Online Mock NMAT 01 Analysis

8/8/2019 Online Mock NMAT 01 Analysis

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ANA

LYSI

S

Detailed Solutions

Online-NMAT # 01ANALYSIS

P

TE

ducation,A

llr

ights

reserve

d.

IC : PTpnr

Corp. Office: Delhi Regd. Office: IndorePT centres spread across India ~ Established 1993

Our motto Kar Ke Dikhayenge is delivered through ourunique Technology Driven Process Engine (TDpro engine).

Email: pinnacle@PTeducation .com Web: www.PTeducatio n.com

1 . Ans.(1). The opening paragraph very clearly states that the main objective of the British

Government was to place Britain on the top of the world as regards usage of Internet and

promote e-commerce. Option (1) seems to be the most apt one. Other options (2), (3), (4)

and (5) are incorrect ones.

2 . Ans.(4). Option (4) is the correct one. The first job of Britains first e-minister was to

introduce Internet usage in schools and make the teachers adapt themselves to the

system. Libraries have Internet arrangements whereby references could be on-line.

Other options (1), (2), (3) and (5) are incorrect.

3 . Ans.(3). Option (3) is what the passage says. Other options (1), (2), (4) and (5) are not

the correct ones. The government wants to procure 90% of low-value requirements and

render 25% of its services online.

4 . Ans.(3). The 8th paragraph mentions that the parliament is tabling the Electronic

Commerce Bill which will give legal force to electronic signatures. This is in tune with thethird option. Hence, the answer is (3). Options (1), (2), (4) and (5) are incorrect in the

light of the passage and hence can be discarded.

5 . Ans.(5). The correct solut ion is (4). The passage makes a candid observation that

prohibit ively high costs might deter people from having an access to Internet. I f the

government were to take care of this and reduce the cost substantially, the number of

users would rise. Other options (1), (2), (3) and (4) are incorrect.

6 . Ans.(3). Option (3) is the correct pick. The passage states about the manner in which

British Telecom (BT), the single company which controls the pricing and the persons at

the helm of affairs, have not been able to arrest this monopolist ic behaviour. Otheroptions (1), (2), (4) and (5) are not appropriate.

7 . Ans.(4). Options (1), (3) and (5) can be sidelined as they do not qualify to be the captions.

These are examples put down by the author to clarify the main idea. Option (2), though

focuses on the main issue, is not all encompassing. Option (4), by representing thepassage in a holistic manner, becomes the apt caption for the passage.


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8 . Ans.(1). In the ninth paragraph, it is stated that architecting a business involves far more than

merely re-engineering business processes. So, option (1) is the apt answer. Options (2), (3), (4)and (5) can be sidelined as they are not the desired answers.

9 . Ans.(2). The author, in the tenth paragraph, holds that e-business strategists should expand

their horizons to search for radical thinking, which includes new schemes, new configurations

and game-changing business architectures. Hence, the answer is (2). Options (1), (3) and (5)are not upheld by the author.

10 . Ans.(3). In the eleventh paragraph, the author gives the example of insurance business, in

order to show the implications of doing business on the net, bypassing agents. These companieshave a lot of distribution and lead generation channels. Option (3) is in tune with the above idea

and therefore, is the apt answer. Options (1), (2), (4) and (5) can be sidelined as they are

inappropr ia te .

11. Ans.(5). In the last lines of the passage, the author clearly states the essence of strategy. Option

(5) puts down the strategy as it is and hence, it is the apt answer. Options (1), (2), (3) and (4) canbe ignored as they are not the desired answers.

12 . Ans.(4). Prosaic refers to being dull, commonplace and banal means being ordinary, boring.The relationship is that of synonyms. Articulation means the art of vocal expression. The correct

relationship is displayed in option (4). Hence prosaic is related to banal as articulation to

voice. None of the other options display this type of relationship.

13 . Ans.(3). Peripatetic means a person who walks or travels about pericentric means arrangedor situated around a centre or central body. Peripheric means located on a circumference.

