Nonlinear Equations Your nonlinearity confuses me

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Nonlinear Equations Your nonlinearity confuses me 0 2 3 4 5 f ex dx cx bx ax “The problem of not knowing what we missed is that we believe we haven't missed anything” Stephen Chew on Multitasking x x ) tanh( http://numericalmethods.eng.usf.edu Numerical Methods for the STEM undergraduate

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Nonlinear Equations Your nonlinearity confuses me. “The problem of not knowing what we missed is that we believe we haven't missed anything” – Stephen Chew on Multitasking. http://numericalmethods.eng.usf.edu Numerical Methods for the STEM undergraduate. - PowerPoint PPT Presentation

Transcript of Nonlinear Equations Your nonlinearity confuses me

Page 1: Nonlinear Equations Your nonlinearity confuses me

Nonlinear EquationsYour nonlinearity confuses me

02345 fexdxcxbxax

“The problem of not knowing what we missed is that we believe we haven't missed anything” – Stephen Chew on Multitasking

xx )tanh(

http://numericalmethods.eng.usf.eduNumerical Methods for the STEM undergraduate

Page 2: Nonlinear Equations Your nonlinearity confuses me

Identify the picture of your EML3041 instructor

A. B. C. D.

25% 25%25%25%A.

B.

C.

D.

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3

Example – General EngineeringYou are working for ‘DOWN THE TOILET COMPANY’ that makes floats for ABC commodes. The floating ball has a specific gravity of 0.6 and has a radius of 5.5 cm. You are asked to find the depth to which the ball is submerged when floating in water.

Figure Diagram of the floating ball

010993.3165.0 423 xx

Page 4: Nonlinear Equations Your nonlinearity confuses me

For the trunnion-hub problem discussed on first day of class where we were seeking contraction of 0.015”, did the trunnion shrink enough when dipped in dry-ice/alcohol mixture?

1. 2.

50%50%1. Yes2. No

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Example – Mechanical Engineering

Since the answer was a resounding NO, a logical question to ask would be:

If the temperature of -108oF is not enough

for the contraction, what is?

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Finding The Temperature of the Fluid

dTTDDc

a

T

T

)(

Ta = 80oFTc = ???oFD = 12.363"∆D = -0.015" -350 -300 -250 -200 -150 -100 -50 0 50 100

2

2.5

3

3.5

4

4.5

5

5.5

6

6.5

7

T

3528 10349.610457.710992.5015.0 cc TT

TT 009696.0033.6

010651.810457.710992.5)( 3528 ccc TTTf

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Finding The Temperature of the Fluid

dTTDDc

a

T

T

)(

Ta = 80oFTc = ???oFD = 12.363"∆D = -0.015"

352639 10166.610435.710829.310059.5015.0 ccc TTT

015.610195.610228.1 325 TT

010834.810435.710829.310059.5)( 352639 cccc TTTTf

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Nonlinear Equations(Background)

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Page 9: Nonlinear Equations Your nonlinearity confuses me

How many roots can a nonlinear equation have?

-20 -10 0 10 20-3

-2

-1

0

1

2

3sin(x)=2 has no roots

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How many roots can a nonlinear equation have?

-20 -10 0 10 20-3

-2

-1

0

1

2

3sin(x)=0.75 has infinite roots

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How many roots can a nonlinear equation have?

-20 -10 0 10 20-3

-2

-1

0

1

2

3sin(x)=x has one root

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How many roots can a nonlinear equation have?

-20 -10 0 10 20-3

-2

-1

0

1

2

3sin(x)=x/2 has finite number of roots

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The value of x that satisfies f (x)=0 is called the

1. 2. 3. 4.

0% 0%0%0%

1. root of equation f (x)=0 2. root of function f (x) 3. zero of equation f (x)=0 4. none of the above

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A quadratic equation has ______ root(s)

1. 2. 3. 4.

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1. one2. two3. three4. cannot be determined

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For a certain cubic equation, at least one of the roots is known to be a complex root. The total number of complex roots the cubic equation has is

1. 2. 3. 4.

0% 0%0%0%

1. one2. two3. three4. cannot be

determined

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Equation such as tan (x)=x has __ root(s)

1. 2. 3. 4.

0% 0%0%0%

1. zero2. one3. two4. infinite

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A polynomial of order n has zeros

1. 2. 3. 4.

