MMC Math 2009
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Transcript of MMC Math 2009
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Relationship and Applications of MATHEMATICS
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OutlineOutline Selected topics review
1. PROBABILITY2. POWERS AND EXPONENTS3. LINEAR EQUATIONS4. END
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PROBABILITYPROBABILITYLEARNING OUTCOMESTOPICEXAMPLES
OUTLINEOUTLINE
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LEARNING OUTCOMESLEARNING OUTCOMES At the end of the class, students should be
able to:1. Determine whether an outcomes is a possible
outcome of an experiment.2. Determine the sample space of an experiment.3. Write the sample by using set notation.4. Identify the elements of a sample space which satisfy
given condition.5. Find the ratio of the number of times an event occurs
to the number of trials.
PROBABILITY PROBABILITY MENUMENU
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1) PROBABILITY 1) PROBABILITY
EVENTEVENT
SAMPLE SPACESAMPLE SPACE
PROBABILITY OF EVENTPROBABILITY OF EVENT
PROBABILITY PROBABILITY MENUMENU
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PROBABILITY IPROBABILITY I1.1 SAMPLE SPACE1.1 SAMPLE SPACE
TOPIC MENUTOPIC MENU
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SAMPLE SPACESAMPLE SPACEAn experimentexperiment is a process or an
operation with an outcomes.
Toss a balanced die once and observe its uppermost face.
TOPIC MENUTOPIC MENU
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SAMPLE SPACESAMPLE SPACE When toss the coin, we can get only 2
results:
1.1. HeadHead2.2. TailTail
TOPIC MENUTOPIC MENU
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SAMPLE SPACESAMPLE SPACE The set of all possible outcomes of an experiment is
called the sample spacesample space. It usually denoted by SS.
Example 1:
En. Adam has a fruit stall that sells bananas, apples, watermelons, papayas and durians. Students of class 4KP are asked to select their favorite fruit from the fruits at En. Adam’s stall.
S S = { banana, apple, watermelon, papaya, durian}
TOPIC MENUTOPIC MENU
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SAMPLE SPACESAMPLE SPACE Example 2:
A month is randomly selected from a year. Describe the sample space of this experiment by using set notation.
SS= { January, February, March, April, May, June, July, August, September, October, November, December}
TOPIC MENUTOPIC MENU
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PROBABILITY PROBABILITY 1.2 EVENT1.2 EVENT
TOPIC MENUTOPIC MENU
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EVENTEVENT Is a subset of the sample space. Is an outcome or a set of outcomes
that satisfies certain condition. Denoted by a capital letter.
TOPIC MENUTOPIC MENU
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EVENTEVENT Example 1:
A box contains five cards written with 1,2,3,4 and 5 respectively. A card is picked randomly from the box.
S = {1, 2, 3, 4, 5}. If we define J as ‘the card with J as ‘the card with
an even number’an even number’,, the outcome of J in set notation will be
J = { 2, 4 }.J = { 2, 4 }.
J is known as an event of the experiment.
The number of outcome of an event n(P)=2
TOPIC MENUTOPIC MENU
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EVENTEVENT Example 2:
A letter is randomly selected from the word ‘COMPUTER’. Determine the number of possible outcomes of the event that the selected letter is
i. A vowel ii. A consonant
SolutionSolutioni. Let A = event that the selected letter is vowel = {O, U, E}
Therefore n (A) = 3
ii. Let B = event that the selected letter is consonant = {C, M, P, T, R} Therefore n (B) = 5
TOPIC MENUTOPIC MENU
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PROBABILITY PROBABILITY 1.3 PROBABILITY OF AN EVENT1.3 PROBABILITY OF AN EVENT
TOPIC MENUTOPIC MENU
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PROBABILITY OF AN EVENTPROBABILITY OF AN EVENT
Probability of an event E,
P(E) = number of outcomes of the eventP(E) = number of outcomes of the eventnumber of outcomes of thenumber of outcomes of the sample spacesample space
P(E) = n (E)P(E) = n (E) n (S)n (S)
0 ≤ P(E) ≤ 10 ≤ P(E) ≤ 1
TOPIC MENUTOPIC MENU
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PROBABILITY OF AN EVENTPROBABILITY OF AN EVENT
P(E) = 0P(E) = 0 means that it is impossible for the event to happen.