Parabasis means go aside, step forward. Pharisaical means hypocritical, self-righteous

osseous means pertaining to bone apogee means the point furthest from the earth in the

path of a body orbiting around the earth. Itinerant means a person who travels in connectionwith sell ing. Hence it is evident that option (3) best expresses the relat ionship between the

words which is similar to the one expressed in the given pairwhen 'relaxed' one feels to have

relief from pain, burden etc. The remaining options can be sidelined, as they do not have words

expressing a relationship similar to the one in the given pair.

14 . Ans.(1). Conscript means to compulsorily enlist for State service especially military service.Draft also means the same, malfeasance means evil doing, monad means a simple organism,

any ultimate unit of being scad means a fish having an elongated body and very large spiky

scales. Philter means a drink supposed to excite a sense of sensuality in the drinker. Option

(1) contains words that exhibit a synonymous relationship which is similar to that in the given

pairmonody means a poem lamenting a persons death while 'dirge' also means a slow sad

song etc. The remaining options can be discarded for they do not contain words that exhibit arelationship similar to the one expressed in the given pair.

15 . Ans.(3). Sophic means learned, wise. Encomium means praise in a high-flown language.

Sophomoric means pretentious, crude, immature juvenile, superf icial erudite means

learned multitudinous means numerous vicissitudinous means change of circumstances,variations in fortune. The given pair has words displaying a synonymous relationship. Hence,

the search is for that option which has words showing a similar type of relationship. Option (3)

best comes out with words whose relationship is synonymous with those appearing in the given

pairhosanna means an expression of adoration while hymn means a song of praise that

Christians sing to God. The remaining options can be bypassed as they do not have words thatexpress the relationship matching with that in the given pair.


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16 . Ans.(3). Epitaph means words written in memory of a person who has died inscription means

words written on a monument, coin, stone or in a book. Obverse means the counterpart of afact or a truth. Epiphora means excessive watering of the eye. Diaspora means dispersion

of a group of people. The given pair contains words that are related to one another. The

relat ionship is that of synonyms. The search is for that option which contains words that are

similarly related puncti l ious means precise in behaviour while ' inscript ion' also means awritten expression or carving. Option (3) best fits in as the apt one. The remaining options can

be bypassed, as they do not contain words displaying a similar type of relationship.

17 . Ans.(3). Options (1), (2), (4) and (5) do not fit into the blank grammatically. Option (3) 'plan to' fits

into the blank most suitably.

18 . Ans.(3). The clue is could not be used. Hence, crushed under option (3) is contextually and

grammat ica l ly correct . Opt ions (1), (2) , (4) and (5) are contextua l ly incorrect , hence not

considered.

19 . Ans.(5). The clue is discussed enough. So, option (5) best fits into the blank. Options (1), (2),(3) and (4) are contextually incorrect.

20 . Ans.(2). Only option (2) despite can fit into the blank grammatically. Options (1), (3), (4) and (5)are incorrect.

21 . Ans.(1). Effective measures could prevent the recurrence of events. Options (2), (3), (4) and (5)

cannot fit into the blank contextually and grammatically. Only option (1) is the apt answer.

22 . Ans.(2). In option (2), disapprovingly is the correct replacement.

23 . Ans.(2). In option (2), she answers in a flash is the apt replacement.

24 . Ans.(2). In option (2), presence of women is the correct replacement.

25 . Ans.(1). In option (1), keep away from is the proper usage.

26 . Ans.(1). In option (1), bizarre perceptions is the correct usage.

27 . Ans.(5). (BD) is the key. (1) opens the paragraph by stating that combat is ill affordable to wildanimals. (C) follows (1) by referring to it. (A) further elaborates (C) and (D) refers to (A). (D) also

helps (6) to conclude the paragraph.28 . Ans.(2). (DC) is the key. (1) opens the paragraph by unfolding the cause of the destruction of

ozone layer. (D) strongly puts forth an argument for the stoppage of production of CFC. (B)

follows (C). (A) gives more data to substantiate (B). (A) also helps (6) to conclude the paragraph.

