Nmr Lecture

download Nmr Lecture

of 133

Transcript of Nmr Lecture

  • 8/10/2019 Nmr Lecture

    1/133

    Organic ChemistryLaboratoryBuilding A Toolset

    For

    The Identification of Organic Compounds

    11/10/201

    41

    Physical Properties

    Melting Point

    Boiling PointDensity

    Solubility

    Refractive Index

    Chemical Tests

    Hydrocarbons

    AlkanesAlkenes

    Alkynes

    Halides

    Alcohols

    AldehydesKetones

    Spectroscopy

    Mass

    (Molecular Weight)Ultraviolet

    (Conjugation, Carbonyl)

    Infrared

    Functional Groups

    NMR(Number, Type, Location

    of protons)

    Gas Chromatography

    (Identity, Mole %)

  • 8/10/2019 Nmr Lecture

    2/133

    Spectroscopy

    The Absorption of Electromagnetic

    Radiation and the use of the Resulting

    Absorption Spectra to Study the

    Structure of Organic Molecules

    11/10/201

    42

  • 8/10/2019 Nmr Lecture

    3/133

    SpectroscopySpectroscopy Types:

    Mass Spectrometry (MS)Hi-Energy Electron-Beam

    Bombardment

    Use Molecular Weight, Presence of Nitrogen, Halogens

    Ultraviolet Spectroscopy (UV)Electronic Energy States

    Use Conjugated Molecules; Carbonyl Group, Nitro Group

    Infrared Spectroscopy (IR) Vibrational & Rotational

    Movements

    Use Functional Groups; Compound Structure

    Nuclear Magnetic Resonance (NMR) Magnetic Properties

    of Nuclei

    Use The number, type, and relative position of protons

    (Hydrogen nuclei) and Carbon-13 nuclei11/10/2014

    3

  • 8/10/2019 Nmr Lecture

    4/133

    The Electromagnetic Spectrum

    11/10/201

    44

    MicrowaveInfraredX-RayVacuum

    UV

    VisibleNear

    Ultraviolet

    Vibrational

    Infrared

    Nuclear

    MagneticResonance

    Radio Frequency

    400 nm200 nm 800 nm 2.5 15

    1 m 5 m

    Blue Red

    Cosmic

    &

    Ray

    0.01 nm

    3 x 1019Hz 3 x 1016Hz 2 x 1013Hz

    10 nm 30 cm

    1 x109cm-1

    0.002 cm-1

    10 cm-1 3 cm-1 0.01 cm-1

    1 mm

    Frequency ()

    Energy (E)

    High

    High Low

    Low

    Wavelength (

    )Short Long

    1 x107cm-1 5 x104cm-1

    2.5 x104cm-1

    1.25 x104cm-1

    667cm-1

    4 x103cm-1

    6 x 107Hz

    3 x 108Hz

    1.5 x 1015Hz 1 x 109Hz3 x 1011Hz

    1.2 x 1014HzFrequency

    Wave Number

    Wavelength

  • 8/10/2019 Nmr Lecture

    5/133

    NMR

    Nuclear Magnetic Resonance Spectroscopy

    NMR

    11/10/201

    45

  • 8/10/2019 Nmr Lecture

    6/133

    NMR Nuclear Magnetic Resonance Spectroscopy (NMR)

    Nuclear Spin

    Nuclear Spin State

    Magnetic Moments

    Quantized Absorption of Radio Waves

    Resonance Chemical Shift

    Chemical Equivalence

    Integrals (Signal Areas)

    Chemical Shift - Electronegativity Effects

    Chemical Shift - Anisotropy (non-uniform) effects of pi

    bonds

    Spin-Spin Splitting11/10/2014

    6

  • 8/10/2019 Nmr Lecture

    7/133

    NMR NMR

    NMR is an instrumental technique to determine the

    number, type, and relative positions of certain Nuclei in amolecule

    NMR is concerned with the magnetic properties of thesenuclei

    Many Nuclei types can be studied by NMR, but the twomost common nuclei that we will focus on are Protons(1H1) and Carbon-13 (

    13C6)

    The magnetic properties of NMR suitable nuclei include:

    Nuclear Magnetic Moments

    Spin Quantum Number (I)

    Nuclear Spin States

    Externally Applied Magnetic Field

    Frequency of Angular Precession

    Absorption of Radio Wave Radiation - Resonance11/10/2014

    7

  • 8/10/2019 Nmr Lecture

    8/133

    NMR The Magnetic Properties

    Many atomic nuclei have a property called Spin

    Since all nuclei have a charge (from the protons in thenucleus), a spinning nuclei behaves as if it were a tinymagnet, generating its own Magnetic field

    The Magnetic Field of such nuclei has the followingpropertiesMagnetic Dipole, Magnetic Moment andQuantized Spin Angular Momentum

    The Magnetic Moment ()of a nuclei is a function of itsCharge and Spin and is defined as the product of the polestrength and the distance between the poles

    Only Nuclei with Mass & Atomic number combinations ofOdd/Odd, Odd/Even, Even/Odd possess Spin Properties,which are applicable to NMR

    Note: Nuclei with a Mass & Atomic number combination ofEven/Even do not have Spin and are not useful for

    NMR11/10/2014

    8

  • 8/10/2019 Nmr Lecture

    9/133

    NMR Nuclear Spin States

    Nuclei with spin (Magnetic Moment, Quantized Spin

    Angular Momentum, Magnetic Dipole) have a certainnumber of Spin States.

    The number of Spin States a nuclei can have isdetermined by its Spin Quantum Number I, a physicalconstant, which is an intrinsic (inherent) property of a

    spinning charged particle. The Spin Quantum Number (I) is a non-negative integer

    or half-integer (0, 1/2, 1, 3/2, 2, etc.).

    The Spin Quantum Number value for a given nuclei is

    associated with the Mass Number and Atomic Number ofthe nuclei.

    Odd Mass / Odd Atomic No - 1/2, 3/2, 5/2 Spin

    Odd Mass / Even Atomic No - 1/2, 3/2, 5/2 Spin

    Even Mass / Even Atomic No - Zero (0) Spin

    Even Mass / Odd Atomic No - Integral (1, 2, 3) Spin11/10/2014

    9

  • 8/10/2019 Nmr Lecture

    10/133

    NMR Nuclear Spin States (Cont)

    The number of allowed Spin States for a nuclei is:2I + 1

    with integral differences ranging from +I to -I

    Ex. For I = 5/2 2I + 1 = 2 * 5/2 + 1 = 5 + 1 = 6

    Thus, Spin State Values = 5/2, 3/2, 1/2, -1/2, -3/2, -5/2 The Spin Quantum number (I) for either a Proton (1H1)

    or a Carbon-13 (13C6) nuclei is 1/2

    Thus, the number of Spin States allowed for either a

    Proton (1H1) or a Carbon-13 (13C6) nuclei is:

    [2 * + 1 = 1 + 1 = 2]

    Therefore, the two spins states for either nuclei are:

    1/2 & - 1/211/10/2014

    10

  • 8/10/2019 Nmr Lecture

    11/133

    NMR Nuclear Spin States (Cont)

    In the absence of an applied Magnetic field, all the spinstates of a given nuclei are of equivalent energy(degenerate), equally populated, and the spin vectorsare randomly oriented

    When an external Magnetic Field is applied, the

    degenerate spin states are split into two opposing statesof unequal energy

    + 1/2 spin state of the nuclei is aligned with theapplied magnetic field and is in a lower energy state

    - 1/2 spine state of the nuclei is opposed to theapplied magnetic field and is in a higher energy state

    There is a slight majority of the lower energy (+1/2)

    nuclei11/10/2014

    11

  • 8/10/2019 Nmr Lecture

    12/133

    NMR Two Allowed Spin States for a Proton

    11/10/201

    412

    Direction of an

    Externally Applied

    Magnetic Field (Ho)

    Spin +1/2

    Aligned

    Spin -1/2

    Opposed

    -1/2 Opposed to Field

    +1/2 Aligned with Field

    E

    No

    Field

    Externally Applied

    Magnetic Field Ho

    Ho

    +1/2 Aligned

    -1/2 Opposed

    Alignments

    Ho

    Eabsorbed = (E-1/2 state - E+1/2 state) = h

    E = f(Ho)

    The stronger the applied magnetic field (Ho

    ),

    the greater the energy difference between the spin states

    E

  • 8/10/2019 Nmr Lecture

    13/133

    NMR Applied Magnetic Field, Frequency of Angular Precession

    Under the influence of an externally applied magnetic field,

    Nuclei with Spin Properties, such as Protons & Carbon-13atoms, begin to Precess about the axis of spin with AngularFrequency , similar to a toy top

    The Frequency which a proton precesses is directly

    proportional to the strength of the applied magnetic field For a proton in a magnetic field of 14,100 gauss (1.41

    Tesla), the Frequency of Precession is approximately 60MHz

    That same proton, in a magnetic field of 23,500 gauss(2.35 Tesla), will have a Frequency of Precession ofapproximately 100 MHz

    The stronger the applied magnetic field, the higher theFrequency of Precession and the greater energy difference

    between the +1/2 and -1/2 spin states11/10/2014

    13

  • 8/10/2019 Nmr Lecture

    14/133

    NMR NMR Spectrometers

    NMR spectrometers are rated according to the frequency,in MHz, at which a proton precesses - 60 MHz, 100 MHz,300 MHz, 600 MHz, or even higher.

    Continuous Wave (CW) NMR instruments are set up sothat the externally applied magnetic field strength is held

    constant while a RF oscillator subjects the sample to thefull range of Radio Wave frequencies at which protons(or C-13 nuclei) resonate.

    In Fourier Transform (FT) NMR instruments, the RF

    oscillator frequency is held constant and the externallyapplied magnetic field strength is changed.

    Most NMR instruments today are of the Continuous Wavetype

    11/10/201

    414

    NMR

  • 8/10/2019 Nmr Lecture

    15/133

    NMRTypically, Continuous Wave (CV) Spectrometers are used inwhich the externally applied magnetic field is held constant

    and RF Radio Oscillator applies a full range of frequenciesat which protons or C-13 nuclei resonate

    11/10/201

    415

    NMR

  • 8/10/2019 Nmr Lecture

    16/133

    NMR Energy Absorption, Resonance

    If long wave radio radiation (1-5 m) is applied from a RF

    Oscillator to a sample under the influence of a strongexternally applied magnetic field, and the frequency of the

    oscillating electric field component of the incoming

    radiation matches the Angular Frequency of Precession of

    the nuclei, the two fields couple and energy is transferredfrom the incoming radiation to the protons.

