Photoelectron Spectroscopy
-
Upload
kamal-wiggins -
Category
Documents
-
view
25 -
download
3
description
Transcript of Photoelectron Spectroscopy
Photoelectron Spectroscopy
• Lecture 2: Ionization Transitions– Transition moment integral– Ionization selection rules and probability– Atomic and molecular term symbols– A bit of molecular orbital theory
Ionization is still a transition between states
• Initial State: Neutral (or anion)• Final State: Atom/Molecule/Anion after an electron
is removed, plus the ejected electron• M → M+ + e-
init = M final = M+ + e-• Transition Probability = ∫ init m final d• For direct photoionization, transition probability is
always > 0• Photoionization probability is typically described in
terms of a cross-section (much more on this later)
hn + Molecule
= Ionization Energy
e- + Molecule+
Ehn - Ee- = EM+ - EM
IE = Difference in energy between states of M, M+
Each electronic state has its own term symbol
spin multiplicityL = 0 S termL = 1 P termL = 2 D termL = 3 F term
Within each term, there can be several degenerate microstates with different ML and MS
Use Russell Saunders Coupling to describe electron-electron repulsion
L = 0, 1, 2…total orbital angular momentum (term)
ML = -L…+L component of L (ML = ml)
S = total spin quantum number (S = s)
Ms = -S….+S component of S (MS = ms)
2S+1
L J
J = |L+S| ...|L-S|
orbital angular momentum
spin orbit coupling
When consideringsymmetry use theMulliken symbol
How do we label states?
Photoelectron Spectra of Atoms (Noble Gases)
Ionization Energy (eV)17 16 15 14 13 12 11
Ar
Kr
Xe
Ionization Energy (eV)17 16 15 14 13 12 11
Ar
Kr
Xe
What’s the term symbol for the ground state of Ar?
Ground State: 1s22s22p63s23p6
No unpaired electrons: 1S
Remove one 3p electron:
First Ion State: 1s22s22p63s23p5
S = |1/2| (2S+1) = 2
L = 1 (P)
J = L+S ...L-S J = 1/2 and 3/2
2P1/2 and 2P3/2
We are observing transitions between the neutralground state and cation states formed by removing an electron from the highest occupied orbital.
Ionization Energy (eV)17 16 15 14 13 12 11
Ar
Kr
Xe
Ionization Energy (eV)17 16 15 14 13 12 11
Ar
Kr
Xe
1S
2P3/2
2P1/2
Ene
rgy
Ionization Energy (eV)
161718 15
↿⇂↿ ⇂H 1sH 1s
σ
σ*
What about molecules?
molecular rotationslower energy microwave radiation
electron transitionshigher energy visible and UV radiation
molecular vibrationsmedium energy IR radiation
Ground State
Excited StateDuring an electronic transition
the complex absorbs energy
electrons change orbital
the complex changes energy state
Timescale : ≈10-15 sec
Timescale of geometry changes (vibrations): ≈10-12 sec
As a result, observe vertical (Franck-Condon) transitions
In other words, we assume that we only have to consider the electronic portion of the ground- and excited-state wavefunctions to understand these transitions: Born-Oppenheimer approximation
Transitions between molecular potential energy surfaces
18
17
16
15
0
Ioni
zatio
n E
nerg
y (e
V)
H2+
r (Å)0 1 2
H2
Potential Energy Surface Description of the Ionization of Dihydrogen
Much more on this next time!!
Molecular Term Symbols
spin multiplicity
Use Russell Saunders Coupling to describe electron-electron repulsion
L = total orbital angular momentum expressed by orbital symmetry (term)
S = total spin quantum number (S = s)
Ms = -S….+S component of S (MS = ms)
2S+1
L J
molecular orbital angular momentum
spin orbit coupling (we will ignore this for now)
When consideringsymmetry use theMulliken symbol
Ground state (X) = 1g+
Ionization Energy (eV)151617181920
:N≡N:
2p
2s
2p
2s
1g+
2g+
1u+
2u
1u
1g
First ion state (X) = 2g+
Second ion state (A) = 2u
Third ion state (B) = 2u+
Consider Dinitrogen
N21g
2g+
2u+
2u+
Ground state (X) = 1g+
:N≡N:
2p
2s
2p
2s
1g+
2g+
1u+
2u
1u
1g
Potential Well Description
Models to describe molecular electronic structure
MO Theory compared to
Valence Bond Theory
Consider methane.
