Module 20.1 Connecting Intercepts And Zeroes...Module 20.1 Connecting Intercepts And Zeroes How can...

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Module 20.1 Connecting Intercepts And Zeroes How can you use the graph of a quadratic function to solve its related quadratic equation? P. 937

Transcript of Module 20.1 Connecting Intercepts And Zeroes...Module 20.1 Connecting Intercepts And Zeroes How can...

Module 20.1

Connecting Intercepts And Zeroes

How can you use the graph of a quadratic functionto solve its related quadratic equation?

P. 937

As we said in Module 19.2 – Quadratic functions can take more than one form.

The first is called Vertex Form. Here it is: π’ˆ 𝒙 = 𝒂(𝒙 βˆ’ 𝒉)𝟐 + π’ŒExample: π’ˆ 𝒙 = πŸ‘(𝒙 βˆ’ 𝟐)𝟐 + πŸ’We learned how to graph a quadratic function in this form on page 908.

Now we focus on the second, called Standard Form.Here it is: π’š = π’‚π’™πŸ + 𝒃𝒙 + 𝒄Example: π’š = πŸ‘π’™πŸ + πŸ”π’™ βˆ’ πŸ’

How do we graph a quadratic function in this form?

One way is to create a table of x and y values, and then plot them.

π’š = πŸ‘π’™πŸ + πŸ”π’™ βˆ’ πŸ’

How do you determine the axis of symmetry?

The axis of symmetry for a quadratic equation

in standard form is given by the equation 𝒙 = βˆ’π’ƒ

πŸπ’‚

So if we have the equation π’š = πŸ‘π’™πŸ + πŸ”π’™ βˆ’ πŸ’

Then the axis of symmetry is βˆ’π’ƒ

πŸπ’‚= βˆ’

πŸ”

𝟐 πŸ‘= βˆ’

πŸ”

πŸ”= –1

That’s a vertical line with the equation 𝒙 = βˆ’πŸ.

So we know the x-coordinate of the vertex ( –1),which is one half of the vertex.

How do you find the vertex?

Substitute the value of the axis of symmetry for 𝒙 into the equation and solve for y.

π’š = πŸ‘π’™πŸ + πŸ”π’™ βˆ’ πŸ’= πŸ‘(βˆ’πŸ)𝟐+πŸ” βˆ’πŸ βˆ’ πŸ’= πŸ‘ 𝟏 βˆ’ πŸ” βˆ’ πŸ’= πŸ‘ βˆ’ πŸ” βˆ’ πŸ’ = βˆ’πŸ•

So the vertex is at (–1, –7).

P. 937

P. 938Just like there are quadratic functions, like 𝒇 𝒙 = π’‚π’™πŸ + 𝒃𝒙 + 𝒄There are also quadratic equations, like πŸπ’™πŸ βˆ’ πŸ“ = βˆ’πŸ‘

How do you solve a quadratic equation?One way to do it is to factor it and find the β€œzeroes”.Another way is to do it graphically.

It’s a 5-Step process.

Step 1: Convert the equation into a β€œrelated” function by rewriting it so that it equals zero on one side.

πŸπ’™πŸ βˆ’ πŸ“ = βˆ’πŸ‘+ 3 + 3 Add 3 to both sides, so the right side will equal 0

πŸπ’™πŸ βˆ’ 𝟐 = 𝟎

Step 2: Replace the zero with a y.πŸπ’™πŸ βˆ’ 𝟐 = π’šπ² = πŸπ’™πŸ βˆ’ 𝟐 Re-order it

Step 3: Make a table of values for this β€œrelated” function.𝐲 = πŸπ’™πŸ βˆ’ 𝟐

Step 4: Plot the points and sketch the graph.

Step 5: The solution(s) of the equation are the x-intercepts, also known as the β€œzeros” of thefunction. In this case they’re 𝒙 = 𝟏 and 𝒙 = βˆ’πŸ.

P. 938

A zero of a function is an x-value that makes the value of the function 0.

The zeros of a function are the x-intercepts of the graph of the function.

A quadratic function may have one, two, or no zeros.

P. 938

One Zero: 𝑦 = 2π‘₯2

When is 2π‘₯2 = 0 ?Only when π‘₯ = 0.

Two Zeros: 𝑦 = 2π‘₯2 βˆ’ 2When is 2π‘₯2 βˆ’ 2 = 0 ?When π‘₯ = βˆ’1 π‘Žπ‘›π‘‘ π‘₯ = 1.

No Zeros: 𝑦 = 2π‘₯2 + 2When is 2π‘₯2 + 2 = 0 ?Never!

P. 939

P. 939

P. 941

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You can solve this algebraically:Subtract 10 from both sides to get βˆ’πŸπŸ”π’•πŸ + πŸ‘πŸ” = 𝟎.Add πŸπŸ”π’•πŸ to both sides, to get πŸπŸ”π’•πŸ = πŸ‘πŸ”.Divide both sides by 16, so π’•πŸ = 𝟐. πŸπŸ“.Take the square root of both sides to get 𝒕 = ±𝟏. πŸ“.Since time can’t be negative, the answer has to be 1.5 seconds.

Or you can solve this graphically:

βˆ’16𝑑2 + 36 = 0βˆ’16𝑑2 + 36 = 𝑦

Create a table of x (or t) and y values, then graph those coordinates.

The y-axis represents the height, and the x-axis represents time.

When y=0, what is x (or t) ?

P. 942