MEP PB4b-Ans 81-110 - CIMT

MEP Primary Practice Book 4b ANSWERS

See Lesson Plans for Year 4 at http://www.cimt.plymouth.ac.uk/projects/mepres/primary/default.htm

What part of the ribbon is grey and what part is white? Write an addition and asubtraction about each ribbon.

Fill in the missing fractions.

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a)1

3

1

4

1

6

1

9

1

2

1

12

b) 2

3

3

4

5

6

5

9

2

2

7

12

How many apples are in:

of the 36 apples?

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a)15

+ = 1 + = 1 – = 1 – = 135

65

45

b)38

+ = 1 + = 1 – = 1 – = 188

108

88

c)710

+ = 1 + = 1 – = 1 – = 1510

2010

510

a)

3+ = = 1

– =12

b)

6+ = = 1

– =1

i)

ii)

i)

ii)

c)

4+ = = 1

– =1

d)

+ = = 1

– =1

i)

ii)

i)

ii)

1

36

9 6

30

4

20

3

21

21 3

3 3 6 6

5 1

3 3

6 10 3 4

6 4

10 10

3 1

4 4

1010 10

15 6

44 4

6 6

1

4

5

2

0

3 5

1

2

9

16

10 15

5

8

5

8

5

8

5

8

10 10 10 10

18 12

24 27

0 or



Each rectangle is 1 unit. Write an addition and a subtraction about each diagram

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

Write the additions and subtractions with fractions in your exercise book andcalculate the results.

a) 1 third + 1 third b) 1 half + 1 half + 1 half1

3 + 1

3 = 2

3

1

2 + 1

2 + 1

2 = 3

2 = 1 1

2

c) 3 quarters – 1 quarter d) 2 fifths + 2 fifths3

4 – 1

4 = 2

4 = 1

2

2

5 + 2

5 = 4

5

e) 5 sixths – 4 sixths f) 1 seventh + 3 sevenths – 4 sevenths5

6 – 4

6 = 1

6

1

7 + 3

7 – 4

7 = 0

7 = 0

g) 3 eighths + 10 eighths – 5 eighths h) 8 ninths – 3 ninths3

8 + 10

8 – 5

8 = 8

8 = 1 8

9 – 3

9 = 5

9

i) 10 tenths – 7 tenths + 2 tenths j) 10 tenths – 8 tenths – 1 tenth10

10 – 7

10 + 2

10 = 5

10 = 1

2

10

10 – 8

10 – 1

10 = 1

10

Calculate the sums and differences.

a)12

+ 12

= 2

2 = 1 b)

35

+ 15

= 4

5

c)23

–13

= 1

3d)

34

–24

= 1

4

e)45

– 45

= 0

5 = 0 f)

66

+ 16

= 7

61

1

6=

g)7

10 –

410

= h)3

20 +

020

= 3

20

Hedgehog lives 400 m away from Squirrel.One day, Squirrel went to visitHedgehog. In the first minute, Squirrel covered 2 fifths of the route. In thesecond minute, Squirrel covered another 2 fifths of the route.

How many metres did Squirrel still have to go? 15 of 400 m = 400 5 = 80 m

11111

a) b) c) d) e)

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720

+ 1320

= 11420

+ 620

= 120

+20

= 1 1220

+ 820

= 1 920

+ 1120

= 1

620

_ 1320

=_= 1020

_ _= _

1010

111111420

720

1020

820

1220

=20 20

=11 9

33333

3

10

..

E.g:



3

5

11111

Join up the equal numbers.

Each rectangle is 1 unit. Colour the parts given.

Complete the diagrams to match the problems.

a) The distance between two cities is 369 km.

A family drove 1 third of the distance beforelunch and completed the journey after lunch.

How far did they drive

i) before lunch ii) after lunch?

b) Some men are laying a pavement.

They have already paved 120 m,which is 2 thirds of the pavement.

i) How much do they still have to do?

ii) How long will the finished pavement be?

a)15

+ 15

+ 15

= b)38

+ 28

= c)7

12 –

212

=

d)1120

–9

20 = 2

201

10= e)

710

+ 35

= = f)34

– 38

=

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33333

44444

25

36

410

1020

2

12

510

43

52

63

421

13

6 7 4 4 8 4 4 km

km

(part)

km

1 2 3

1 2 3

(part)

m

(part)

m

(part)

m

1 2 4 4 4 3 4 4 4

6 7 4 4 8 4 4

6 7 4 8 4

58

5

12

38

13

23

123 246

13

23

120 60

180

13

101

3

10

E.g:12

a)24

34

48

23

b)46

69

1218

369



11111

44444

0 1 2 3

b)

c)

a) + + =12

34

12

– =45

15

+ – =56

26

46

0 1 2

0 1 2

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a

b

310

110

810

510

710

510

1210

410

1

110

215

3110

45

9

10

6

10

6

10

27

104

10

Sam has equal numbers of all the trees.

Sam has 20 plum trees.

They are 14 of all Sam's trees.

Solve the problem. Do the calculations in your exercise book.

Sam has 80 fruit trees. Two eighths of them are apple trees, one quarter of themare pear trees, four sixteenths of them are cherry trees and the rest are plum trees.

a) What kind of tree does he have most of? . . . . . . . . . . . . . . . . . . . . .

b) i) How many plum trees does Sam have? . . . . . . . . . . . . . . . . . . . . .

ii) What fraction of all Sam's trees are they? . . . . . . . . . . . . . . . . . . . . .

Use the number lines to help you do the additions and subtractions.

Solve the problems in your exercise book. Remember to convert the units.

a) Mum bought a loaf which weighed 34

kg. Rob ate 15

of it.

How much bread did Rob eat?

b) Diane spent £616, which was 25

of her money.

How much money did Diane have before?

Work out the rule and complete the table. Write the rule in different ways.