29 . Ans.(4)

30 . Ans.(3)

31 . Ans.(1)

32 . Ans.(1)

33 . Ans.(3) 34 . Ans.(4)

35 . Ans.(2) 36 . Ans.(3)

37 . Ans.(3) 38 . Ans.(5)

39 . Ans.(2) 40 . Ans.(1)

41 . Ans.(1) 42 . Ans.(2)

43 . Ans.(5) 44 . Ans.(3)45 . Ans.(4) 46 . Ans.(3)

47 . Ans.(1)


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48. Let the fraction be x/y.

According to the question,x

y

+

+=

1

1

4

5

5x + 5 = 4y + 4 5x 4y + 1 = 0 .....(1)

x

y

-

-=

5

5

1

2 2x 10 = y 5 2x y 5 = 0 .....(2)

Solving these two equations we get, x = 7, y = 9.

\ Required fraction = 7/9. Ans.(4)

Short-cut: Work back from the options.

49. Let starting salary = X and Annual increment = Y

According to the question, X + 4Y = 1500 .....(i)

and X + 10 Y = 1800 .....(ii)

By substituting the value of X + 4Y in equation (ii) from equation (i) we get

6Y = 300 Y = Rs.50, X = Rs.1300. Ans.(5)

Short-cut: Salary increase in 6 years is Rs.300 means Rs.50 every year, that means at the startit should Rs.1300. (200 increase in 4 years becomes 1500)

50. If coordinates of 3 vertices of a triangle are (x1, y1), (x 2, y 2) and (x 3, y 3)

then the coordinates of centroid are

x = (x1 + x2 + x3)/3 and y = (y1 + y2 + y3)/3.

So, the vertices of three triangles are (7/4, 1/2), (3/4, 9/2), (5/4, 8/2). Ans.(3)

51. Let Y get Rs.100. Therefore X gets Rs.125.

Hence S = Rs.(100 + 125) = Rs.225.

Percentage of money that X gets = (125 100)/225 = (500/9)%. Ans.(1)52. Here, OC = 3, PC = 1, \ OP = 2

A

O

Q

B

C

P

q

In triangle OPQ, sinq = =PQ

OP

1

2

q = 30 Angle of sector = 60

Required Area =

60

360

p 9 =

3

2

p

. Ans.(2)

53. Student two take approximate 110 seconds in first trial and after that it reduce to 60 and 30seconds in trial 2 and 3 respectively. After trial three student two maintain the time of 30seconds through trial 5. Now by comparing with the performance of other two we can easilysay that the best performer is student two on the basis of time graph. Ans.(2)


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54. Student one make 135 errors in the first trial, he consistently reduces the error in each trialand in fifth trial he make 30 errors. By comparing with the other students it is clear thatstudent one is the best performer on the basis of error graph. Ans.(1)

55 . Ans.(1)

56 . Ans.(1)

57. Statement (A) alone gives = = CQR BQR BQC1

2, but this is not sufficient to get the answer.

Statement (B) alone gives = = AQP PQC AQC1

2, but this is also not sufficient to get the answer.

Combined statements (A) & (B) give

= + = + PQR PQC CQR AQC BQC12

[ ] = 12

[ ]AQB ,

but whether AQB is a straight line or not is not given. So we can not get the answer even usingboth statements. Ans.(5)

58. Let the side of the given square be a units.

From statement (A) we get, 2 5( 2 1 5a a a- = - =) units.

Required area = a 2 = 25 square units. So, statement (A) alone is sufficient.

From statement (B) we are not getting anything as it is a gives known fact. Ans.(1)

59. Statement (A) gives only their LCM, so this does not give a unique answer.

Statement (B) gives only their HCF, so again this alone does not give a unique answer.

On combining statements (A) and (B) we get, 9p and 9q are the required numbers

Then, 9pq = 108 pq = 12 (1, 12) & (3, 4).

