Need for Risk Managementpeople.math.gatech.edu/~peng/6783Spring10/Chap11.pdf · 2010. 1. 3. ·...
Transcript of Need for Risk Managementpeople.math.gatech.edu/~peng/6783Spring10/Chap11.pdf · 2010. 1. 3. ·...
Chapter 11 1
Need for Risk Management
Example: (from Jorion (2001), Value at Risk)
• David Askin managed $600 million fund invested in
collateralized mortgage obligations (CMOs)
– somewhat like derivatives
– difficult to price
• Askin claimed his funds were market neutral “with
no default risk, high triple-A bonds, and zero
correlation with other assets”
• Askin used his own model to identify, purchase, and
hedge underpriced securities
Chapter 11 2
• objective was 15% return
• leveraged so a total of $2 billion was invested
• Askin was betting on interest rates remaining low
• Feb – Apr 1994:
– rates go up
– collateral call
Chapter 11 3
• $600 million hedge fund reduced to $30 million
• irate investors
– claimed they were mislead
– it is true that they had little idea of the risks
• Askin used valuation models to price his position
– first reported a 2% loss
– revised to 28%
• investors were subject to
– market risk
– liquidity risk
– model risk
Chapter 11 4
Barings
• Feb 26, 1995: 233-year old Barings PLC goes
bankrupt
• rogue trader – 28-year old Nicholas Leeson lost $1.3
billion (more than the firm’s equity capital)
• Leeson bought stock index futures on the Nikkei 225
($7 billion position)
• beginning of 1995 – value fell more than 15%
• Barings was a conservative bank – so this was a
wake-up call
Chapter 11 5
• Problems:
– lack of control: Leeson was in charge of trading
desk and back office
– Singapore and Osaka exchanges did not notice the
size of the positions
– problem was not peculiar to derivatives
Chapter 11 6
Origins of Value-at-Risk
From Jorion:
• Till Guldimann was head of global research at J.P.
Morgan in late ’80s
• risk-management needed to decide between
– long bonds ⇒ stable earnings
– cash ⇒ stable market value
• decided that “value risks” were more important that
“earnings risk”
Chapter 11 7
• concern at this time about managing derivatives risks
• Group of 30 (with representative from J.P. Morgan):
G-30 report in July 1993 used term “value at risk”
• October 1994: J.P Morgan introduces Riskmetrics
– data represent an elaborate covariance-matrix of
risk and correlation measures that evolve through
time
Chapter 11 8
Introduction
Loss is the loss (−revenue) from some portfolio.
• It is a random variable
Two parameters:
• T = horizon
• 1− α = confidence level
P (Loss > VaR) = α.
or
P (Loss ≤ VaR) = 1− α.
Chapter 11 9
From previous slide:
P (Loss ≤ VaR) = 1− α.
(−∞, VaR) is a 1− α confidence interval for the loss
Stated differently:
(−VaR, ∞) is a 1− α confidence interval for the revenue
Chapter 11 10
VaR for One Asset
Nonparametric method
Data: n returns
• Take the Kth smallest return where K = α n,
rounded.
– call it R(K)
• S is the size of the initial investment
• VaR = −S ×R(K)
– R(K) will be negative so that VaR is positive
Chapter 11 11
VaR for One Asset
Parametric method
• Assume that the returns are normally distributed
• X and s are the sample mean and standard deviation
• µ + Φ−1(α)σ is the α-quantile of the return
distribution
• S is the value of the portfolio
• VaR = −S × {X + Φ−1(α)s}
Chapter 11 12
VaR for a Portfolio of Stocks
• Assume that all returns are normally distributed
• X i and s2i are the sample mean and variance for the
ith stock
• sij is the sample covariance
• w1, . . . , wN are the portfolio weights
• µP = wiµ1 + . . . + wNµN
• σP =√∑N
i=1
∑Nj=1 wiwjσij
• µ̂P and σ̂P substitute sample means, variances, and
covariance
Chapter 11 13
• µ̂P + Φ−1(α)σ̂P is the α-quantile of the return
distribution
• VaR = −S × {µ̂P + Φ−1(α)σ̂P}
If the portfolio holds Mi shares of the ith stock which is
selling at Pi, then
S =N∑
j=1
MiPi
and
wi =MiPi
S
Chapter 11 14
VaR for a Portfolio of One Stock and An Option
on that Stock
Review
change in price of option ≈ ∆× change in price of asset.