P(E) =1P(E) =1 means that the event is certain to happen.
The closer the probability of a given event is to 1, the more likely it is to happen.
TOPIC MENUTOPIC MENU
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PROBABILITY OF AN EVENTPROBABILITY OF AN EVENT ExampleExample
A bag contains 3 red balls and 4 white ones. If Rashid puts his hand in the bag and picks a ball, what is the probability that the ball he picked is white?
Solution:Solution:
S = {R1,R2,R3,W1,W2,W3,W4}n(S)= 7
Let E is the event of drawing a white ballE = {W1,W2,W3,W4}n(E)=4
Therefore, the probability of drawing a white ball is 4 7
TOPIC MENUTOPIC MENU
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PROBABILITY PROBABILITY EXAMPLESEXAMPLES
TOPIC MENUTOPIC MENU
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EXERCISE 1EXERCISE 1
A number from 1 to 11 is chosen at random. What is the probability of choosing an odd number?
A. 1/11B. 5/11C. 6/11D. None of above
TUTORIAL TUTORIAL
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EXERCISE 2EXERCISE 2 A bag consists of 3 green, 1 white and 1
purple chips. Two chips are drawn from the bag. Which of the following outcomes are possible?
A. (green, red)B. (green, green)C. (purple, purple)D. (white, white)
TUTORIALTUTORIAL
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EXERCISE 3EXERCISE 3 A dice is rolled 420 times. How many
times will a number greater than 4 occur?
A. 70B. 140C. 210D. 360
TUTORIALTUTORIAL
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EXERCISE 4EXERCISE 4 There are 45 boys and girls in a class.
Given the probability that a boy is chosen is 4/15. the number of girls is
A. 8B. 12C. 25D. 33
TUTORIALTUTORIAL
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EXERCISE 5EXERCISE 5 Out of 5000 applicants, only 275 are
chosen. If Hazni is one of the applicants, what is the probability that he is chosen?
A. 11/200B. 200/11C. 189/200D. 200/189
TUTORIALTUTORIAL
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GAMING EXAMPLE – 2 DICE
The probability of outcomes of throwing 2 dice! What are the odds of choosing the right numbers - winning!
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Two dice totals
Die 1Die 2
1 2 3 4 5 6
1 2 3 4 5 6 72 3 4 5 6 7 83 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
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P(E) = P(E) = n (E)n (E) n (S) n (S)
The probability of throwing any given total (an EVENT) is the number of ways to throw that total divided by the total number of combinations (SAMPLE SPACE(36)).
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Total Number of combinations Probability
2 1 2.78%3 2 5.56%4 3 8.33%5 4 11.11%6 5 13.89%7 6 16.67%8 5 13.89%9 4 11.11%
10 3 8.33%11 2 5.56%12 1 2.78%
Total 36 100%
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RulesIf you roll a total of 7 or 11 on the first roll,
you win.If you roll a total of 2, 3, or 12 on the first
roll, you lose.If you roll a total of 4, 5, 6, 8, 9, or 10 on
your first roll, this number becomes your point
Let’s look at the game of STRAIGHT CRAPS?
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Two dice totals
Die 1Die 2
1 2 3 4 5 6
1 2 3 4 5 6 72 3 4 5 6 7 83 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
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what is the probability of winning if you initially roll a total of 5?
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???????
GOT the answer yet?
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ANSWER!!!!probability of rolling a 5 is 4/36There are ten cells containing 5 or 7 the probability of rolling a 5, and then
rolling a 5 before a 7 is (4/36)(4/10), or about 4.44%.
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Two dice totals
Die 1Die 2
1 2 3 4 5 6
1 2 3 4 5 6 72 3 4 5 6 7 83 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
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Here is a summary of your winning probabilities in craps:
INITIAL TOTAL
PROBABILITY OF WINNING PROBABILITY
4 (3/36)*(3/9) 0.027778 5 (4/36)*(4/10) 0.044444 6 (5/36)*(5/11) 0.063131 7 6/36 0.166667 8 (5/36)*(5/11) 0.063131 9 (4/36)*(4/10) 0.044444
10 (3/36)*(3/9) 0.027778 11 2/36 0.055556
TOTAL 0.492929
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CONCLUSION
You are making what is known as a Pass Bet. As the table indicates, the probability of winning a Pass Bet is 49.29%.
The casino (sometimes called the house) has a 50.71% probability of winning.