But two digit numbers are obtained only from (3, 4). Ans.(3)60. Let the numbers be x & y. Statement (A) gives, x y = 12 (HCF). This is a linear equation with

three unknowns, so statement (A) alone is not sufficient. Statement (B) gives only their HCF, sothis is also not sufficient. Combining statements (A) & (B) gives that x & y are multiples of 6.

Let x = 6p, y = 6q and 6pq = 72 pq = 12. So, the possible value of p, q is (1, 12) or (3, 4) andrequired number is (6, 72) or (18, 24). So combined statements also dont give a unique answer.Ans.(5)

61. Statement (A) gives only the area of the triangle but does not give the type of triangle andinformation about A. So, statement (A) is not sufficient.

Statement (B) gives that A is the intersection of medians but no other data is given. So, we can notanswer the question.

Taking both statements (A) & (B) together we get that side of triangle

2500 34

3

50 2 100 = = metres.

Median = - = =100 50 150 50 50 32 2 metres.

Required PA = =2

350 3

100

33 metres. Ans.(3)


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62. Let the maximum marks be x and passing marks be y.

\ From the given conditions, we get

0.25x + 60 = y

0.42x 8 = y

Solving both these equations we get, x = 400.

Hence maximum possible marks in the test are 400. Ans.(3)

63. Let the number of child workers be X.

\20 25 15 20 8

20 1521 5.

+ +

+ += =

X

XX Ans.(2)

64. Number of transmissions made by the new and the old robots are X and

X/8 respectively per hour each.

Total number of transmissions per hour = XX X

+ =8

9

8

Total in 5 days, i.e., 120 hours =9

8

X 120 = 135 X. Ans.(5)

65. Every hour, it moves 360/12 = 30.

Every minute it moves 30/60 = 0.5.

Thus total degrees covered = (4 30) + (24 0.5)

= 120 + 12 = 132. Ans.(5)

66. A tourist starts from O.

O

E

7 D

33

A

BC

2

10

OE = 5 Km. (South). Ans.(4)

67. Directly checking options we get 1681 = 41, 16 = 4, 81 = 9. Ans.(2)

68. Since on the whole a man neither gained nor lost anything, the gain on one was equal to the losson the other

25

100of cost of one =

331

3100

of the cost of the other.

The ratio = 331

3: 25 = 100 : 75 = 4 : 3

The cost of the first =1120 4

7= Rs.640.

The cost of the second = Rs.(1120 640) = Rs.480. Ans.(1)


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69. The circle on BC as diameter will subtend 900 at D. Therefore CD is the altitude from C to AB.Therefore D will be the mid point of AB.

The area ofD BDC = 1/2 D ABC =1

2

3

414 49

3

2

2 2F

HG

I

KJ = .c h cm

The area of semicircle BDC = (p/2) r2 = p/2 (49) = 49/2 22/7 = 77 cm 2.

\ The area of the shaded portion = 77 493

2-

F

HG

I

KJ

F

HGG

I

KJJcm 2. Ans.(2)

70. Let the number of articles of types A, B and C be "3a", "2a" and " 3a" respectively. Thus, we get,

(150 3a) + (90 2a) + (60 3a) = 3240 a = 4.

Hence, the number of articles of type "B" = 4 2 = 8. Ans.(2)

71. 73 + 17 + 53 + 86 = 229. Total requirement till 13th day = 223. So, he places order on 13th day.Ans.(3)

72. The required dif ference =2071 104.4

360

2199 79.2

360

-

= 600.59 483.78 = Rs.116.81 crore. Ans.(2)

73. Morning of 7th day + 48 hours = Morning of 9th day.

Hence the requirements of 9th day should be checked.

Total requirements till the end of 9th day = 163 which can be met by the starting inventory itself. Ans.(1)

74. Starting inventory = 100, Total pilferage = 5 15 = 75,

Total requirement = 253.

Net total to be ordered = 253 100 + 75 = 228. Ans.(4)

75 . Ans.(5)76. Let us assume that Indians spent $100 in 1998

In 1998 In 1999

Indi vi duals 7 1 71 2 = 142

Governm ent 2 5 25 4 = 100

Insu rance 4 4 4 = 16

Total 100 258.

