More applications of the Z-Score NORMAL Distribution The Empirical Rule.
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Transcript of More applications of the Z-Score NORMAL Distribution The Empirical Rule.
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More applications of the Z-Score
NORMAL DistributionThe Empirical Rule
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Normal Distribution?These density curves are symmetric, single-peaked, and bell-shaped.We capitalize Normal to remind you that these curves are special.
Normal distribution is described by giving its mean μ and its standard deviation σ
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Shape of the Normal curve
The standard deviation σ controls the spread of a Normal curve
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The Empirical Rule68-95-99.7 rule
In the Normal distribution with mean μ and standard deviation σ:
• Approximately 68% of the observations fall within σ of the mean μ.
• Approximately 95% of the observations fall within 2σ of μ.
• Approximately 99.7% of the observations fall within 3σ of μ.
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The Normal Distribution and Empirical Rule
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Example: YOUNG WOMEN’s HEIGHT
The distribution of heights of young women aged 18 to 24 is approximately Normal with mean μ = 64.5 inches and standard deviation σ = 2.5 inches.
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Importance of Normal Curve
• scores on tests taken by many people (such as SAT exams and many psychological tests),
• repeated careful measurements of the same quantity, and
• characteristics of biological populations (such as yields of corn and lengths of animal pregnancies).
even though many sets of data follow a Normal distribution, many do not.
Most income distributions, for example, are skewed to the right and so are not Normal
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Standard Normal distribution
Standard Normal DistributionThe standard Normal distribution is the Normal distribution N(0, 1) with mean 0 and standard deviation
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Standard Normal Calculation
The Standard Normal TableTable A is a table of areas under the standard Normal curve. The table entry for each value z is the area under the curve to the left of z.
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Area to the LEFTUsing the standard Normal table
Problem: Find the proportion of observations from the standard Normal distribution that are less than 2.22.
illustrates the relationship between the value z = 2.22 and the area 0.9868.
How to use the table of values
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illustrates the relationship between the value z = 2.22 and the area 0.9868.
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Example
Area to the RIGHTUsing the standard Normal table
Problem: Find the proportion of observations from the standard Normal distribution that are greater than −2.15
z = −2.15
Area = 0.0158
Area = 1-0.0158
Area = .9842
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Practice
(a) z < 2.85
(b) z > 2.85
(c) z > −1.66
(d) −1.66 < z < 2.85
(a) 0.9978.
(b)0.0022.
(c) 0.9515.
(d) 0.9493.
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CODY’S quiz score relative to his classmates
79 81 80 77 73 83 74 93 78 80 75 67 73
77 83 86 90 79 85 89 84 77 72 83 82 x
z = 0.99
Area = .8389
Cody’s actual score relative to the other students who took
the same test is 84%