Or, using math notation,
P optiont − P option
t−1 ≈ ∆(P assett − P asset
t−1 )
Therefore,
P optiont − P option
t−1
P optiont−1
≈
(∆
P assett−1
P optiont−1
)P asset
t − P assett−1
P assett−1
Chapter 11 15
From last slide:
P optiont − P option
t−1
P optiont−1
≈
(∆
P assett−1
P optiont−1
)P asset
t − P assett−1
P assett−1
Define:
L =
(∆
P assett−1
P optiont−1
)Then:
R option ≈ L×R stock
Chapter 11 16
From previous slide:
R option ≈ L×R stock
If w and 1− w are the weights on the stock and option,
then
• RP ≈ wR option + (1− w)L×R option or
• RP ≈ {w + (1− w)L} ×R stock
• VaRportfolio ≈−S × {w + (1− w)L} × α-quantile of stock return
• S = value of portfolio = value of stock + value of
options
Chapter 11 17
Example:
• S = 75 (stock price), σ = 0.3/year, µ = 0.04/year,
r = 0.01/year, for option: T = 0.5 year, K = 80
• for calculating VaR: T = 1 month
Portfolio 1: own 100 shares and call options on 200
shares –
C = 4.4835 and ∆ = Φ(d1) = 0.4307
L = 0.430775
4.4835= 7.2046
S = (100)(75) + (200)(4.4835) = 8, 396.70
Chapter 11 18
w =(100)(75)
(100)(75) + (200)(4.4835)= 0.8932, 1−w = 0.1068
w + (1− w)L = 1.6626
(0.1-quantile of R stock) =
(0.04
12− 1.645
0.03√12
)= −0.1391
VaRportfolio ≈ −S{w + (1− w)L}(0.1-quantile of R stock)
= −(8, 396.70)(1.6626)(−0.1391) = 1, 942.30
Chapter 11 19
Notes:
• Does not account for time-erosion of option value
• Standard deviation of one-month return is 1/√
12
times the standard deviation of one-year return
Chapter 11 20
Portfolio 2: own 100 shares and put options on 150
shares –
P = 9.0845 and ∆ = Φ(d1)− 1 = 0.4307− 1 = −0.5693
L = −0.569375
9.0845= −4.7001
w =(100)(75)
(100)(75) + (150)(9.0845)= 0.8462, 1−w = 0.1538
w + (1− w)L = 0.1236
S = (100)(75) + (150)(9.0845) = 8, 862.70
Chapter 11 21
VaRportfolio = −S{w + (1− w)L}(0.1-quantile of R stock)
= −(8, 862.70)(0.1236)(−0.1391) = 152.39
Note: Does not account for time-erosion of option value
Chapter 11 22
C(S, T, t, K, σ, r) = price of an option
∆ =∂
∂SC(S, T, t, K, σ, r) “Delta”
Θ =∂
∂tC(S, T, t, K, σ, r) “Theta”
R =∂
∂rC(S, T, t, K, σ, r) “Rho”
V =∂
∂σC(S, T, t, K, σ, r) “Vega”
Chapter 11 23
Chapter 11 24
0 0.1 0.20
1
2
3
4
σ
Pric
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cal
l
90 100 1100
5
10
15
E
Pric
e of
cal
l
90 100 1100
5
10
15
S0
Pric
e of
cal
l
0 0.04 0.08 0.121
1.5
2
2.5
3
r
Pric
e of
cal
l
0 0.04 0.08 0.120
0.5
1
1.5
T
Pric
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cal
l
Chapter 11 25
Differentiating Black-Scholes: for call
Θ =−Sσφ(d1)
2√
T − t−Kre−r(T−t)Φ(d2)
Get Θ for the put from put-call parity:
P = C + e−r(T−t) − S
Chapter 11 26
In examples:
• Θ for call = −6.5293
• Θ for put: −5.7333
• So price of both put and call will drop by about $0.50
in one-month (1/12 year) due to time erosion
• These drops could be incorporated into the expected
return
Chapter 11 27
Expected shortfall
ES = E{Loss|Loss > VaR}.
Example 1:
Buy $2000 of bonds from a corportation.
Loss is
• 0 with probability 0.96
• 2000 with probability 0.04
If α = 0.05, then VaR = 0.
ES = 2000
Chapter 11 28
Example 2 :
Buy $1000 of bonds from each of two corportations.
Loss is
• 0 with probability 0.962 = 0.9216
• 1000 with probability 2(0.96)(0.04) = 0.0768
• 2000 with probability 0.042 = 0.0016
If α = 0.05, then VaR = 1000.
ES =(1000)(0.0768) + (2000)(0.0016)
0.0768 + 0.0016= 1020
Chapter 11 29
Comparison
Portfolio VaR ES
Non-diversified 0 2000
Diversified 1000 1020
Chapter 11 30
Subadditivity
• P1, P2, . . ., Pm are portfolios
• R(·) is a risk measure
R(·) is subadditive if
R(P1 + · · ·+ Pm) ≤ R(P1) + · · ·+ R(Pm).
Subadditivity encourages diversification and has
other benefits
• VaR is not subadditive
• ES is subadditive
Chapter 11 31
Confidence Intervals for VaR by Resampling
There is a “true VaR” but it is unknown
• The VaR we report is just an estimate
• How accurate is it?
• Need a confidence interval for VaR
– Easily done by resampling
Chapter 11 32
Example: VaR for one asset – confidence interval
using the nonparametric estimator
• S, α, and T are known.
• What is unknown is the α-quantile of the return
distribution.
• Assume a sample of n returns
• K = α n, rounded.
For the bth of B resample, compute:
• Rb1, . . . , R
bn, a resample from the sample
• VaRb = −S ×Rb(K)
Chapter 11 33
Suppose we want a 1− γ confidence interval for VaR. For
concreteness, take γ = 0.02 and B = 50, 000.
• Then γB/2 = (0.02)(50, 000)/2 = 500
• The confidence interval is the 500th smallest to the
500th largest value of VaRb
Chapter 11 34
Example
$20,000 position in an S&P 500 index fund.
• 1000 daily returns for S&P 500
• α = 0.05 ⇒ K = 50
• 50th smallest return was −0.0227
• VaR = $454 = 20,000× 0.0227
• 50,000 resamples
• 98% confidence interval for VaR is $412 to $495