Measure Theory Notes
Transcript of Measure Theory Notes
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1 Measure Theory
Definition 1.1. (Measure). Let be a set andA a -algebra of subsets of. The pair (, A) is call a measurable space. A set function onAis called ameasure if is an extended real-valued function satisfying
(1) (A) 0 for all A A(2) () = 0(3) IfA1, A2,... are disjoint sets inA, then
n
An
=n
(An).
The triple (, A, ) is called a measure space.Theorem 1.1. Properties of Measure). Let (, A, ) be a measure spaceand letA, B beA-measurable sets. Then:(a) If(A)< and A B, then (B A) = (B) (A)(b) Monontonicity: A B (A) (B).(c) Countable Subadditivity: if{An}n=1 A, then
n
An
n
(An)
(d) If{An}n=1 Awith A1 A2... and (Ak)< for somek , then
n=1
An
= lim
n(An).
(e) If{An}n=1 Awith A1 A2..., then
n=1
An
= lim
n(An).
Corollary 1.2. More Properties of Measure). Let (, A, ) be a measurespace and
{An
}
n=1
A. Then
(i) (lim infn An) lim infn (An)(ii) (lim supn An) lim supn (An), as long as (
n=kAn)
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Theorem 1.3. (Linear Combinations of Measures). Let (, A) be a mea-surable space,
{n
}n=1a sequaence of measures on
A, and
{n
}n=1a sequence
of nonnegative real numbers. Then if we define
n=1 nn onAbyn=1
nn
(A) =
n=1
nn(A),
then we have defined a new measure onA.Definition 1.2. (Complete Measure Space). A measure space (, A, ) issaid to be completeif, for everyA-measurable setA with (A) = 0,
B A B A.Every measure space can be extended to a complete measure space.
Theorem 1.4. (Completion of a Measure Space). If (, A, ) is a measurespace,
2 Measurable Functions
2.1 Real and Complex valued Functions
Definition 2.1. (Measurable Function). Let (, A) be a measurable space,the function f : Ris said to be anA-measurable function if
f1(O) A, for every open setO R.A complex valued function g :
Cis said to be an
A-measurable function if
both its real part, [g], and its imaginary part, [g], are A-measurable functions.Theorem 2.1. (Measurability). Let (, A) be a measurable space and f : Ra real-valued function. The following are equivalent:(a) f isA-measurable.(b) For eacha R, f1((, a)) A(c) For eacha R, f1((, a]) A(d) For eacha R, f1((a, )) A(e) For eacha R, f1([a, )) ATheorem 2.2. (Measurable Functions Form an Algebra). Let (, A) bea measurable space. The collection of real-valuedA-measurable functions on forms an algebra. That is, if f, g : R areA-measurable functions, and R, then(1) f+ g isA-measurable
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(2) f isA-measurable
(3) f g isA-measurableThis also holds for complex valued functions.
Theorem 2.3. (More Properties of Measurable Functions). Let (, A)be a measurable space and f : RanA-measurable function. Then:
(i) Ifg : R Ris a Borel measurable function, then g f isA-measurable.(ii) f+, f and|f| :=f+ + f areA-measurable.
2.2 Extended Real-valued Functions
see p.179 in Mcdonald.
Theorem 2.4. (More Properties). Let (, A) be a measurable space. Letf, g : R be extended real-valuedA-measurable functions, and{fn}n=1 asequence of extended real-valuedA-measurable functions, fi: R. Then:
(i) f g andf g areA-measurable.(ii)|f| :=f f isA-measurable.
(iii) supn fn and infn fn areA-measurable.(iv) lim supn and lim infn areA-measurable.(v) If{fn}n=1 converges pointwise, then limn fn isA-measurable.
(vi) If (,A
, ) is a complete measure space,{
fn}
n=1 a sequence of extended
real-valued or complex real-valuedA-measurable functions, and fn f-almost everywhere, then f isA-measurable.
Theorem 2.5. (Egorovs Theorem). Let (, A, ) be a measure space, andlet E Abe a set with (E) 0,there is a measurable set A Esuch that
(E A)< and fn funiformly onA
2.3 Approximation with Simple Functions
Recall that the indicator function (or characteristic function) IEof a set E isgiven by
IE=
1 ifx E0 ifx =E
Note that IEis measurable if and only ifE is measurable.