    This causes the nuclei with +1/2 spin state to absorb

    energy and change to the -1/2 spin state.

    When Energy is absorbed at specific frequencies it isreferred to as being Quantized.

    When a proton absorbs a radio wave, whose frequency

    matches its Angular Frequency of Precession, it is said

    to be in Resonance with the incoming signal.11/10/2014

    16

    NMR

  • 8/10/2019 Nmr Lecture

    17/133

    NMR Electron Density, Frequency of Angular Precession

    Protons exist in a variety of chemical and magnetic

    environments, each represented by a unique electrondensity configuration.

    Under the influence of a strong externally appliedmagnetic field, the electrons around the proton are

    induced to circulate, generating a secondary magneticfield (local diamagnetic current), which acts inopposition (diamagnetically)to the applied magneticfield.

    This secondary field shields the proton (diamagneticshielding or diamagnetic anisotropy)from the influenceof the applied magnetic field.

    Recall from slide # 13 that the Angular Frequency ofPrecession is directly proportional to the applied

    Magnetic Field strength.11/10/2014

    17

    NMR

  • 8/10/2019 Nmr Lecture

    18/133

    NMR Electron Density, Frequency of Angular Precession (Cont)

    As the shielding of the proton increases (increased

    electron density)it diminishesthe net applied magneticfield strength reaching the proton; thus the AngularFrequency of Precession is lower

    If the electron density decreases, more of the applied

    magnetic field strength impacts the proton and it willprecess at a higher Angular Frequency

    Thus, each proton with a unique electron densityconfiguration willResonateat a unique Frequency ofAngular Precession

    In a 60 MHz NMR Spectrometer all protons will resonateat a magnetic field strength of approximately 60 MHz,but each unique proton will resonate at its own uniquefrequency, with differences among unique protons ofonly tens of Hertz in a field of 60 MHz

    11/10/201

    418

    NMR

  • 8/10/2019 Nmr Lecture

    19/133

    NMR NMR SpectraFourier Transform vs. Continuous Wave

    Fourier Transform

    In a Fourier Transform (FT) NMR, the spectrumproduced is a plot of the magnetic field strengthrepresenting the frequency of the resonance signalon the X-axisversus the intensity of the

    absorption on the Y-Axis.

    Each signalconsisting of one or more peaksrepresents the Resonance Frequency of aparticular type of proton with a unique chemical &

    magnetic (electron density) environment.

    11/10/201

    419

    NMR

  • 8/10/2019 Nmr Lecture

    20/133

    NMR NMR SpectraFourier Transform vs. Continuous Wave

    Fourier Transform (Cont)

    As the pen of the recorder moves from left to right,the value recorded on X-axis of the NMR spectrumrepresents small increments of increasing magneticfield strength.

    The right side of the NMR Spectrum is referred toas being Upfield (higher magnetic field strength).

    The left side of the NMR Spectrum is referred to asbeing Downfield (lower magnetic field strength).

    11/10/201

    420

    NMR

  • 8/10/2019 Nmr Lecture

    21/133

    NMR NMR SpectraFourier Transform vs. Continuous Wave

    (Cont)

    Continuous Wave

    In a Continuous Wave NMR, the spectrum producedis a plot of the RF Radio Oscillator Frequencyversus the intensity of the absorption on the Y-Axis.

    As before, each signalconsisting of one or morepeaksrepresents the Resonance Frequency of aparticular type of proton with a unique chemical &magnetic (electron density) environment.

    As the pen of the recorder moves from left to right,the value recorded on X-axis of the NMR spectrumrepresents a decreasing RF Oscillator Frequency(Resonance Frequency)

    11/10/201

    421

    NMR

  • 8/10/2019 Nmr Lecture

    22/133

    NMR NMR SpectraFourier Transform vs. Continuous Wave

    (Cont)

    Continuous Wave (Cont)

    The Signals on the right side of the NMR Spectrumrepresent protons (C-13 nuclei) that Resonate atlower frequencies.

    The Signals on the left side of the NMR Spectrumrepresent protons (C-13 nuclei) that Resonate athigher frequencies.

    11/10/201

    422

    NMR

  • 8/10/2019 Nmr Lecture

    23/133

    NMR NMR SpectraFT or CW: the spectrum looks the same

    A FT or CW spectrometer will produce the same spectrum.

    The peaks on the right side of the spectrum representthose protons (or C-13 nuclei) that resonate at the highestexternally applied magnetic field strength and the lowestfrequency.

    This statement would appear to be in conflict with thestatement on Slide #13:

    The Frequency which a proton Precesses is directlyproportional to the strength of the applied magnetic field

    This apparent conflict is resolved by consideration of theinfluence of the secondary magnetic field set up by theDiamagnetic Current from circulating valence electrons.

    This magnetic field opposes the externally applied fieldreducing the effect of the applied Magnetic Field on the

    proton, which in turn lowers the Resonance Frequency11/10/2014

    23

    NMR

  • 8/10/2019 Nmr Lecture

    24/133

    NMR NMR SpectraFT or CW: the spectrum looks the same (Cont)

    The protons that resonate and produce signals on the right

    side of the NMR Spectrum (up field) have higher electrondensity shields than protons that resonate downfield

    The net effect of the difference between the externallyapplied magnetic field and the amount prevented from

    actually reaching the proton results in a significantly reducedResonance Frequency

    As the NMR spectrum moves from right to left, the electrondensity about the various proton environments isdecreasing, resulting in more of the externally appliedmagnetic field getting through to the proton

    As this net magnetic force is increasing downfield towardthe left side of the spectrum, the Resonance Frequencyincreases in conformance with the statement on Slide #13

    11/10/201

    424

    NMR

  • 8/10/2019 Nmr Lecture

    25/133

    NMR NMR SpectraBackground Summary

    11/10/201

    425

    In a continuous Wave NMR, thestrength of the externally applied

    magnetic field is held constant.

    Protons that produce signals on theright side of the NMR spectrumhave a higher amount of valenceelectron shielding.

    The Magnetic Field produced by

    circulating valence electrons(Diamagnetic Current) opposes theexternally applied Magnetic Field.

    The Diamagnetic Field diminishesthe amount of Applied MagneticField reaching the proton.

    The net amount of magnetic forceimpacting the proton is reducedresulting in a lower ResonanceFrequency.

    As the Electron Density about aproton decreases downfield, theResonance Frequency increasesbecause more of the applied

    Magnetic Field impacts the Proton.

    Applied Magnetic Field StrengthHois held constant

    Shielding of Proton by Valence Electrons

    Diamagnetic (Anisotropic) Magnetic Field Strength

    Produced by Circulation of Valence Electrons

    Net Magnetic Field Impacting Proton

    Frequency of Angular Precession

    (Resonance Frequency)

    Signal

    TMS

    PPM 013

    Applied Radio Frequency - RF

    NMR

  • 8/10/2019 Nmr Lecture

    26/133

    NMR NMR SpectraThe Chemical Shift

    The differences in the applied Magnetic Field strength(Angular Frequency of Precession) at which thevarious proton configurations in a molecule Resonateare extremely small.

    The differences amount to only a few Hz (parts per

    million) in a magnetic field strength of 60, 100, 300,.... MHz (megahertz).

    It is difficult to make direct precise measurements ofresonance signals in the parts per million range.

    11/10/201

    426

    NMR

  • 8/10/2019 Nmr Lecture

    27/133

    NMR NMR SpectraThe Chemical Shift

    The typical technique is to measure the differencebetween the Resonance signals of various samplenuclei and the Resonance signal of a standardreference sample (see slides 25 & 26).

    A parameter, called the Chemical Shift (), is

    computed from the observed frequency shiftdifference (in Hz) of the sample and the standardresonance signal divided by the applied MagneticField rating of the NMR Spectrometer (in MHz).

    Thus, the Chemical Shift ()is field-independent ofthe Magnetic Field rating of the instrument.

    11/10/201

    427

    NMR

  • 8/10/2019 Nmr Lecture

    28/133

    NMR NMR SpectraThe Chemical Shift (Cont)

    The Chemical Shift is reported in units of:

    Parts Per Million (ppm)

    11/10/201

    428

    Ex: If a proton resonance was shifted downfield 100 Hz relative tothe standard in a 60 MHz machine, the chemical shift would be:

    = 100 Hz / 60 MHz = 1.7 ppm

    By convention, the Proton Chemical Shift values increase from

    right to left, with a range of 013 In other words: Chemical Shift values decrease with increasing

    Magnetic field strength or Chemical Shift values increase withincreasing Resonance frequency!

    Observed Shift from TMS(Hz) HzChemical Shift = = = PPM

    60 MHz MHz

    NMR

  • 8/10/2019 Nmr Lecture

    29/133

    NMR NMR SpectraThe Internal Reference Standard

    The universally accepted standard used in NMR is:

    Tetramethylsilane (TMS)

    The 12 protons on the four carbon atoms have the samechemical and magnetic environment and they resonate atthe same field strength, i.e., one signal (1 peak) isproduced

    The protons are highly protected from the appliedmagnetic field because of high valence electron density

    The strength of the Diamagnetic Field generated by thevalence electrons in TMS is greater than most otherorganic compounds

    11/10/201

    429

    NMR

  • 8/10/2019 Nmr Lecture

    30/133

    NMR NMR SpectraThe Internal Reference Standard

    Thus, little of the applied magnetic field gets through to

    the TMS protons reducing the Frequency of AngularPrecession (Resonance Frequency) to a value that islower than most other organic compounds.

    For most all other Proton environments, the electron

    density is less than TMS and slightly more of the appliedmagnetic field gets through to the protons resulting in aslightly higher frequencies of Angular Precession.

    11/10/201

    430

    NMR

  • 8/10/2019 Nmr Lecture

    31/133

    NMR NMR SpectraThe Internal Reference Standard

    The TMS signal appears on the far right hand side of

    the X-axis.

    Small amount TMS in the sample produces large signal

    By definition, the Chemical Shift value for TMS is

    0 ppm

    Thus, most all other protons will have Chemical Shifts> 0and will be downfieldfrom the TMS signal.

    11/10/201

    431

    NMR

  • 8/10/2019 Nmr Lecture

    32/133

    NMR NMR SpectraSimple Example

    11/10/201

    432

    All six protons of Ethane are

    chemically and magnetically

    equivalent and all resonate at thesame frequency producing one signal

    consisting of one peak, i.e., a

    singlet.