Required percent = (142/258) 100 = 55%. Ans.(1)

7 7 . T h e m o n e y s p e n t b y t h e S t a t e & l o c a l g o v e r n m e n t s i n C h i n a i n th e y e a r

1998 = =6 820

1001 36. $ . billion

T h e m o n e y s p e n t b y t h e S t a t e & l o c a l g o v e r n m e n t s i n I n d i a i n t h e y e a r

1999 = =3 5

25

100 0 875. $ . billion .

Required percentage dif ference =-

= 1 36 0 875

0 875100 55 43% 55%

. .

.. .

Ans.(4)


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78. Total money spent by individuals in India on healthcare

= $2.48 billion $2.5 billion.

\ Total healthcare spending in Asia = (100/5) 2.5

= $50 billion. (Nearest option). Ans.(4)

79. The total amount spent by individuals of three countries in the year 1998

= + + 3 571

1006 8

45

10049 5

35

100. . .

= 2.485 + 3.06 + 17.325

= $22.87 $22.5 billion. Ans.(3)

80. In 1999, total healthcare spending in US = 49.5 1.5 = $74.25 billion.

The spending by individuals in US in 1999

= = 74 2545

10033 41 33 50. $ . $ .billion billion . Ans.(3)

81. Option (1) is eliminated as V is operated before R. Option (2) is eliminated as the endprogram is W. Option (4) is eliminated as T is not operated after Q. Ans.(3)

82. Since V is operated after R and cannot operated on the last position. So R cannot beoperated at fourth place. Ans.(3)

83. If R is operated at third place then V must be operated on fourth place. Now for the secondplace only possibilities remaining will be S, U or T. Q cannot be at second place as T isoperated after Q. Ans.(5)

84. Option (1) is not correct as Ashish is not with Swatantra or Manoj. Options (2) and (3) are not

correct as Manoj cannot be in the red canoe. Option (4) is correct as it satisfies all the conditions.

Ans.(4)

85. If two people are in the green canoe, Manoj is there and the other person, either Jitendra or

Gajendra should be with Manoj. Ans.(3)

86. When any change takes place between the groups only one person, i.e. Sachin can change thecanoe. Ans.(2)

87. Since Ashish is in the red canoe, Swatantra or Manoj should be there with him. But as Manoj is

always in the green canoe, so Swatantra is there with Ashish. Ans.(1)

88. Statement I may not be true as Gajendra could have travelled with Sachin in the red canoe.

Statements II and IV are perfectly correct as only Gajendra or Jitendra can be with Sachin in order

to satisfy all the conditions. Statement III is not certain as it may be Gajendra also. Ans.(2)

89. 3 9 6 9 9 2 6 9 3 4 9 2 3 9 3 4 8 6 9 6 3 7 3 9 3 2 5 1 9 4.

1 2

We want a group of 3 numbers with "9" at the centre such that it would be exactly divisible by bothits preceding and following numbers. There are 2 such groups. (See the underlined groups

above). Ans.(4)

90 . Ans.(1). All rhombus are quadrilaterals. All quadrilaterals are polygons.

Quadrilaterals

PolygonsRhombus


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91. The maximum 9 edges you can trace. To verify this, we can make a drawing of a cube, and number

each of its 12 edges.9

1

2

3

4

5

6

7

8

Then, always starting from 1 corner and 1 edge, you can determine all of the possible combinations

for tracing along the edges of a cube. Ans.(5)

92. Clearly, `dog' is reared as pet. But `dog' is called `mongoose'. So, a `mongoose' is reared as pet.

Ans.(3)

93. Counting from the right in the given alphabet series i.e. Z, the eleventh letter is P. The sixth letter

to the right of P is V. Ans.(2)94. The alphabets are coded as shown i.e. P as 3, I as 1, L as 8, E as 2 and R as 6. So, PILLER is coded

as 318826. Ans.(1)

