Mt Answer Part Abcd
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Transcript of Mt Answer Part Abcd
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7/31/2019 Mt Answer Part Abcd
1/11
Bank A
Monthly auto renewable= RM 50 000
= RM 51 572.21
Interest
= RM 51 572.21 RM 50 000
= RM 1 572.21
Three months auto renewable= RM 50 000
= RM 51 593.70
Interest
= RM 51 593.70 - RM 50 000
= RM 1 593.70
Six Months auto renewable
= RM 50 000
= RM 51 612.80
Interest= RM 51 612.80 RM 50 000
= RM 1 612.80
Twelve months withoutwithdrawal
= RM 50 000
= RM 51 625.00
Interest
= RM 51 625 RM 50 000
= RM 1 625.00
Bank B
Monthly auto renewable= RM 50 000
= RM 51 520.80
Interest
= RM 51 520.80 RM 50 000
= RM 1 520.80
Three months auto renewable= RM 50 000
= RM 51 542.53
Interest
= RM 51 542.53 RM 50 000
= RM 1 542.53
Six months auto renewable= RM 50 000
= RM 51 562.01
Interest
= RM 51 562.01 RM 50 000
= RM 1 562.01
Twelve months withoutwithdrawal
= RM 50 000
= RM 51 575.00
Interest
= RM 51 575.00 RM 50 000
= RM 1 575.00
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7/31/2019 Mt Answer Part Abcd
2/11
Bank C
Monthly auto renewable= RM 50 000
= RM 51 520.80
Interest
= RM 51 520.80 RM 50 000
= RM 1 520.80
Three months auto renewable= RM 50 000
= RM 51 542.53
Interest
= RM 51 542.53 RM 50 000
= RM 1 542.53
Six months auto renewable= RM 50 000
= RM 51 562.01
Interest
= RM 51 562.01 RM 50 000
= RM 1 562.01
Twelve months withoutwithdrawal
= RM 50 000
= RM 51 600.00
Interest
= RM 51 600 RM 50 000
= RM1 600.00
PeriodInterest (RM)
Bank A Bank B Bank C
Monthly auto renewable RM 1 572.21 RM 1 520.80 RM 1 520.80
Three months auto renewable RM 1 593.70 RM 1 542.53 RM 1 542.53
Six months auto renewable RM 1 612.80 RM 1 562.01 RM 1 562.01
Twelve months without withdrawal RM 1 625.00 RM1 600.00 RM1 600.00
Therefore, we will choose Bank A because the interest of Bank A is higher than Bank B and
C.
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7/31/2019 Mt Answer Part Abcd
3/11
(a)(i)
Rental for photocopy
machine/month
= RM 480
Cost for a rim of paper
(500 pieces)
= RM 10
Price of a bottle of toner
(10 000 pieces)
= RM 80
Cost for a photocopy of a piece of
paper
= ( )
= RM 0.076
(ii)
Charge of a piece of
photocopy of a paper
= RM 0.10
Cost for a photocopy of a
piece of paper
= RM 0.076
Profit obtained
= (RM 0.10 RM0.076)(10 000)
= RM 240
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7/31/2019 Mt Answer Part Abcd
4/11
(b)(i)
METHOD 1
Cost of photocopy of a
piece of paper in 2013
=
= RM 0.084
Percentage increase
=
x 100%
= 10.5263%
METHOD 2
I =
=
=
() ()() ()()
=
= 111.17
Percentage increase
=
x 100%
= 10.5263%
Price Index,
I
Weightage,
WRental
25
Toner 125 5
Paper 120 12
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7/31/2019 Mt Answer Part Abcd
5/11
(ii)Pieces of paper should
cooperative photocopy
=
( )=
= 15 000 piece
(iii)Profit obtained
= (RM 0.10)(10 000)
(RM 0.084)(10 000)= RM 160
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7/31/2019 Mt Answer Part Abcd
6/11
Months
Saving
Balance
(RM)