*Hence, the casino has a 1.4% advantage on any Pass Bet.
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Conclusion (cont.)
Probability can help you find the advantages and eventually the payoff of playing any casino games!
OUTLINEOUTLINE
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POWERS AND POWERS AND EXPONENTSEXPONENTS
LEARNING OUTCOMESTOPICTOPICEXAMPLES
OUTLINEOUTLINE
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LEARNING OUTCOMESLEARNING OUTCOMES At the end of the class, students should
be able to:1. Identify index notations2. Define laws of indices3. Simplify expressions using laws of indices4. Solve real life problems
Powers MENUPowers MENU
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2) Powers and 2) Powers and ExponentsExponents
Laws of indices
Index notations
Exercises
OUTLINEOUTLINE
Time Value of MoneyTime Value of Money
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Powers and Powers and ExponentsExponents
2.1 2.1 Index notations
POWERS topic POWERS topic MENUMENU
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POWERS topic POWERS topic MENUMENU
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Powers and Powers and ExponentsExponents
2.2 Laws of indices2.2 Laws of indices
POWERS topic POWERS topic MENUMENU
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LAWS OF INDICES
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POWERS topic MENU
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Powers and Powers and ExponentsExponents
2.3 Exercises2.3 Exercises
POWERS topic POWERS topic MENUMENU
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POWERS topic POWERS topic MENUMENU
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Powers and Powers and ExponentsExponents
2.4 Time Value of Money2.4 Time Value of Money
POWERS topic POWERS topic MENUMENU
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Application of Powers and Exponents in Finance
Time Value of Money The timing of cash outflows and inflows has
important economic consequences. Money that a firm has in its possession today is
more valuable than money in the future because funds can be used to invest to earn a positive return
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Time Value of Money: Know this terminology and notation
FV Future Value (1+i)t
Future Value Interest Factor [FVIF]
PV Present Value 1/(1+i)t Present Value Interest Factor [PVIF]
i Rate per period t # of time periods
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Question: Why are (1+i) and (1+i)t called interest factors?Start with simple arithmetic problem on interest:How much will $10,000 placed in a bank account paying 5% per year be worth compounded annually?Answer: Principal + Interest $10,000 + $10,000 x .05 = $10,500
2. Factor out the $10,000. 10,000 x (1.05) = $10,5003. This leaves (1.05) as the factor.
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So (1+i)t = (1+i)·(1+i)·(1+i)·(1+i)·(1+i)·(1+i)·(1+i)… ·(1+i) for “t” times
1. Find the value of $10,000 earning 5% interest per year after two years. Start with the amount after one year and multiply by the factor for each year. [Amount after one year] x (1.05)
= [$10,000 x (1.05)] x (1.05)
= $10,000 x (1.05)2
= $11,025.
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Instead of calculating each of the value of money of each year, we can use exponents’ law of multiplication to find factors of a given interest and period for ease of calculation and reference! Thus creating tables for reference!
am X a n = a mn
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Future Value Calculations
Find the value of $10,000 in 10 years. The investment earns 8% for four years and then earns 4% for the remaining six years.
FV = $10,000·(1+i1)·(1+i1)·(1+i1)·(1+i1)·(1+i2)·(1+i2)·(1+i2)·(1+i2)·(1+i2)·(1+i2)
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Future Value Interest Factors
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Future Value Interest Factors
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Future Value Calculations (cont.)
FV = $10,000·(1.08)·(1.08)·(1.08)·(1.08)·(1.04)·(1.04)·(1.04)·(1.04)·(1.04)·(1.04)FV = $10,000 x (1.08)4 x (1.04)6
FV = $17,214.53
AlternativelyFV = $10,000 x 1.3605 x 1.2653FV = $17,214.41 * difference due to rounding
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Present Value Calculations
PV = FV÷ [(1+i)·(1+i)·(1+i)·(1+i)·(1+i)·(1+i)·(1+i)·(1+i)·(1+i)·(1+i)]
PV = FV ÷ (1+i)t
Example: How much do I need to invest at 8% per year, in order to have $10,000 in One year.
