MECH4301 2008 Lecture 6 (1/3) Shape Factors 1/23 Material and Shape: Textbook Chapters 11 and 12...
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Transcript of MECH4301 2008 Lecture 6 (1/3) Shape Factors 1/23 Material and Shape: Textbook Chapters 11 and 12...
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 1/23
Material and Shape:
Textbook Chapters 11 and 12
Lecture 6 (1/3)
Efficient?
Materials for efficient structuresTute # 3, 6 exercises, 3 afternoons to solve
them. Read the instructions (BB) carefully. Due Mo
Sept. 15, 4:00 pm
MECH4301 2008 Materials Selection in Mechanical Design
Laboratory Group II: Meet on Friday Au 29, 8 am, room 413, Bldng 43.
“Efficient” = use least amount of
material for given stiffness
or strength.
To create a deformation work-stress chart for foams, use (densification strain * yield strength) as y-axis and yield strength as x-axis.) See Announcement in Bb.
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 2/23
Shape and mechanical efficiency
• Section shape becomes important when materials are loaded in bending, in torsion, or are used as slender columns.
• Examples of “Shape”:
• Shapes to which a material can be formed are limited by the material itself.
Shapes from: http://www.efunda.com/math/areas/RolledSteelBeamsS.cfm
Is shape important for
tie rods?
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 3/23
Shape and mode of loadingStandard structural members
Loading: tension/compression
Area A and shape IXX, IYY matter
Area A and shape J matter
Area A and shape Imin matter
Area A matters,not shape
Loading: bending
Loading: torsion
Loading: axial compression
Certain materials can be made to certain shapes: what is the best material/shape combination (for each loading mode)?
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 4/23
Shape efficiency: bending stiffness pp. 289-290
1212
24
oo
AbI
b
b
Area A is constant
Area Ao = b2
modulus E unchanged
Neutral reference section
Shaped sections
Define a standard reference section: a solid square, area A = b2
30
L
IECSo
3
L
IECS
31
L
EICFS
Moments of Sections; p 477
12
3bhI
221212
AAE
E
S
S
oooo
e
IIII
II
Ao = A
Define shape factor for elastic bending,
measuring efficiency, as
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 5/23
A shaped beam of shape factor for elastic bending, e = 10, is 10 times stiffer than a solid square section
beam of similar cross section area.
212
AE
E
S
S
ooo
e
III
II
bending stiffness
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 6/23
I-sections
Properties of the shape factor The shape factor is dimensionless -- a pure number.
It characterises shape, regardless of size.
Circular tubes
10e
10e
These sections are φe times stiffer in bending than a solid square section of the same cross-sectional area
Increasing size at constant shape = constant SF
Rectangular Sections e = 2
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 7/23
Define a standard reference section: a solid square, area A = b2
Shape efficiency: bending strength p. 294/5
66
2/3
0
3 Ab
y
IZ
m
o
o
** Zy
IM
mf
maxy
ZI
b
b
Area A is constant
Area A = b2
yield strength unchanged
*
Neutral reference section
Moments of Sections; p 477
my
IZ ,modulussection
• Define shape factor for the onset of plasticity (failure),
measuring efficiency, as
** Zy
IM
m
f
*
0
*0
0 Z
y
IM
m
f
2/3*
*
6A
Z
Z
Z
Z
Z
M
M
oofo
ff
A = Ao
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 8/23
A shaped beam of shape factor for bending strength, f = 10, is 10 times stronger than a solid square section
beam of similar cross section area.
2/3*
*
6A
Z
Z
Z
Z
Z
M
M
oofo
ff
bending strength
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 9/23
Section shape Area Am
Secondmoment I, m4
Elastic shapefactor
bh12
hb 3b
h
ab ba4
3b
a3
tr2
)rr( 2i
2o
tr
)rr(4
3
4i
4o
)tr(
t
r3
)tb,h(
)bh(t2
)
h
b31(th
6
1 3 tb,h(
)h/b1(
)h/b31(
t
h
2
12
)tb,h(
tb2
)hh(b io
2o
3i
3o
htb2
1
)hh(12
b
)tb,h(
tb
h
2
3 2o
)tb,h(
)bh(t2
)
h
b31(th
6
1 3
)tb,h(
)h/b1(
)h/b31(
t
h
2
12
h
t
2t
b
h
b
t
2a
2b
h
b
b
t
hohi
2ro2ri
t
Tabulation of shape factors (elastic bending) p. 292/3
t
r
t
r
rt
tr
Ao
e
3
)2(1212
2
3
2 I
II
b
h
hb
bh
Ao
e
22
3
2
1
121212
III
A2 = Ao2
Second moment of section, I
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 10/23
Comparison of shapes done so far at constant material (E, y) and given cross section area, A
How to compare different materials and different shapes at:
Constant structural stiffness, S ?
