Peng Robinson Mixtures

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Thermodynamic Properties for Mixtures from the Peng-Robinson Equation of State Solution by Phillip Savage - University of Michigan R = 8.31E-06 m^3 MPa/mol-K Enter data into outlined cells onlyPseudocritical Properties from Kay's Rules T ref = 273.159 K T = 500.0 K T'c = 247.45 K P ref = 0.001 MPa P = 5.00E+01 MPa P'c = 5.99 MPa T'r = 2.0206 Calculate parameters in Peng-Robins use binary interaction parameters? P'r = 8.3500 am = 1.87E-07 m^6 MPa/mol^2 yes bm = 2.67E-05 m^3/mol Compound Mole fugacity Am = 5.40E-01 Z = 1.09E+00 Frac (MPa) Bm = 3.22E-01 f = 4.79E+01 MPa Argon 0.000 0.00E+00 dam/dT = ### m^6 MPa/mol^2-K H = 6.25E+03 J/mol CO2 0.500 2.13E+01 Solve Peng-Robinson EOS for Z S = -7.13E+01 J/mol-K CO 0.000 0.00E+00 a1 = ### Q = 1.9E-01 G = 4.19E+04 J/mol Ethane 0.000 0.00E+00 a2 = ### R = ### A = 3.74E+04 J/mol Methane 0.500 2.69E+01 a3 = ### Q^3-R^2= 8.4E-04 U = 1.72E+03 J/mol Methanol 0.000 0.00E+00 V = 9.06E-05 m^3/mol N2 0.000 0.00E+00 O2 0.000 0.00E+00 Three Real Roots Exist H-Higm = -2.93E+03 J/mol Propane 0.000 0.00E+00 Theta = 2.7804 Z min = -0.2959 S-Sigm = -5.51E+00 J/mol-K Water 0.000 0.00E+00 0.00E+00 Z1 = -0.2959 gacity = #NUM! G-Gigm = -1.80E+02 J/mol Z2 = 1.0892 Z max = 1.0892 Higm = 9.18E+03 J/mol 1.000 Z3 = -0.1150 gacity = ### Sigm = -6.58E+01 J/mol-K Flag for Z<0 1 ratio = #NUM! Compound Moles in Tc Pc w Constants in Cp=a+bT+cT^2+dT^3 (J/mol b k a a Mixture (K) (MPa) Cpa Cpb Cpc Cpd Argon 0.000 150.8 4.874 ### 2.08E+01 0.00E+00 0.00E+00 0.00E+00 2.00E-05 0.368 0.487 ### CO2 50.000 304.2 7.376 0.225 2.22E+01 5.98E-02 ### 7.46E-09 2.67E-05 0.708 0.640 ### CO 0.000 133.0 3.496 0.049 2.71E+01 6.55E-03 ### 0.00E+00 2.46E-05 0.450 0.334 ### Ethane 0.000 305.4 4.884 0.098 6.90E+00 1.73E-01 ### 7.28E-09 4.04E-05 0.523 0.729 ### Methane 50.000 190.7 4.600 0.008 1.99E+01 5.02E-02 1.27E-05 ### 2.68E-05 0.387 0.578 ### Methanol 0.000 513.2 7.954 0.559 1.90E+01 9.15E-02 ### ### 4.17E-05 1.152 1.030 ### N2 0.000 126.2 3.394 0.040 2.89E+01 ### 8.08E-06 ### 2.41E-05 0.436 0.323 ### O2 0.000 154.4 5.046 0.021 2.82E+01 6.30E-03 ### 0.00E+00 1.98E-05 0.407 0.455 ### Propane 0.000 369.8 4.246 0.152 6.80E+01 2.26E-01 ### 3.17E-08 5.63E-05 0.603 0.813 ### Water 0.000 647.3 22.048 0.344 2.92E+01 1.45E-02 ### 0.00E+00 1.90E-05 0.873 1.223 ### TOTAL 100.000 2.11E+01 5.50E-02 ### ### Binary Interaction Parameters: Argon CO2 CO Ethane Methane Methanol N2 O2 Propane Water Argon 0 0 0 0 0 0 0 0 0 0 CO2 0 0 0.3 0.13 0.09 0 -0.02 0 0.12 0 CO 0 0.3 0 0.026 0.03 0 0.012 0 0.03 0 Ethane 0 0.13 0.026 0 -0.003 0 0.044 0 0.001 0 Methane 0 0.09 0.03 0 0 0 0.03 0 0.016 0 Methanol 0 0 0 0 0 0 0 0 0 0 N2 0 -0.02 0.012 0.044 0.03 0 0 0 0.078 0 O2 0 0 0 0 0 0 0 0 0 0 Propane 0 0.12 0.03 0.001 0.016 0 0.078 0 0 0 Water 0 0 0 0 0 0 0 0 0 0

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Peng Robinson

Transcript of Peng Robinson Mixtures

Page 1: Peng Robinson Mixtures

Thermodynamic Properties for Mixtures from the Peng-Robinson Equation of StateSolution by Phillip Savage - University of Michigan