Rule:

35

134

36 = 1

2

150 g

£1540

210=

810=2

5

10

0

b = a +4

10 or a = b 4

10 or b a = 4

10 (a b = 4

10 )



11111 Compare the solids to the 1 unit. Complete the table.

Do the additions and subtractions.

a) 63 chairs + 58 chairs + 120 chairs =

b) 3 quarters + 2 quarters + 1 quarter =

c) 4q + 7q + 11q = d)37

+ 27

+ 47

– 57

=

e) 312 chicks + 243 dogs – 250 chicks + 21 dogs =

f) 4a + 6a + 8b – 5b = g)12

+ 14

+ 34

+ 12

=

Fill in the missing fractions.

Solve the problems in your exercise book.

a) David ate 2 fifths of a 500 g bar of chocolate. How many grams did he eat?

b) Marion spent £318, which was 2 thirds of her money. How much did shehave at first?

a)

b)

e)

c)

1 =

1 =

1 =

1 =d)

1 =

22222

a)16

+ = 1 + = 1 – = 1 1 – = 34

43

25

b)37

+ = 1 + = 1 – = 158

1 – = 49

76

33333

44444

16

16

8

8

4

4

2

2

6

6

816 =

12

416 =

14

216 =

18

616 =

38

168 = 2

48 =

12

28 =

14

68 =

34

164 = 4

84 = 2

24 =

12

162 = 8

82 = 4

42 = 2

62 = 3

46 =

23

26 =

13

64 = 1 2

4 = 1 1

2

86 = 1

26 = 1

13

166 = 2

46 = 2

23

241 chairs

1 12

22q

10a + 3b 2

62 chicks + 264 dogs

47

56

14

13

35

47

38

16

59

David ate 200 g.

Marion had £477 at first.

(= 326 animals)



11111

44444

22222

33333

6 1 75

d)

6 3 57

1+

0 2 87

2 0

e)

52 04–

f)

1 0 86

67 23–

b)

6 ×

c) 3 69 ×

7 d)8 76

e)7 39 6

8 7

1380 1540 1700 +160

81 27 9

5500 4900 4400

3..

The difference is decreasing by 100.

E.g:

8 8 7 0 1 4 1 2 2 3 8 2

1 4 r 3 8 1 r 7

5 2 2 6 6 2 4

69

79

89 + 1

9

56

48

912 =

34

610 = 3

5

120 40 900

b)

c)23

a)13

1 1 1

4 sevenths

1 1 1

10

2

1 1

0 1 32

1 1 1

1

6 7 8

6 7 8

0 1

Continue each sequence for 3 more terms. What rule did you use?

a) 740, 900, 1060, 1220, , , , Rule:

b) 6561, 2187, 729, 243, , , , Rule:

c) 8900, 7900, 7000, 6200, , , ,

Rule: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

d)29

, 39

, 49

, 59

, , , , Rule:

Show the fractions in different ways.

a) 4100 + 810 + 70 + 2400 =

b) 5210 – 2300 = c) 3050 – 2500 + 800 =

g) 2 sixths + 3 sixths = h) 7 eighths – 3 eighths =

i)5

12 +

112

+ 3

12 = j)

910

– 3

10 =

a) i) 40 × 3 = ii) 280 ÷ 7 = iii) 30 × 30 =

7380

2910 1350

= 12



11111

Write an equation and calculate the missing number in your exercise book.

a) We thought of a number. If we added 420 to it we wouldget 3150. Which number were we thinking of?

b) We thought of a number. If we subtracted 200 from it wewould get 5002. Which number were we thinking of?

c) We thought of a number. If we multiplied it by 7 wewould get 203. Which number were we thinking of?

d) We thought of a number. If we divided it by 7 we would get 203. Which number were we thinking of?

Fill in the missing numbers.

a) 438 + = 1000 b) – 4500 = 2900

c) 8200 – = 2800 d)38

+ = 78

e) – 2

15 =

1115

f) 1 – = 47


a) 9 × = 387 b) ÷ 9 = 387 c) 378 ÷ = 7

d)13

× = 33

e) ÷ 2 = 25

f) 58

÷ = 18

a) Complete the table if this is the rule. Rule: B = 2 thirds of A.

Write the rule in a different way. . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

b) Find a rule and complete the table. Write the rule in different ways.

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33333

44444

A

B

3 6 9 12 15 18 21 24 27 30 33

2 4 24 26 28 30

450

70

34

25

5

Rule:

X

Y

1 2

25

1 25

35

0

45

15

35

125

135

65

5 25

20

40

36 39 42 45 105 7

6 8 10 12 14 16 18 20 22 300

35

12

24

2730

5202

29

1421

x + 420 = 3150so 3150 – 420 = x x = 2730

x 7 = 203so x = 203 7

x = 1421

x 7 = 203so x = 203 7

x = 29

x – 200 = 5002so x = 5002 + 200

x = 5202

562 7400

540048

1315

37

43 3483 54

345 5

65

95 6 40 42 60 73

19 41 60 72

35

35

15

45

105

25

25

35

E.g: E.g: E.g:

A = B 2 3 or B = A 3 2or B = A 2 3 or A = B 3 2

X = Y + 35 or Y = X

35 or X Y =

35 (Y X =

35 )

8



Solve the problem in your exercise books. Write the answer here.

A roll of film is 675 m long.

a) How long are 9 rolls of film? . . . . . . . . . . . . . . . . . . . . . . . .

b) How long is 3 fifths of a roll of film? . . . . . . . . . . . . . . . . . . . . . . . .

Complete the table.

Complete the table.

Complete the tables to show the capacity and mass of clear water at 4° Celsius.

11111

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Capacity

1 half

1 quarter

1 tenth

1 fifth

2 fifths

3 tenths

100 litres 800 litres 1 litre 8 litres 10 cl 80 cl

cl cl ml ml

cl cl ml ml

cl cl ml ml

cl cl ml ml

cl cl ml ml

cl cl ml ml

l l

l l

l l

l l

l l

l l

33333

Mass 1 kg 12 kg 24 kg 200 g 400 g 6 tonnes

g g g kg12141

101525

g g

g g g kgg g

g g g kgg g

g g g kgg g

g g g kgg g

44444

Capacity 1 litre 7 litres litre

gMass 1 kg 4 kg 250 g

100

50 kg g

12

34 litre

a)

Capacity 1 ml 8 ml 1 cl

Mass 1 g 13 g 10 g

200 ml

50 g

ml

b)121

l l

(9 675 = 6075) 6075 m

(675 5 3 = 405) 405 m..