    An NMR Signal can consist of one or

    more peaks

    Multiple peaks are produced by aphenomenon called spin-spin

    splitting

    NoteSee slides 53-62 for a

    discussion of Spin/Spin Splitting

    For the chemically equivalent

    protons in Ethane there is no

    splitting, thus the signal consists of

    one peak, a singlet

    See next slide for more NMR

    Spectrum examples, showing basic

    splitting patterns

    Typical location (1 ppm) of resonance signal for Methyl groupprotons not under the influence of an electronegative group(see slide )

    Note the 6 at the top of the signal

    This is the peak integration value and represents the electronicallyintegrated area under the signal curve and is proportional to thenumber of Protons generating the signal, i.e., Ethane has 6 chemicallyand magnetically equivalent protons

    See slides 36-39 for a discussion of signal integration

    Signal(singlet)

    Chemical Shift (PPM)

    13 12 11 10 9 8 7 6 5 4 3 2 1 0

    Ethane TMS

    (6)

    NMR

  • 8/10/2019 Nmr Lecture

    33/133

    NMR NMRSimple Examples

    11/10/201

    433

    The Six (6) equivalent Methyl Protons arerepresented as a Triplet at about 1 ppm.

    The 3 Triplet peaks are produced by Spin-Spinsplitting based on the 2 protons attached tothe Methylene Group (n + 1 rule).

    Chemical Shift (PPM)

    Propane The Two (2) equivalent Methylene Protonsare represented as a Septet at about 2 ppm.

    The 7 Septet peaks are produced by spin-spinsplitting based on the 6 protons attached tothe two Methyl groups (6 +1 = 7).

    13 12 11 10 9 8 7 6 5 4 3 2 1 0

    (6)(2)

    TMS

    Toluene

    3 equivalent Protons on

    Methyl Group Carbonattached to a Benzenering Carbon that has no

    attached protons.

    Therefore, the signal is asinglet with no splitting.

    5 unsubstituted Protons

    on Benzene ring are notequivalent, producingcomplex spitting

    patterns typical of theresonance structures in

    aromatic rings.See slides 60-65.

    13 12 11 10 9 8 7 6 5 4 3 2 1 0

    (3)(5)

    The Methyl group donates

    electrons to Benzene ringactivating it. The Methyl

    protons have less electron

    density (deshielded), thus,

    the Chemical Shift is moved

    downfield.

    NMR

  • 8/10/2019 Nmr Lecture

    34/133

    NMR Chemical Equivalence

    Protons in a molecule that are in chemically identical

    environments will often show the same chemical shift Protons with the same chemical shift are chemically equivalent

    Chemical equivalence can be evaluated through symmetry

    Protons in different chemical environments have differentchemical shifts, i.e. a signal is produced for each.

    11/10/201

    434

    Chemicals giving rise to 1 NMR signal Chemicals giving rise to 2 NMR signalsH

    H H

    H

    H

    H

    H H

    H

    CH3

    H

    CH3

    O

    CH3 C O CH3

    CH3 O CH2Cl

    CH3 CH3

    C

    O

    Cyclopentane

    Acetone

    Benzene Methyl Acetate 1,4 dimethyl benzene

    (p-xylene)

    1-Chloro Methyl Ether

    NMR

  • 8/10/2019 Nmr Lecture

    35/133

    NMR An Isomer ExampleC5H12O

    11/10/201

    435

    2-Dimethyl Propanol

    Signals Rel Area

    Value of Signal

    a ~1 9

    b >2 2

    c ~2 1

    t-Butyl Methyl Ether

    Signals

    Rel Area

    Value of Signal

    a ~1 9

    b >>1 3

    9 protons on 3 Methyl groups are equivalent and are not under the influence of theelectronegative OH group.2 protons on Methylene group are equivalent and are influenced by electronegative OH group.The proton on OH group is concentration and hydrogen bonding dependent. Location onspectrum variable.Note: All signals are singlets, i.e., no adjacent protons to produce spin-spine splitting.

    3 2 0.9 0

    tms

    a

    9

    c

    1

    b

    2

    3 2 1 0

    tms

    a

    9

    b3

    (a)

    CH3

    CH3

    CH3 C O CH3(b)(a)

    (a)

    CH3 C CH2OH

    CH3

    CH3

    (a)

    (b) (c)(a)

    (a)

    9 protons on 3 Methyl groups are equivalent and not under the influence of electronegative group.

    3 protons on single Methyl groups are equivalent and are under influence of electronegative oxygen.

    NMR

  • 8/10/2019 Nmr Lecture

    36/133

    NMR Integrals (Signal Area)

    An NMR spectrum also provides means of determining How

    Many of each type of proton the molecule contains. The Area under each signal is proportional to the number

    of protons generating that signal.

    In the Phenylacetone example below there are three (3)

    chemically distinct types of protons:Aryl (7.2 ppm), Benzyl (3.6 ppm), Methyl (2.1 ppm)

    The three signals in the NMR spectrum would have Relative

    Areas in the ratio of 5:2:3.

    Thus, 5 Aryl protons, 2 Benzyl protons, and 3 Methyl

    protons

    11/10/201

    436

    2.1 ppm

    (3 protons)3.6 ppm

    (2 protons)

    7.2 ppm

    (5 protons)

    Phenylacetone

    NMR

  • 8/10/2019 Nmr Lecture

    37/133

    NMR NMR SpectrumPhenylacetone (103-79-7)

    11/10/201

    437

    C9H

    10O

    Methyl

    3 Protons

    Methylene

    2 Protons

    Ring

    5 Protons

    NMR

  • 8/10/2019 Nmr Lecture

    38/133

    NMR Integrals (Signal Area) (Cont)

    NMR Spectrometer electronically integrates the area under a

    signal and then traces rising vertical lines over each peak by anamount proportional to the area under the signalsee nextslide.

    The heights of vertical lines give RELATIVE numbers of each typeof hydrogen.

    Integrals do not always correspond to the exact number ofprotons,e.g., integrals of 2:1 might be 2H:1H or 4H:2H or...

    Computation

    Draw Horizontal lines separating the adjacent signals.

    Measure vertical distance between the Horizontal lines. Divide each value by the smallest value.

    Multiple each value by an integer >1 to obtain wholenumbers.

    See example computation on next Slide.

    11/10/201

    438

    NMR

  • 8/10/2019 Nmr Lecture

    39/133

    NMR Integrals (Signal Area) (Cont)

    NMR SpectrumBenzylacetate (C9H10O2)

    11/10/201

    439

    Peak 7.3 ppm (c) - (h1) 55.5 Div

    Peak 5.1 ppm (b) - (h2) 22.0 Div

    Peak 2.0 ppm (a) - (h3) 32.5 Div

    55.5 div

    22.0 div

    = 2.52

    22.0 div

    22.0 div= 1.00

    32.5 div

    22.0 div= 1.48

    2.52 : 1.00 : 1.48

    5 : 2 : 3

    c : b : a

    Each value multiplied by 2

    to obtain integral values

    h1

    h2

    h3(a)(b)(c)

    NMR

  • 8/10/2019 Nmr Lecture

    40/133

    NMR Chemical ShiftImpact of Electronic Density

    Valence Electrons

    In the presence of the applied magnetic field, thevalence electrons in the vicinity of the proton areinduced to circulate (Local Diamagnetic Current)producing a small secondary magnetic field

    The greater the electron density circulating about thenuclei, the greater the induced magnetic shieldingeffect

    The induced magnetic field acts in opposition(diamagnetically opposed) to the applied magnetic

    field, thus shielding the proton from the effects of theapplied field in a phenomenon called LocalDiamagnetic Shielding or Diamagnetic Anisotropy

    As the Diamagnetic Anisotropy increases, the amountof the applied magnetic field reaching the proton is

    diminished, decreasing the frequency of Resonance11/10/2014

    40

    NMR

  • 8/10/2019 Nmr Lecture

    41/133

    NMR Chemical Shift - Anisotropy (non-uniformity)

    For some proton types, the chemical shifts can be

    complicated by the type of bond present

    Aryl compounds (benzene rings), Alkenes (C=),Alkynes (C ), and Aldehydes (O=CH) showanomalous resonance effects caused by the presence

    of electrons in these structures The movement of these electrons about the proton

    generate secondary non-uniform (anisotropic)magnetic fields

    The relative shielding and deshielding of protons ingroups with electrons is dependent on theorientation of the molecule with respect to the appliedmagnetic field

    11/10/201

    441

    NMR

  • 8/10/2019 Nmr Lecture

    42/133

    NMR Chemical Shift - Anisotropy (non-uniformity) (Cont)

    The Diamagnetic Anisotropic effect diminishes with

    distance

    In most cases, the effect of the DiamagneticAnisotropic effect is to Deshield the protons,increasing the Chemical Shift

    In some cases, such as acetylene hydrogens, theeffect of the anisotropic field is to shield thehydrogens, decreasing the Chemical Shift

    In a Benzene ring , the electrons are induced tocirculate around the ring by the applied magneticfield, creating a ring current, which in turn produces amagnetic field further influencing the shielding of thering protons

    11/10/201

    442

    NMR

  • 8/10/2019 Nmr Lecture

    43/133

    NMR Chemical Shift - Anisotropy (non-uniformity) (Cont)

    The presence of ring current causes the applied

    magnetic field to become non-uniform (diamagneticanisotropy) in the vicinity of the benzene ring

    The effect of the anisotropic field is to further deshieldthe benzene protons, increasingthe chemical shift

    Thus, protons attached to the benzene ring areinfluenced by three (3) magnetic fields:

    Strong Applied Magnetic Field

    Local Diamagnetic Shielding by Valence Electrons Anisotropic Effect from the Ring Current

    The net effect of the deshielding of the Benzene Ringprotons is to increase the Chemical Shift far downfield

    to about 7.0 ppm11/10/2014

    43

    NMR

  • 8/10/2019 Nmr Lecture

    44/133

    NMR Electron Density and Electronegativity

    Protons in a molecule exist in many different electronicenvironments (Methyl group (CH3), Methylene group(CH2), bonds, unsubstituted Benzene ring Protons,Amino protons (NH), Hydroxyl protons (OH), etc.)