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Definition 2.2. (Simple Function). Asimple functionfis a function whichassumes a finite number of finite values. When fis simple, it has the represen-
tation
f(x) =Nk=1
akIEk(x),
wherea1,...,aNare the distinct values taken by fon the disjoint sets E1,...,EN.Note thatfis measurable iff each Ek is measurable.
Theorem 2.6. (Approximation by Simple Functions).
(i) Any (measurable) function f 0 can be represented as the limit of anincreasing sequence of (measurable) simple functions. One such represen-tation is given by:
fk(x) = j2k if j2k
f(x)< j+12k
, j = 0,...,k2k
1
k iff(x) kwherefk(x)f(x) as k . Note that we can also write each simplefunctionfk(x) as
fk(x) =Kj=0
j
2kIf[ j
2k, j+12k
)(x) + kIfk(x)
whereK:= k2k 1(ii) Any (measurable) functionfcan be represented as the limit of a sequence
of (measurable) simple functions. In particular, apply the previous resultto approximate f+ and f respectively by increasing simple functions,
and then:f+k (x) fk (x) f+(x) f(x) = f(x)
3 Convergence of Functions
For all that follows, let (, A, ) be a measure space. Let {fn}n=1be a sequenceof (complex-valued) measurable functions on E A.Theorem 3.1. (The Set of Convergence). If{fn} is a sequence of functions,the set on which convergence occurs is characterized by
{x : limn
fn(x) = f(x)} =
m=1
n=1
k=n
x: |f(x) fk(x)| < 1
m=
m=1
liminfn
x: |f(x) fn(x)| < 1
m
= limm
liminfn
x: |f(x) fn(x)| < 1
m
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Definition 3.1. (Uniform Convergence).{fn} converges uniformlytofon if
limn
supx
{|fn(x) f(x)|}
= 0.
That is, fn funiformly on if for all >0,N such thatsupx
{|fn(x) f(x)|} , n N.
4 Abstract Lebesgue Integral
4.1 Integral of Nonnegative Functions
4.1.1 Convegence of Integrals of Nonnegative Functions
Theorem 4.1. (Monotone Convergence Theorem). Suppose 0 fn fae onE. Then for each E A, Efnd Ef d.Corollary 4.2. Let f,g, {fn}n=1 0 be extended real-valuedA-measurablefunctions and letE A. Then
(i)E(f+ g)d=
E
f d +E
gd
(ii)E
n=1 fnd=
n=1
E
fnd
(iii) If{E}n=1 A are pairwise disjoint and E :=
n=1 En, thenE
f d =n=1
En
f d.
(iv) If{E}n=1 A is an increasing sequence of sets, En E:=n=1 En, and
iff
0 is an extended real-valued
A-measurable function, then Ef d=
limnEn fd.
4.2 Integral of General Functions
Definition 4.1. (Integral of Extended Real-Valued Function). Let (, A, )be a measure space. Letfbe an extended real-valuedA-measurable functionon E A. Then the Lebesgue integral off overEwith respect to is definedby
E
f(x)d(x) =
E
f d:=
E
f+d E
fd,
as long as at least one of the integrals is finite (in which case the Lebesgueintegral is said to exist). If both integrals are finite,
Ef+d,
Efd
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Theorem 4.3. (Properties of Lebesgue Integrals). Let (, A, ) be ameasure space. Let f, g be extended real-valued
A-measurable functions on
E A.(i) f L1(E, ) |f| L1(E, ).
(ii)| Ef d| E |f|d(iii) If|f| |g| -ae in E, and if g L1(E, ), then f L1(E, ) and
E|f|d
E|g|d.
(iv) Iff L1(E, ), thenf is finite-ae inE.(v) Iff = g -ae in E and
E
f d exists, thenE
gd exists andE
f d =E
gd.
(vi) IfEf d exits and R, then Efd exists and Efd= Ef d.
(vii) Iff, g L1(E, ), then f+g L1(E, ) and E(f+g)d) = Ef d+Egd.
(viii) Iff 0 and m g Mae on E, then
m
E
fd E
fgd ME
f d
Theorem 4.4. (Tchebyshevs Inequality). For >0,
({x E: |f(x)| }) 1p
{f>}
fp
Proposition 4.1. (Contructing New Measures). Let (,A
, ) be a mea-sure space. Ifg : R+ is a nonnegativeA-measurable function, andE A,then the set function defined by
(E) :=
E
gd
is a measure onA. Moreover, iff isA-measurable, then
f d=
fgd.
