Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet...

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Parametric Equations

Transcript of Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet...

Page 1: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

Parametric Equations

Page 2: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal. After t seconds, the path of the ball can be described by

x = (90 cos 40º)t and y = 6 + (90 cos 40º)t – 16t2.

This is the ball’s horizontal distance, in feet.

This is the ball’s vertical height, in feet.

Using these equations, we can calculate the location of the ball at any time t. For example, to determine the location when t = 1 second, substitute 1 for t in each equation:

x = (90 cos 40º)(1) 68.9 feet.y = 6 + (90 cos 40º)(1) – 16 (1)2 47.9 feet.

Plane Curves and Parametric Equations

Page 3: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

This tells us that after 1 second, the ball has traveled a horizontal distance of approximately 68.9 feet, and the height of the ball is approximately 47.9 feet. The figure below displays this information and the results for calculations corresponding to t = 2 seconds and t = 3 seconds.

t = 3 secx = 206.8 fty = 35.6 ft

t = 2 secx = 137.9 fty = 57.7 ft

t = 1 secx = 68.9 fty = 47.9 ft

20

40

60

40 80 120 160 200 240x (feet)

y (feet)

Plane Curves and Parametric Equations

Page 4: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

• Suppose that t is a number in an interval I. A plane curve is the set of ordered pairs (x, y), where

• x = f (t), y = g(t) for t in interval I.• The variable t is called a parameter, and the

equations x = f (t) and y = g(t) are called parametric equations for this curve.

Plane Curves and Parametric Equations

Page 5: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

Graphing a Plane Curve Described by Parametric Equations

1. Select some values of t on the given interval.

2. For each value of t, use the given parametric equations to compute x and y.

3. Plot the points (x, y) in the order of increasing t and connect them with a smooth curve.

Page 6: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

Graph the plane curve defined by the parametric equationsx = t2 – 1, y = 2t, -2 < t < 2.

Step 1 Select some values of t on the given interval. We will select integral values of t on the interval -2 < t < 2. Let t = -2, -1, 0, 1, and 2.

Solution

Step 2 For each value of t, use the given parametric equations to compute x and y. We organize our work in a table. The first column lists the choices for the parameter t. The next two columns show the corresponding values for x and y. The last column lists the ordered pair (x, y).

Text Example

Page 7: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

Step 3 Plot the points (x, y) in the order of increasing t and connect them with a smooth curve. The plane curve defined by the parametric equations on the given interval is shown. The arrows show the direction, or orientation, along the curve as t varies from –2 to 2.

Solution

(3, 4)2(2) = 422 – 1 = 4 – 1 = 32

(0, 2)2(1) = 212 – 1 = 1 – 1 = 01

(-1, 0)2(0) = 002 – 1 = 0 – 1 = -10

(0, -2)2(-1) = -2(-1)2 – 1 = 1 – 1 = -2-1

(3, -4)2(-2) = -4(-2)2 – 1 = 4 – 1 = 3-2

(x, y)y = 2 tx = t2 – 1t

-5 -4 -3 -2 -1 1 2 3 4 5

5

4

3

2

1

-1-2

-3

-4-5t = -1, (0, -2)

t = 1, (0, 2)t = 2, (3, 4)

t = 0, (-1, 0)

t = -2, (3, -4)

Text Example

Page 8: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

Parametric Equations for the Function y = f(x)

A set of parametric equation for the plane curve defined by y = f (x) is

x = t and y = f (t)in which t is in the domain of f.

Page 9: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

Example• Graph the plane curve defined by the

parametric equations x = 3t, y = t2+4, -3 < t < 3

Solution: t x y-3 -9 13-2 -6 8-1 -3 50 0 41 3 52 6 83 9 13

Page 10: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

-9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9

2

4

6

8

10

12

14

16

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Example cont.• Graph the plane curve defined by the

parametric equations x = 3t, y = t2+4, -3 < t < 3

Page 11: Parametric Equations. You throw a ball from a height of 6 feet, with an initial velocity of 90 feet per second and at an angle of 40º with the horizontal.

Parametric Equations