    Each proton with a unique electron density configurationwill have a unique Angular Frequency of Precession

    The electron density of a given proton and thus, thefrequency of precession, can be further influenced by

    the presence of electronegativegroups in the vicinity ofthe proton

    Electronegative groups (or elements) are electronwithdrawing, pulling electron density away from the proton

    11/10/201

    444

    NMR

  • 8/10/2019 Nmr Lecture

    45/133

    NMR Chemical ShiftImpact of Electronegative Elements

    The decrease in electron density about the proton

    results in a lower secondary magnetic field, a

    diminished shielding effect, an increase in the

    strength of the applied magnetic field reaching the

    nuclei, resulting in an increase in the precession

    frequency

    Electronegative elements are electron withdrawing

    When added to a carbon atom with protons attached,

    the Electronegative element withdraws electrondensityabout the proton

    Reducing electron density deshieldsthe proton from

    the effect of the applied field, allowing more of the

    magnetic field to impact the proton11/10/2014

    45

    NMR

  • 8/10/2019 Nmr Lecture

    46/133

    NMRChemical ShiftImpact of Electronegative Elements

    (Cont)

    Recall that Deshieldingthe proton increasestheResonance Frequency producing a greater chemicalshift, i.e., the resonance peak is moved downfield tothe left on the spectrum

    The chemical shift increasesas the electronegativityof the attached element increases

    Multiple substitutions have a stronger effect than asingle substitution

    Electronegativity also affects the Chemical Shift ofProtons further down the chain. But the effect isdiminished as distance from the ElectronegativeElement increases

    11/10/201

    446

    NMR

  • 8/10/2019 Nmr Lecture

    47/133

    NMR Chemical ShiftImpact of Electronegative Elements

    11/10/201

    447

    Compound CH3X CH3F CH3OH CH3Cl CH3Br CH3I CH4 (CH3)4SiElement X F O Cl Br I H Si

    Electronegativity of X 4.0 3.5 3.1 2.8 2.5 2.1 1.8

    Chemical Shift (ppm) 4.26 3.40 3.05 2.68 2.16 0.23 0

    CH4 CH3OH CH3CH2OH CH3CH2CH2OH

    0.23 ppm 3.39 ppm 1.18 ppm

    3.59 ppm

    0.93 ppm

    1.53 ppm

    3.49 ppm

    Note: The Chemical Shift of the Proton increases as the

    distance from the Electronegative Oxygen increases.

    NMR

  • 8/10/2019 Nmr Lecture

    48/133

    NMR

    11/10/201

    448

    Chemical Shift values of typical

    Proton environments and the effects

    of Electronegative Elements on the

    Chemical Shift.

    12 11 10 9 8 7 6 5 4 3 2 1 0

    (ppm)

    CHCl3

    -OH, -NH

    TMS

    H

    CH2FCH2Cl

    CH2Br

    CH2I

    CH2O

    CH2NO3

    CH2ArCH2NR2

    CH2S

    C C H

    CH2 C

    O

    CH2

    C CH CC

    C CH2 C

    C CH3

    Acids RCOOH 11.0 - 12.0 ppmAldehydes RCOH 9.0 - 10.0

    Phenols ArOH 4.0 - 7.0

    Alcohols ROH 0.5 - 5.0

    Amines RNH2 0.5 - 5.0

    Amides RCONH2 5.0 - 8.0

    Enols CH=CH-OH 15.0

    Groups with variable chemical shifts

    (Protons attached to elements other than Carbon)

    Methine (1H)

    Methylene (2H)

    Methyl (3H)

    Effects of Electronegativity

    F > O > Cl = N > Br > S > I

    Electronegative Elements will pull electron density away

    from the proton diminishing the electron density. Proton is

    exposed to increased effects of the applied magnetic field,

    which increases the frequency of absorbance (Chemical Shift)moving the Resonance Signal downfield to the left.

    NMR

  • 8/10/2019 Nmr Lecture

    49/133

    NMR General Regions of Chemical Shifts

    11/10/201

    449

    12 11 10 9 8 7 6 5 4 3 2 1 0 (ppm)

    TMSAldehydic

    Aromatic & Heteroaromatic

    Alkene

    -Disubstituted Aliphatic

    -Monosubstituted Aliphatic

    Alkyne

    -Substituted Aliphatic

    Aliphatic Alicyclic (CH2, CH3)

    Carboxylic

    NMR

  • 8/10/2019 Nmr Lecture

    50/133

    NMRApproximate Chemical Shifts

    Protons (1H1) Carbon (13C6)

    11/10/201

    450

    Type of Proton Chemical Shift, (ppm)

    a Chemical shifts of these protons

    vary in different solvents and

    with temperature

    Type of Carbon Atom Chemical Shift , (ppm)

    1oAlkyl, RCH3 0.8 - 1.0

    2o Alkyl, RCH2R 1.2 - 1.4

    3oAlkyl, R3CH 1.4 - 1.7

    Allylic, R2C C CH3 1.6 - 1.9

    R

    Ketone, RCCH3 2.1 - 2.6

    O

    Benzylic, ArCH2-R 2.2 - 2.5Acetylenic, RC CH 2.5 - 3.1

    Alkyl Iodide, RCH2I 3.1 - 3.3

    Ether, ROCH2R 3.3 - 3.9

    Alcohol, HOCH2R 3.3 - 4.0

    Alkyl Bromide, RCH2Br 3.4 - 3.6

    Alkyl Chloride, RCH2Cl 3.6 - 3.8

    Vinylic, RC2 CH

    2 4.6 - 5.0

    Vinylic, RC2 CH2-R 5.2 - 5.7

    Aromatic, ArH 6.0 - 9.5

    Aldehyde, RCH 9.0 - 10.0

    O

    Alcohol hydroxyl, ROH 0.5 - 6.0a

    Amino, R NH2 1.0 - 5.0a

    Phenolic, ArOH 4.5 - 7.7a

    Carboxylic, RCOOH 11 - 12a

    1oAlkyl, RCH3 0 - 402o Alkyl, RCH2R 10 - 50

    3oAlkyl, RCHR2 15 - 50

    Alkyl Halide or Amine, C-X 10 - 65

    Alcohol or Ether, C-O 50 - 90

    Alkyne, C 60 - 90

    Alkene, C = 100 - 170

    Aryl, Ar- 100 - 170

    Nitriles, -C N - 120 - 130

    O

    Amides, -C - N - 150 - 180

    O

    Carboxylic Acids, Esters, C O 160 - 185

    O

    Aldehydes, Ketones, -C - 182 - 215

    C-

    NMR

  • 8/10/2019 Nmr Lecture

    51/133

    NMRFunctional Chemical Functional Chemical

    Group Shift, ppm Group Shift, ppm

    11/10/201

    451

    TMS (CH3)4Si 0 AromaticARH 6.58.0Cyclopropane 0 - 1.0 ARCH (benzyl) 2.32.7Alkanes Fluorides

    RCH3 0.9 FCH 4.24.8R

    2

    CH2

    1.3 ChloridesR3CH 1.5 ClCH 3.14.1

    ClAlkenes ClCH 5.8

    C = CH 4.65.9C = CCH3 1.52.5 Bromides

    BrCH 2.54.0

    AlkynesC CH 1.72.7 IodidesC CCH3 1.62.6 ICH 2.04.0

    NitroalkanesO2NCH 4.24.6

    NMR

  • 8/10/2019 Nmr Lecture

    52/133

    NMRFunctional Chemical Functional Chemical

    Group Shift, ppm Group Shift, ppm

    11/10/201

    452

    Alcohols Carboxylic AcidsHCOH 3.44 O

    ROH 0.55.0 HOCCH 2.12.6

    Phenols O

    ArOH 4.07.0 R COH 11.012.0

    AminesRNH2 0.54.0 Ketones

    Ethers O

    ROC - H 3.23.8 RCCH 2.12.4

    Acetals

    RO R Aldehydes

    C 5.3 O

    RO H RCH 9.010.0

    Esters Amides

    O O

    ROCCH 3.54.8 RCNH 5.09.0

    NMR

  • 8/10/2019 Nmr Lecture

    53/133

    NMR SpinSpin Splitting

    In addition to the Chemical Shift and Signal Area, the

    NMR spectrum can provide information about thenumber of the protons attached to a Carbon atom.

    Through a process called Spin-Spin Splitting, a Protonor a group of equivalent Protons can produce

    multiple peaks (multiplets). Protons on a Carbon atom are affected by the

    presence of Protons on nearby, generally adjacentatoms.

    Spin - Spin splitting is the result of the interaction orcoupling of the +1/2 & -1/2 spins of the protons onthe adjacent carbon atoms.

    Spin - Spin coupling effects are transferred primarilythrough the bonding electrons

    11/10/201

    453

    NMR

  • 8/10/2019 Nmr Lecture

    54/133

    NMR SpinSpin Splitting (Cont)

    Those Protons on the adjacent Protons aligned with

    the applied magnetic field (+1/2 spin state), willtransfer Magnetic Moment to, and thus augment, the

    strength of the magnetic field applied to the Proton

    sensing the adjacent Protons.

    This increase in the magnetic field strength affecting

    the sensing Proton makes it more difficult for the

    secondary or diamagnetic field produced by the

    valence electrons to protect the proton; thus, the

    Proton is deshielded causing the Chemical Shift toincrease slightly

    11/10/201

    454

    NMR

  • 8/10/2019 Nmr Lecture

    55/133

    NMR SpinSpin Splitting (Cont)

    If the spins of the adjacent Protons are opposed to

    the magnetic field (-1/2 spin state), the strength ofthe applied magnetic field around the sensing protonis slightly decreased

    With a reduced applied magnetic field strength, the

    secondary diamagnetic field is better able to shieldthe Proton from the applied field resulting in a slightdecrease in the Chemical Shift (increased ResonanceFrequency)

    With 2 or more Protons on the adjacent Carbonatoms, there will be mixtures of +1/2 & -1/2 spinsstates producing unique Chemical Shift effects

    11/10/201

    455

  • 8/10/2019 Nmr Lecture

    56/133

    NMR

  • 8/10/2019 Nmr Lecture

    57/133

    NMR Spin-Spin Splitting (Cont)

    11/10/201

    457

    1,1,2-Trichloroethane Tert-Butyl Methyl Ether

    (a)

    (a)

    (a) (b)

    All protons chemically equivalent(a) protons & (b) protons are separated by more thanthree (3) bonds

    No signal splitting - 2 signals (a) & (b)

    Possible spincombinations ofadjacent protons

    Net Spin+1 0 -11 2 1

    +1/2 -1/21 1 Signal Intensity

    0

    TMS

    b

    3H

    a

    9H

    NMR

  • 8/10/2019 Nmr Lecture

    58/133

    NMR Spin-Spin SplittingAn example

    11/10/201

    458

    1,1,2-Trichloroethane

    NMR

  • 8/10/2019 Nmr Lecture

    59/133

    NMR Spin - Spin Splitting - Multiplet Signal Intensities

    11/10/201

    459

    Example Spectrum: Ethyl group

    1.833.20

    CH3 CH2

    Note Relative Signal Intensities

    Net Spin +3/2 +1/2 -1/2 -3/2

    = spin +1/2

    = spin -1/2

    There are 3 times as many protons with+1/2 or - 1/2 spin arrangements than +3/2 & -3/2

    Therefore, the signal intensities are greater.