50 400 50 400 50 400

25 200 25 200 25 200

10 80 10 80 10 80

20 160 20 160 20 160

40 320 40 320 40 320

30 240 30 240 30 240

500 6000 12000 100 200 3000

250 3000 6000 50 100 1500

100 1200 2400 20 40 600

200 2400 4800 40 80 1200

400 4800 9600 80 160 2400

4 litres14 50 litres

7 kg 500 100 kg 750

13 ml 10 ml 50 ml

8 g 10 g 200 g 1 12 g



11111

a) 5600+ 500 + 300 + 200

b) 5600

c) 5600

+ 400

+ 200 + 400 + 300+ 500

– 500 + 300 – 200+ 400

d) 5600

e) 5600

– 500 – 300 – 200– 400

– 200 – 400 – 500– 300

44444


Write a plan, estimate, calculate, check and write the answer as a sentence inyour exercise book.

a) A farmer collected the cherries from his orchard and packed them inboxes. Each box held 18 kg of cherries.

He filled 79 boxes and loaded them on a lorry to take to the supermarket.If an empty box weighed 2 kg, what was the total load on the lorry?

b) The total mass of 8 containers of building material is 5600 kg.

If the containers weighed 1600 kg in total when they were empty, howmuch building material is in each container?

a) How many small squares are needed to cover thisrectangle?

b) Draw a rectangle which needs:

of this number of small squares to cover it.

Complete the table to show different parts of the total number of walnuts.

22222

small squares

33333

12

Part oftotal

Number of

13

16

32

33

36

23

46

63

i) 12

ii) 23

iii) 34

iv) 59

6000 6500 6800 7000

6100 6300 6700 7000

6000 5500 5800 5600

5200 4700 4400 4200

5300 5100 4700 4200

The total load was 1580 kg.

There was 500 kg of building material in each container.

36

E.g:

6 4 2 18 12 6 8 8 24



11111

b)

c)12

a)14

1 1 1

three fifths10

1

1 1 1

6 7 8

0 1

0 1 2

1

1 1 1

6 7 8

22222

b)

7 ×

c) 6 86 ×

3 d)9 35

e)5 47 6

4 7

33333

A

B

0 5 10 15 20 25 30

14 16 18 200 2

100

100

2

44444

55555

2 litres 4 litres 44 litres

5 km 3 km 6 km

1 kg 1 kg 6 kg

120 40 1600 12

Show the fractions in different ways.

Practise calculation.

a) 30 × 4 = 360 ÷ 9 = 40 × 40 = 240 ÷ 20 =

Complete the table if the rule is : B = 2 fifths of A.

Write the rule as: A = . . . . . . . . . . . . . . . . . . . . . . .

Which numbers can be written instead of the star?

a) 1525 < < 1530 : . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

b) 611

≤ < 1 : . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

c) 118

≤ < 112

: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

Round these measures to the nearest

a) litre: 234 cl ≈ 375 cl ≈ 4390 cl ≈

b) km: 4.6 km ≈ 3 km 45 cm ≈ 6390 m ≈

c) kg: 13

8 kg ≈ 1456 g ≈ 5.5 kg ≈

1 8 r 3 7 8

3 2 9 2 2 0 8

35 40 45 50 250

4 6 8 10 12 40 45

,

1526, 1527, 1528, 1529

E.g:611 , 7

11 , 811

911 , 10

11

E.g: 118 , 1 2

8 , 1 38

B 2 5E.g:



Change the quantities to the units required and write them in the table.

Write the sums in the table.

Write the quantities in different forms in your exercise book.

a) i) £4.99 ii) £41.05 iii) £204.50

b) i) 4.3 cm ii) 63.5 cm iii) 8.24 m iv) 57.06 m

a) Draw these lines with a ruler in your exercise book and label them.

a = 87 mm, b = 11.6 cm, c = 6 cm 4 mm, d = 75

10 cm

b) Measure the length of these line segments and write it in different forms.

i)

ii)

11111

22222

a) 5 10 + 3 1 + 2

6 1 + 8 + 4

H T U t h100 10 1 1

101

100

d) 9 + 2

6 10 + 0 1 + 3

b)

c)

e)

× × × 110

× × × × 110

× × ×110

× 110 ×

3 100 + 4 10 + 7 1 + 51

1001

100× × ×

110

33333

44444

a) 35 cm 6 mm =

1 m 20 cm 4 mm =

3208 mm =

H T U t h100 10 1 1

101

100

b) 1 m 63 cm =

28 m 40 cm =

605 cm =

£8 70 p =

£41 5 p =

£120 15 p =

3648 p =

(cm)

(m)

(£)

c)

4.3 cm, 43 mm

11.8 cm, 118 mm

3 5 6

1 2 0 4

3 2 0 8

1 6 3

2 8 4 0

6 0 5

8 7 0

4 1 0 5

1 2 0 1 5

3 6 4 8

5 3 2

3 4 7 5

6 8 4

0 9 2

6 0 3

499 p 4105 p 20450 p

43 mm 635 mm 824 cm 5706 cm

4105 p

E.g:



Join up the decimal numbers to the matching point on the number line.

Continue the pattern. Write the decimal numbers as fractions below the line.

Find equivalent fractions in the diagram. Write them as decimals too.

Complete the table and the equations. Follow the pattern.

