Ordinary Differential EquationsOrdinary Differential Equations Swaroop Nandan Bora...
Transcript of Ordinary Differential EquationsOrdinary Differential Equations Swaroop Nandan Bora...
Ordinary Differential Equations
Swaroop Nandan Bora
Department of Mathematics
Indian Institute of Technology Guwahati
Guwahati-781039
Teachers’ Training Camp, IITG, June 30, 2016
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Modelling a situation
We study a model, a sort of idealized world
that contains things we do not see come across in everyday life.
We study straight lines, rectangles, circles, spheres.
NOT a burger or a chair or a hill or a human being.
If one works in a practical area of mathematics
then there will be two conflicting criteria which makes a good model.
On the one hand,
the model should be accurate enough to be useful.
On the other hand,
it should be simple and elegant enough to generate realistic and interesting
mathematical problem.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Modelling a situation
It is tempting, as a mathematician,
to attach far more importance to the second criterion:
mathematical interest and elegance
rather to the first:
accuracy .
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Mathematicians’ Approach
In particular, if mathematicians work on difficult practical problems
they do not do so in isolation from the rest of mathematics.
Rather, they bring to the problems several tools –
mathematical tricks, rules of thumb, theorems known to be useful and so on.
They do not know in advance which of these tools they will use, but they hope
that
after they have thought hard about a problem they will realize what is needed to solve
it.
If they are lucky, they can simply apply their existing expertise straightforwardly.
More often, they will have to adapt it to some extent.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Practical Problems: Applicable mathematics
LET’s now move to the practical side of mathematics in various stages.
In doing so, we need to restrict ourselves
since applications are also as vast as the subject itself.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Tea/Coffee
Figure : Hot Coffee
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Tea/Coffee
Figure : Cold Coffee
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Falling Body
Figure : Falling Body
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Pendulum
Figure : Motion of a pendulum
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Impulsive Force
Figure : Impulsive Force
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
River
Figure : River flow with current
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
River
Figure : Quiet River flow
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Sloshing
Figure : Sloshing
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Building Construction
Figure : Building Construction
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Flow through porous media
Figure : Aquifer
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Ocean wave mechanics
Figure : An ocean wave
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Ocean Engineering
Figure : Rectangular platform in ocean
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Ocean Engineering
Figure : Offshore Oil drilling platform
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Figure : An aeroplane in its flight
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
General Information
Many of the general laws of nature – in physics, chemistry, biology and
astronomy –
find their most natural expression in differential equations.
Applications are mainly in the areas of mathematics itself, engineering, economics and
many other fields of applied sciences.
Why is it so??
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Differential Equations
We know that if y = f(x) is a given function,
then its derivativedy
dxcan be interpreted as the rate of change of y with respect to x.
In many natural processes,
the variables involved and their rates of changes are connected to one another by
means of the basic scientific principles that govern the process.
When this connection is expressed in mathematical symbols, the result is quite often a
differential equation. Let us consider some examples we already know.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Example 1
According to Newton’s second law of motion, the acceleration a of a body of
mass m is proportional to the total force F acting on it, with 1/m as the
constant of proportionality,
so that a = F/m or
ma = F. (1)
Suppose, for instance, that a body of mass m falls freely under the action of gravity
alone, then the only force acting on it is mg.
If y is the distance down to the body from some fixed height,
then its velocity v =dy
dtis the rate of change of position and its acceleration
a =dv
dt=
d2y
dt2is the rate of change of velocity.
With this notation,
(22) becomes
md2y
dt2= mg,
or,d2y
dt2= g. (2)
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Example 1
If we change the situation by assuming that there is an air resistance proportional
to the velocity,
then the total force acting on the body is mg − k(dy/dt).
(22) becomes
md2y
dt2= mg − k
dy
dt. (3)
Equations (??) and (??) are the differential equations that express the essential
attributes of the physical processes under consideration.
They are respectively called undamped and damped motion of the body.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Example 2
Newton’s Law of Cooling states that the rate of change of the temperature of an
object is proportional
to the difference between its own temperature and the ambient temperature (i.e. the
temperature of its surroundings).
Newton’s Law makes a statement about an instantaneous rate of change of the
temperature.
When we translate this verbal statement into mathematical symbols,
we arrive at a differential equation.
The solution to this equation will then be a function that tracks the complete record of
the temperature over time.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Example 2
If T is the temperature of an object at time t and S is the temperature of its
surroundings,
then this law formulates intodT
dt= −k(T − S), (4)
where k is a constant of proportionality.
If T0 is the initial temperature,
the temperature of the object at any time t is given by
T (t) = S + (T0 − S)e−kt. (5)
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Example 3
Consider a pendulum of length l
whose bob has a mass m
Then the equation of motion (undamped case) is given by
d2θ
dt2+
g
lsin θ = 0.
Is this the equation we usually know?
Or the equation we know is different from this?
The accepted form is the linearized version
d2θ
dt2+
g
lθ = 0.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Boundary and Initial Conditions
Boundary conditions are conditions prescribed on the boundary
Boundary may be boundary with respect to any of the independent variables
Initial conditions are conditions prescribed at one point only
These conditions are in terms of some form of the dependent variable at some
specific value of the independent variable
The main component of this type of problems is what is called Governing Equation
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Boundary and Initial Conditions (Contd.)
