N 2 Translations - TaiSee Island · 2 Lesson 2: Translations 15 572GASE_GEO_SE_U1_PDF.indd 15...

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Duplicating this page is prohibited by law. © 2016 Triumph Learning, LLC 12 Unit 1: Transformations in the Coordinate Plane UNDERSTAND A translation is an operation that slides a geometric figure in the plane You can think of a translation of a geometric figure as a function in which the input is not a single value, x, but rather a point on the coordinate plane, (x, y) When you apply the function to a point, the output will be the coordinates of the translated image of that point You can translate not only individual points but also entire graphs and figures When you apply a translation function to every point on a figure, the resulting points will form the translated figure For each line segment on the original figure, the translated image will contain either a corresponding parallel line segment or a collinear line segment of equal length In a horizontal translation, the x-coordinate changes, but the y-coordinate stays the same A horizontal translation of a units can be represented by the function T (x, y) 5 (x 1 a, y) If a . 0, the figure slides to the right If a , 0, the figure slides to the leſt The transformation shown on the right is the result of applying the function T (x, y) 5 (x 1 7, y) to nJKL In this example, a is a positive number, 7, so the figure slides to the right In a vertical translation, the y-coordinate changes, but the x-coordinate stays the same A vertical translation of b units can be represented by the function T (x, y) 5 (x, y 1 b) If b . 0, the figure slides up If b , 0, the figure slides down The transformation shown on the right is the result of applying the function T (x, y) 5 (x, y 1 5) to nDFG In this example, b is a positive number, 5, so the figure slides up In a slant translation, both the x- and y-coordinates change Slant translations can be described by the function T (x, y) 5 (x 1 a, y 1 b) The transformation shown on the right is the result of applying the function T (x, y) 5 (x 2 8, y 2 6) to nABC In this example, a and b are both negative, so the figure slides to the leſt and down y –2 –4 –6 –2 –4 –6 2 4 6 0 2 4 J K K' L' L J' Translated 7 units right x y –2 –4 –6 –2 –4 –6 2 4 6 0 2 4 x 6 D' F' F G' D Translated 5 units up G y –2 –4 –6 –2 –4 –6 2 4 6 0 2 4 x 6 A' B' B C' A Translated 8 units left and 6 units down C 2 Translations LESSON

Transcript of N 2 Translations - TaiSee Island · 2 Lesson 2: Translations 15 572GASE_GEO_SE_U1_PDF.indd 15...

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12 Unit 1: Transformations in the Coordinate Plane

UNDERSTAND A translation is an operation that slides a geometric figure in the plane . You can think of a translation of a geometric figure as a function in which the input is not a single value, x, but rather a point on the coordinate plane, (x, y) . When you apply the function to a point, the output will be the coordinates of the translated image of that point .

You can translate not only individual points but also entire graphs and figures . When you apply a translation function to every point on a figure, the resulting points will form the translated figure . For each line segment on the original figure, the translated image will contain either a corresponding parallel line segment or a collinear line segment of equal length .

In a horizontal translation, the x-coordinate changes, but the y-coordinate stays the same . A horizontal translation of a units can be represented by the function T (x, y) 5 (x 1 a, y) . If a . 0, the figure slides to the right . If a , 0, the figure slides to the left .

The transformation shown on the right is the result of applying the function T (x, y) 5 (x 1 7, y) to nJKL . In this example, a is a positive number, 7, so the figure slides to the right .

In a vertical translation, the y-coordinate changes, but the x-coordinate stays the same . A vertical translation of b units can be represented by the function T (x, y) 5 (x, y 1 b) . If b . 0, the figure slides up . If b , 0, the figure slides down .

The transformation shown on the right is the result of applying the function T (x, y) 5 (x, y 1 5) to nDFG . In this example, b is a positive number, 5, so the figure slides up .

In a slant translation, both the x- and y-coordinates change . Slant translations can be described by the function T (x, y) 5 (x 1 a, y 1 b) .

The transformation shown on the right is the result of applying the function T (x, y) 5 (x 2 8, y 2 6) to nABC . In this example, a and b are both negative, so the figure slides to the left and down .

y

–2

–4

–6

–2–4–6 2 4 60

2

4

6

J

K K� L�L

J�Translated 7 units right

x

y

–2

–4

–6

–2–4–6 2 4 60

2

4

x

6

D�

F�

F

G�

D Translated5 units upG

y

–2

–4

–6

–2–4–6 2 4 60

2

4

x

6

A�

B�

B

C�

ATranslated 8 units left

and 6 units down

C

2 TranslationsLESSON

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Lesson 2: Translations 13

Translate trapezoid WXYZ 4 units to the left and 2 units up to form trapezoid W9X9Y9Z9 . Identify the coordinates of the vertices of the translated image .

y

–2

–4

–6

–2–4–6 2 4 60

2

4

x

6

Z

XW

Y

Starting at point W, count 4 units to the left and 2 units up .

y

–2

–4

–6

–2–4–6 2 4 60

2

4

x

6

W�

2 un

its

Z

XW

Y

4 units

Plot point W9 there . Notice that its coordinates are (23, 3) .

1

Translate every other point in the same way—by sliding it 4 units to the left and 2 units up . Then connect the points to form trapezoid W9X9Y9Z9 .

x

y

–2

–4

–6

–2–4–6 2 4 60

2

4

6

Z�

X�W�

Z

XW

Y

Y�

▸The coordinates of the vertices of the translated image, W9X9Y9Z9, are W9(23, 3), X9(0, 3), Y9(0, 1), and Z9(22, 1) .