    1 6 15 20 15 6 1

    1 5 10 10 5 1

    1 4 6 4 1

    1 3 3 1

    1 2 1

    1 1

    1

    Pascals Triangle

    0 Singlet

    1 Doublet

    2 Triplet

    3 Quartet

    4 Quintet

    5 Sextet

    6 Septet

    Intensity ratios derived from the n + 1rule

    Each entry is the sum of the two entriesabove it to the left and right.

    The relative intensities of the outersignals in sextet & septet multiplets arevery weak and sometimes obscured.

    (a)

    (a)

    (b)

    (b)

    Intensity 1 3 3 1

    No.

    AdjacentProtons

    No.

    PeaksSeen Relative

    Intensity

    NMR

  • 8/10/2019 Nmr Lecture

    60/133

    NMR Spin - Spin Splitting - Common Splitting Patterns

    11/10/201

    460

    X CH CH Y(X Y)

    CH2 CH

    X CH2 CH2 Y(X Y)

    CH3 C H

    CH3 CH2

    CH3CH

    CH3

    2 signals

    (see 1)

    2 signals(see 1)

    3 signals

    (see 2)

    2 signal(see 1)

    4 signals(see 3)

    4 signals(see 3)

    7 signals(see 6)

    Singlet

    Triplet

    Doublet

    Quartet

    Quintet Sextet

    Septet

    No. signals produced based on the no. of adjacent protons

    2 signals(see 1)

    3 signals(see 2)

    3 signals(see 2)

    2 signals(see 1)

    3 signals(see 2)

    NMR

  • 8/10/2019 Nmr Lecture

    61/133

    NMR Spin - Spin Splitting - Isomer Example

    11/10/201

    461

    1-Chloropropane

    2-Chloropropane

    CH3 CH2 CH2 Cl

    (a) (b) (c)

    Cl

    CH3 CH CH3

    (a)

    (b)

    (a)

    3 signals

    2 signals

    Signal Rel Chem Rel Signal Neighbors MultiplicityShift Area

    a lowest 3 2 3 (Triplet)

    b middle 2 5 6 (Sextet)

    c highest 2 2 3 (Triplet)0 ppm

    0 ppm

    a

    bc

    a

    bSignal Rel Chem Rel Signal Neighbors Multiplicity

    Shift Areaa lowest 6 1 2 (Doublet)b highest 1 6 7 (Septet)

    NMR

  • 8/10/2019 Nmr Lecture

    62/133

    Spin - Spin Splitting - Coupling Constant

    The Coupling Constant (J) is the spacing between thecomponent signals in a multiplet.

    The distance is measured on the same scale as thechemical shift (Hz or cycles per second (CPS)). Note: 60Hz = 1 ppm in a 60 MHz instrument.

    The Coupling Constant has different magnitudes fordifferent types of protons

    11/10/201

    462

    H

    HH H

    C C

    H

    H

    H H

    H

    H

    H C C CH

    CH

    H

    H

    H

    H

    H

    O

    H

    H

    H

    H

    H

    H

    H

    H

    H

    H

    6-8 Hz

    11-18 Hz

    6-15 Hz

    0-5 Hz

    4-10 Hz

    0-3 Hz

    Ortho

    6-10 Hz

    para

    1-4

    Hz

    meta

    0-2 Hz

    8-10 Hz

    a,a 8-14 Hza,e 0-7 Hz

    e,e 0-5 Hz

    cis 6-12 Hz

    trans 4-8 Hz

    cis 2-5 Hz

    trans 1-3 Hz

    5-7 Hz

    NMR

  • 8/10/2019 Nmr Lecture

    63/133

    Magnetic Equivalence

    11/10/201

    463

    They behave as an integral group.

    Protons attached to the same carbon atom and have the same chemicalshift do not show spin-spin splitting.

    These protons are coupled to the same extent to all other protons in the

    molecule.

    They have the same Coupling Constant value J to the HAproton.

    Protons that have the same chemical shift and are coupled equivalentlyto all other protons are magnetically equivalent and do not show spin-spin splitting.

    In the spin-spin example of 1,1,2-Trichloroethane, the two

    (geminal) protons attached to the same carbon atom (HB& HC),do not split each other

    H H

    Cl C C Cl

    Cl H

    A B

    C

    H H

    Cl C C Cl

    Cl HC

    BA

    NMR

  • 8/10/2019 Nmr Lecture

    64/133

    Differentiation of Chemical and Magnetic Equivalence

    11/10/201

    464

    Br

    CH3Br HA

    HBCH3

    Cyclopropane Compound

    Two geminal protons (HA& HB) are chemically equivalent, butnot magnetically equivalent

    Proton HAis on same side of ring as two halogens

    Proton HBis on same side of ring as the two methyls

    Protons HA& HB,therefore have different chemical shifts

    They couple to one another and show spin-spin splitting

    Two doublets will be seen for both HA& HB

    Coupling Constant J for them is about 5 Hz

    NMR

  • 8/10/2019 Nmr Lecture

    65/133

    Differentiation of Chemical and Magnetic Equivalence (Cont)

    11/10/201

    465

    Geminal protons (HA& HB) are chemically equivalent, but not magneticallyequivalent

    Protons HA& HBhave different chemical shifts

    Each has different coupling constant with HC

    Constant JACis a ciscoupling constant

    Constant JBCis a transcoupling constant

    Therefore, HA& HBare not magnetically equivalentThey do not act as group to split proton HC

    HBsplits HCwith constant JBC into a doublet

    HAsplits each component of doublet into doublets with coupling constantJAC

    C = C

    HB

    HA HC

    X

    Vinyl Compound

    NMR

  • 8/10/2019 Nmr Lecture

    66/133

    Proton (1H) NMR Spectrum and Splitting Analysis of Vinyl Acetate

    11/10/201

    466

    Ha& Hbchemically equivalent, butnot magnetically equivalent.

    Each has different chemical shift.

    Each has different coupling constantwith Hc.

    Hbsplits Hcinto doublet (Jbc).

    Hathen splits each Jbcdoublet into adoublet.

    Similary, Hasplits Hcinto doublet (Jac).

    Hbthen splits each Jacdoublet into adoublet.

    Hcsplits Ha& Hb into doublets.

    Ha& Hbeach then split thesedoublets.

    NMR

  • 8/10/2019 Nmr Lecture

    67/133

    Aromatic Compounds (Substituted Benzene Rings)

    We have previously stated that a magnetic fieldapplied to an Aromatic ring becomes non-uniform(anisotropic) by the stabilizing effect of the BenzeneRing Current resulting in the protons beingdeshielded(electron density becomes less); thus,

    increasing the chemical shift. i.e., the absorptionsignal (Resonance Frequency) moves to the left onthe chartin the vicinity of 7.0 ppm.

    Depending on the number and type of groupssubstituted on an Aromatic ring, the NMR spectra ofthe remaining protons on the ring are often complex,with the Chemical Shift moving up field or downfield.

    11/10/201

    467

    NMR

  • 8/10/2019 Nmr Lecture

    68/133

    Some groups, such asCyano, Nitro, Carboxyl,Carbonylare electron-withdrawing(deactivate the

    ring), decreasing the electron density, and resultingin an increase in the Chemical Shift, i.e., resonancefrequency moves further down field.

    For Electron-Withdrawing groups the Ortho & Para

    protons lose more electron density that the Metaprotons; thus, are less shielded moving (increasing)the chemical shift downfieldrelative to the Metaprotons.

    11/10/201

    468

    NMR

  • 8/10/2019 Nmr Lecture

    69/133

    Aromatic Compounds (Substituted Benzene Rings) (Cont)

    Electron-donating groups such asMethyl, Methoxy, Amino,Hydroxyactivatethe ring and increase the electron densityresulting in a decrease in the Chemical Shift, i.e., resonancefrequency moves up field to the right.

    For ElectronDonating groups, the Ortho & Para protons gainmore electron densitythan the Meta protons; thus are moreshieldedmoving (decreasing) the chemical shift up field slightly

    from the Meta protons.

    MonoSubstituted Aromatic Rings

    When a single substituted group is neither strongly electron-withdrawing (deactivates ring by decreasing electron density

    about the ring protons) nor strongly electron-donating(activates ring by increasing the electron density)Methyl &Alkyl groups, all ring protons (ortho, meta, para) have nearidentical chemical shifts resulting in a slightly broad singlet(the protons are not quite chemically equivalent).

    See pattern A on slide 7311/10/201

    469

    NMR

  • 8/10/2019 Nmr Lecture

    70/133

    Aromatic Compounds (Substituted Benzene Rings) (Cont)

    MonoSubstituted Aromatic Rings (Cont)

    In general, electron withdrawing groups (Cyano, Nitro,Carboxyl, Carbonyl) decrease the electron density of theOrtho & Para protons more so than the Meta protons,resulting in the signal for the O & P protons being slightlymore downfield than the Signal for the Meta protons as seenin pattern C on slide 73).

    In the case of electron withdrawing groups with double bondssuch as Nitro (NO2) and Carbonyl (C=O) groups, or otherdouble bonds attached directly to the ring, MagneticAnisotropy causes the Ortho protons to be much moredeshielded than the Para & Meta protons, resulting in theOrtho protons having a significantly increased Chemical shiftas seen in pattern D on slide 73.

    In the case of electron donating group such as Methyl,Methoxy, Amino, Hydroxy, the Chemical Shift of the Ortho &Para protons, while not exactly the same, will be distinctly upfield from the Meta protons as seen in pattern B on slide 73.

    11/10/201

    470

    NMR

  • 8/10/2019 Nmr Lecture

    71/133

    Aromatic Compounds (Substituted Benzene Rings) Cont)

    MonoSubstituted Aromatic Rings (Cont)

    For Monosubstituted Electronegative elements, such asHalides, which are electron withdrawing due to the Dipoleeffect, the electron withdrawing effect is less dominant thanthe electron donating resonance effect.

