Over Lesson 1–2 5-Minute Check 1. Over Lesson 1–2 Answers.

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Over Lesson 1–2

Transcript of Over Lesson 1–2 5-Minute Check 1. Over Lesson 1–2 Answers.

Page 1: Over Lesson 1–2 5-Minute Check 1. Over Lesson 1–2 Answers.

Over Lesson 1–2

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Over Lesson 1–2

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Lesson 1-3

Glencoe Algebra 1

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You used the order of operations to simplify expressions.

• Recognize the properties of equality and identity.

• Recognize the Commutative and Associative Properties.

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• equivalent expressions – expressions that represent the same number

• additive identity – zero, because the sum of any number and zero is equal to the number

• multiplicative identity – 1, because the product of any number and 1 is equal to the number

• multiplicative inverses –Two numbers whose product is 1

• reciprocal – another name for a multiplicative inverse

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Evaluate Using Properties

Name the property used in each step.

Substitution: 12 – 8 = 4

Substitution: 15 ÷ 5 = 3

Substitution: 3 – 2 = 1

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Multiplicative Identity: 3(1) = 3

= 4Substitution: 1 + 3 = 4

Multiplicative Inverse: (4) = 1

Answer: 4

Evaluate Using Properties

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A. 4

B. 5

C. 1

D. 0

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Apply Properties of Numbers

HORSEBACK RIDING Migina made a list of trail lengths to find the total miles she rode. Find the total miles Migina rode her horse.

Bent Tree Knob Hill Meadowrun Pinehurst

4.25 + 6.50 + 9.00 + 7.75

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= 4.25 + 7.75 + 6.50 + 9.00 Commutative (+)= (4.25 + 7.75) + (6.50 + 9.00) Associative (+)

= 12.00 + 15.50 Substitution

= 27.50 Substitution

Answer: Migina rode 27.5 miles on the trails.

Apply Properties of Numbers

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A. 4.5 mi

B. 5.5 mi

C. 6.0 mi

D. 6.2 mi

TRANSPORTATION Darlene rode the city train from the Winchester Street Station to the airport. How far did she travel on the train?

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Use Multiplication Properties

Evaluate 2 ● 8 ● 5 ● 7 using properties of numbers. Name the property used in each step.

You can rearrange and group the factors to make mental calculations easier.

Answer: 560

2 ● 8 ● 5 ● 7 = 2 ● 5 ● 8 ● 7 Commutative (×)

= (2 ● 5) ● (8 ● 7) Associative (×)

= 10 ● 56 Substitution

= 560 Substitution

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A. 45

B. 36

C. 15

D. 180

Evaluate 3 ● 5 ● 3 ● 4.

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•p 20 #9-27 odd, 31-49 odd, 56-59

•Mixed Review 1