Total Loans
To Be Pay
(RM)
1 148150.00 1850.00
2 147040.75 3700.00
3 145925.95 5550.00
4 144805.58 7400.00
5 143679.61 9250.00
6 142548.01 11100.00
7 141410.75 12950.00
8 140267.80 14800.00
9 139119.14 16650.00
10 137964.74 18500.00
11 136804.56 20350.00
12 135638.58 22200.0013 134466.78 24050.00
14 133289.11 25900.00
15 132105.56 27750.00
16 130916.08 29600.00
17 129720.67 31450.00
18 128519.27 33300.00
19 127311.86 35150.00
20 126098.42 37000.00
21 124878.92 38850.00
22 123653.31 40700.00
23 122421.58 42550.00
24 121183.69 44400.00
25 119939.60 46250.00
26 118689.30 48100.00
27 117432.75 49950.00
28 116169.91 51800.00
29 114900.76 53650.00
30 113625.27 55500.00
31 112343.39 57350.0032 111055.11 59200.00
33 109760.38 61050.00
34 108459.19 62900.00
35 107151.48 64750.00
36 105837.24 66600.00
37 104516.43 68450.00
Months
Saving
Balance
(RM)
Total Loans
To Be Pay
(RM)
38 103189.01 70300.0039 101854.95 72150.00
40 100514.23 74000.00
41 99166.80 75850.00
42 97812.63 77700.00
43 96451.70 79550.00
44 95083.95 81400.00
45 93709.37 83250.00
46 92327.92 85100.00
47 90939.56 86950.00
48 89544.26 88800.00
49 88141.98 90650.00
50 86732.69 92500.00
51 85316.35 94350.00
52 83892.93 96200.00
53 82462.40 98050.00
54 81024.71 99900.0055 79579.83 101750.00
56 78127.73 103600.00
57 76668.37 105450.00
58 75201.71 107300.00
59 73727.72 109150.00
60 72246.36 111000.00
61 70757.59 112850.00
62 69261.38 114700.00
63 67757.69 116550.00
64 66246.48 118400.00
65 64727.71 120250.00
66 63201.35 122100.00
67 61667.35 123950.00
68 60125.69 125800.00
69 58576.32 127650.00
70 57019.20 129500.00
71 55454.30 131350.00
72 53881.57 133200.00
73 52300.96 135050.0074 50712.48 136900.00
Months
Saving
Balance
(RM)
Total Loans
To Be Pay
(RM)
75 49116.04 138750.00
76 47511.62 140600.00
77 45899.18 142450.00
78 44278.67 144300.00
79 42650.07 146150.00
80 41013.32 148000.0081 39368.39 149850.00
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7/31/2019 Mt Answer Part Abcd
7/11
82 37715.23 151700.00
83 36053.81 153550.00
84 34384.08 155400.00
85 32706.00 157250.00
86 31019.53 159100.00
87 29324.62 160950.00
88 27621.24 162800.00
89 25909.35 164650.00
90 24188.90 166500.00
91 22459.84 168350.00
92 20722.14 170200.00
93 18975.75 172050.00
94 17220.63 173900.00
95 15456.74 175750.00
96 13684.02 177600.0097 11902.44 179450.00
Months
Saving
Balance
(RM)
Total Loans
To Be Pay
(RM)
98 10111.95 181300.00
99 8312.51 183150.00
100 6504.07 185000.00
101 4686.60 186850.00
102 2860.03 188700.00
103 1024.33 190550.00
104 192400.00
105 194250.00
106 196100.00
107 197950.00
108 199800.00
109 201650.00
110 203500.00
111 205350.00
112 207200.00
113 209050.00
114 210900.00115 212750.00
116 214600.00
117 216450.00
118 218300.00
119 220150.00
120 222000.00
223850.00
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7/31/2019 Mt Answer Part Abcd
8/11
Pay RM 150 000 in cash is better than keep the RM 150 000 in a fixed deposit account at
a rate of 6% p.a. then loan RM 150 000 from the other bank and pay with the period of 10
years with the rate of 4.8% p.a..
