Nuclei
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Transcript of Nuclei
Nuclear ForcesShort Ranged Force ( ~ femtometers 10-15)
In short range , they are very strong(even stronger than Coulomb and Gravitation) . Other than this they are very weak.
Nuclear force does not depend on charge , Hence it is same for neutron-neutron , proton-proton and neutron-proton
From Graph: r > r0 attractive
r<ro repulsive
R0
Strong force region
Basic Facts A = Mass number = No of protons + Number of electrons
Z = Atomic Number = No of protons
Radius of Nucleus A∝ 1/3
Volume = (4/3) π R3 A∝
Density = Mass / Volume = Mass number /Volume = Constant
So Density of nucleus is independent of Mass number .
Density of nucleus is very high . As it was concluded in Rutherford’s Experiment
Mass Energy EquivalenceMass is condensed form of Energy
Energy Equivalent for Mass : E = mc2
Energy Equivalent of 1 amu = 931 MeV. ~930
So , If mass is known in amu just multiply it by 931 to get energy equivalent .
Energy ConceptsTo break things we need energy . Example to break a chemical bond energy is required , To break an ice cube ,energy is required .
When things are formed on their own , energy is released .
Binding Energy
Since we are breaking , Energy should be added . Energy Equal to Binding Energy is required to break nucleus . So Binding Energy Stability
Applying Energy Conservation
Energy of Nucleus + Binding Energy = Energy of nucleons
Mnucleusc2 + Binding Energy = Mnucleons c2
Mnucleons > Mnucleus .. This is called mass defect (खु�ल्ले� का� mass ज्या�दा� हो ता� हो�) So Binding Energy = (Mass Defect) c2 = (Mnucleons-Mnucleus) c2
Consider a nucleus having Atomic Number Z and Mass number A and Atomic mass M
Number of Proton = Z
Number of neutrons = A- Z
Mass of Nucleons = Z mproton + (A-Z ) mneutron
Energy Equivalent = (Z mproton + (A-Z ) mneutron) c2
Mass of Nucleus = M
Energy Equivalent = Mc2
Energy of Nucleus + Binding Energy = Energy of Nucleons
Mc2 + Binding Energy =(Z mproton + (A-Z ) mneutron) c2
But Binding Energy is not a good measure , Rather (Binding Energy / nucleon) is better
Example Protons = 8 Neutrons = 16-8=8
But Actual Mass = Atomic Mass = ( Mass Defect !!)
Energy of Nucleus + Binding Energy = Energy of nucleons
(15.99493)x931 + Binding = (16.12744)X931
Binding Energy = 127.5 MeV No of nucleon =16
Binding energy/ nucleons = 127.5 / 16 =7.96 MeV
Binding Energy CurveCurve is on Binding Energy /Nucleon
Most stable : Iron Group
30< A<70 almost constant , because nuclear force is
short ranged .
Binding Energy / nucleon is low for light as well as heavy elements
Interpretations of curve Light elements can combine to form a bigger element So that
BE / nucleon increase . Hence they are suitable for Fusion
Similarly ,Heavy Elements can break into two to form elements
in mid . So they are suitable for fission
Middle Elements are stable , so they are not suitable for any nuclear reactions
Alpha Decay Alpha Particle ( ) is emitted
Energy Calculations :
Initial Mass = Mx Initial Energy = Mx c2
Final Mass = (My + MHe ) c2
If Initial Mass is higher Initial energy is more . So , Energy will be released(spontaneous)
If Final Mass is higher Final energy is more . So Energy will be absorbed .
Energy released is carried by alpha particle in form of kinetic energy
Qvalue = (initial mass – final mass ) c2 = (Mx – My-MHe ) c2
Qvalue> 0 for spontaneous (Reactions with negative Q will not occur)
Example Uranium
Initial Mass = 238.05079 u
Final Mass = 234.04363 + 4.00260 = 238.04623 u
Initial Mass > Final Mass
Initial Energy > Final Energy Energy will be Released Spontaneous
Energy released = (238.05079 -238.04623 ) X 931
= 0.00456 X931 MeV = 4.35 MeV
1 u = 931 MeV
Beta - decay Electron is emitted . Ve is antineutrino ( zero mass)
Neutron breaks into electron and proton
Explanation
LHS : Protons = Z Neutrons = A-Z Electrons = Z
RHS : Since One Neutron has converted into electron + proton
Protons = Z+1 Neutrons = (A-Z)-1 Electrons = Z+1
So New Atomic number = Z+1 New Mass Number = (Z+1) +(A-Z)-1 = A !
Z Z +1 A unchanged
Energy Calculations
Initial Mass = Mx
Initial Energy = Mxc2
Final Mass = (My + Me)
Final Energy = (My + Me)c2
Qvalue = ( Initial Mass – Final Mass ) c2 = (Mx- My -Me)c2
Qvalue > 0 Spontaneous
This energy ( Q) is carried away as kinetic energy by the electron and antineutrino.
Beta plus decay Proton breaks into Neutron and positive electron
Explanation :
LHS : Protons : Z Neutrons : A-Z
Now one proton converts into positive electron and neutron
RHS : Proton : Z-1 Neutron : (A-Z+1)
New Atomic number : Z-1 New Mass Number = (Z-1) + (A-Z+1 ) = A !
Z Z-1 A Unchanged
Energy Calculations
Initial Mass = Mx
Initial Energy = Mxc2
Final Mass = (My + Me)
Final Energy = (My + Me)c2
Qvalue = ( Initial Mass – Final Mass ) c2 = (Mx- My -Me)c2
Qvalue > 0 Spontaneous
This energy(Q) is carried away as kinetic energy by the electron and neutrino.
Gamma Decay Like electrons , nuclei also have energy states .
But energy gap is very high in case of nucleus . In case of electrons it is relatively small ( 13.6 eV, 10.2eV etc)
But in case of nucleus it is of the order of MeV ( Mega = 10 6 , as in megabytes)
When nucleus , jumps down from excited state to lower state energy is released in the form of photons . Efinal- Einitial = h v
Example Fact : Beta / alpha decay are generally accompanied by gamma decay
In this example , Cobalt first goes beta minus decay , In beta
Minus decay Z increases by 1 ( 2728)
Then it undergoes two gamma decays
First gamma : 1.17 Mev 1.17X106 = 1240/ λ λ =10-3 nm
Second gamma : 1.33 MeV
Radioactivity First Order Reaction
N = Number of nuclei present
N0 initial number of nuclei
So number of nuclei will decrease with time .
Half life : Time at which number of nuclei present become half of initial nuclei
T1/2 depends only on decay constant .not on N
Average life : Life a nuclei is expected to live .
Like some humans die at early age , some at high age . The average comes in middle which is called life expectancy .