Constant failure moment, Mf ?
Material substitution at constant stiffness or strength allowing for differences in shape
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 11/23
L
mA
A
Ae
o
e
12 I 12
I
I 2
2
I
m = massA = areaL = length = densityb = edge lengthS = stiffnessI = second moment of areaE = Youngs Modulus
Beam (shaped section).
Bending stiffness of the beam S:
Trick to bring the Shape Factor in ?
Eliminating A from the eq. for the mass gives:
3L
IECS
2/1
2/1512
EC
LSm
e
LAm
Chose materials with largest
2/1Ee
Minimise mass, m, where:
Function
Objective
ConstraintL
FArea A
Shape factor part of the material index
Indices that include shape (1): minimise mass at constant stiffness p. 310
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 12/23
Indices that include shape (2): minimise mass at constant strength p . 311
L
mA
A
Af
of
6 Z
Z6
Z
Z2/3
2/3
m = massA = areaL = length = densityMf = bending strengthI = second moment of areaE = Youngs ModulusZ = section modulus
Beam (shaped section).
Bending strength of the beam Mf:
Trick to bring the Shape Factor in ?
Eliminating A from the equation for m gives:
** Zy
IM
mf
3/2*
3/26
f
f LMm
LAm
Chose materials with largest
3/2*f
Minimise mass, m, where:
Function
Objective
ConstraintL
FArea A
Shape factor part of the material index
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 13/23
From Lecture 4: Demystifying Material Indices (elastic bending)
2/11
1
2/15
1
12
EC
LSm
2/12
2
2/15
2
12
EC
LSm
2
1
1
2/11
2/12
2
1
2
M
ME
Em
m
For given shape, the reduction in mass at constant bending stiffness
is determined by the ratio of material indices.
Same conclusion applies to bending strength.
Unshaped mass, Material 1
Unshaped mass Material 2
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 14/23
Demystifying Shape Factors (elastic bending)
2/1
1
1
2/1512
EC
LSmo
2/1
1
1
2/1512
EC
LSm
e
s
2/11
2/11
2/11
1 1
)(
E
Em
m
o
s
Shaping (material fixed) at constant bending stiffness
reduces the mass of the component in proportion to e
-1/2 .
Optimum approach: simultaneously maximise
both M and .
Unshaped mass
Shaped mass, same material, same S
Q: Is the cross section area constant when going
from mo to ms?
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 15/23
Demystifying Shape Factors (failure of beams)
3/2*
3/26
LMm fo 3/2*
3/26
f
fs LMm
3/23/2*
3/2* 1
ffo
s
m
m
Unshaped mass
Shaped mass, same material, same Mf
Shaping (material fixed) at constant bending strength
reduces the mass of the component in proportion to f
-
2/3.Optimum approach:
simultaneously maximise both M and .
EXAM QUESTION: Is the cross section area constant when going
from mo to ms?