0% 0%0%0%

1. n -12. n3. n +14. n +2

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The velocity of a body is given by v (t)=5e-t+4, where t is in seconds and v is in m/s. The velocity of the body is 6 m/s at t =

1. 2. 3. 4.

0% 0%0%0%

1. 0.1823 s2. 0.3979 s3. 0.9162 s4. 1.609 s

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END

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Page 20: Nonlinear Equations Your nonlinearity confuses me

Newton Raphson Method

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Page 21: Nonlinear Equations Your nonlinearity confuses me

This is what you have been saying about your TI-30Xa

A. B. C. D.

25% 25%25%25%A. I don't care what people say The rush is worth the priceI pay I get so high when you're with meBut crash and crave you when you are away

B. Give me back now my TI89Before I start to drink and whine TI30Xa calculators you make me cryIncarnation of of Jason will you ever die

C. TI30Xa – you make me forget the high maintenance TI89.

D. I never thought I will fall in love again!

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Newton-Raphson method of finding roots of nonlinear equations falls under the category of __________ method.

1. 2. 3. 4.

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1. bracketing2. open3. random4. graphical

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The next iterative value of the root of the equation x 2=4 using Newton-Raphson method, if the initial guess is 3 is

1. 2. 3. 4.

0% 0%0%0%

1. 1.5002. 2.0663. 2.1664. 3.000

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The root of equation f (x)=0 is found by using Newton-Raphson method. The initial estimate of the root is xo=3, f (3)=5. The angle the tangent to the function f (x) makes at x=3 is 57o. The next estimate of the root, x1 most nearly is

1. 2. 3. 4.

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1. -3.24702. -0.24703. 3.24704. 6.2470

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The Newton-Raphson method formula for finding the square root of a real number R from the equation x2-R=0 is,

1. 2. 3. 4.

25% 25%25%25%

21i

i

xx

2

31

ii

xx

iii x

Rxx

2

11

iii x

Rxx 3

2

11

1.

2.

3.

4.

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END

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Page 27: Nonlinear Equations Your nonlinearity confuses me

Bisection Method

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Page 28: Nonlinear Equations Your nonlinearity confuses me

Bisection method of finding roots of nonlinear equations falls under the category of a (an) method.

1. 2. 3. 4.

0% 0%0%0%

1. open2. bracketing3. random4. graphical

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If for a real continuous function f(x),f (a) f (b)<0, then in the range [a,b] for f(x)=0, there is (are)

1. 2. 3. 4.

0% 0%0%0%

1. one root2. undeterminable number of roots3. no root4. at least one root

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The velocity of a body is given by v (t)=5e-t+4, where t is in seconds and v is in m/s. We want to find the time when the velocity of the body is 6 m/s. The equation form needed for bisection and Newton-Raphson methods is

1. 2. 3. 4.

25% 25%25%25%1. f (t)= 5e-t+4=02. f (t)= 5e-t+4=63. f (t)= 5e-t=24. f (t)= 5e-t-2=0

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To find the root of an equation f (x)=0, a student started using the bisection method with a valid bracket of [20,40]. The smallest range for the absolute true error at the end of the 2nd iteration is

1. 2. 3. 4.

25% 25%25%25%1. 0 ≤ |Et|≤2.5

2. 0 ≤ |Et| ≤ 5

3. 0 ≤ |Et| ≤ 10

4. 0 ≤ |Et| ≤ 20

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For an equation like x2=0, a root exists at x=0. The bisection method cannot be adopted to solve this equation in spite of the root existing at x=0 because the function f(x)=x 2

1. 2. 3. 4.

0% 0%0%0%

1. is a polynomial2. has repeated zeros at

x=03. is always non-negative4. slope is zero at x=0

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Page 34: Nonlinear Equations Your nonlinearity confuses me

How and Why?

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Study Groups Help?Studying

Alone

Studying with Peers

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I walk like a pimp – Jeremy Reed

You know it's hard

out here for a

pimp,

When he tryin to

get this money for

the rent,

For the Cadillacs

and gas money

spent

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Final Grade vs. First Test Grade

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A New Book on How Brain Works

The Compass of Pleasure:

How Our Brains Make Fatty Foods, Orgasm, Exercise, Marijuana, Generosity, Vodka, Learning, and Gambling Feel So Good