Nonslender Wall by Chapter 14.5
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Transcript of Nonslender Wall by Chapter 14.5
[email protected] (HELP) phone847.581.0644 faxk lc0.3h 40 =if eh6> "NG" , "OK" ,"OK" =h61.333in =h 8in :=hmin4.8in = hminmax 4inlc25,:=Select trial wall thickness h 1.Minimum thicknessTrial thicknessCheck eccentricitySlendernessCalculationsk 0.8 :=e 1.33in :=lc10ft := Wall heightAssumed load eccentricityEffective length factorGeometryminv0.0012 :=minh0.0020 :=Minimum reinforcement ratios 0.65 :=f'c4000psi :=ConcreteNeglect weight of wallPL30klf :=PD55klf :=Floor beam reactions:Design DataA concrete bearing wall supports a floor system. The height of the wall is 10 ft, and the wall is considered laterally restrained at the top.Empirical Design Method (ACI 318-05, 14.5)Nonslender Bearing WallNonslender Wall by Chapter 14.5.mcd M-1 5/15/2006www.pcaStructurePoint.cominfo@pcaStructurePoint.com847.966.4357 (HELP) phone847.581.0644 faxCalculate factored loading 2.Calculate design strength of wall 3.Determine single layer of reinforcment 4.b 1ft :=Pub 1.2PD1.6PL+( ) := Pu114kips =Agb h := Ag96in2=Pn0.55 f'c Ag 1k lc32h 2 :=Pn117.975kips =PuPn0.966 =if PnPu< "NG" , "OK" ,( )"OK" =Asminvminvh := Asminhminhh :=Asminv0.115in2ft= Asminh0.192in2ft=Nonslender Wall by Chapter 14.5.mcd M-2 5/15/2006