95. The advertisement does not mention the provisions of the coaching classes. So, assumption I is

not implicit . Clearly, the advert isement is meant for students who expect success on joiningcoaching classes. So, assumption II is implicit. Ans.(2)

96. The advice particularly mentions a specialist doctor and not simply doctor. So, assumption I is

implicit. It is not mentioned whether B agrees or not with As advice. So, assumption II is not

implicit . Ans.(1)

97. The lacking of stimulation in first four or five years can be adverse because it is the main period

of development. So, assumption I is implicit. Since, nothing is mentioned about the predictability

of intelligence, assumption II is not implicit. Ans.(1)

98. The thorough overhauling is needed only in case of an obsolete system. So, assumption I is

implicit. Overhauling is done for improvement. So, assumption II is also implicit. Ans.(4)

99. According to statement banking is connected to business activity. So, assumption I is implicit.Banking is adjusted in a way to promote business needs. This means that business is promotedby better banking. So, assumption II is also implicit. Ans.(4)

10 0. G and B have some area in common. So, I follows.W

B

G

G and W have some area in common.

III does not always hold.

Since B lies within W, so IV does not follow. Ans.(1)

1 0 1 .

F B

C

C

Clearly, i t follows from the Venn diagram that some cakes are frogs and some are not i.e.,conclusions III and IV cannot follow. Ans.(2)


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102 . Clearly, two Venn diagrams (i) and (ii) are possible as shown.

P C

B

(i)

P C

B

(ii)

From diagram (i), conclusions III and IV follow.

From diagram (ii), conclusions I and III and IV follow.

The common solution is Only III and IV follow. Ans.(1)

103 . Since R and S must both be females, so, S cannot be X's son. However. P, Q, T and U each couldbe X's son because any of them might be a male. Ans.(5)

104 . The only son among the six relatives is X's son. If U were T's son, then U would also be X's son. Accordingly, T would be X's husband. However, T and U cannot both be males. Thus statement(4) is false. Ans.(4)

105 . If Q is U's daughter then Q and U must either be X's daughter and husband respectively, or X'ssister and mother respectively. If P is X's sister, P and Q would both be females, which is i mpossibleso option (1) must be false. Since none of the six relatives could be U's niece, so option (2) mustbe false. If T and S would have to be X's son and sister respectively. Accordingly, U and Q wouldhave to be X's husband and daughter but T and U cannot both be males. So, option (3) must befalse. Option (4) could be true because U would be X's mother, S would be U's sister and Q wouldbe X's sister. Ans.(4)

106 . "Bicycle" i s not an automobile. In the code language, "bicycle" is called "scooter". Ans.(2)

107 . After reversal of the second half of the sequence of alphabets, we get

A B C D E F G H I J K L M Z Y X W V U T S R Q P O N. The eleventh lette r from the left end of the abovesequence of alphabet is K. The letter which is 4th to the right of K is Y. Ans.(3)

Short-cut: Simply count (11 + 4) = 15th letter from the left after changing the second half.

108. Ans.(2)

109. Ans.(5)

For Q.110 to Q.113:

Here the positions of two elements (M, N) and the existence of an overlap between J & K are

uncertain these uncertainties are indicated by broken lines.

k

H

C

J

ML

N


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110. From the diagram, statement 6 says that all Ms must lie outside the Cs, but all Ns must lie insideMs, according to statement 5. Since the only information about Ms is that they are not Cs noneof the other statements, which attempt to put Ms inside or outside the Hs, can be deduced. Ans.(4)

111. This statement is inconsistent with the condition that no Ms are Cs. Option (1) is possible if wecould draw the C circle so that it coincided with the H circle. Options (2) and (4) are all possible,

since we can draw M anywhere outside C. Ans.(3)

112. It states that all Cs are Js or Ks, but doesnt exclude the possibil ity that some Cs are both andthat J & K overlap. So statement 4 doesnt imply the statement given here, and (I) is out. It ispossible that no Ls are Js, however, even if J & K do overlap (II). Finally the additional statementwould mean that if Ls were Ks, they couldnt be Js (III). Ans.(4)