R = 8.31E-06 m^3 MPa/mol-K

Enter data into outlined cells only Pseudocritical Properties from Kay's Rules T ref = 273.159 K

T = 500.0 K T'c = 247.45 K P ref = 0.001 MPa

P = 5.00E+01 MPa P'c = 5.99 MPa T'r = 2.0206 Calculate parameters in Peng-Robinson EOS

use binary interaction parameters? P'r = 8.3500 am = 1.87E-07 m^6 MPa/mol^2yes bm = 2.67E-05 m^3/mol

Compound Mole fugacity Am = 5.40E-01Z = 1.09E+00 Frac (MPa) Bm = 3.22E-01f = 4.79E+01 MPa Argon 0.000 0.00E+00 dam/dT = -3.74E-10 m^6 MPa/mol^2-K

H = 6.25E+03 J/mol CO2 0.500 2.13E+01 Solve Peng-Robinson EOS for ZS = -7.13E+01 J/mol-K CO 0.000 0.00E+00 a1 = -6.78E-01 Q = 1.9E-01G = 4.19E+04 J/mol Ethane 0.000 0.00E+00 a2 = -4.13E-01 R = -7.7E-02A = 3.74E+04 J/mol Methane 0.500 2.69E+01 a3 = -3.71E-02 ^3-R^2= 8.4E-04U = 1.72E+03 J/mol Methanol 0.000 0.00E+00V = 9.06E-05 m^3/mol N2 0.000 0.00E+00

O2 0.000 0.00E+00 Three Real Roots ExistH-Higm = -2.93E+03 J/mol Propane 0.000 0.00E+00 Theta = 2.7804 Z min = -0.2959S-Sigm = -5.51E+00 J/mol-K Water 0.000 0.00E+00 0.00E+00 Z1 = -0.2959fugacity = #NUM!G-Gigm = -1.80E+02 J/mol Z2 = 1.0892 Z max = 1.0892

Higm = 9.18E+03 J/mol 1.000 Z3 = -0.1150fugacity = ###Sigm = -6.58E+01 J/mol-K Flag for Z<0 1ug ratio = #NUM!

Compound Moles in Tc Pc w Constants in Cp=a+bT+cT^2+dT^3 (J/mol b k a aMixture (K) (MPa) Cpa Cpb Cpc Cpd

Argon 0.000 150.8 4.874 -0.004 2.08E+01 0.00E+00 0.00E+00 0.00E+00 2.00E-05 0.368 0.487 7.17E-08

CO2 50.000 304.2 7.376 0.225 2.22E+01 5.98E-02 -3.50E-05 7.46E-09 2.67E-05 0.708 0.640 2.54E-07

CO 0.000 133.0 3.496 0.049 2.71E+01 6.55E-03 -9.99E-07 0.00E+00 2.46E-05 0.450 0.334 5.34E-08

Ethane 0.000 305.4 4.884 0.098 6.90E+00 1.73E-01 -6.40E-05 7.28E-09 4.04E-05 0.523 0.729 4.40E-07

Methane 50.000 190.7 4.600 0.008 1.99E+01 5.02E-02 1.27E-05 -1.10E-08 2.68E-05 0.387 0.578 1.44E-07

Methanol 0.000 513.2 7.954 0.559 1.90E+01 9.15E-02 -1.22E-05 -8.03E-09 4.17E-05 1.152 1.030 1.08E-06

N2 0.000 126.2 3.394 0.040 2.89E+01 -1.57E-03 8.08E-06 -2.87E-09 2.41E-05 0.436 0.323 4.79E-08

O2 0.000 154.4 5.046 0.021 2.82E+01 6.30E-03 -7.49E-07 0.00E+00 1.98E-05 0.407 0.455 6.80E-08

Propane 0.000 369.8 4.246 0.152 6.80E+01 2.26E-01 -1.31E-04 3.17E-08 5.63E-05 0.603 0.813 8.28E-07

Water 0.000 647.3 22.048 0.344 2.92E+01 1.45E-02 -2.02E-06 0.00E+00 1.90E-05 0.873 1.223 7.34E-07

TOTAL 100.000 2.11E+01 5.50E-02 -1.12E-05 -1.77E-09

Binary Interaction Parameters:

Argon CO2 CO Ethane Methane Methanol N2 O2 Propane Water

Argon 0 0 0 0 0 0 0 0 0 0

CO2 0 0 0.3 0.13 0.09 0 -0.02 0 0.12 0

CO 0 0.3 0 0.026 0.03 0 0.012 0 0.03 0

Ethane 0 0.13 0.026 0 -0.003 0 0.044 0 0.001 0

Methane 0 0.09 0.03 -0.003 0 0 0.03 0 0.016 0

Methanol 0 0 0 0 0 0 0 0 0 0

N2 0 -0.02 0.012 0.044 0.03 0 0 0 0.078 0

O2 0 0 0 0 0 0 0 0 0 0

Propane 0 0.12 0.03 0.001 0.016 0 0.078 0 0 0

Water 0 0 0 0 0 0 0 0 0 0