    Thus, the increased electron density about the Ortho & Para

    protons would be increased relative to the Meta protons,resulting in an decrease in the Chemical Shiftsignal movesup field as seen in pattern E on slide 64.

    Note: The m/p signal is actually an overlapping of the mand p signals with the p signal slightly up field from

    the m signal.The o proton has more electron density than the pproton because of the Magnetic Anisotropy effects of thering current.

    11/10/201

    471

    NMR

  • 8/10/2019 Nmr Lecture

    72/133

    Aromatic Compounds (Substituted Benzene Rings) Cont)

    ParaDisubstituted Rings

    P-Disubstituted patterns are generally easy to recognize.

    When the Aromatic ring has two groups substituted in thepara position, three distinct patterns are possible, dependingon the relative electronegativity of the two groups.

    If the two p-substituted groups are identical, the fourremaining protons on the ring are chemically and magneticallyequivalent producing a singlet as seen in pattern F (a) onslide 73.

    If the two p-substituted groups are different, the protons onone side of the symmetrically ring split the protons on the

    other side of the ring into a doublet.

    The patterns produced by the two doublets will be differentdepending on the relative electronegativity of the twosubstituted groups as seen in patterns F (b) & F (c) on slide73.

    11/10/201

    472

    NMR

  • 8/10/2019 Nmr Lecture

    73/133

    Common Aromatic Patterns

    11/10/201

    473

    NMR

  • 8/10/2019 Nmr Lecture

    74/133

    Activating and Deactivating groups and the impact ofthe changing electron density in the Benzene ring on

    Chemical Shift of ortho, meta, para protons

    11/10/201

    474

    Methoxyl (0-CH3) group is ElectronDonating, activates ring by addingelectron density to o/p protons.

    Chemical Shifts,

    , of ring o/pprotons are moved up field, i.e.,

    decreasing ppm because ofincrease electron density.

    Note location of Methyl Protonsabsorption at 3.7 ppm (withoutinfluence of O it would be around1 ppm).

    m o, p

    m

    m

    p o

    o

    3 Methyl Protons

    Anisole (C7H8O)

    NMR

  • 8/10/2019 Nmr Lecture

    75/133

    Activating and Deactivating groups and the impact ofthe changing electron density in the Benzene ring on

    Chemical Shift of ortho, meta, para protons

    11/10/201

    475

    m o/p

    The Amino group is Electron Donatingand Activates the ring.

    Increases electron density aroundOrtho & Paraprotons relative to Meta.

    Chemical Shift,,of ring protons is up

    field, decreased ppm

    o

    m

    m

    op

    2 Amino

    Protons

    Aniline (C6H7N)

    NMR

  • 8/10/2019 Nmr Lecture

    76/133

    Activating and Deactivating groups and the impact ofthe changing electron density in the Benzene ring on

    Chemical Shift of ortho, meta, para protons

    11/10/201

    476

    Nitro group is electron withdrawing anddeactivates the ring.

    Protons in ring are deshielded movingChemical Shift downfield.

    Magnetic Anisotropy causes the Orthoprotonsto be more deshielded than the Para & Metaprotons.

    p m

    o

    o

    m

    m

    p

    o

    Nitrobenzene (C6H5NO2)

  • 8/10/2019 Nmr Lecture

    77/133

    NMR

  • 8/10/2019 Nmr Lecture

    78/133

    Activating and Deactivating groups and the impact ofthe changing electron density in the Benzene ring onChemical Shift of ortho, meta, para protons

    11/10/201

    478

    c

    b a

    The Methoxy group ismoderately activating,while the Nitro groups arestrongly deactivating

    (electron withdrawing) Net effect is to Decrease

    the electron density aboutthe ring protons

    The a & b protons areOrtho to the stronglydeactivating Nitro groups,thus, they have reducedelectron density and theirChemical Shift is down

    field relative to the cproton

    All protons interact toproduce Spin-SpinCoupling.

    ab c

    3H

    2,4-Dinitroanisole (C7H6N2O5)

    NMR

  • 8/10/2019 Nmr Lecture

    79/133

    Protons attached to atoms other than carbon atoms

    Widely variable ranges of absorptions.

    Protons on heteroelements, such as oxygen (hydroxyl,carboxyl, enols), and nitrogen (amines, amides)normally do not couple with protons on adjacentcarbon atoms to give spin- spin splitting.

    Solvent effect - The absorption position is variablebecause these groups undergo varying degrees ofhydrogen bonding in solutions of differentconcentrations.

    Amount of hydrogen bonding can radically affect thevalence electron density producing large changes inchemical shift.

    11/10/201

    479

    NMR

  • 8/10/2019 Nmr Lecture

    80/133

    Protons attached to atoms other than carbon atoms(Cont)

    Absorption signals are frequently broad relative toother singlets, which can be used to help identify thesignal.

    Protons attached to Nitrogen atoms often show

    extremely broad signals and can be indistinguishablefrom the base line.

    11/10/201

    480

    Typical Ranges for Groups with Variable Chemical Shifts

  • 8/10/2019 Nmr Lecture

    81/133

    NMR

  • 8/10/2019 Nmr Lecture

    82/133

    NMR Spectra at Higher Field Strengths (Cont)

    For example, a proton group resonating at 60 Hz in a

    60 Mhz instrument would resonate at 100 Hz in the100 Mhz instrument.

    This effectively stretches the X-axis scale improvingresolution.

    Note, however, the value in ppm, does not change.

    11/10/2014

    82

    NMR

  • 8/10/2019 Nmr Lecture

    83/133

    Chemical Shift Reagents

    Interactions between molecules and solvents, such as

    those due to hydrogen bonding can cause largechanges in resonance positions of certain types ofprotons, such as hydroxy (OH) and amino (NH2).

    Changes in resonance positions can also be affected

    by changing from the usual NMR solvents, such aschloroform (CCL4) and deuterochloroform (CDCl3) tosolvents like benzene which impose local anisotropiceffects on the surrounding molecules.

    In some cases a solvent change allows partiallyoverlapping multiplets to be resolved.

    Most chemical shift reagents are organic complexes ofthe Lanthanide elements.

    11/10/2014

    83

    NMR

  • 8/10/2019 Nmr Lecture

    84/133

    Chemical Shift Reagents (Cont)

    When added to a compound, these complexesproduce profound chemical shifts, sometimes up fieldand sometimes downfield, depending on the metal.

    Europium, erbium, thulium, and ytterbium shiftresonances to the lower field (higher ).

    Cerium, praseodymium, neodymium, samarium,

    terbium, and holmium shift resonances to the higherfield (lower ).

    Another advantage of shift reagents is that shiftssimilar to those observed at higher fields can beinduced without the need to purchase an expensive

    higher field instrument. The amount of the shift change depends on the

    distance separating the lanthanide element from theproton group and the concentration of the shiftreagent.

    11/10/2014

    84

    NMR

  • 8/10/2019 Nmr Lecture

    85/133

    Example 1H1NMR Spectra

    11/10/2014

    85

    Suggestions

    For

    Interpreting NMR Spectra

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    86/133

    NMR Spectra Interpretation Procedure

    The following 4 slides provide a suggested process to

    follow in attempting to interpret an NMR Spectra.

    The 1stslide is a typical NMR spectra showing 5signals each consisting of one or more peaks.

    Note that each signal has a number associated with itrepresenting the area integration, i.e., the number ofprotons generating the signal.

    Also note the expanded spectra of the signal at 2.6ppm. Expanded spectra are often provided when the

    signal lacks sufficient resolution to clearly display thenumber of peaks being generated by the protons onthe carbon atom generating the signal.

    11/10/2014

    86

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    87/133

    The 2ndslide presents interpretations of each signalrelative to the number of protons (n) on the carbon

    atom generating the signal and the number of protonsattached to adjacent carbons atoms that produce then+1 peaks comprising the signal as a result of spin-spin splitting.

    The 3rdslide shows how the fragments from slide 2might fit together.

    The 4thslide ties it all together.

    11/10/2014

    87

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    88/133

    Four slides demonstrating a process for interpreting anNMR Spectra

    11/10/2014

    88

    3H

    Chemical Shift (

    ) in PPM

    Note: Magnetic Field (Ho) increases

    Slide 1

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    89/133

    Slide 2

    11/10/2014

    89

    Sextet

    Quintet

    2 protons see 4 protons

    5 peaks (quintet) produced

    3 protons see 2 protons

    3 peaks (triplet) produced

    1 proton sees 5 protons

    6 peaks (sextet) produced

    3 protons see 1 proton

    2 peaks (doublet) produced

    3H

    Mono-substituted

    Benzene Ring

    Doublet TripletFrom chemical shifts, peak

    integration values, and splitting

    patterns, develop substructures for

    each signal.

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    90/133

    Slide 3

    11/10/2014

    90

    Solve the Puzzle

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    91/133

    Slide 4

    11/10/2014

    91

    The Solution: 2-Phenylbutane (C10H14)

    3H

    Integration value (Area under signal)is proportional to No. of Protons

    generating the signal

    3 + 2 +1 = 6

    Spin-Spin Splitting

    No. of peaks in a signal is equal

    to the number of protons on all

    adjacent carbon atoms plus 1

    (N+1 rule)

    5 protons on a

    mono-substitutedBenzene Ring

    3 protons on a

    Methyl group

    see 2 adjacent

    protons

    2 protons on a

    Methylene group

    see 4 adjacen

    protons

    sextet

    quintet

    doublet

    1 proton on

    Methine groupsees 5 adjacen

    protons

    3 protons on a

    Methyl group

    see 1 adjacentproton

    triplet

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    92/133

    11/10/2014

    92

    Benzyl Acetate (C9H10O2)

    Methyl Protons (3)

    No adjacent protons;

    no splitting

    Methylene Protons (2)

    No adjacent protons;

    no splittingAromatic Protons (5)

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    93/133

    Cyclohexene (C6H10)

    11/10/2014

    93

    c

    c

    b

    b

    a

    ac

    b

    a

    3 different chemical environments

    Peaks actually show splitting,

    but is hard to see at this

    resolution (90Hz)

    n+1=2+1=3

    (triplet)

    n+1=3+1=4

    (quartet)

    2H

    4H

    4H

    The single protons on the

    c carbons are equivalent;

    thus, they do not split each

    other.The single protons on each

    c carbon split the

    respective adjacent b

    proton to form two equal

    overlapping triplets

    The a protons have a

    smaller Chemical Shift

    than the b protons

    because of their

    relative position to the

    electron rich bond.

