Measuring Evolution within Populations. 5 agents of evolutionary change Mutation Gene Flow Genetic...
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![Page 1: Measuring Evolution within Populations. 5 agents of evolutionary change Mutation Gene Flow Genetic Drift Selection Non-random mating MigrationSexual Selection.](https://reader035.fdocuments.in/reader035/viewer/2022062322/5697c01f1a28abf838cd1a30/html5/thumbnails/1.jpg)
Measuring Evolution within Populations
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5 agents of evolutionary changeMutation Gene Flow
Genetic Drift Selection
Non-random mating
Migration Sexual Selection
Small population
ChemicalChanges to DNA
Natural SelectionDifferential Survival
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Hardy-Weinberg Equilibrium Hypothetical situation
◦ Serves as a null hypothesis
A non-evolving population◦ Remove all agents of evolutionary change◦ 1. No genetic drift (a very large population)◦ 2. No gene flow (no migration in or out)◦ 3. No mutation (no chemical change to DNA)◦ 4. Random mating (no sexual selection)◦ 5. No natural selection (equal survival)
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Hardy-Weinberg Equations If the previous conditions are met, then … p2 + 2pq + q2 = 1 p + q = 1
p = frequency of dominant allele (B) q = frequency of recessive allele (b) p2 = % of homozygous dominant individuals (BB) q2 = % of homozygous recessive individuals (bb) 2pq = % of heterozygous individuals (Bb)
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Hardy-Weinberg Equations p2 + 2pq + q2 = 1 p + q = 1 Cystic fibrosis is a recessive condition (cc) that affects 1 in 2,500 babies in the Caucasion population in the U.S. What is the frequency of the recessive allele? q2 = 1/2500 = 0.0004 q = √0.0004 = 0.02 (or 2%)
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Hardy-Weinberg Equations p2 + 2pq + q2 = 1 p + q = 1 Cystic fibrosis is a recessive condition (cc) that affects 1 in 2,500 babies in the Caucasion population in the U.S. What is the frequency of the dominant allele? p = 1 - q p = 1 - 0.02 = .98 (or 98%)
![Page 7: Measuring Evolution within Populations. 5 agents of evolutionary change Mutation Gene Flow Genetic Drift Selection Non-random mating MigrationSexual Selection.](https://reader035.fdocuments.in/reader035/viewer/2022062322/5697c01f1a28abf838cd1a30/html5/thumbnails/7.jpg)
Hardy-Weinberg Equations p2 + 2pq + q2 = 1 p + q = 1 Cystic fibrosis is a recessive condition (cc) that affects 1 in 2,500 babies in the Caucasion population in the U.S. What is the percentage of heterozygotes in the population? 2pq = 2(.98)(.02) = 0.04 (or 4% … or 1 in 25)
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Example of strong selective pressure Tay Sachs
◦ Primarily in Ashkenazi Jews and Cajuns◦ Recessive disease = aa◦ Lysosomal storage disease
◦ Lack of 1 functional digestive enzyme in lysosome
◦ Build up undigested fat in brain cells◦ Children die before the age of 5
So where do new cases of Tay-Sachs come from?
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Example of heterozygote advanage
Sickle Cell Anemia◦ Inherit a mutation in gene coding for one of the subunits in
hemoglobin◦ Oxygen-carrying blood protein◦ Normal allele = Hb
◦ Sickle allele = Hs
◦ Recessive trait = HsHs
◦ Low oxygen levels cause RBC to sickle◦ Clogs small blood vessels◦ Damages organs
◦ Often lethal
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Sickle Cell Frequency High frequency of heterozygotes 1 in 5 in Central Africans = HbHs
Unusual for individuals with homozygous recessive genotype◦ 1 in 100 = HsHs
◦ Usually die before reproductive ageWhy is the Hs allele maintained at such high levels
in African populations?
Suggests some selective advantage of being heterozygous… HbHs
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Malaria Single-celled eukaryote parasite (Plasmodium) spends part of its
life cycle in red blood cells
Single-celled eukaryote parasite (Plasmodium) spends part of its
life cycle in red blood cells
1
2
3
liver
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Heterozygote advantage In tropical Africa where malaria is common:
◦ Homozygous dominant (normal)◦ Reduced survival or reproduction due to malaria (HbHb)
◦ Homozygous recessive◦ Reduced survival or reproduction
due to sickle cell disease (HsHs)◦ Heterozygote carriers
◦ Survival & reproductive advantage (HbHs)