Convert the quantities. Follow the pattern. Fill in the missing numbers.

a) 5 cm 8 mm = 5 8

10 cm = 5.8 cm

36 cm 5 mm = cm = cm

b) 8 m 63 cm = 863 cm = 8 63

100 m = 8.63 m

1 m 24 cm = cm = m = m

25 m 70 cm = cm = m = m

11111

3210

0.2 0.5 0.8 1.1

22222

33333

44444

1 = 1010

1 = 22

1 = 55

2 10 + 5 1 + 1 + 8

H T U t h100 10 1 1

101

100

8 100 + 0 10 + 3 1 + 4

× × × 110

× ×

× = 25 + 1100

= 25.18181002 5 1 8

0 4 3

6 5 7

1 = =

= =

= = × ×

= 26 + = 710

= 10.05=

110

8 0 3 4

2 6 7

1 0 0 5

1.4 1.7 2 2.3 2.6 2.9 3.2

210

1110

1410

2310

2910

2610

1710

510

810

210 =

15 = 0.2

610 =

35 = 0.6

410 =

25 = 0.4

810 =

45 = 0.8

510 =

12 = 0.5

1010 =

55 = 1.0

104 +3

10 104.3

6 +57

100 6.57

803 +4

10 803.4

26.7

10 +5

100

1

1 100 0 10 4 1 31

10× + × + × + ×

2 10 6 1 71

10× + × + ×

1 10 0 1 01

105

1100

× + × + × + ×

36510 36.5

124 1 24100 1.24

2570 25 70100 25.70

3210

6 1 51

107

1100

× + × + ×



11111 Fill in the missing numbers and write the quantities in the place-value table

using the units given.

Write the numbers in increasing order in your exercise book.

a) 9999, 683, 2015, 71, 452, 3, 2009, 460

b)4

15,

1415

, 1115

, 1

15,

2015

, 3

15,

1615

, 3015

c) 0.3, 3.1, 7.0, 0.08, 0.32, 7, 0.4, 6.9

Compare the pairs of numbers and fill in the missing signs. (<, >, =)Use the diagrams to help you.

Calculate the quantities and compare each pair. Write <, > or = in the boxes.

15 m + 8100a) m + m = m cm

H T U t h100 10 1 1

101

100

(m)

(m)

( )

(£)

(kg)

300.45 m =b) m cm

110

7 litres =c) litres cl 8100

£106.80 = £d) p

28.5 kg =e) kg g

l

22222

33333

44444

d) 0.25 of £220 =

c) of 28 kg = 0.5 of 14 kg =14

b) 0.6 of 150 litres =

a) of 450 m = 0.28 of 1 km =15

of 100 litres =710

of £90 =34

1 5 1 8

3 0 0 4 5

7 0 8

1 0 6 8 0

2 8 5

15 18

300 45

7 8

106 80

28 500

< < >

< < >

< > <

= > <

> < >

a) 0.9210

710

810 0.6 0.3 1

b) 0.7015100

72100 0.52 0.49

43100

1c) 0.27 0.30.04 0.1

210

18100

d) 0.60.215

0.33

10

e) 0.5117100 0.53

15

310

78100

25

<

>

=

<

3, 71, 452, 460, 683, 2009, 2015, 9999

115

315

415

1115

1415

1615

2015

3015

, , , , , , ,

0.08, 0.3, 0.32, 0.4, 3.1, 6.9, 7.0 = 7

7 kg

90 m

90 litres

£55 £67.50

7 kg

70 litres

280 m



11111 Convert the fractions to decimals and the decimals to fractions.


a) i)12

litre = ml ii)14

m = cm = mm

iii)15

kg = g iv)1

10 km = m

b) i)34

m = cm = mm ii)25

litre = ml

iii) 212

km = m iv)3

10 hour = minutes

c) i) 0.1 km = m ii) 0.2 litre = ml

iii) 0.3 m = cm = mm iv) 0.7 kg = g

d) i) 1.3 kg = g ii) 2.5 km = m

iii) 5.6 m = cm = mm iv) 6.25 litres = ml

Solve the problems in your exercise book.

a) A group of friends went on a 3-day trip. They covered 4 tenths ofthe journey on the first day and 0.3 of the journey on the second day.

How much of the journey would they have to do on the 3rd day?

b) Lucy spent 1 and a half hours on her homework. She spent 0.4 of the timeon mathematics. How long did she spend on mathematics? How long didshe spend on other subjects? i) 36 mins ii) 54 mins

c) Sam spent £72, which was 0.6 of his savings, on Christmas presents.How much had Sam saved? £120 How much did he have left?

22222

33333

a)1 =1

2

1010

1 = 100100

=22

=52

= 12

=

b) 0.1 = 0.2 = 0.5 = 0.9 =

c)14

=34

= 194

=

d) 0.17 = 0.30 = 2.1 = 6.5 =

e) 1.2 = 3.80 = 12.05 = 0.75 =

6

14

=2

0.5 1 2.5 6.5

110

910

0.25 0.75 2.25 4.75

17100

310

2110

6510

115 3

45 12

120

4

10

3

10

7

10+ =

310

4

1090 10 4of 90 = ÷ ×

500 25 250

200 100

75 750 400

2500 18

100 200

30 300 700

1300 2500

560 5600 6250

34

510 = 1

2210 =

15

£48

110 of savings

= £12



11111 Write the sums in the table.

Join up the decimal numbers to the matching points on the number line.

Write the decimal numbers as fractions below the number line.

Continue each sequence for 3 more terms. Write the rule you used.

a) 0.1, 0.5, 0.9, 1.3, , , , Rule:

b)18

, 38

, 58

, 78

, , , , Rule:

c) 8, 4, 2, 1, , , , Rule:

d) 2.1, 1.9, 1.7, 1.5, , , , Rule:

Calculate the quantities and give the answer in the units asked for.

a)12

of 35 m = m = m cm = cm

b) 0.2 of 2 kg = kg = g

c)34

of 10 litres = litres = litres cl = cl

d) 0.25 of £22 = £ = £ p = p

Tim watched television for 2 and a half hours. He spent 0.6 ofhis time watching sport. For how long did he watch sport? . . . . . . . . . . . . . .

a) 4 100 + 5 1 + 3

1 100 + 3 + 9

H T U t h100 10 1 1

101

100

d) 9 + 2

7 1 + 5

b)

c)

e)

× × × 110

× × × 1100

× × ×110

× 110 ×

7 10 + 1 1 + 4

1100

1100

× ×1

100

22222

33333

44444

55555

4 0 5 3

7 1 0 4

1 0 0 3 9

0 9 2

7 0 5

..

+ 0.4

+ 28

2

– 0.2

17.5 17 50 1750

0.4 400

7.5 7 50 750

5.50 5 50 550

90 mins

310

710

2101 5

101 8101 95

100110

0.3 1.2 1.5 1.8

2

0.7 1.95

1.7 2.1 2.5

118 1

38 1

58

12

14

18

1.3 1.1 0.9



Add the quantities in the different units. Write the addition in the table.