2

Lesson 2: Translations 13

What function represents the translation that you performed? How do you know?

T (x, y) 5

DISCUSS

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14 Unit 1: Transformations in the Coordinate Plane

EXAMPLE A Translate nPQR according to the rule below:

T (x, y) 5 (x 1 6, y 2 1)

y

–2

–4

–6

–2–4–6 2 4 60

2

4

x

6

P

Q R

Identify the coordinates of the vertices of nPQR.

The vertices are P (23, 4), Q (24, 2), and R (21, 3) .

1

Treat each point as an input and substitute it into the rule above to find the coordinates of the translated image .

T (23, 4) 5 (23 1 6, 4 2 1) 5 (3, 3)

T (24, 2) 5 (24 1 6, 2 2 1) 5 (2, 1)

T (21, 3) 5 (21 1 6, 3 2 1) 5 (5, 2)

2

Plot points P9, Q9, and R9 . Connect them to form the translated image .

▸ y

–2

–4

–6

–2–4–6 2 4 60

2

4

x

6

P

Q

P�

Q� R�R

3

On the diagram in Step 3, trace the path of each vertex of nPQR to its translated image on nP9Q9R9 . Compare how each point moves from the preimage (or original figure) to the image . Explain what this means about the relationship between the sides of the preimage and the sides of the image .

DISCUSS

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EXAMPLE B Use a function to describe how parallelogram ABCD could be translated so it covers parallelogram WXYZ exactly .

y

–2

–4

–6

–2–4–6 2 4 60

2

4

x

6

Z

XW

Y

D

BA

C

Describe the slide needed to move vertex C of parallelogram ABCD onto point Y, the corresponding point on parallelogram WXYZ.

y

–2

–4

–6

–2–4–6 2 4 60

2

4

x

6

4 units

3 units

Z

XW

Y

D

BA

C

The diagram shows that point C must slide 3 units to the right and 4 units up to move onto point Y . Every other point in ABCD must slide in the same way .

1

Use a function to describe the translation .

A horizontal translation 3 units to the right is in the positive direction . It can be represented by the expression x 1 3 .

A vertical translation 4 units up is also in the positive direction . It can be represented by the expression y 1 4 .

▸The rule for the translation is: T (x, y) 5 (x 1 3, y 1 4) .

Substitute the coordinates of the vertices of parallelogram ABCD into the rule T (x, y) 5 (x 1 3, y 1 4) . Check that the resulting coordinates match those of the vertices of parallelogram WXYZ.

CHECK

2

Lesson 2: Translations 15

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16 Unit 1: Transformations in the Coordinate Plane

PracticeDraw the image for each translation of the given preimage. Use prime (9) symbols to name points on each image.

1. Translate ‹

___

› AB 3 units to the right .

y

–2

–4

–6

–2–4–6 2 4 60

2

4

6

x

A

B

A translation to the right affects the x-coordinate.

HINT

2. Translate trapezoid PQRS 7 units to the left and 4 units down .

y

–2

–4

–6

–2–4–6 2 4 60

2

4

6

x

S

QP

R

3. T (x, y) 5 (x, y 2 4)

y

–2

–4

–6

–2–4–6 2 4 60

2

4

6

x

X Y

Z

4. T (x, y) 5 (x 2 8, y 1 3)

y

–2

–4

–6

–2–4–6 2 4 60

2

4

6

X

Y

Z

x

Write a function to describe how the quadrilateral ABCD was translated to form A9B9C9D9 in each graph.

5. y

–2

–6

–2–4–6 2 4 60

2

4

6

CD

A

A�

D� C�

B

–4B�

x

T (x, y) 5

6. y

–2

–6

–2–4–6 2 4 60

2

4

6

CD

A

BC�

D�

A�

B�

–4

x

T (x, y) 5

REMEMBER The preimage and the image should be the same size and same shape.

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Lesson 2: Translations 17

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Use the graph on the right for questions 7–9.

7. Name the line segment that is parallel to ____

MN .

8. Name a line segment that is parallel to ___

MP .

9. How does ___

NP compare to ____

N9P9 ?

Solve.

10. A triangle with vertices A(1, 23), B(27, 12), and C (5, 0) is translated according to the rule T (x, y) 5 (x 2 3, y 1 9) . What are the coordinates of the vertices of the translated image?

11. Point P at (24, 3) is translated to form its image, point P9, at (6, 1) . Write a function to represent the translation . If point R (25, 26) and point S (1, 2) are also translated using that rule, what will be the coordinates of their images?

12. DESCRIBE A librarian wants to move the bookcase shown in the diagram from its current location to the “New” location . Describe a series of translations that could be used to move the bookcase to its new location, keeping in mind that it cannot be moved through a wall .

1 2 3 4 5 6 7 8 9 10 11 12 13x

y

0

123456789

10111213

New

Bookcase

P�

P

Wall

Wall

Wall

13. EXPLAIN Use a function to describe the translation that moves pentagon ABCDF so it covers pentagon KLMNP exactly. Then write the function that moves pentagon KLMNP so it covers pentagon ABCDF exactly . Compare the two functions and explain any differences between them .

x

y

–2

–6

–2–4–6 2 4 60

2

4

B

C D

A

F

–4 L

M N

K

P

y

–2

–6

–2–4–6 2 4 60

2

4

6

x

P

MN

P�

M�

N�

–4

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