field, it generates a weak field in the same direction.

Ferromagnetic materials, unlike diamagnets and paramagnets, may stay magnetized when taken out of a magnetic field.

Page 4: Physics 2 for Electrical Engineering

Magnetism in matter

For diamagnetic and paramagnetic materials, the induced field is proportional to the applied field; the proportionality constant is called the magnetic susceptibility and denoted by the letter χ.In an applied field B, the material generates a field χB and the total field inside the material is B + χB.

χ for some diamagnetic and paramagnetic materials at 300 KParamagnetic χ Diamagnetic χ

Page 5: Physics 2 for Electrical Engineering

Magnetism in matter

A current in an empty solenoid creates a magnetic field B. What happens to B if we fill the solenoid with (a) aluminum or (b) copper?

χ for some diamagnetic and paramagnetic materials at 300 KParamagnetic χ Diamagnetic χ

Page 6: Physics 2 for Electrical Engineering

Magnetism in matter

It is conventional to define two more vector fields, the magnetic field H and the magnetization M, as follows:

• μ0H is the magnetic field in vacuum due to currents.• μ0M is the magnetic field generated by a diamagnetic or paramagnetic material.

We have defined the magnetic susceptibility by μ0M = χB =

χ(μ0H). Therefore the effective B inside a diamagnetic or

paramagnetic material is

B + χB = μ0H + χ(μ0H) = μ0(1 + χ)H = μH ,

where μ = μ0(1 + χ) is the magnetic permeability of a material.

Page 7: Physics 2 for Electrical Engineering

Magnetism in matter

Rank the following:

• μ0

• μ for a paramagnet

• μ for a diamagnet

Page 8: Physics 2 for Electrical Engineering

Magnetism in matter

A qualitative explanation of diamagnetism: In some atoms, electrons are paired so that the total magnetic moment of the atom is zero. The electrons orbit the nucleus in opposite directions, hence their magnetic dipole moments cancel.

But as we saw in Lecture 6 on the Lorentz force, Slides 47, 48 and 49, an external magnetic field B decreases the cyclotron frequency ω of one electron and increases ω of the other.

B

ω increases

B

ω decreases

Page 9: Physics 2 for Electrical Engineering

Magnetism in matter

A qualitative explanation of diamagnetism: In some atoms, electrons are paired so that the total magnetic moment of the atom is zero. The electrons orbit the nucleus in opposite directions, hence their magnetic dipole moments cancel.

The result is a slight magnetic dipole moment opposite to B!

B

ω increases

B

ω decreases

Page 10: Physics 2 for Electrical Engineering

Magnetism in matter

Living beings are diamagnets because water is diamagnetic.

Frog levitation

Page 11: Physics 2 for Electrical Engineering

Magnetism in matter

A qualitative explanation of paramagnetism: Some atoms have permanent magnetic moments that interact only weakly with each other and their orientation is random. But in an external magnetic field, the atomic moments tend to line up with the field, though thermal motion may still scatter their orientations.

Some ferromagnetic materials become paramagnetic above a critical temperature called the Curie temperature, named after Pierre Curie.

Page 12: Physics 2 for Electrical Engineering

Magnetism in matter

A qualitative explanation of paramagnetism: Some atoms have permanent magnetic moments that interact only weakly with each other and their orientation is random. But in an external magnetic field, the atomic moments tend to line up with the field, though thermal motion may still scatter their orientations.

This explanation sounds a lot like what happens to a dielectric material in a capacitor. Why does a dielectric decrease E while a paramagnetic increases B?

E ≠ 0E = 0

Page 13: Physics 2 for Electrical Engineering

Magnetism in matter

A qualitative explanation of paramagnetism: Some atoms have permanent magnetic moments that interact only weakly with each other and their orientation is random. But in an external magnetic field, the atomic moments tend to line up with the field, though thermal motion may still scatter their orientations.

Answer: A magnetic dipole μ tends to line up with B just as an electric dipole p tends to line up with E. But p decreases E and μ increases B.

E ≠ 0E = 0

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2

4

B

IBa

IBa

θ θ3

Torque on a current loop REVIEW

Whenever moves to the right of , the torque switches direction. The area vector A always tends to line up with B.

Defining the magnetic dipole moment of the current loop to be μ = IA, we can write τ = μ × B.

This is a slide from Lecture 6 on the Lorentz force. Note,if we line up these current loops, they will behave like solenoids with their magnetic fields parallel to B.

