Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x...

16
Module 22.1 Solving Equations by Taking Square Roots How can you solve quadratic equations using square roots? P. 1033

Transcript of Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x...

Page 1: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

Module 22.1

Solving Equationsby Taking Square Roots

How can you solve quadratic equations using square roots?

P. 1033

Page 2: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

Since 42 = 16

(−4)2 = 16The square roots of 16 are 4 and –4.

Thus, every positive real number has two square roots, one positive and one negative.

The positive square root is given by 𝑎and the negative square root is given by − 𝑎.

These can be combined as ± 𝑎.

P. 1033

Page 3: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1033

Page 4: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1033

Page 5: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1034

(That’s just one way)

Page 6: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1034

Page 7: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

If 𝟒𝒙𝟐 = 𝟕then the related function is:

𝒇(𝒙) = 𝟒𝒙𝟐 − 𝟕

The approximate solutions are:x ≈ 1.32 and x ≈ –1.32

They are also:• the roots of the equation• the zeros of the related function• the x-intercepts.

Page 8: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1035

Page 9: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1035

Page 10: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1036

Page 11: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1036-1037

Page 12: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1037

A contractor is building a fenced-in playground at a daycare. The playground will be rectangular with its width equal to half its length. The total area will be 5000 square feet. Determine how many feet of fencing the contractor will use.

Page 13: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1036-1037

Page 14: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1038

Page 15: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both

P. 1038

Page 16: Module 22.1 Solving Equations by Taking Square Roots€¦ · 4x2 — 2 Solve the equation for x. x = 1.75 4x2— 5 = = 2 Original equation Add 5 to both sides. Simplify. Divide both