Monday, December 2 nd
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Transcript of Monday, December 2 nd
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Monday, December 2nd
Review for Final:
1.What is the variable(s) in the expression?
2.What is the constant in the expression?
WARM UP
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Grade Check
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Grades Left the Semester1.1 more quiz 2.1 more Warm up(Daily
grade)3. Exponential Test (Test
Grade) 4. Semester I Final (Final
grade) 5.3 Weekly Reviews-(daily
Grade)
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Weekly Review 1. We will have three
weekly Reviews 2. Each will count as a
Daily Grade 3. They are eligible to
replace QUIZ grades
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High School GPA A: 4.0B: 3.0 C. 2.0 D. 1.0 F-Receive no Credit. You will have to retake first semester all over again during semester II.
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Tutoring Option 1: Ms. Evans
Tuesday and ThursdaysBefore School 6:40-7:00After School 2:10-2:30
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Tutoring Option 2: Lunch
Tuesday and ThursdaysEither lunch
Go to room 400 FIRST, then to lunch
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Tutoring Option 3: Algebra
Department*Check Schedule in Back
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Discussion QuestionWhat’s the difference between exponential
growth and exponential decay equations?!
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Growth & Decay in graph
Growth Decay
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Growth & Decay in Equation
x
y
322
y
x
y
232Growth
Decay
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Growth and Decay in Table
x -2 -1 0 1 2
y 2 4 8 16 32
x -2 -1 0 1 2
y 32 16 8 4 2
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For compound interest • annually means “once per year” (n = 1).• quarterly means “4 times per year” (n =4).• monthly means “12 times per year” (n = 12).
Reading Math
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Write a compound interest function to model each situation. Then find the balance after the given number of years.
$1200 invested at a rate of 2% compounded quarterly; 3 years.
Step 1 Write the compound interest function for this situation.
= 1200(1.005)4t
Write the formula.
Substitute 1200 for P, 0.02 for r, and 4 for n.
Simplify.
Example #1
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Step 2 Find the balance after 3 years.
≈ 1274.01
Substitute 3 for t.A = 1200(1.005)4(3)
= 1200(1.005)12
Use a calculator and round to the nearest hundredth.
The balance after 3 years is $1,274.01.
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Write a compound interest function to model each situation. Then find the balance after the given number of years.$15,000 invested at a rate of 4.8% compounded monthly; 2 years.
Step 1 Write the compound interest function for this situation.
Write the formula.
Substitute 15,000 for P, 0.048 for r, and 12 for n.
= 15,000(1.004)12t Simplify.
Example #2
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Step 2 Find the balance after 2 years.
≈ 16,508.22
Substitute 2 for t.A = 15,000(1.004)12(2)
= 15,000(1.004)24 Use a calculator and round to the nearest hundredth.
The balance after 2 years is $16,508.22.
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Write a compound interest function to model each situation. Then find the balance after the given number of years.$1200 invested at a rate of 3.5% compounded quarterly; 4 yearsStep 1 Write the compound interest function for this situation.
Write the formula.
Substitute 1,200 for P, 0.035 for r, and 4 for n.
= 1,200(1.00875)4t Simplify.
Example #3
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Step 2 Find the balance after 4 years.
1379.49
Substitute 4 for t.A = 1200(1.00875)4(4)
= 1200(1.00875)16
Use a calculator and round to the nearest hundredth.
The balance after 4 years is $1,379.49.
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1. The number of employees at a certain company is 1440 and is increasing at a rate of 1.5% per year. Write an exponential growth function to model this situation. Then find the number of employees in the company after 9 years.
y = 1440(1.015)t; 16462. $12,000 invested at a rate of 6% compounded
quarterly; 15 yearsA = 12,000(1 + .06/4)4t, =$29,318.64
Write a compound interest function to model each situation. Then find the balance
after the given number of years.
LESSON SUMMARY