2 4

A

Page 15: Physics 2 for Electrical Engineering

Magnetism in matter

Since μ increases B, a diamagnetic material (which has μ antiparallel to B) tends to decrease B while a paramagnetic material (which has μ parallel to B) tends to increase B, as stated.

Page 16: Physics 2 for Electrical Engineering

Magnetism in matter

The liquid oxygen in this photograph is suspended between the poles of a magnet.

Is liquid oxygen a diamagnetic or a paramagnetic material?

Page 17: Physics 2 for Electrical Engineering

2

4

B

IBa

IBa

θ θ3

A

Torque on a current loop REVIEW

Whenever moves to the right of , the torque switches direction. The area vector A always tends to line up with B.

If we integrate τ dθ' starting from θ' = 0, we get the work due to the magnetic torque:

so the potential energy U of a magnetic dipole μ in a field B is U = –μ · B.This slide from Lecture 6 shows that U = –μ · B.

2

, cos

''sin

'

IBA

dIBA

dWB

4

Page 18: Physics 2 for Electrical Engineering

Magnetism in matter

The liquid oxygen in this photograph is suspended between the poles of a magnet.

So is liquid oxygen a diamagnetic or a paramagnetic material?

Answer: If liquid oxygen were diamagnetic, μ · B would be negative; then U = –μ · B would be minimized by small B and the liquid would go to where the B field is weakest. No, liquid oxygen is paramagnetic! μ · B is positive, hence U = –μ · B is minimized by large B and the liquid goes to where B is strongest, i.e. between the poles.

Page 19: Physics 2 for Electrical Engineering

Magnetism in matter

The response of a ferromagnetic material to B is not linear. Therefore the magnetic susceptibility χ is not defined for a ferromagnetic material such as iron, although B = μH is still in use.

Every ferromagnetic material divides into magnetized domainsof volume 10–12 – 10–8 m3, each containing 1017 – 1021 atoms.

Page 20: Physics 2 for Electrical Engineering

Magnetism in matter

Every ferromagnetic material divides into magnetized domainsof volume 10–12 – 10–8 m3, each containing 1017 – 1021 atoms.

Experiments show that, in an external magnetic field, domains parallel to the external field grow larger at the expense of the other domains. The material may remain magnetized when theexternal field is turned off. This effect is called hysteresis.

B

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Magnetism in matter

Hysteresis curve of ferromagnetism: Bapp is the applied field, B is the resultant field.

Start

Decreasing Bapp

Increasing Bapp

B

Bapp

Page 22: Physics 2 for Electrical Engineering

Magnetism in matter

This “memory” of ferromagnetic materials is the basis for magnetic memory in audio and video tapes, and magnetic computer disks!

Start

Decreasing Bapp

Increasing Bapp

B

Bapp

Page 23: Physics 2 for Electrical Engineering

Faraday’s law of induction

In 1831, Michael Faraday (in England) and Joseph Henry (in the U.S.) independently discovered that a changing magnetic flux ΦB through a conducting circuit induces a current!

Source: UCSC

Page 24: Physics 2 for Electrical Engineering

Faraday’s law of induction

In 1831, Michael Faraday (in England) and Joseph Henry (in the U.S.) independently discovered that a changing magnetic flux ΦB through a conducting circuit induces a current!

The sign of the current depends on the sign of dΦB/dt.

Page 25: Physics 2 for Electrical Engineering

Faraday’s law of induction

In 1831, Michael Faraday (in England) and Joseph Henry (in the U.S.) independently discovered that a changing magnetic flux ΦB through a conducting circuit induces a current!

The sign of the current depends on the sign of dΦB/dt.

Page 26: Physics 2 for Electrical Engineering

Faraday’s law of induction

In 1831, Michael Faraday (in England) and Joseph Henry (in the U.S.) independently discovered that a changing magnetic flux ΦB through a conducting circuit induces a current!

The sign of the current depends on the sign of dΦB/dt.

Page 27: Physics 2 for Electrical Engineering

Faraday’s law of induction

In fact, the induced “emf” E is directly proportional to dΦB/dt.

What is an “emf”? It is short for “electromotive force”, which is not the correct term because an “emf” is not a force. It has units of volts.

An “emf” is like a potential, but here, evidently, the concept of a potential doesn’t work.

Physically, an “emf” is an electric field that is created in a conductor. A better version of Faraday’s law is

. )(dt

dd B

rrE

Page 28: Physics 2 for Electrical Engineering

Faraday’s law of induction

Example 1: A conducting circuit wound 200 times has a total resistance of 2.0 Ω. Each winding is a square of side 18 cm. A uniform magnetic field B is directed perpendicular to the plane of the circuit. If the field changes linearly from 0.00 to 0.50 T in 0.80 s, what is the magnitude of (a) the induced “emf” E in the circuit (b) the induced electric field E, and (c) the induced current I?