    The sets of 2 protonson each of the adjacent

    a carbons are

    equivalent and do not

    split each other.

    Each 2 proton set on

    an a carbons splits

    its respective adjacent

    2 b protons to form 2overlapping triplets.

    The 2 protons on each of

    the equivalent b carbonssplit their respective

    adjacent protons (1 on the

    c carbon and 2 on the a

    carbon) to form two equal

    overlapping quartets

    n+1=2+1=3

    (triplet)

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    94/133

    2,5-Hexanedione (Acetonylacetone) (C6H10O2)

    11/10/2014

    94

    n+1=0+1=1

    (singlet)

    n+1=0+1=1

    (singlet)

    2 Sets Methylene ProtonsChemical & Magnetically Equivalent

    They do not split each other

    6H

    4H

    NMR Example SpectraCi Stilb (C H )

  • 8/10/2019 Nmr Lecture

    95/133

    Cis-Stilbene (C14H12)

    11/10/2014

    95

    Aromatic Protons (10)

    (very fine splitting)

    Vinyl Protons (2)

    Chemically & Magnetically Equivalent

    Do Not Split

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    96/133

    Methyl Phenyl Acetate (C9H10O2)

    11/10/2014

    96

    Aromatic Protons (5)

    Methylene Protons (2)n+1 = 0 + 1 =1

    Chem Shift3.65 ppm

    Methyl Protons (3)n+1 = 0 + 1 = 1

    Chem Shift3.60 ppm

    Note: 2 OverlappingAbsorptions!! Electronegative

    Carboxyl Oxygen forces shift

    of Methyl Proton absorptions

    downfield to about same

    location as shift of Methylene

    Protons forced downfield by

    effects of electronegative

    Carbonyl group.

    NMR Example Spectra4 H t (C H O)

  • 8/10/2019 Nmr Lecture

    97/133

    4-Heptanone (C7H14O)

    11/10/2014

    97

    n+1 = 2+1=3 n+1 = 5+1=6 n+1 = 2+1=3

    The Methyl & Methylene group

    protons on the left side of the

    Molecule are Chemically & MagneticallyEquivalent to their counterparts on the

    right side, thus, the Chemical Shifts are

    the same and signals overlap

    NMR Example SpectraI l B (C H )

  • 8/10/2019 Nmr Lecture

    98/133

    Isopropyl Benzene (C9H12)

    11/10/2014

    98

    6H

    1H

    5H

    1 proton sees6 protons

    Producing Septetn+1=6+1=7

    6 protons see

    1 proton

    producing

    Doublet

    n+1=1+1=2

    NMR Example SpectraP Nit t l (C H NO )

  • 8/10/2019 Nmr Lecture

    99/133

    P-Nitrotoluene (C7H7NO2)

    11/10/2014

    99

    3H

    Nitro group is strongly deactivating and

    the Methyl group is weakly activating.The net withdrawing effect on benzene ring

    moves the chemical shift downfield, the

    Protons ortho to the Nitro group more so than

    The protons ortho to the Methyl group.

    P- Dibsubstitution

    4H

    NMR Example Spectra

  • 8/10/2019 Nmr Lecture

    100/133

    Phenacetin (C10H13NO2)

    11/10/2014

    100

    n+1=0+1=1

    (singlet)

    n+1=3+1=4

    (quartet)

    2H

    1H

    3H

    P-Disubstitutionn+1=2+1=3

    (triplet)

    3H

    4H

    NMR Example SpectraIsobutyric Acid (C H O )

  • 8/10/2019 Nmr Lecture

    101/133

    Isobutyric Acid (C4H8O2)

    11/10/2014

    101

    n+1=1+1= 2

    (doublet)

    n+1=6+1=7

    (septet)

    CarboxylicProton

    6H

    1H1H

    NMR Example Spectra4 Amino Acetophenone (C H NO)

  • 8/10/2019 Nmr Lecture

    102/133

    4-Amino-Acetophenone (C8H9NO)

    11/10/2014

    102

    2 2

    2

    3

    P-Disubstitution

    3 Methyl protons see

    0 adjacent protons

    producing singlet

    n+1=0+1=1

    Chemical Shift moved

    downfield because

    of proximity toElectronegative

    Carbonyl group (C=O)

    Withdrawing Donating

    NMR Example SpectraButyrophenone (C H O)

  • 8/10/2019 Nmr Lecture

    103/133

    Butyrophenone (C10H12O)

    The Chemical Shift of the Methylene group nearest the moderately

    deactivating Carbonyl group is greater than the adjacent Methylene group,

    because the deactivating effect diminishes with distance

    11/10/2014

    103

    3

    2

    Propoxyl group is moderately

    deactivating, deshielding oring protons more so than p

    protons (aniostropic effect)

    m protons are deshielded least

    2

    ortho

    (2)

    para, meta

    (3)

    NMR Example SpectraCyclohexanone (C H O)

  • 8/10/2019 Nmr Lecture

    104/133

    Cyclohexanone (C6H10O)

    11/10/2014

    104

    4

    4

    2The 2 (c) protons see the 4 (b) protons

    producing a 4 + 1 = 5 quintet

    The 4 (a) protons, probably 2 identical

    Methylene groups each of which is attached to

    a (b) Carbon with 2 protons.The net effect of these equivalent structures is

    that two protons see two adjacent protons

    producing a triplet: 2+1 = 3.

    The 4 (b) protons represent 2 identical

    Methylene groups each of which is attached to

    an equivalent Methylene group.The (b) protons also see the two (c) protons.

    The net effect of this is that the 4 (b) protons

    see effectively 2 (a) protons and 2 (c) protons

    producing a 4 +1 = 5 quintet.

    Two quintets

    overlappiing

    a a

    bb

    c

    NMR Example SpectraIsobutyl Acetate (C H O )

  • 8/10/2019 Nmr Lecture

    105/133

    Isobutyl Acetate (C6H12O2)

    11/10/2014

    105

    6

    2

    2

    3

    Nonet DoubletTriplet

    Singlet

    1 proton sees

    8 adjacent protons

    producing (8+1) 9 peaks

    3 protons see 0 protons on

    Carbonyl carbon producing a singlet

    6 protons see

    1 adjacent proton

    producing doublet

    2 protons see1 adjacent proton

    produces doublet

    NMR (Carbon13) Carbon-13 Nuclear Magnetic Resonance

  • 8/10/2019 Nmr Lecture

    106/133

    Carbon 13 Nuclear Magnetic Resonance Carbon-13 (13C6) possesses spin (I=1/2); thus it is a

    candidate for NMR

    Carbon-13 resonances are not easy to observe: Natural abundance of of C-13 is 1.08 %

    Magnetic Moment () is low

    Resonances are 6000 times weaker than those of

    hydrogen Fourier Transform instrumental techniques make it possible

    to observe 13C6nuclear magnetic resonance.

    Chemical Shift is most useful parameter derived from 13C6spectra.

    Integrals (signal areas) are Unreliable and not necessarilyrelated to the relative number of 13C6atoms present.

    Hydrogens attached to 13C6atoms cause spin-spin splitting,spin-spin interaction between adjacent carbon atoms israre.

    11/10/2014

    106

    NMR (Carbon13) Carbon-13 Nuclear Magnetic Resonance

  • 8/10/2019 Nmr Lecture

    107/133

    Carbon-13 Nuclear Magnetic Resonance

    The Chemical Shifts for 13C6spectra are reported by the

    number of ppm (units) that the signal is shifted downfieldfrom TMS, just as in the proton NMR.

    The 13C6scale ranges from 0 (TMS) in the upper (highermagnetic)_field to 225 ppm in the lower field.

    Resonance signals are more distinct providing moreresolution.

    Adjacent CH2 carbons have distinct resonance signals.

    Unusual to find two carbon atoms in a molecule with thesame chemical shift unless they are chemically equivalentby symmetry.

    11/10/2014

    107

    NMR (Carbon13) Coupled C 13 Spectra

  • 8/10/2019 Nmr Lecture

    108/133

    Coupled C-13 Spectra

    In coupled C-13 NMR spectra, the spectra diagram

    exhibits spin-spin splitting, similar to Proton NMR, butwith a significant difference

    The splitting pattern exhibited by a particular C-13atom follows the N+1 rule, but the value of N is based

    on the number of protons attached to the C-13 atom,NOT the number of protons attached to the adjacentcarbon atoms.

    11/10/2014

    108

    NMR (Carbon13) Coupled C-13 Spectra - Example

  • 8/10/2019 Nmr Lecture

    109/133

    Coupled C-13 Spectra - Example

    11/10/2014

    109

    A. In the coupled spectra of Ethyl Phenyl Acetate (Slide 107),

    the Methyl group at 14.2 ppm is split into quartet by the three

    hydrogen atoms attached to the carbon itself, not the protons

    on the adjacent Methylene (CH2) group

    B. Each quartet line is split into a triplet by the adjacent CH2

    group (not seen on chart).

    Ethyl Phenyl Acetate

    Carbons

    1 Aromatic Ar1 Benzyl CH21 Methylene CH21 Methyl CH31 Carboxyl O=C-O

    (See Slide 113)

    CH2 C O CH2 CH3

    O

  • 8/10/2019 Nmr Lecture

    110/133

    NMR (Carbon13) Broad-Band Decoupled 13C6 Spectra

  • 8/10/2019 Nmr Lecture

    111/133

    Broad Band Decoupled C6Spectra

    Simple molecules such a Ethyl Phenyl Acetate can

    yield interesting and useful structural information,namely the number of hydrogens attached to eachcarbon.

    However, for larger molecules the spectra can become

    very complex with overlapping splitting patterns. A broader range of 13C6spectra can be obtained if all

    the protons are decoupledfrom the molecule byirradiating them simultaneously with a broad spectrum

    of frequencies in the appropriate range.

    11/10/2014

    111

    NMR (Carbon13) Broad-Band Decoupled 13C Spectra (Cont)

  • 8/10/2019 Nmr Lecture

    112/133

    Broad Band Decoupled C6Spectra (Con t)

    The decoupled spectra are much simpler and easier to

    interpret. Each signal represents a different carbon atom.

    If two carbon atoms are represent by a single signal,they must be equivalent by symmetry.

    In the Aromatic ring of Ethyl Phenyl Acetate, thecarbons at positions 2 & 6 produce a single signal,and the carbons at positions 3 & 5 also produce asingle signal.