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 16/23
Material , Mg/m3 E, GPa e,max
1020 Steel 7.85 205 65 1.8 14.7
6061 Al 2.70 70 44 3.1 20.4
GFRP 1.75 28 39 2.9 18.9
Wood (oak) 0.9 13 8 4 11.4
/2/1E /ρE 1/2maxe,
Practical examples of material-shape combinations
/2/1E
• Materials for stiff beams of minimum weight
• Fixed shape (e fixed): choose materials with greatest
• Shape e a variable: choose materials with greatest
Same shape for all (up to e = 8): wood is best
Maximum shape factor (e = e,max): Al-alloy is best
Steel recovers some performance through high e,max
/ρE 1/2maxe,
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 17/23Density (typical) (Mg/m^3)
0.01 0.1 1 10
Yo
un
g's
Mo
du
lus
(typ
ica
l) (
GP
a)
1e-004
1e-003
0.01
0.1
1
10
100
1000
Concrete
Titanium
Cork
PP
Flexible Polymer Foams
Rigid Polymer Foams
Tungsten Carbides
Steels Nickel alloys
Copper alloys
Zinc alloys
Lead alloys
Silicon CarbideAluminaBoron Carbide
Silicon
Al alloys
Mg alloys
CFRP
GFRPBamboo
Wood
Plywood PET
PTFE
PE
PUR PVC
EVA
Silicone
Polyurethane
Neoprene
Butyl Rubber
Polyisoprene
CE
2/1
Note that new material with
Shape on selection charts: stiffness p. 312/3
Al: e = 44
Al: e = 1
Density (Mg/m3)
You
ng’s
mod
ulus
(G
Pa)
e
e
e
e
e
e EE
E
/
/
/
2/1
2/1
2/1
e
s /
es EE /
Material substitution at constant stiffness or strength allowing for differences in shape
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 18/23
Shape on selection charts: stiffness p. 314
Density (Mg/m^3)0.1 1 10
Yo
un
g's
Mo
du
lus
(GP
a)
1
10
100
1000
Al Sf=44
Bamboo SF=1
Steel SF = 65
Bamboo SF =5.6
steel SF=1
Al SF =1
Drag the labels along lines of slope 1
Selection line of slope 2
Unshaped Steel SF =1
Unshaped Aluminium
Unshaped Bamboo SF= 1
Shaped aluminium SF = 44
Shaping makes Steel competitive with Al and Bamboo
Shaped Bamboo SF=5.6
Shaped steel SF=65
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 19/23
Note that new material with
2
3/22*
2
2
3/2*
3/2*
/
/
/f
f
f
f
f
f
2** / f
s 2/ f
s
Shape on selection charts: strength p. 314
3/2*
100 2 fsteel
1 2 fsteel
Material substitution at constant stiffness or strength allowing for differences in shape
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 20/23
Shape on selection charts: strength p. 314
Density (Mg/m^3)0.01 0.1 1 10
Te
nsi
le S
tre
ng
th (
MP
a)
10
100
1000
Bamboo SF =1
Al 2024, SF=10 SF^2=100
steels SF=7 SF^2=49
bamboo SF = 2 SF^2=4
steel SF =1
Al Sf =1
selection line slope 1.5Selection line of slope 1.5
Shaped Steel SF=7; (SF)2=49
Shaped Bamboo SF=2 (SF)2=4
Shaping makes Steel competitive with Al and Bamboo
Shaped Aluminium SF=10; (SF)2=100
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 21/23
Shaping at constant cross section A increases the bending stiffness or strength by at constant mass. This stems from the definition of shape factor e = S/So= I/Io f = M/Mo = Z/Zo
Dragging the labels in the CES charts is equivalent to shaping at constant bending stiffness or strength, so the mass is reduced by 1/e
1/2 (stiffness) or
by 1/f2/3 (strength).
Exam question: (to get everybody confused!)
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 22/23
Examples of indices including shape p. 318
Same as elastic bending
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 23/23
This afternoon: solve Exercises E8.1, 8.8, 8.9 and 8.12.
Leave 8.6 / 8.7 for next sessions.
-Tutorial 3 (E8. Materials and Shape) (6 Exercises). Solve in this order: E8.1; E8.8; E8.9; E8.12; (solve either E8.6 or E8.7) (see
hints and instructions in BB). Exercise #6 for Tute 3: Show that the shape factors of Table 12.5 (p.
325) are a factor 4/3 = 1.33 too large.
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 24/23
Example using CES: dragging labels
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 25/23
End of Lecture 6
two more lectures re. shape factors to follow
MECH4301 2008 Lecture 6 (1/3) Shape
Factors 26/23
Shape factors for twisting and buckling
2T2
0o
T
A
K14.7 14.0K
K
K
S
S A
ToT
3/2A
Q8.4
Q
Q
ofT
Failure under torsion p. 296
Buckling p. 296
212
AE
E
S
S
ooe
III
Same as elastic bending
Elastic twisting p. 294Moments of Sections; p 477Moments of Sections; p 477