0
20000
40000
60000
80000
100000
120000
140000
160000
Saving Balance (RM)
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7/31/2019 Mt Answer Part Abcd
9/11
Compound interest
Interest that is paid both on the original amount of money saved and on the interestthat has been added to it.
Simple interest
Interest that is paid only on the original amount of money that you invested, and noton any interest that is earned.
YearSimple
Interest (RM)
Compound
Interest (RM)0 50000 50000
1 52500 51750
2 55000 53561.25
3 57500 55435.89
4 60000 57376.15
5 62500 59384.32
6 65000 61462.77
7 67500 63613.96
8 70000 65840.45
9 72500 68144.87
10 75000 70529.94
11 77500 72998.49
12 80000 75553.43
13 82500 78197.80
14 85000 80934.73
YearSimple
Interest (RM)
Compound
Interest (RM)15 87500 83767.44
16 90000 86699.30
17 92500 89733.78
18 95000 92874.46
19 97500 96125.07
20 100000 99489.44
21 102500 102971.57
22 105000 106575.58
23 107500 110305.72
24 110000 114166.42
25 112500 118162.25
26 115000 122297.93
27 117500 126578.36
28 120000 131008.60
29 122500 135593.90
30 125000 140339.69
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7/31/2019 Mt Answer Part Abcd
10/11
From the table and the graph above,
Simple interest is suitable for
savings in a short period. It is because of
its interest is higher than compound
interest and it is paid only on the original
amount of money that you invested, and
not on any interest that is earned. Forexample, when you keep RM50 000 with
an interest of 5% for 2 years, then you will
gain RM 5 000 after two years. So the
total amount in the bank is RM 55 000
after two years. When one keeps RM 50
000 with the interest of 3.5 % of
compound interest for 2 years, then you
will gain RM3 561.25. So the total amount
in the bank is RM 53 561.25 after two
years.
Compound interest is suitable for
savings in a long period. It is because of
the original amount of money saved and
on the interest that has been added to it.
For example, RM50 000 for the plan of 3.5
% of compound interest plan for 21 yearsthen we will have RM 102 971.57 in our
saving account. But when one keeps RM
50 000 for the plan of 5 % of simple
interest for 30 years, then we will only
have RM 102 500 in our savings account.
Therefore, it is better to save in the
compound interest plan account for long-
term savings and simple interest for short-term savings.
0
20000
40000
60000
80000
100000
120000
140000
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
Simple Interest
Compound Interest
99459.44317
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7/31/2019 Mt Answer Part Abcd
11/11
Tn = 50 000
r =
= 1.08
a = 5 000
Tn = arn-1
Let,
Tn > 50 000
5 000 (1.08n-1) > 50 000
1.08n-1 > 10log 1.08
n-1> log 10
(n-1) log 1.08 > log 10
n-1 >
n-1 > 29.92
n > 30.92
The least value of n = 31, age = 30.
Terms, Tn Value of saves Age of Ahmad
1 5000 0
2 5400 1
3 5832 2
4 6298.56 3
5 6802.44 4
6 7346.64 5
7 7934.37 6
8 8569.12 7
9 9254.65 8
10 9995.02 9
11 10794.62 10
12 11658.19 11
13 12590.85 12
14 13598.12 1315 14685.97 14
16 15860.85 15
17 17129.71 16
18 18500.09 17
19 19980.09 18
20 21578.51 19
21 23304.79 20
22 25169.17 21
23 27182.70 22
24 29357.32 23
25 31705.90 24
26 34242.38 25
27 36981.77 26
28 39940.31 27
29 43135.53 28
30 46586.37 29
31 50313.28 30
Ahmad will have a saving of RM 50 000 at the age of 30