With respect to ODEs
we can have only boundary conditions or only initial conditions, not both for the same
problem
They are called boundary value problems or initial value problems.
However, with respect to PDEs
We can have both boundary conditions and initial conditions for the same problem
This type of problems are called
Initial Boundary Value Problems (IBVP)
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
BVPs and IVPs
A boundary value problem is a differential equation together with a set of additional
constraints, called the boundary conditions.
In other words, a solution to a BVP is a solution to the differential equation which also
satisfies the boundary conditions.
To be useful in applications, a BVP should be well-posed. This means that given the
input to the problem there exists a unique solution, which depends continuously on the
input.
An initial value problem (IVP) consists of a differential equation and a set of
conditions to be satisfied at the initial value of the independent variable (for ODE) or
at that of one of the independent variables (for PDE).
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
BVPs and IVPs
A more mathematical way to picture the difference between a BVP and an IVP is
an IVP has all of the conditions specified at the same value of the independent variable
in the equation (and that value is at the lower value of the boundary of the domain,
thus the term ‘initial’ value), while a BVP has conditions specified at the extremes of
the independent variable.
For example
for a second-order differential equation
if the independent variable is time over the domain [0, 1], an IVP would specify a value
of y(t) and y′(t) at time t = 0, to be precise, the initial conditions will be something
like y(0) = α, y′(0) = β.
On the other hand
a BVP would specify values for y(t) (or its derivatives) at both t = 0 and t = 1, to be
precise, the boundary conditions will be something like y(0) = α1, y(1) = β1 or
y′(0) = α2, y′(1) = β2.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
IBVPs
If the problem is dependent on both space and time (meaning the governing
equation is a PDE)
then instead of specifying the value of the problem at a given point for all time only,
data could be given at a given time for all space also.
This type of problems is known as initial boundary value problems (IBVP).
Prime examples are the problems
involving the wave equations and the transient heat conduction equations.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Types of conditions
The type of boundary conditions that will be considered for a BVP will depend on the
dimension of the object under consideration.
For example
for the heat conduction in a thin rod, the boundaries will be the two end points of the
rod
while
for a thin rectangular plate, the boundary will consist of the four edges that bound the
plate
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Types of conditions
If the boundary conditions are prescribed in terms of some values of the dependent
variable (solution of the BVP) on the boundary, then these conditions are called
Dirichlet Conditions and the corresponding BVPs are called Dirichlet boundary value
problems
If the boundary conditions are prescribed in terms of some values of the normal
derivatives on the boundary, then these conditions are called
Neumann conditions and the corresponding BVPs are called Neumann boundary value
problems.
Neumann conditions are also known as flux conditions. If there is no flux across the
boundary, then the flux conditions become insulation conditions (for heat conduction
problems).
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Types of conditions
If the boundary conditions for a specific problem contain both types, then these
conditions are called
mixed or Robin conditions and the corresponding BVPs are called Robin boundary
value problems.
For heat conduction problems, Robin conditions are also known as radiation conditions.
A typical problem in heat conduction may have a combination of Dirichlet,
flux/insulation and radiation boundary conditions.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Continuity conditions
Sometimes there may be virtual boundaries.
Say
For a fluid problem, the fluid is of two layers.
Then
at the boundary of the layers, called interface, there exist some conditions
known as
continuity conditions
They usually imply
continuity of pressure and velocity along the boundary
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Idealizations
Given to us:
a real life problem
Can
we solve the problem exactly with the given conditions?
Perhaps not.
Under this circumstances
we need to idealize the situation, that is, we want to ignore some of the given
situations/properties in order to obtain a feasible solution.
What do we do?
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Idealizations
Idealization can take place in three ways
Property
Governing Equation
Boundary Conditions
We need to idealize the situation, that is, we want to ignore some of the given
situations/properties in order to obtain a feasible solution.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Moving ahead
Recall Newton’s Second Law of Motion
F = ma
In terms of differential equation, it is
d2y
dt2= g
and the solution can be obtained as
y =gt2
2+ c1t+ c2
Given two initial conditions
the arbitrary constants can be eliminated
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Moving ahead
Does the equation represent the real situation?
Perhaps not. What was ignored??
–The air resistance the particle encounters while falling down
If air resistance is taken into account,
md2y
dt2= mg − k
dy
dt
A new term is appended due to the air resistance
The former equation is an idealized version of the latter one.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Moving ahead
Now consider the pendulum equation
What was ignored??
–The air resistance the bob encounters while moving from one end to the other
Now what we will have a
damped version of the equation.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41
Remarks
There are many functions/polynomials
which are solutions of some specific ODEs.
They are called special functions, such as
Bessel function, Legendre polynomial, Hermite polynomial, Laguerre polynomial etc.
More interestingly, they
are part of Mathematical Physics rather than only of Mathematics.
Swaroop Nandan Bora [email protected] (Department of MathematicsIndian Institute of Technology GuwahatiGuwahati-781039 )IITG, Differential EquationsTeachers’ Training Camp, IITG, June 30, 2016
/ 41