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Answers:
One year: PV =10,000 ÷ (1.08) = $9,259.26
Two years: = $10,000 ÷ (1.08) ÷ (1.08) OR $10,000 ÷ (1.08)2 = $8,573 Ten years PV = $10,000 ÷ (1.08)10 = $10,000 ÷
2.1589 = $4,632
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Present Value Interest Factors
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Present Value Interest Factors
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Can you find the PVIF – present Value interest factors? Example: How much do I need to
invest at 5% per year, in order to have $10,000
1. In 2 years2. In 3 years3. In 10 years
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Why do we need all these factors???
All cash flows in the future can be added when converted into present values
NPV makes cash flows of different project comparable
Financial managers can use this technique to evaluate which projects to take on!
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Example of NPV
If we assume a 10% interest rate,
40.44$1.130$
1.170$
1.1120$100$ 32 NPV
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Example 2: Project 1: $100 a year for 4 years, or Project 2: $500 at the end of 4 years.
NPV of Project 1:
NPV of Project 2:
At an interest rate of r = 10%, NPV of project 1 is $316.99. NPV of project 2 is $341.51.
432 1100
1100
1100
1100
rrrrNPV
41
5002r
NPV
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Conclusion
Powers and Exponents makes Net Present Value calculations for managers much easier!!
OUTLINEOUTLINE
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Solving Linear Solving Linear EquationsEquations
LEARNING OUTCOMESLEARNING OUTCOMESTOPICTOPIC
OUTLINEOUTLINE
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Linear MENULinear MENU
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3) 3) Linear Linear EquationsEquations
Solving equationsSolving equations
PropertiesProperties
Linear MenuLinear Menu
Economic exampleEconomic example
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Properties
Linear MENULinear MENU
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Linear MENULinear MENU
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Solving equations
How do we calculate the height of a certain building if we have limited information on only surrounding buildings?
Say the HSBC building in London?
Linear MENULinear MENU
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Linear MENULinear MENU
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Economic Example with linear equations
Economic order quantity is the level of inventory that minimizes the total inventory holding costs and ordering costs.
It is one of the oldest classical production scheduling models.
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Assumptions:
demand for a product is constant over the year
each new order is delivered in full when the inventory reaches zero
fixed cost charged for each order a holding or storage cost for each unit held
in storage
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The ordering cost is constant. The rate of demand is constant The lead time is fixed The purchase price of the item is
constant i.e no discount is available The replenishment is made
instantaneously, the whole batch is delivered at once.
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Problem!
How do we determine the optimal number of units of the product to order so that we minimize the total cost associated with the purchase, delivery and storage of the product ?
(EOQ is the quantity to order, so that ordering cost + carrying cost finds its minimum)
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Constructing the equation:
Parameters : Total demand Purchase cost Fixed cost to place the order Storage cost for each item per year
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Variable Cost
Q = order quantity Q * = optimal order quantity D = annual demand quantity of the product P = purchase cost per unit C = fixed cost per order (not per unit, in addition
to unit cost) H = annual holding cost per unit (also known as
carrying cost or storage cost) (warehouse space, refrigeration, insurance, etc. usually not related to the unit cost)
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So the equation becomes:
Total Cost = purchase cost + ordering cost + holding cost
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Purchase cost: This is the variable cost of goods: purchase unit price × annual demand quantity.
This is P×D or PD
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Ordering cost: This is the cost of placing orders: each order has a fixed cost C, and we need to order D/Q times per year.
This is C × D/Q
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Holding cost: the average quantity in stock (between fully replenished and empty) is Q/2.
so this cost is H × Q/2
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The equation is :
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This looks like what we did before , no?
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Now we can find the optimal point by:
To determine the minimum point of the total cost curve, set its derivative equal to zero:
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The result of this derivation is:
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Solving for Q gives Q* (the optimal order quantity):
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Now all you need is to know is C, D and H
If you know that: H = annual holding cost per unit = $500 C = fixed cost per order =$100 D = annual demand quantity of the product =
2000 units
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What is the quantity at which a company should order new inventory to minimize cost? REMEMBER:
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Answer:
Q* = SQRT (2 *100*2000 /500 ) =???????
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ECONOMIC APPLICATIONS
A BRANCH OF SCIENCE CALLED DECISION SCIENCE USES LINEAR EQUATIONS TO SOLVE ECONOMIC PROBLEMS USING OPTOMIZATION / MINIMIZATION!
OUTLINEOUTLINE
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Thank you
Q&AEnjoy your stay!
Materials will be posted @ http://mathMMC.blogspot.com