113. Option (1) is not necessarily true, for the reasons given in the answer to above question. Options(2) & (3) are possible, but not necessarily true. It would be true only if the Js and Ks overlapped

completely. Option (4) is correct. Statement 2 means that any C that is not a K must be a J. Notethat this option is true even if Js and Ks do not overlap completely. Ans.(4)

114. The two women are not blood relatives. So, from (2), if the teacher is a woman, the manager is aman. Then, from (3), the teacher is a man. Because a contradiction arises from assuming theteacher is a woman, the teacher must be a man. Mr. Pitambars son i s the youngest of the four andis a blood relative of each of the other three. So from (1), the teacher is not Mr. Pitambars son.Then we know the occupation of Mr. Pitambar : he is the teacher. From (1), the manager cannotbe Mr. Pitambars mother. So the manager is either his wife or his son. The teacher may be olderthan the manager. Hence we dont know the occupation of anyone else. Ans.(1)

115. Maximum number of people involved in the scam = 7 + (7 2) + (7 4) = 49. Ans.(5)

For Q.116 to Q.120:

The last sentence gives a definite information about the positions of Fiat and Ambassador. If Fiat

is at one of the ends and it is third to the left of Ambassador, it must be at the left end. Hence:

Fi ___ ___ Am ___ ___ ___

Now, the second sentence gives comparative information about Fiat and Fargo. Hence:Fi ___ ___ Am Fa ___ ___

Now, by virtue of the first sentence:

Fi ___ ___ Am Fa Ca ___

Now, the third sentence. Maruti must be to the left of Ambassador since the right place is already

filled. Hence, Bedford and Maruti would come to the immediate left of Ambassador. The rightmost

place would then go to the only car remaining, viz. Mercedes. Hence, the final arrangement will

be :

Fi Be Ma Am Fa Ca Me

116. Ans.(4) 117. Ans.(2)

118. Ans.(4) 119. Ans.(1)

1 2 0 . Ans.(3)


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Objective key

1.(1) 2.(4) 3.(3) 4.(3) 5.(5)

6.(3) 7.(4) 8.(1) 9.(2) 10.( 3)

11.(5) 12.(4) 13.(3) 14.(1) 15.(3)

16.(3) 17.(3) 18.(3) 19.(5) 20.(2)

21.(1) 22.(2) 23.(2) 24.(2) 25.(1)

26.(1) 27.(5) 28.(2) 29.(4) 30.(3)

31.(1) 32.(1) 33.(3) 34.(4) 35.(2)

36.(3) 37.(3) 38.(5) 39.(2) 40.(1)

41.(1) 42.(2) 43.(5) 44.(3) 45.(4)

46.(3) 47.(1) 48.(4) 49.(5) 50.(3)

51.(1) 52.(2) 53.(2) 54.(1) 55.(1)

56.(1) 57.(5) 58.(1) 59.(3) 60.(5)

61.(3) 62.(3) 63.(2) 64.(5) 65.(5)

66.(4) 67.(2) 68.(1) 69.(2) 70.(2)

71.(3) 72.(2) 73.(1) 74.(4) 75.(5)

76.(1) 77.(4) 78.(4) 79.(3) 80.(3)

81.(3) 82.(1) 83.(5) 84.(3) 85.(2)

86.(2) 87.(1) 88.(2) 89.(4) 90.(1)

91.(5) 92.(3) 93.(2) 94.(1) 95.(2)

96.(1) 97.(1) 98.(4) 99.(4) 100.( 1)

101.(2) 102.(1) 103.(5) 104.(4) 105.(4)

106.(2) 107.(3) 108.(2) 109.(5) 110.(4)111.(3) 112.(4) 113.(4) 114.(1) 115.(5)

116.(4) 117.(2) 118.(4) 119.(1) 120.(3)

Online Mock NMAT 01 Analysis

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