VSEPR gives 4 sp3 hybrid orbitals.
24 22 20 18 16 14 12
Ionization Energy (eV)
CH 4
24 22 20 18 16 14 12
Ionization Energy (eV)
CH 4
Photoelectron Spectroscopy
2s
2p
sp3
So why are there two valence ionizations separated by almost 10 eV?
Use of reducible representations in M.O. theory
Consider transformation properties ofvectors aligned with the 4 C-H bonds.
Td E 8C3 3C2 6S4 6σd
σ 4 1 0 0 2
1]120084[24
11
Aa
0]120084[24
12
Aa
0]00088[24
1Ea
0]1200012[24
11
Ta
1]1200012[24
11
Ta
C-H = A1 + T2
http://www.mpip-mainz.mpg.de/~gelessus/group.html
Apply Reduction Formula:
24 22 20 18 16 14 12
Ionization Energy (eV)
CH4
24 22 20 18 16 14 12
Ionization Energy (eV)
CH4
CH4
t2 (1, 2, 3)
a1 (1)
2p (t2)
2s (a1)
C H4
LCAO Description of Methane
t2g3d
4s
6 x LGO
L
LL
L
L
L
oct
t1u
t1u*
a1g*
a1g
eg*
eg
t1u
a1g
t2g
eg
a1g t1ueg
M(CO)6 M = Cr, Mo, W, d6 metals
Ligand * orbitals
t1g + t2g + t1u + t2u
t2g*
t1g + t2g + t1u + t2u
Ligand orbitals
18
Ionization Energy (eV)
M(CO)6
Cr
Mo
W
16 14 12 10 8
vertical
2T2g
Photoelectron spectra of d6 metal hexacarbonyls
• Neutral molecules are closed shell; term symbol for ground state in Oh symmetry is 1A1g
• First ionization is from metal t2g orbital; term symbol for resultant state is 2T2g
• Followed by series of overlapping ionizations due to ionization from CO orbitals; M-C σ orbitals, etc.
• States due to ionization from CO orbitals:
– t1g → 2T1g
– t2g → 2T2g
– t1u → 2T1u
– t2u → 2T2u
V(CO)6 a 17 e- complex.
To this point we have only considered molecules with closed shellground states: What if there are unpaired electrons in the ground state?
V(CO)6
68101214161820Ionization Energy (eV)
V(CO)6
68101214161820Ionization Energy (eV)
Ground State: t2g5 : 2T2g
First ion state: t2g4 : T2g x T2g
= 3T1g, 1T2g, 1E1g, 1A1g
Second ion state: t1u5t2g
5 : T1u x T2g
= 3,1T2u, 3,1T1u, 3,1Eu, 3,1A2u
Open shell ground states
And so on and so on…
Ionization Energy (eV)
10 7 689
2Au2B1u
2A1u2A2u
H2(oep)
Mg(oep)
VO(oep)
But, open-shell molecules aren’t always this complicated…
• Energy splitting of ionizations is dependent upon the amount of electronic communication between the unpaired electrons as defined by the exchange integral.
• This is referred to as the exchange splitting.
• If exchange splitting is relatively small, spectra of molecules with open shell ground states can be treated as though they are closed shell systems.
For low symmetries, term symbols often aren’t that useful
Summary
• Photoionization is a transition between states• States are described using term symbols• Simple valence bond theory does not explain all
features observed in spectroscopy, requiring use of molecular orbital theory.
• “Koopmans’ Theorem” begins to break down for systems with unpaired electrons in the initial state