Subtract the quantities in the different units. Write the subtraction in the table.

Calculate with fractions and decimals. Follow the example.

b) Calculate 6.81 – 2.7 in your exercise book in the same way.

11111

a) 1.1 m + 230 cm + 8600 mm

In mm In cm In m 10 m 1 m 10 cm 1 cm

b) 13.4 litres + 1580 cl + 2500 ml

In ml In cl In litres 10 1 1 cl l l 10 cl

a) 4.73 m – 210 cm

In mm In cm In m

b) 18.6 litres – 7900 ml

In ml In cl In litres 10 1 1 cl l l 10 cl

1 m 10 cm 1 cm

22222

33333

1 1 0 0 1 1 0 1 . 1

2 3 0 0 2 3 0 2 . 3+ 8 6 0 0 + 8 6 0 + 8 . 61 2 0 0 0 1 2 0 0 1 2 . 0

1 8 6 0 0 1 8 6 0 1 8 . 6 0

7 9 0 0 7 9 0 7 . 9 01 0 7 0 0 1 0 7 0 1 0 . 7 0

– – –

1 1 02 3 08 6 0

1 2 0 0

1 3 4 01 5 8 0

2 5 03 1 7 0

4 7 32 1 02 6 3

1 8 6 07 9 0

1 0 7 0

1 3 4 0 0 1 3 4 0 1 3 . 4

1 5 8 0 0 1 5 8 0 1 5 . 8+ 2 5 0 0 + 2 5 0 + 2 . 53 1 7 0 0 3 1 7 0 3 1 . 7

+

+

4 7 3 0 4 7 3 4 . 7 3

– 2 1 0 0 – 2 1 0 – 2 . 1 02 6 3 0 2 6 3 2 . 6 3

–

–

a) 910

90100

4.9

10.23

7.04

=

=

=+

4 + =

=

=

4 + =

=

=

4.90

= =22.17 = 22 +1

10 +7

100 22 +17

100 22.17

6.81 = 6 +8

10 +1

100 = 6 +81

100 = 6.81

2.7 – 2 7

10 – 2 + 70

100 = 2.70–

4.11 4 + 1

10 +1

100 4 +11

100 = 4.11

–

E.g:

10 +210 + 10 +

23100 10.23

7 + 010 +

4100 7 +

4100 7.04

3100



11111

Continue each sequence for the next 5 terms. Write down the rule you used.

a) 0.2, 0.4, 0.6, 0.8, . . . . ., . . . . ., . . . . ., . . . . ., . . . . .,

b) 12.1, 11.8, 11.5, 11.2, . . . . ., . . . . ., . . . . ., . . . . ., . . . . .,

c) 4.7, 5.9, 7.1, 8.3, . . . . ., . . . . ., . . . . ., . . . . ., . . . . .,

d) 1, 1.1, 1.3, 1.6, 2, 2.5, . . . . ., . . . . ., . . . . ., . . . . ., . . . . .,

Rule: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

Calculate these quantities. Write the operation, then give the result in cm and m.Follow the example.

a) 1

4 of 3 m = 300 cm ÷ 4 = 75 cm = 0.75 m

b) 3

4 of 1 m = = =

c) 1

5 of 2 m = = =

d) 2

5 of 1 m = = =

e) the sum ofb) and d) = = =

Estimate the result by rounding the numbers to the nearest whole number.Write the additions and subtractions in the tables.

22222

33333

a) 1.1 + 42.6 + 0.8 b) 62 + 6.2 + 0.62

c) 22.5 – 13.7

T U t

d) 32.8 – 13

T U t

e) 32 – 13.7

T U t

≈

T U t

≈

T U t h

≈ ≈ ≈

1.0 1.2 1.4 1.6 1.8 + 0.2

10.9 10.6 10.3 10.0 9.7 – 0.3

9.5 10.7 11.9 13.1 14.3 + 1.2

3.1 3.8 4.6 5.5 6.5

The differences between terms are increasing by 0.1.

100 cm..

3100 cm 4 0.75 m

200 cm 5 40 cm 0.40 m

100 cm 5 40 cm 0.40 m

115 cm 1.15 m

..

..2

75 cm+ 40 cm 115 cm

1 1

4 2 6

0 8

4 4 5

2 2 5

1 3 7

8 8

6 2

6 2

0 6 2

6 8 8 2

3 2 8

1 31 9 8

3 2 0

1 3 7

1 8 3

– – –

+ +

1 + 43 + 1 = 45 62 + 6 + 1 = 69

23 – 14 = 9 33 – 13 = 20 32 – 14 = 18

25 cm3

= 75 cm



11111 Calculate the sums and differences in different ways.

a) 6.8 + 4.7 =

b) 2 1

10 + 3

410

=

c) 5.2 – 1.6 =

d) 6 8

10 – 1

710

=

e) 4 3

10 + 11.8 =

f) 7.2 – 3 6

10 =

Charlie went on a shopping spree. He spent £29 80 p on food, £37.60 on tools,£30.50 on things for his house and £38.50 on clothes.

a) How much did Charlie spend altogether?

b) How much money did he have left if he had £200 to start with?

22222 a) 2 4

0 37 2+

d) 0 89 46

02 90

0064

+ 1

18

b) 2 15 60 7+

4

e) 0 54 6

1 7+

15

32

f) 30 9

0 5+

1

3

c) 3 67 25

19 8+

21

4

a) 9 66 2–

42

56 71

8–

41

f) 4 05 6– 3

2 19

48–

b) 9 52 6–

85

c) 5

d) e) 5 63–

493

6

33333

44444

9 9 . 9 4 8 . 4 6 3 6 . 6

7 4 3 7 . 1 3 8 . 3 2 1 6 .9 5

3 3 . 4 3 6 . 9 3 3 . 2 5

6 9 . 1 3 2 6 . 3 4 4 . 4

£136.40£63.60

11.5

5.5

3.6

5.1

16.1

3.6



How much of each shape has been shaded? Join up the fractions tothe matching diagrams.

