OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.)...

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OPENER : Solve and CHECK the following equations. 1.) 12 + a = 36 2.) t – (16) = 9 10 5 2 y 3.) ¼ + x = ⅔ 4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 x = 12 5 12 3 12 8 2 5 ) 1 10 ( ) 5 2 ( 2 5 y y = 25

description

Solve Multi-Step Equations To solve equations with more than one operation, often called multi-step equations, undo operations by working backwards.  For example, 2x + 1 = x = x = 4 CHECK!! 2x + 1 = 9 2(4) + 1 = = 9 9 = 9

Transcript of OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.)...

Page 1: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

OPENER: Solve and CHECK the following equations.1.) −12 + a = − 36 2.) t – (−16) =

9

1052

y3.) ¼ + x = ⅔ 4.)

+12 +12 t + 16 = 9

a = -24 -16 -16

t = -7

-¼ -¼

x = 125

123

128

25)

110()

52(

25

y

y = 25

Page 2: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

Algebra 1 ~ Chapter 3 - 4

Solving Multi-Step Equations

Page 3: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

Solve Multi-Step Equations To solve equations with more than one operation, often called multi-step equations, undo operations by working backwards.

For example, 2x + 1 = 9 -1 -1 2x = 8 2 2

x = 4

CHECK!!

2x + 1 = 9

2(4) + 1 = 9

8 + 1 = 9

9 = 9

Page 4: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

Example – Solve and Check!1.) 7m – 17 = 60 + 17 +17

7m = 77 7 7

m = 11

CHECK

7m – 17 = 60

7(11) – 17 = 60

77 – 17 = 60

60 = 60

2.) − 2a + 10 = 22 - 10 -10

-2a = 12 -2 -2

a = -6

CHECK-2a + 10 = 22-2(-6) + 10 = 2212 + 10 = 2222 = 22

Page 5: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

Example – Solve and Check each equation.3.)

-6 -6

y = -153

4563

y

513

y

3)51()3(3 y

4.)

4x + 5 = -35

- 5 -5

4x = -40

4 4

x = -10

5754

x

7)5()754(7

x

Page 6: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

Examples – Solve and Check!!5.) 6.)

118

23

a 1724

b

Page 7: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

Writing EquationsEx. 1 – “Twelve decreased by twice a number equals -34.”

12 – 2n = -34

Ex. 2 - “Two-thirds of a number minus six is -10.”

⅔n – 6 = -10

Ex. 3 – “A number is multiplied by seven, and then the product is added to 13. The result is 55.”

7n + 13 = 55

Page 8: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

Solve a Consecutive Integer Problem*** Find three consecutive integers whose sum is 42.

“3 #’s in a row”

Integer #1 = n

Integer #2 = n + 1

Integer #3 = n + 2 (n) + (n + 1) + (n + 2) = 42

3n + 3 = 42

3n = 39

n = 13

Conclusion - The three consecutive integers whose sum is 42 are 13, 14 and 15.

*** 13 + 14 + 15 = 42

Page 9: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

Example – Find three consecutive ODD integers whose sum is -51.Integer #1 = n

Integer #2 = n + 2

Integer #3 = n + 4

Remember we are only looking for odd numbers, so every OTHER number!!

(n) + (n + 2) + (n + 4) = -51

3n + 6 = -51

3n = -57

n = -19

So the three consecutive odd integers are -19, -17 and -15.

Page 10: OPENER: Solve and CHECK the following equations. 1.) − 12 + a = − 362.) t – ( − 16) = 9 3.) ¼ + x = ⅔4.) +12 +12 t + 16 = 9 a = -24 -16 -16 t = -7 -¼ -¼.

Example – Find three consecutive EVEN integers whose sum is 72.Integer #1 = n

Integer #2 = n + 2

Integer #3 = n + 4

Remember we are only looking for even numbers, so every OTHER number!!

(n) + (n + 2) + (n + 4) = 72

3n + 6 = 72

3n = 66

n = 22

So the three consecutive even integers are 22, 24 and 26.