Nonequilibrium Quantum Mechanics of a Single-Molecule Heterojunction
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Transcript of Nonequilibrium Quantum Mechanics of a Single-Molecule Heterojunction
Dan Wanegar
Nonequilibrium Quantum Mechanics of a Single-Molecule
Heterojunction
Supervisor: Charles Stafford
The ProblemFinding the electron transport through a single-molecule junction.
•Electrons, as fermions, obey the Pauli Exclusion Principle, so learning creation and annihilation operators was necessary.
•The Green’s function, G, which describes the quantum dynamics, was the next step.
•Physics observables, such as electric current, can be expressed in terms of G
The HamiltonianH=Hmol+Hleads+HT
d and d+ are creation and annihilation operators obeying:{di,dj
+}=didj+
+dj+di=i,j
{di,dj}={di+,dj
+}=0
(Hmol)ij = hijdi+dj
(Hleads)k = kck+ck
(HT)nk=Vn,kdn+ck+Vn,k
*ck+dn
The Retarded Green’s Function
Plugging in previous equations followed by a Fourier transform (right) gives
G = [IE – Hmol – ]-1, where
i,j =
The i0+ ensures a retarded function as opposed to advanced
In the broad-band limit, = i(r – a) =And r = a
* is taken to be imaginary, so r = -i/2
Current and The Transmission Matrix
The probability of transmission from lead i to lead j is given by the i,j component of the transmission matrix.
The current into lead i is given by
The transmission matrix is given byTij = Tr(iGrjGa)
A proof can be found in Electronic Transport in Mesoscopic Systems by Supriyo Datta
The General Diatomic Conductor
When 1, 2, and G are entirely arbitrary, the matrix multiplication gives:T12=ijkm
ijkmGjkGim
*
Which can be expanded and simplified due to symmetries to:
T12 = ij |ii||
jj||Grij|+2Re(
1112Gr11
*Gr12 + 12
11Gr11*Gr12
+ 12
12Gr12*Gr21 +
1221Gr11
*Gr22 +
1222Gr12
*Gr22 + 22
12Gr22*Gr21)
In general, the 12 and
12 terms are small enough and complex, so the nasty part usually averages to zero.
The Vertical Diatomic Conductor:Fano Antiresonances
An interesting case to note is the
1.1 and 1.1 being the nonzero in the
connection terms. This gives
G-1=
Since 111 and 2
11 are the only nonzero terms, this means that
T11 = 1 2|G11|2,
Which has exactly one node at E=2.
This can also be looked at as an atomic conductor (atom 1) with three leads (atom 2 being the 2nd). This makes
G =
The Horizontal Diatomic Conductor:Exceptional Points
For a horizontal conductor, the time-dependant transmission function is
[1]
where
So if 1 = 2,
Which is either purely imaginary or purely real. As can be seen above, there is a very large difference between 2V>|’| and 2V<|’|, so |’|=2V is called the exceptional point.
So how does this relate to the energy-dependant transmission function?
[1] D.M.Cardamone, C.A.Stafford, and B.R.Barrett, Phys. Stat. Sol. (b) 230, No. 2 (2002)
What About The Energy-Dependant Transmission Function ?Using the energy-dependant Green’s function from earlier,T12=1
11211|G12|2,
and
Which is especially interesting to look at when 1=2, as it turns into
E =
A Less Distinguishable ResultFor large enough real E and small enough , the transmission function has two peaks. Otherwise, only one peak is observed.
However, E ± lies in the complex plane, but E can only be real. This means that peaks don’t occur at exactly E = Re(E ±).
So for small enough E and large enough , the transmission function doesn’t appear to be qualitatively different for E real or imaginary.
E / = 2.3 E / = 1.2
E / = .59 E / = .22
Taking the n-th Derivative…Shows that even for very small real E, there is still a qualitative difference from imaginary E.
n=0
E / = 2.3 1.2 .59 .22
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2
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Conclusions•The nonequilibrium quantum dynamics of electrons in a single-moleule junction can be solved exactly using Green’s functions when neglecting electron-electron interactions•For a diatomic molecule, both a Fano antiresonance and an exceptional point can occur, depending on the geometry.