Module 20.1 Connecting Intercepts And Zeroes...Module 20.1 Connecting Intercepts And Zeroes How can...
Transcript of Module 20.1 Connecting Intercepts And Zeroes...Module 20.1 Connecting Intercepts And Zeroes How can...
Module 20.1
Connecting Intercepts And Zeroes
How can you use the graph of a quadratic functionto solve its related quadratic equation?
P. 937
As we said in Module 19.2 β Quadratic functions can take more than one form.
The first is called Vertex Form. Here it is: π π = π(π β π)π + πExample: π π = π(π β π)π + πWe learned how to graph a quadratic function in this form on page 908.
Now we focus on the second, called Standard Form.Here it is: π = πππ + ππ + πExample: π = πππ + ππ β π
How do we graph a quadratic function in this form?
One way is to create a table of x and y values, and then plot them.
π = πππ + ππ β π
How do you determine the axis of symmetry?
The axis of symmetry for a quadratic equation
in standard form is given by the equation π = βπ
ππ
So if we have the equation π = πππ + ππ β π
Then the axis of symmetry is βπ
ππ= β
π
π π= β
π
π= β1
Thatβs a vertical line with the equation π = βπ.
So we know the x-coordinate of the vertex ( β1),which is one half of the vertex.
How do you find the vertex?
Substitute the value of the axis of symmetry for π into the equation and solve for y.
π = πππ + ππ β π= π(βπ)π+π βπ β π= π π β π β π= π β π β π = βπ
So the vertex is at (β1, β7).
P. 938Just like there are quadratic functions, like π π = πππ + ππ + πThere are also quadratic equations, like πππ β π = βπ
How do you solve a quadratic equation?One way to do it is to factor it and find the βzeroesβ.Another way is to do it graphically.
Itβs a 5-Step process.
Step 1: Convert the equation into a βrelatedβ function by rewriting it so that it equals zero on one side.
πππ β π = βπ+ 3 + 3 Add 3 to both sides, so the right side will equal 0
πππ β π = π
Step 2: Replace the zero with a y.πππ β π = ππ² = πππ β π Re-order it
Step 3: Make a table of values for this βrelatedβ function.π² = πππ β π
Step 4: Plot the points and sketch the graph.
Step 5: The solution(s) of the equation are the x-intercepts, also known as the βzerosβ of thefunction. In this case theyβre π = π and π = βπ.
P. 938
A zero of a function is an x-value that makes the value of the function 0.
The zeros of a function are the x-intercepts of the graph of the function.
A quadratic function may have one, two, or no zeros.
P. 938
One Zero: π¦ = 2π₯2
When is 2π₯2 = 0 ?Only when π₯ = 0.
Two Zeros: π¦ = 2π₯2 β 2When is 2π₯2 β 2 = 0 ?When π₯ = β1 πππ π₯ = 1.
No Zeros: π¦ = 2π₯2 + 2When is 2π₯2 + 2 = 0 ?Never!
P. 941-942
You can solve this algebraically:Subtract 10 from both sides to get βππππ + ππ = π.Add ππππ to both sides, to get ππππ = ππ.Divide both sides by 16, so ππ = π. ππ.Take the square root of both sides to get π = Β±π. π.Since time canβt be negative, the answer has to be 1.5 seconds.
Or you can solve this graphically:
β16π‘2 + 36 = 0β16π‘2 + 36 = π¦
Create a table of x (or t) and y values, then graph those coordinates.
The y-axis represents the height, and the x-axis represents time.
When y=0, what is x (or t) ?