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POWERPOINT PRESENTATIONPREPARED BY

Noufiya.AMathematics

Reg.no:18014354008MMTC,Vilakudy

Topic: Interior angles of polygon

POLYGONS

A closed plane figure, having three or more, usually straight sides are called polygon

EXAMPLES OF POLYGONS

SUM OF INTERIOR ANGLES OF THE

QUADRILATERAL Sum of interior angles of a quadrilateral ABCD

= sum of interior angles of ADB+Sum of interior angles of DCB=180°+180°

=2×180°=360°

A B

CD

SUM OF INTERIOR ANGLES OF THE PENTAGON

Sum of interior angles of pentagon ABCDE

= AED + ABD + BCD = 3 × 180° = 540°

A B

C

D

E

SUM OF INTERIOR ANGLES OF THE HEXAGON

Sum of interior angles of hexagon ABCDEF = Sum of angles of 4 triangles

= 4 × 180° = 720 °

A B

C

DE

F

SUM OF INTERIOR ANGLES OF THE HEPTAGON

sum of interior angles of heptagon ABCDEF = sum of angles of 5 triangles

= 900°

= 5× 180°

A

B C

D

E

F

G

SUM OF INTERIOR ANGLES OF THE OCTAGON

sum of interior angles of the octagon ABCDEFGH = Sum of angles of 6 triangles

= 6× 180° = 1080 °

A

B C

D

E

FG

H

POLYGON NO:OF SIDES SUM OF INTERIOR ANGLES

Triangle 3 180°

Quadrilateral 4 2× 180° = 360°

Pentagon 5 3× 180° = 540°

Hexagon 6 4× 180° = 720°

Heptagon 7 5× 180° = 900°

Octagon 8 6× 180° = 1080°

………….. ………………. …………

n n (n-2)× 180°

If a polygon having sides ‘n’,then its interior angle=(n-2)$180 ◦

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