Which number is more? How much more? Write the missing signs and differences.

a) 0.7 0.32 b) 5.8 7.1 c) 2.5 2.05

d) 0.50 0.5 e) 3.2 4 f) 0.6 0.66

Solve the problem in your exercise book.

The sides of a rectangular play area are 54.8 m wide and 23.6 m long.

How much fencing is needed to surround the play area if the gate is 1.8 m wide?

Which numbers can be written instead of the letters?

a) a + 3.4 = 5.6 b) b – 3.1 = 0 c) c + 2.7 = 10

a = b = c =

d) 7.8 + d = 12.3 e) 8.2 – e = 6.4 f) f – 11.9 = 6.3

d = e = f =

g) g + g + 5.4 = 10 h) 0.4 + h = 0.8 – h

g = h =

i)25

+ i = 1.3 j) j – 0.8 = 15

10k)

34

– k = 0.07

i = j = k =

11111

33333

22222

44444

13 0.5

14

59 0.3 0.6 0.7

0.2512

310

820

49 0.4

816

34

> < >

0.38 1.3 0.45

= < <

0 0.8 0.06

2 (54.8 m + 23.6 m) – 1.8 m = 155 m 155 m of fencing is needed.

2.2 3.1 7.3

4.5 1.8 8.2

2.3 0.2

0.9 2.3 0.68



Which is more? How much more? Fill in the missing signs and differences.

a) 0.312

b)34

0.75 c)35

0.2

= =

Fill in the missing numbers. Follow the example.

a) i) 3 mm = 3

10 cm = 0.3 cm ii) 6 mm = cm = cm

b) i) 5 cm = m = m ii) 9 cm = m = m

c) i) 76 cm = m = m ii) 12 m = km = km

Which numbers can be written instead of the letters?

a) a + 2.3 = 3.7 b) b – 4.6 = 8 c) 6.1 – c = 4

a = b = c =

d)35

+ d = 115

e) e –14

= 2.6 f) 4.3 – f = 312

d = e = f =

Solve the problem in your exercise book. Write only the answer here.

On Monday Paul spent £5.27, on Tuesday he spent £3.59, on Wednesday hespent £4.57, on Thursday he spent £3.12 and on Friday he spent £2.27.

a) How much did Paul spend altogether? . . . . . . . . . . . . . .

b) How much did he have left if he had £20 to start with? . . . . . . . . . . . . . .

Join thenumbersto thematchingdiagrams.

11111

22222

44444

55555

33333

0.25310

0.314 0.4

212

410

25

39

28

16

13

< = >

0.2 210 0 0.4 4

10

1.4 12.6 2.1

35 2.85 0.8

£18.82

£1.18

610 0.6

5100 0.05 9

100 0.09

76100 0.76 12

1000 0.012



Write a plan, estimate, calculate and check in your exercise book. Write theanswer here.

a) Helen spent £8.40, Jane spent £3.90 and Lisa spent £5.20.How much did they spend altogether?

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

b) Frank and Barry each dug up 25

of the vegetable plot.

i) What part of the vegetable plot did they dig up altogether?

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

ii) What part did they still have to dig?

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

c) Polly bought 1.5 kg of apples and 5

10 kg less of bananas.

i) How many kg of bananas did she buy? . . . . . . . . . . . . . . . . . . . .

ii) How much fruit did she buy altogether? . . . . . . . . . . . . . . . . . . . .

Draw a diagram to help you solve the problem.

Kate wants to cut a 2.4 m length of ribbon into two pieces, so that one piece istwice as long as the other piece.What will be the length of each piece.

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

Divide up the shapes into 4 congruent parts so that the sum of the numbers ineach part is 2.

11111

a) b)0.3 0.3 0.3 0.3

0.2 0.3 0.4 0.4

0.5 0.5 0.4 0.1

0.3 0.2 0.2 0.4

0.6 0.3 0.2 0.7

0.2 0.5 0.1 0.3310

510

510

310

210

610

510

110

510

310

210

110

310

210

410

310

410

310

410

110

310

410

610 0

22222

33333

£17.50

Short = 80 cm = 0.8 m Long = 160 cm = 1.6 m

1 kg

2.5 kg

45

15

2.4 m

13

23

510

E.g:



1000 5 200÷ =

200 4 800× =

11111

Write a plan, estimate, calculate and check the result in your exercise books.Write the answer in a sentence here.

a) If I were to give you £6.40, you would have £25.80.How much do you have?

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

b) After gathering another 125

kg of mushrooms, I have 215

kg of mushrooms

altogether. How many kg of mushrooms did I have at first?

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

c) What length is the perimeter of this rectangle?

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

Solve the problems.

a) Divide 20.3 kg into three parts so that the lightest part is half the weight ofthe middle-sized part and the middle-sized part is half the weight of theheaviest part.

Lightest part: . . . . . . . . . . . . . . . . .

Middle-sized part: . . . . . . . . . . . . . . . . .

Heaviest part: . . . . . . . . . . . . . . . . .

b) Which is more and how much more: 23

of 1200 litres or 45

of 1000 litres?

Write it as an inequality.


2.5 cm

1 cm14

+ 14

34

+ 141

+ 34

+2 34

+ 34

+ 13

+ 18

+ 12

22222

33333

45 kg

(1.25 cm)

2.9 kg

5.8 kg

11.6 kg

x 2x 4x

7 20 3x = . kg

x = 2 9. kg

2 9 2 5 8. .× =

2 9 4 11 6. .× =

1200 3 400÷ =

400 2 800× =23 of 1200 litres =

45 of 1000 litres

7.50 cm

£19.40

2

112

112

114

78

312

11

12

1



11111 Solve the problems in your exercise book. Write the answers here.

a) Sarah cut 2 m 10 cm from a 3.3 m piece of lace to trim a cushion.How much lace did she have left?

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

b) Jim bought 5 litres of plant food. He used 2 litres 70 cl on his vegetablesand 1.2 litres on the other plants in his garden.How much plant food did he have left?

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

How can the butterfly get to the flower? Calculate the length of the possibleroutes.

Three boys are giving each other clues about their heights. How tall is each boy?

Adam says, "My height is two thirds of 180 cm." A: . . . . . . . . . . . . . . . . .

