On time domain methods for Computational Aeroacoustics › people › myh › CFD-Conference ›...
Transcript of On time domain methods for Computational Aeroacoustics › people › myh › CFD-Conference ›...
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On time domain methods forComputational Aeroacoustics
Fang Q. Hu and Ibrahim KocaogulOld Dominion University, Norfolk, Virginia
Xiaodong Li, Xiaoyan Li and Min JiangBeihang University, Beijing 100191, China
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Noise prediction by linear acoustic wave propagation
FW−H equationKirchhoff integral
Noise source modelling + Noise propagation
Linearized Euler EquationsGreen’s function......
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Time Domain Wave Packet (TDWP) method
sinusoidal wave wave packet(single frequency) (broadband andmulch-frequency)
Proposed broadband acoustic test pulse function for source:
Ψ(t) = ∆t sin(ω0t)πt e(ln0.01)(t/M∆t)2 , |t| ≤M∆t
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Advantages of Time Domain Wave Packet (TDWP) method
One computation for all frequencies (within numericalresolution) for linear problems
Ability to synthesize broadband noise sources
Acoustic source has a short time duration, so computation ismore efficient than driving a time domain calculation to a timeperiodic state
Separation of acoustic and hydrodynamic instability wavesbecomes possible
Long numerical transient state is avoided
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Application Examples
1. Sound propagation through shear flows
2. Vortical gust-blade interaction
3. Duct sound radiation problem
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1. Sound source in a jet flow (a CAA Benchmark problem)
x=100
JetFlow
y=15
y=50
Single frequency source function:S(x ,y ,t) = sin(Ωt)e−(ln2)(Bxx2+Byy2)
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Instability wave in a shear flow
x
y
-50 0 50 100 150-60
-40
-20
0
20
40
60
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Instability wave in duct radiation computation
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Time Domain Wave Packet (TDWP) method
Separation of acoustic and instability waves:
instability waveShear layer
1
2
t
t
t3
Acoustic and instability waves travel at different speeds.An acoustic wave packethas a short time duration, it will be separated from the instability wave in timedomain calculation, heret1 < t2 < t3.
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Time Domain Wave Packet approach
x=100
JetFlow
y=15
y=50
Single frequency source function:S(x ,y ,t) = sin(Ωt)e−(ln2)(Bxx2+Byy2)TDWP source function:S(x ,y ,t) = Ψ(t)e−(ln2)(Bx x2+By y2)
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without suppression with suppression
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Frequency domain solution recovered by FFT(Symbol: analytical; Line: computation)
y = 15 y = 50x = 100
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2. Vorticalgust-blade interaction
Incident Vortical Gust :
0(U ,V )0
ug =−Vβα
os(αx +βy−ωt)vg = V os(αx +βy −ωt)
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Vortical gust imposition in TDWP
vortical wave packet
θug (x ,y ,t) =−BΨ(t−Ax −By)vg (x ,y ,t) = AΨ(t−Ax −By)A= os(θ )u0 os(θ )+ v0 sin(θ ) , B =
sin(θ )u0 os(θ )+ v0 sin(θ ) =⇒ ∂ug∂x +
∂vg∂y = 0
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Example of time domain solution(v-velocity and pressure,u0 = 0.45)
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Frequency domain solution by FFT (u-velocity andpressure)
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Frequency domain solution (pressure magnitudes)
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3. Duct mode imposition in TDWP
P M
L
Source plane
Pressure equation at in-flow region:
∂p∂ t + u0 ∂p
∂x + γ p0(∂u∂x +
∂u∂y +
∂u∂z )= φmn(y ,z)Ψ(t)e−σx2
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Example of time domain solution
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Duct mode wave packet—exact solution
p(x ,y ,z , t) = φmn(y ,z)P(x ,t)P(x ,t) = α22 ˆ X−X ˆ T ′
−T J0(λmn√(t− t ′)2− x2) DDt [Ψ(t ′)e−σx ′2]dx ′dt ′P(x ,ω)=
α22 ´ X−X ´ T ′−T e−x√λ2mn−ω2√
λ2mn−ω2 e iω t′ DDt [Ψ(t ′)e−σx ′2]dx ′dt ′ 0< ω < λmn (cut-off)
α22 ´ X−X ´ T ′−T ie i x√ω2−λ2mn√
ω2−λ2mn e iω t′ DDt [Ψ(t ′)e−σx ′2]dx ′dt ′ 0< λmn < ω (cut-on)
(
α =√1−M2, β =
M1−M2 , t ′ = t ′−β(x −x ′), x = |x−x ′|/α2)
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Time history (line: numerical, symbol:theoretical)
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Frequency domain solution
ω1 = 1.6 :ω2 = 1.9 :ω3 = 2.3 :ω4 = 2.6 :