    11/10/2014

    112

    NMR (Carbon13) Carbon-13 Spectra for coupled and decoupled Ethyl

  • 8/10/2019 Nmr Lecture

    113/133

    p p p yPhenyl Acetate

    11/10/2014

    113

    NMR (Carbon13) Chemical Shifts for Carbon-13 NMR

  • 8/10/2019 Nmr Lecture

    114/133

    Chemical Shifts for Carbon 13 NMR

    Chemical Shift of each Carbon indicates its type and

    structural environment. As with proton NMR, electronegativity, hybridization, and

    anisotropy effects influence the chemical shift.

    11/10/2014

    114

    Correlation Chart for Carbon-13 (ppm from TMS)

    NMR (Carbon13) Carbon-13 Spectra (Proton Decoupled)

  • 8/10/2019 Nmr Lecture

    115/133

    Carbon 13 Spectra (Proton Decoupled)

    2,2-Dimethylbutane

    Six carbon atoms, but only 4 signals + solventsignals for CDCl3and TMS.

    Single Methyl Carbon (a), signal at 8.8 ppm.

    Three Methyl Carbons (b) on quaternary Carbon(c), signal at 28.9 ppm.

    Quaternary Carbon (c), which has no hydrogensattached, appears as a small (weak) signal at 30.4

    ppm.

    11/10/2014

    115

    Cont on next slide

    NMR (Carbon13) Carbon-13 Spectra (Proton Decoupled)

  • 8/10/2019 Nmr Lecture

    116/133

    Carbon 13 Spectra (Proton Decoupled)

    2,2-Dimethylbutane (Cont)

    Methylene Carbon (d), signal at 36.5 ppm.

    Relative size of signals gives some idea of numberof each type of carbon

    Note: Signal at 28.9 ppm for 3 carbon atoms.

    11/10/2014

    116

    2,2-Dimethylbutane

    NMR (Carbon13) Aromatic Ring Methyl Substitution

  • 8/10/2019 Nmr Lecture

    117/133

    Aromatic Ring Methyl Substitution

    11/10/2014

    117

    5 Carbon Types 3 Carbon Types 9 Carbon Types 6 Carbon Types

    CH3

    CH3

    CH3

    CH3

    CH3

    CH3

    CH3

    CH3

    CH3

    CH3

    NMR (Carbon13) Bromocyclohexane & Cyclohexanol

  • 8/10/2019 Nmr Lecture

    118/133

    Bromocyclohexane & Cyclohexanol

    A carbon atom should be deshielded by the presence

    of an electronegative element. The ring carbon atoms will resonate at a higher field

    (smaller shift) as they are located farther away fromthe electronegative element

    11/10/2014

    118

    Bromocyclohexane

    Cyclohexanol

  • 8/10/2019 Nmr Lecture

    119/133

    NMR (Carbon13) Toluene (Hydrogen Coupled Spectrum)

  • 8/10/2019 Nmr Lecture

    120/133

    ( y g p p )

    Diamagnetic Anisotropy causes the carbon atomsignals of the aromatic ring [ (e) > (d) > (c) > (b) ] toappear at lower field strengths (higher values).

    The signal (a) for the Methyl carbon atom attached tothe ring located in the higher field (value about 22)illustrates little anisotropic effect of aromatic ring.

    11/10/2014

    120

    Toluenea

    NMR (Carbon13) Cyclohexanone

  • 8/10/2019 Nmr Lecture

    121/133

    y

    Strong deshielding effect of carbonyl group.

    The carbonyl carbon atom (d) resonates at a very low fieldvalue value about 211.3

    11/10/2014

    121

    NMR (Carbon13) Symmetry - 1,2- & 1,3-Dichlorobenzene isomers

  • 8/10/2019 Nmr Lecture

    122/133

    y y , ,

    A plane of symmetry for 1,2-Dichlorobenzene definesthree (3) different Carbon atoms, producing three

    signals. A plane of symmetry for 1,3-Dichlorobenzene defines

    four (4) different Carbon atoms, producing foursignals

    11/10/2014

    122

    1,2-Dichlorobenzene

    1,3-Dichlorobenzene

    NMR Summary NMR Summary Notes

  • 8/10/2019 Nmr Lecture

    123/133

    y

    NMR - An instrumental technique to determine thenumber, type, and relative positions of certain atoms ina molecule.

    The technique is based on the nuclear spin properties ofthe nuclei of certain elements and isotopes.

    When the nuclei of these elements are placed in astrong magnetic field and irradiated with low energyradio waves (wavelengths of 1 - 5 meters) they absorbenergy through a process called magnetic resonance.

    Under these conditions the absorption of energy is

    quantized producing a characteristic spectrum for thecompound.

    The absorption of energy does not occur unless thestrength of the magnetic field and the frequency of theelectromagnetic radiation are at specific values.

    11/10/2014

    123

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    124/133

    y ( )

    1H1and

    13C6have odd atomic number and/or atomic

    mass; thus they have spin properties and are the twoprimary isotopes utilized in NMR.

    1H1and

    13C6have two spins states (+1/2 & -1/2).

    Nuclei with +1/2 spin state align with an appliedmagnetic field.

    Nuclei with -1/2 spin state oppose magnetic field.

    Resonance - If radiofrequency (low energy, longwavelength) waves are applied to nuclei with spin inan applied magnetic field, the lower energy nucleialigned with the field absorb a quantized amount ofenergy, reverse direction, and become opposed to thefield.

    The stronger the magnetic field, the greater the

    energy absorption (resonance).11/10/2014 124

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    125/133

    y ( )

    An NMR instrument applies a constant radiofrequency

    of 60, 100, or 300 MHz and applies an increasingmagnetic field strength.

    A higher field strength instrument allows for cleanerseparation of overlapping signals, i.e., more

    resolution. Protons or Carbon-13 atoms of different types

    (chemical environments electronegativity, anisotropy,etc.) resonate at unique field strengths measured in

    Hertz (cycles per second) producing a signal (peak)on the chart paper.

    11/10/2014 125

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    126/133

    A parameter called the Chemical Shift ()has been

    defined to give the position of the absorption of aproton a quantitative value.

    The Chemical Shift values are report in units of PartsPer Million (ppm).

    Magnetic field, in Hertz, increases from left to right onchart scale, while increases from right to left starting

    with 0 (for TMS) to 13. Protons in molecules in chemically equivalent

    environments will generally have the same chemicalshift - one signal is produced.

    11/10/2014 126

    Observed Shift from TMS (in Hz) HzChemical Shift () = = = PPM

    60 MHz MHz

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    127/133

    The area under an NMR signal is proportional to the

    number of protons generating the signal. The NMR Spectrometer electronically integrates the

    area under the signal.

    The height the of traced vertical line gives the relative

    numbers of each type of hydrogen.

    Diamagnetic Shielding - Valence electrons shieldproton from applied magnetic field.

    Electronegative elements produce an electronwithdrawing effect, deshielding the proton, resultingin a larger chemical shift, that is, a smaller magneticfield is required to induce resonance.

    11/10/2014 127

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    128/133

    The movement of the electrons in aromatic rings(benzene, etc), alkenes C=, Alkynes (C), andaldehydes (O=CH) produce their own magnetic fieldscausing the applied magnetic field to become non-uniform (diamagnetic anisotropy), which deshields theproton increasing the chemical shift.

    In some cases, such as acetylenes, the effect of theanisotropic field is to shield the hydrogens, decreasingthe chemical shift.

    Protons are affected by the presence of protons onnearby, generally adjacent, carbon atoms.

    Each type of proton senses the number ofequivalent protons (n) on the carbon atom next tothe one it is bonded, and splits its resonance signalinto n+1 signals, a multipletSpinSpin Splitting.

    11/10/2014 128

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    129/133

    Coupling Constant (J) - The spacing, in Hz, betweenthe component signals in multiplet.

    The Coupling Constant has different magnitudes fordifferent types of protons.

    Protons that have the same chemical shift and arecoupled equivalently to all other protons are

    magnetically equivalent and do not show spin-spinsplitting.

    For example: Protons attached to the same carbonatom that have the same chemical shift do not spliteach other.

    In monosubstituted aromatic rings, all ring protonshave near identical chemical shifts resulting in asingle, but slightly broader single.

    11/10/2014 129

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    130/133

    Electron-withdrawing (electronegative) groups, such

    as nitro, cyan, carboxyl, and carbonyl, deshield thering moving the chemical shift downfield (increase ).

    Electron-donating groups, such as methoxy, amino,increase the electron density, moving the chemicalshift up field (decrease ).

    Hydrogen on heteroelements - Protons on elementsother than carbon, such as, oxygen (hydroxyl,carboxyl, enols), nitrogen (amines, amides) do notcouple with protons on adjacent carbon atoms; thus

    no spin-spin splitting.

    11/10/2014 130

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    131/133

    Solvent effect - The absorption position in variablebecause these groups undergo varying degrees ofhydrogen bonding in solutions of differentconcentrations.

    The amount of hydrogen bonding can radically affectthe valence electron density producing large changes

    in chemical shift. Chemical Shift Reagents - Chloroform,

    Deuterochloroform, Organic Complexes of LanthanideElements.

    When added to the compound in question, thesecomplexes produce profound chemical shifts,sometimes up field and sometimes downfield,depending on the metal.

    11/10/2014 131

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    132/133

    Europium, erbium, thulium, and ytterbium shiftresonances to the lower field (higher ).

    Cerium, praseodymium, neodymium, samarium,terbium, and holmium shift resonances to the higherfield (lower ).

    Carbon-13 NMR - 13C6

    has spin and produces NMRspectra.

    Carbon-13 resonances not easy to observe - naturalabundance 1.08 %, low magnetic moment, 6000times weaker than those of hydrogen.

    Integrals (signal areas) are not reliable as indicatorsof the number of carbon atoms.

    Chemical shift scale - 0 to 200 (higher resolution).

    11/10/2014 132

    NMR Summary NMR Summary Notes (Cont)

  • 8/10/2019 Nmr Lecture

    133/133

    Higher resolution produces more distinctive signalsmaking it easier to resolve signal overlapping.

    Unusual to find two carbon atoms with same chemicalshift unless chemically equivalent.

    Except for a few simple molecules, 13C6spectra canbecome very complex, making interpretation difficult.

    Irradiation of the molecules simultaneously with abroad spectrum of frequencies decouples thehydrogens from the molecule producing a muchsimpler spectra.

    Electronegativity, hybridization, and anisotropy effectsinfluence the chemical shiftt