Billy says, "My height is eight tenths of 160 cm." B: . . . . . . . . . . . . . . . . .

Chris says, "Three fifths of my height is 72 cm." C: . . . . . . . . . . . . . . . . .

Work out the rule andfill in the missingnumbers.

22222

7

5

6 25

5 35

8 45

4 25

3 45

15

65

8 45

3

10.3 m

11 m 9.1 m

8 m 50 cm

220 cm

410

33333

44444

1 m 20 cm = 1.2 m

1.1 litres

120 cm

128 cm

120 cm

Rule:

outer + inner = centre

535

735

315

145

425

225

0

(or = 845 )

1. 10.3 m+ 8.5 m

18.8 m

2. 10.3 m+ 9.1 m

2.2 m21.6 m

3. 11.4 m+ 2.2 m

8.5 m22.1 m

4. 11.4 m+ 9.1 m

20.5 m



11111

Change the quantities.

a) 40 cm = mm b) 30 mm = cm

508 cm = mm 8060 mm = cm = m cm

70 m = cm 7800 cm = m

68 m = cm 520 cm = m cm = mm

Change the quantities.

a) 73 litres = cl b) 40 ml = cl

57 cl = ml 93 ml = cl ml = cl

6.2 kg = g 1800 g = kg g = kg

5.8 litres = cl 450 cl = litres cl = litres


Work out the rule and fill in the missing numbers.

Solve the problem in your exercise book.

Uncle Jim earned £2400 in February. He spent one fifth of it on food, onesixth on bills and one quarter on his garden. How much did he have left?

22222

33333

400 3

5080 806 8 6

7000 78

6800 5 20 5200

7300 4

570 9 3 9.3

6200 1 800 1.8

580 4 50 4.5

3050

26 13

12

+

29 18 +

82 –

75.2 + 5.2

78 25 –

34 13

– 27 12

– 14

96 –2113

2078

6023

4412

2825

15.6

58

44444

a) b)22.7 14.8 11.2 8.7

2.57.987.9 55.5 33.3 12.1

21.222.2

55555

3.6 32.4

4.3 1.1 10.2 1

3.2 9.2

£2400– £1480

£920 He had £920 left.

80.4

16 part £2400 6 = £400

15 part £2400 5 = £480 1

4 part £2400 4 = £600

£480£400

+ £600£1480



11111

22222

b)

+

+ 0.75

+

+

+

+ 1.2

+ 2.28+

0.8

1.45

0.25

1.5

0.5

1

a)

+

+

141

+

+

+

+ 12

+

1 12

+ 14

12

2 14

2 14

3

1 12

33333

44444

Plan, estimate, calculate and check in your exercise book. Write the answer here.

a) Alice spent £3.27, Barry spent £4.17 and Chris spent £5.82on their meals. How much was the bill altogether? . . . . . . . . . . . .

b) Dan mowed 3

10 of the grass and Erica mowed

15

of it.

i) What fraction of the grass did they mow altogether? . . . . . . . . . . .

ii) What fraction of the grass still has to be cut? . . . . . . . . . . .

c) Jill bought 2.5 kg of apples and half a kg more of pears.

i) How many kg of pears did she buy? . . . . . . . . . . .

ii) How much fruit did she buy altogether? . . . . . . . . . . .


Which quantity is greater? Fill in the missing signs.

a)3

10 m 54 cm b) 0.9 kg 90 g c)

16

hour 30 min

d) £150 20 p £150.2 e) 5 7

100 litres 5 litres 700 ml

f) 412

weeks 29 days g) 84.3 cm 843 mm 8.43 m

Draw a digram to help you solve the problem.

Jack wants to cut a 1.2 m length of wood into two piecesso that one piece is three times as long as the other piece.

What will be the length of each piece? Give your answer in cm

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

£13.26

12

12

3 kg

5.5 kg

< > <

= <

> = <

Short piece = 30 cm; long piece = 90 cm

14

34

1.2 m = 120 cm120 cm 4 = 30 cm3 30cm = 90 cm

..

234

1 34

2 12

2

1

34

1

34

1.45

2.53 1.25

1

1.2 1.25

0.25

0.55



Measure, count or calculate the perimeter and area of the polygons.

.

The sides of a triangular lake are 2400 m, 1350 m and2130 m long. What is the length of its perimeter?

Plan: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

Wite a plan, estimate, calculate and write the answer.

a) A practice book is 29.7 cm long and 20.8 cm wide.How long is its perimeter?

Plan: . . . . . . . . . . . . . . . . . . . . . . . . . C:

E: . . . . . . . . . . . . . . . . . . . . . . . . . . .

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

b) George's room is four and two fifths metres long and three and a half metreswide. How long is its perimeter?

Plan: . . . . . . . . . . . . . . . . . . . . . . . . . C:

E: . . . . . . . . . . . . . . . . . . . . . . . . . . .

Answer: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

Calculate the area and the perimeter of this rectangle.

P = . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

A = . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

How can the fishing lake be enlarged to twice itsarea without moving the 4 oak trees?

11111

22222

2400 m2130 m

1350 m

33333

A B

CD

2.4 cm

0.9 cm

44444

55555

24 30 20

a)

A =

P =

b)

P =

A =

c)

A =

P =P =

7 5 2 4 +7 4= 35 = 36 15

2400 m + 1350 m + 2130 m

5880 m

(l + w) 2

(30 + 21) cm 2 = 51 cm 2 102 cm

101 cm

2 9 . 7 5 0 . 52 0 . 8 2

5 0 . 5 1 0 1 . 0

(425 + 3 5

10 ) 2

(4 + 4) m 2 = 8 m 2 = 16 m

15.8 m

4.4 m 7.9 + 3.5 m 2

7.9 m 15.8 m

2 (0.9 + 2.4) cm = 2 3.3 cm = 6.6 cm

0.9 2.4 cm2 = 2.16 cm2

The lake can be expanded out.



11111

The unit of area is 1 cm2. The unit of length is 1 cm.

Continue the sequence and complete the table. Write the rule in different ways.

Ten pupils measured their heights and wrote them down in various ways.