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NASA/GE Fan Noise Source Diagnostic Test
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Aft fan exhaust radiation problem
Pressure equation at in-flow region:
∂p∂ t + u0 ∂p
∂x + γ p0(∂u∂x +
∂u∂y +
∂u∂z )= φmn(y ,z)Ψ(t)e−σ(x−x0)2
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Aft fan exhaust radiation problem
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Aft fan exhaust radiation problem
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Aft fan exhaust radiation problem
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Aft fan exhaust radiation problem
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Pressure field obtained by FFT at 2BPF, 61.7% design speed
Mode (-10,2) introduced at source plane inside duct
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Pressure field obtained by FFT at 3BPF, 61.7% design speed
Mode (-10,2) introduced at source plane inside duct
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Pressure field obtained by FFT at 4BPF, 61.7% design speed
Mode (-10,2) introduced at source plane inside duct
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Far-field modal transfer function, forward solution
51
50
49
45
4035
Forward Radiation, mode (-10,0)
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Far-field modal transfer function, forward solution
5150
49
45
40
Forward Radiation, mode (-10,1)
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Far-field modal transfer function, forward solution
515049
47
45
35
Forward Radiation, mode (-10,2)
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Far-field modal transfer function, forward solution
515049
45
40
35
Forward Radiation, mode (-10,3)
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Far-field modal transfer function, forward solution
Forward Radiation, mode (-10,4)
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Far-field modal transfer function (2BPF)Pmn = PmnAmn51
50
49
47
4540
35
Forward Radiation
(−10,1)
(−10,2)
(−10,3)
(−10,4)
(−10,0)
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Reciprocity Condition (forward and adjoint problems)
nm ω
nmA
p (r’, ) ~p(r’,t)
Amn~
Pmn(r ′,ω)Amn = αmn A∗mnP(r ′,ω)
(
αmn = ˆD φ∗mnAφmndS = 4π(
∂ω∂k )mn ˆ RrH φ2mn(r)rdr)
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Adjoint solution, time domain
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Adjoint solution, time domain
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Adjoint solution, time domain
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Adjoint solution, time domain
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Adjoint solution, frequency domain at 2BPF
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Adjoint solution, frequency domain at BPF
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Adjoint solution, frequency domain at 3BPF
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Reciprocity condition (2BPF)PmnAmn = αmn A∗mnP51
50
49
47
4540
35
Forward Radiation
45
Adjoint Solution
~
(−10,1)
(−10,2)
(−10,3)
(−10,4)
(−10,0)
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Reciprocity condition (2BPF)PmnAmn = αmn A∗mnP51
50
49
47
4540
35
Forward Radiation
48
Adjoint Solution
~
(−10,1)
(−10,2)
(−10,3)
(−10,4)
(−10,0)
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Reciprocity condition (2BPF)PmnAmn = αmn A∗mnP51
50
49
47
4540
35
Forward Radiation
49
Adjoint Solution
~
(−10,1)
(−10,2)
(−10,3)
(−10,4)
(−10,0)
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Comparison of modal transfer functionPmnAmn = αmn A∗mnP51
50
49
47
4540
35
Forward Radiation
Adjoint Solution
~
(−10,1)
(−10,2)
(−10,3)
(−10,4)
(−10,0)
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Modal detection 1
• Far-field pressure p(r ,ω) = ∑m,nAmn(ω)Pmn(r ,ω)Amn = A(r)mn+ iA(i)mn = AmplitudePmn = Modal transfer function
• Assume duct modes have no interference:
|p(r ,ω)|2 = ∑m,n |Amn(ω)|2 ∣∣∣Pmn(r ,ω)
∣
∣
∣
2(1)
• Minimization:51∑i=38(∑m,n |Amn|2 ∣∣∣Pmn(r i ,ω)
∣
∣
∣
2−P2i (ω)
)2=MIN (2)
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Far-field SPL
measurementscomputation
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Summary
Time Domain Wave Packet formulation can be used toeliminate the initial long transient state that is oftenrequired in single frequency formulation
Computational time is reduced due to shortened timeduration of the wave packet; the wave packet method ispreferred for linear propagation problems even if onlysolutions at a few frequencies are of interest
Solution of the adjoint problem provides a useful tool forverifying the numerical results of Euler equations