mititab solve
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ASSIGNM X1 X2 X1 Decision variable 30 40 Decision variable 150 objective functio 410 Objective functio 11450 Constraints LHS RHS Constraints LHS 240 <= 240 Wiring 1075 100 <= 100 Drilling 2350 X1 >= 10 Assembly 1800 X2 >= 10 Inspection 525 X1 150 X2 100 PROBLEM 2 X3 300 X1 X2 X4 400 Decision variable 24 20 objective functio 204 Constraints LHS RHS material 600 <= 600 Machinery 1000 <= 1000 Labor 1080 <= 1200
Transcript of mititab solve
ASSIGNMENTX1 X2 X1 X2
Decision variables 30 40 Decision variables 150 100.000004
objective function 410 Objective function 11450
Constraints LHS RHS Constraints LHS240 <= 240 Wiring 1075 <=100 <= 100 Drilling 2350 <=
X1 >= 10 Assembly 1800 <=X2 >= 10 Inspection 525 <=
X1 150 >=X2 100 >=
PROBLEM 2 X3 300 >=X1 X2 X4 400 >=
Decision variables 24 20
objective function 204
Constraints LHS RHSmaterial 600 <= 600Machinery 1000 <= 1000Labor 1080 <= 1200
X3 X4
300 400
RHS1500235026001200
150100
300400
ASSIGNMENTX1 X2 X3 X4
Decision va 150 -1.42E-14 950 0
objective f 15600
ConstraintLHS RHSWiring 1500 <= 1500drilling 2350 <= 2350Assembly 1250 <= 2600Inspection 550 <= 1200
X1 X2
Decision variables 40 20
objective function 380
Constraints LHS RHS220 <= 240100 <= 100
X1 40 >= 60X2 20 >= 0
A B C D E F G H I
1 ASSIGNMENT 52 X1 X2 X3 X434 Decision variables 150 100 300 40056 Objective function =9*B4+12*C4+15*D4+11*E4 11450789 Constraints LHS RHS
10 Wiring =0.5*B4+1.5*C4+1.5*D4+1*E4 1075 <= 150011 Drilling =3*B4+1*C4+2*D4+3*E4 2350 <= 235012 Assembly =2*B4+4*C4+1*D4+2*E4 1800 <= 260013 Inspection =0.5*B4+1*C4+0.5*D4+0.5*E4 525 <= 120014 X1 =B4 150 >= 15015 X2 =C4 100 >= 10016 X3 =D4 300 >= 30017 X4 =E4 400 >= 4001819 Answer2021222324
We can conclude that we use 1075 hours of Wiring, full 2350 hours of Drilling, 1800 hours of Assembly and only 525 hours of Inspection time. This would give us the optimum profit of $11450 while we also produce the minimum number of each unit required per month.