A = 1.3 m, B = 1 m 35 cm, C = 134 cm, D = 1350 mm, E = 1 m 340 mm

F = 1 34

100 m, G = 140 cm, H = 1 m 36 cm, I = 1 m 400 mm, J = 1.34 m

a) Show the data inthis tally chart.

b) Write the data in decreasing order.

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

c) Which height is the most frequent? This is the mode. . . . . . . . . . . . . . . .

d) Which are the middle data? . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

1 cm

1 cm

1 cm2

a

b

P

A

1 1 1 1 1 1 1 1 1 1 1 1

0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9

2.2 2.4

0.1 0.2

P = a = b =b = A =

22222

130 131 132 133 134 135 136 137 138 139 140 cm

33333 3 8 1

68 3 9

40 9 2

2

a) 4 1 766+ 024+ 0–

655 –

3 4 54

25+ 67

2 9 34

6 4 38

0 8 25

b) 7 860+ 57+ 0–

532 –

8 3 46

75– 812

54

44444 3 6 4

7 ×5 5 5

6 ×

b)

8 4 84

a) 2 1 3 3 × 2 0 2 × 41

9 0 33 6 3 6 46 2 8 8 87

1 1.1 1.2

2.6 2.8 3.0 3.2 3.4 3.6 3.8 4.0 4.2 4.4

0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1.2

2 (a + b) P2 – b P

2 – a a b

IIII II I II

140 cm, 140 cm, 136 cm, 135 cm, 135 cm, 134 cm, 134 cm, 134 cm, 134 cm, 130 cm

134 cm

135 cm and 134 cm

4 8 3 4 5 8 7 3 3 5 6 0 4 0 9 9 9 9

2 8 4 6 0 4 7 4 3 5 4 6 4 7 5 9 7 8

6 3 9 8 0 8 42 5 4 8 3 3 3 0

2 1 2 3 0 1 2 6 0 7 1 2 6 r 6



11111

Write true statements about each diagram in your exercise book.


Fill in the next nearest:

These were the fruit that 20 children in a class brought for their lunch.

Tally

a) What fraction of the fruit were apples? . . . . . . . . . . . . . . . . . . .

b) What fraction of the fruit were oranges? . . . . . . . . . . . . . . . . . . .

c) What fraction of the fruit were bananas? . . . . . . . . . . . . . . . . . . .

d) Which was the most popular fruit? . . . . . . . . . . . . . . . . . . .

a) b)

1

c)

1 1

22222

a) 9000

4000 +

3900 +

+ 850

+ 67

1 +

12

5.6 +

12 +

3

+ 11

b)

15 +

23

c) 16

8

1

3

0.5

×

4 ×

×

÷

×

tens

5420

657

43.2

<

<

<

<

<

<

units

5420

657

43.2

<

<

<

<

<

103 << 78

a) tenths

5420

657

43.2

<

<

<

<

<

<

2.93 <<103 << 78

<

b) c)

33333

44444

620 =

310 6

12 = 12

516 = 10

32

5000 6.4 2

5100 0 4

8150 16

8933 48

8999 3213

845

5410 5430 5419 5421 5419.9 5420.1

650 660 656 658 656.9 657.1

40 50 43 44 43.1 43.3

100 110 103 104 2.9 3.0

IIII IIII 10

IIII I 6

IIII 4

201020 =

12

620 =

310

420 =

15

Apples

E.g:



11111

Length of 1 edge

Area of cube

Volume of cube

1 2 3 4 5 6

22222

a b c A V

a

b

c

33333

Imagine these cubes built from unit cubes.Fill in the missing numbers.

Imagine the cuboid which has this net. Calculate its surface area and volume.

Complete the table.

The pie chart shows which part ofthe class chose which game to play.

a) Write each part as a fraction. B: . . . . . . F: . . . . . . T: . . . . . .

b) How many children chose each gameif there were 24 pupils in the class? B: . . . . . . F: . . . . . . T: . . . . . .

Solve the equations.

Basketball

Football

Tennis

44444

a) + = 11337

+ = 67

+ = 129

b)

+ 0.6 = 1

+ 820 = 1000

2.3 + = 4

i) ii) iii)

iv) v) vi)

– = 27i) ii) – 820 = 1000 iii) 89

– = 29

iv) v) vi) – 0.6 = 0.44.3 – = 3.1– =13

13

6 24 54 96 150 216

1 8 27 64 125 216

3 5 2 62 30

58

28

18

15 6 3

8 18037

79 1.7 0.4

5 182069

23 1.2 1



11111

Calculate the area and perimeter of each polygon.

a) Calculate the area and perimeter of this rectangle.

P = . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

A = . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

b) What is the length of the side of a square whichhas a perimeter equal to this rectangle? . . . . . . . . . . . . . . . .

The pie chart shows the favourite colours of the32 pupils in a class.

a) What fraction of the class chose each colour?

Red: Blue: Yellow: Green:

b) How many pupilschose each colour? R: . . . . . . B: . . . . . . Y: . . . . . . G: . . . . . .

Solve the equations.

a) i) 5 + = 6.5 ii) + 3.9 = 5.7 iii) + 14

= 54

iv) + 27

= 1 v) 4.7 + = 6.3 vi) + 0.7 = 1

b) i) 6 – = 4.5 ii) – 2.3 = 4.9 iii) 57

– = 27

iv) – 15

= 45

v) 4.7 – = 3.9 vi) – 0.3 = 0.7

Join up theequal values.

a)

A =

P =

b)

P =

A =c)

A =

P =P =

22222

2.2 cm

8 cm

33333

55555

1 – 0.2

1.5

2.3

0.6452

310

610

1 and a half

34

0.75

44444

Y

BR

G

25

20 32 20

28

13

2 (2.2 + 8) cm = 10.2 cm 2 = 20.4 cm

(2.2 8) cm = 17.6 cm

20.4 cm 4 = 5.1 cm

18

18

48

= 12

28

= 14

4 4 16 8

1.5 1.8 1

1.6 0.3

1.5 7.2

1 0.8 1

57

37

2

MEP PB4b-Ans 81-110 - CIMT

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Transcript of MEP PB4b-Ans 81-110 - CIMT