Page 29: Physics 2 for Electrical Engineering

Faraday’s law of induction

Example 1: A conducting circuit wound 200 times has a total resistance of 2.0 Ω. Each winding is a square of side 18 cm. A uniform magnetic field B is directed perpendicular to the plane of the circuit. If the field changes linearly from 0.00 to 0.50 T in 0.80 s, what is the magnitude of (a) the induced “emf” E in the circuit (b) the induced electric field E, and (c) the induced current I?

Answer: (a) We calculate

dΦB/dt = (dB/dt) (200) (area)= (0.625T/s) (200) (18 cm)2

= 4.05 T · m2/s = 4.05 W/s = 4.05 V = E.

(The weber W = T · m2 is the MKS/SI unit of magnetic flux, and since T = N /(m/s) · C = V · s/m2, we have W/s = V.)

Page 30: Physics 2 for Electrical Engineering

Faraday’s law of induction

Example 1: A conducting circuit wound 200 times has a total resistance of 2.0 Ω. Each winding is a square of side 18 cm. A uniform magnetic field B is directed perpendicular to the plane of the circuit. If the field changes linearly from 0.00 to 0.50 T in 0.80 s, what is the magnitude of (a) the induced “emf” E in the circuit (b) the induced electric field E, and (c) the induced current I?

Answer: (b) The total length of the wire is (200) (4) (0.18 m) = 144 m. From the “emf” = 4.05 V we infer E = 4.05 V/144 m = 0.028 V/m.

(c) The current is I = V/R = 4.05 V/2.0 Ω = 2.0 A.

Page 31: Physics 2 for Electrical Engineering

Faraday’s law of induction

Example 2: Two bulbs are connected to opposite sides of a loop of wire, as shown. A decreasing magnetic field (confinedto the circular area shown) induces an “emf” in the loop that causes the two bulbs to light. What happens to the brightness of each bulb when the switch is closed?

Bulb 1

Bulb 2

B

Page 32: Physics 2 for Electrical Engineering

Faraday’s law of induction

Answer: Bulb 2 stops glowing, since it is shorted out, and Bulb 1 glows brighter, since it is the only resistance in the circuit.

B

Bulb 2

Bulb 1

Page 33: Physics 2 for Electrical Engineering

Faraday’s law of induction

Example 3: The conducting bar at the right is pulled right with force Fapp at speed v. The resistance R is the only resistance in the circuit. The magnetic field B is constant and perpendicular to the plane of the circuit. What is the current I and what is the power applied?

L

x

R

I

vFB

Fapp

Page 34: Physics 2 for Electrical Engineering

Faraday’s law of induction

Answer: The flux ΦB is BLx, so dΦB/dt = BLv. Thus the

current is I = (BLv)/R. The force FB equals BIL so the power applied is FBv = BILv =I2R, i.e. the power applied is the power

lost in “Joule heating” of the resistor.

L

x

R

I

vFB

Fapp

Page 35: Physics 2 for Electrical Engineering

Lenz’s law

Let’s see if we can understand not only the magnitude but also the sign of the current induced by a changing magnetic field. The figure below is taken from Example 3 with one change: The direction of the induced current I is reversed.

L

x

R

I

vFB

Fapp

Page 36: Physics 2 for Electrical Engineering

Lenz’s law

But if the direction of I is reversed, then so is the direction of FB; then the bar accelerates to the right, v increases, I increases,

FB increases further without limit, and energy is not conserved.

L

x

R

I

vFB

Fapp

Page 37: Physics 2 for Electrical Engineering

Lenz’s law

But if the direction of I is reversed, then so is the direction of FB; then the bar accelerates to the right, v increases, I increases,

FB increases further without limit, and energy is not conserved.

L

x

R

I

vFB

Page 38: Physics 2 for Electrical Engineering

Lenz’s law

But if the direction of I is reversed, then so is the direction of FB; then the bar accelerates to the right, v increases, I increases,

FB increases further without limit, and energy is not conserved.

Consider also the direction of the magnetic flux generated by I.

L

x

R

I

vFB

Page 39: Physics 2 for Electrical Engineering

Lenz’s law

These considerations lead us to conclude, with H. Lenz, that the current induced in a loop by a changing magnetic flux must generate an opposite magnetic flux through the loop.

