Mrs. Rivas. Then substitute to answer the question. Mrs. Rivas.
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H om ew ork Mrs. Rivas
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Transcript of Mrs. Rivas. Then substitute to answer the question. Mrs. Rivas.
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
𝟒 𝒙 –𝟏𝟐 𝒙+𝟏𝟓
𝟖 𝒙+𝟖
𝟐 𝒙+𝟏𝟓+𝟒 𝒙 –𝟏=𝟖 𝒙+𝟖𝟔 𝒙+𝟏𝟒=𝟖 𝒙+𝟖
𝟔 𝒙=𝟖 𝒙 –𝟔−𝟐 𝒙=–𝟔𝒙=𝟑
Then substitute to answer the question.
HomeworkMrs. Rivas
4x – 1 2x + 15
8x + 8
X = 3
m∠AOB = 4x – 1 = 4(3) – 1 = 11
m∠BOC = 2x + 15 = 2(3) + 15 = 21
m∠AOC = 8x + 8 = 8(3) + 8 = 32
HomeworkMrs. Rivas
8x + 13
𝟏𝟐𝒙 –𝟔
3x – 10
𝟑 𝒙 –𝟏𝟎+𝟖 𝒙+𝟏𝟑=𝟏𝟐𝒙 –𝟔𝟏𝟏𝒙+𝟑=𝟏𝟐𝒙 –𝟔
𝟏𝟏𝒙=𝟏𝟐𝒙 –𝟗−𝒙=–𝟗𝒙=𝟗
Then substitute to answer the question.
HomeworkMrs. Rivas
8x + 13
12x – 6
3x – 10
X = 9
m∠BOC = 3x – 10 = 3(9) – 10 = 17
m∠COD = 8x + 13= 8(9) + 13 = 85
m∠BOD = 12x – 6
= 12(3) – 6 = 102
HomeworkMrs. Rivas
Always read the question and draw a picture.
A
B
C
E
F
2x + 483x + 8
3x + 8 = 2x + 48– 8 – 8 3x = 2x + 40
– 2x – 2x
x = 403(40) + 8 = 128 2(40) + 48 = 128
HomeworkMrs. Rivas
Always read the question and draw a picture.
J
K
L2x – 3 N
P
M5x + 2
2x – 3 + 5x + 2 = 90º2x – 3 + 5x + 2 = 90º7x – 1 = 90º
+ 1 + 17x = 91º7 7x = 13º2(13) – 3 = 23
5(13) + 2 = 67
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
Always read the question and draw a picture.
J
K
M
L
86
If ∠JKM = 86 then ∠MKL = 86, so ∠JKL has to be equal to 86 + 86 = 172.
HomeworkMrs. Rivas
Always read the question and draw a picture.
R
S
V
T
62
Since bisect means cut in half. Then, m∠RSV = 62 ÷ 2 = 31
HomeworkMrs. Rivas
P
Q
S
R
3x5x – 20
Always read the question and draw a picture.
3x = 5x – 20– 5x– 5x
3(10) = 30
– 2x = – 202 2
x = 105(10) – 20 = 30
So, m∠PQR = 30 + 30 = 60
HomeworkMrs. Rivas
Always read the question and draw a picture.
P
Q
S
R
2x + 1
4x – 15
2x + 1 = 4x – 15
– 4x– 4x– 2x = – 16
2 2x = 8
– 1 – 1 2x = 4x – 16
2(8) + 1 = 17 4(8) – 15 = 17
So, m∠PQR = 17 + 17 = 34
HomeworkMrs. Rivas
Always read the question and draw a picture.
P
Q
S
R
3x – 1230
30 + 30 = 3x – 12
+ 12+ 1272 = 3x
33x = 24
60 = 3x – 12
3(24) – 12 = 60
HomeworkMrs. Rivas
Always read the question and draw a picture.
P
Q
S
R
2x + 10
5x – 17
2x + 10 = 5x – 17
– 5x– 5x– 3x = – 27
3 3x = 9
– 10 – 10 2x = 5x – 27
2(9) + 10 = 28 5(9) – 17 = 28
So, m∠PQR = 28 + 28 = 56
HomeworkMrs. Rivas
Always read the question and draw a picture.
7x – 1 + 4x + 3 = 90º11x + 2 = 90º
– 2 – 211x = 88º11 11
x = 8
m∠MLN = 7(8) – 1 = 55
m∠JKL = 4(8) + 3 = 35a). b).
c). I can check the answer by adding 55 and 35, and it should be 90º. 55 + 35 = 90º
HomeworkMrs. Rivas
HomeworkMrs. Rivas