L

x

R

I

vFB

Fapp

Page 40: Physics 2 for Electrical Engineering

Lenz’s law

Example 1: If we look back at the qualitative explanation of diamagnetism, we see that electrons in atomic orbits are just obeying Lenz’s law.

B

ω increases

B

ω decreases

Page 41: Physics 2 for Electrical Engineering

Lenz’s law

Example 2: The galvanometer indicates a clockwise current (seen from above). The south pole of the magnet is down. Is the hand inserting or withdrawing the magnet?

Page 42: Physics 2 for Electrical Engineering

Lenz’s law

Example 2: The galvanometer indicates a clockwise current (seen from above). The south pole of the magnet is down. Is the hand inserting or withdrawing the magnet?

Answer: A clockwise currentimplies a downward magneticflux. So the flux due to themagnet must be increasing.The flux from the south pole of a magnet increases when the magnet is inserted.

S N

Page 43: Physics 2 for Electrical Engineering

Lenz’s law

Example 3: A cylindrical magnet of mass M fits neatly into a very long metal tube with thin steel walls, and slides down it without friction. The radius of the magnet is r and the strength of the magnetic field at its top and bottom is B. The magnet begins falling with acceleration g. (a) Show that the speed of the magnet approaches a limiting value v. (b) What is the rate of heat dissipation in the tube, in terms of v and the other data?

Page 44: Physics 2 for Electrical Engineering

Lenz’s law

Answer: (a) The falling magnet induces a circulating current in the tube. By Lenz’s law, the magnetic field of this current opposes the falling magnet, until the magnetic force exactly balances the force of gravity on the magnet, which falls with constant speed v. (b) Gravity, the only external force on this system, does work at the rate Mgv. By energy conservation, this must be the rate of heat dissipation in the tube.

Page 45: Physics 2 for Electrical Engineering

“Motional emf”

A so-called “motional emf” arises when a conductor moves in a constant magnetic field. Thus the moving bar (below) is an example of a “motional emf”. But a “motional emf” can arise also from the Lorentz force without any magnetic induction.

L

x

R

I

vFB

Fapp

Page 46: Physics 2 for Electrical Engineering

“Motional emf”

Example 1: A conducting strip of length L moves sideways with constant velocity v through a constant B pointing out of the screen. What is the potential difference ΔV between the two ends of the strip?

L

B

v

FB

––

++

Page 47: Physics 2 for Electrical Engineering

“Motional emf”

Answer: At equilibrium, the force on charges anywhere in the strip must vanish, i.e. E = vB as in Hall effect. The potential difference is then ΔV = EL = vBL.

L

B

v

FB

––

++

Page 48: Physics 2 for Electrical Engineering

“Motional emf”

Example 2: A conducting strip of length L rotates around a point O with constant angular frequency ω, in a constant B pointing out of the screen. What is the potential difference ΔV between the two ends of the strip?

L

O

r

v

dr

Page 49: Physics 2 for Electrical Engineering

“Motional emf”

Answer: An electron in an element dr of the conducting strip is subject to a centripetal magnetic force evB which must be balanced by an electric force eE = evB = eωrB. (Note v is not uniform along the strip.) Integrating E(r)dr along the strip, we

obtain

L

O

r

v

dr

. /2)( 2

00BLrdrBdrrEV

LL

Page 50: Physics 2 for Electrical Engineering

Towards Maxwell’s equations

The set of four fundamental equations for E and B,

together with the Lorentz force law FEM = q (E + v × B), sum

up everything we have learned so far about electromagnetism!

, 0

0

0

AB

rB

rE

AE

d

Id

dt

dd

qd

B

(Ampère’s law)

(Gauss’s law)

(Faraday’s law)

Page 51: Physics 2 for Electrical Engineering

Towards Maxwell’s equations

The set of four fundamental equations for E and B,

are similar to the famous equations named after J. C. Maxwell – “Maxwell’s equations” – describing all of electromagnetism. But they are not yet Maxwell’s equations!

, 0

0

0

AB

rB

rE

AE

d

Id

dt

dd

qd

B

(Ampère’s law)

(Gauss’s law)

(Faraday’s law)

Page 52: Physics 2 for Electrical Engineering

Towards Maxwell’s equations

The set of four fundamental equations for E and B,

include one equation with an error that Maxwell discovered and corrected. What is the error?

, 0

0

0

AB

rB

rE

AE

d

Id

dt

dd

qd

B

(Ampère’s law)

(Gauss’s law)

(Faraday’s law)