Example 4.1. If denotes Lebesgue measure on (R, B(R)), then the standardnormal distribution can be written as
(E) =E
12 e
x2/2
(dx), E B(R),and for measurable fwe can compute
E
f(x)(dx) =
E
f(x) 1
2ex
2/2(dx)
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4.3 Complex Integrals
Whenf is complex-valued on , we have
|f| =
([f])2 + ([f])2.Proposition 4.2. Letfbe a complex-valued function on . Then:
(i)|f| | [f]| + |[f]|(ii)|[f]| |f| and|[f]| |f|
(iii) Iff isA-measurable, then so is|f|.(iv) LetE A. Then|f| L1(E) [f], [f] L1(E), in which case
E
f d= E
[f]d + iE
[f]d.
5 Convegence of Integrals
For all of the following theorems, let (, A, ) be a measure space. Let{fn}n=1be a sequence of (complex-valued) measurable functions on E A.Theorem 5.1. (Monotone Convergence Theorem).
(i) Suppose fnfae on E. IfL1(E, ) such that fn ae on E forall n, then
E
fnd E
f d.
(ii) Suppose fnfae on E. IfL1(E, ) such that fn ae on E forall n, then Efnd Ef d.
Theorem 5.2. (Fatous Lemma).
(i) If L1(E, ) such that fn ae on Efor all n, thenE
(lim infn
fn)d liminfn
E
fnd
Thus iffn fae on E,E
f d liminfn
E
fnd
(ii) If L1(E, ) such that fn ae on Efor all n, then
E
(limsupn fn)d limsupnE
fnd
Thus iffn fae on E,E
f d limsupn
E
fnd
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Theorem 5.3. (Dominated Convergence Theorem). If L1(E, )such that
|fn
| ae on Efor all n, then
(i) E
(lim infn
fn)d liminfn
E
fnd
limsupn
E
fnd E
(lim supn
fn)d
(ii) Thus iffn fae on E, then f L1(E, ) andE
fnd E
fd and limn
E
|fn f|d= 0.
There is a more general result that allows for a sequence of bounding func-tions.
Theorem 5.4. (Extended Dominated Convergence Theorem). Suppose
{n}, L1(E, ) such that|fn| n ae on Efor all n, such that n ae ,and
E
|n|d E
||d. Iffn fae on E, then f L1(E, ) andE
fnd E
f d and limn
E
|fn f|d= 0
Corollary 5.5. (Bounded Convergence Theorem). Suppose (E)
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Corollary 5.8. (Continuity). Suppose thatf L1(, ).
(i) Suppose {E}n=1 Ais an increasing sequence of sets, so thatEn E:=
n=1 En. Then E
fd= limn
En
fd.
(ii) Suppose{E}n=1 Ais a decreasing sequence of sets, so that En E:=n=1 En. Then
E
fd= limn
En
fd.
Corollary 5.9. Suppose that f L1(, ), and{E}n=1 A is a sequence ofpairwise disjoint sets, and E:=
n=1 En. Then
E
f d=
n=1
En
fd.
5.2 Some Approximation Corollaries
For all of the following theorems, let (, A, ) be a measure space.Corollary 5.10. Suppose that f L1(, ).
(i) fis finite ae in .
(ii) Continuity: 0, >0 such that (E)< E |f|d < .(iii) 0, there exists a bounded,A-measurable function g such that
|f g|d <
(iv) 0, there exists a simple,A-measurable function h such that
|f h|d <
Proof: see Athreya pg. 66.
5.3 Convegence in Measure
For all of the following theorems, let (,
A, ) be a measure space, and let
{fn}n=1 be a sequence of (complex-valued) measurable functions on E A.Definition 5.1. (Convergence in Measure). The sequence{fn} is said toconverge in measure to the measurable function f onE if, > 0,
limn
({x E: |f(x) fn(x)| }) = 0.
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This is denoted by fn f on E. In other words, fn f on E iff > 0,
N such that
({x E: |f(x) fn(x)| })< , n N.Definition 5.2. (Cauchy in Measure). The sequence{fn} is said to beCauchy in measure if, >0,
limn,m
({x E: |fm(x) fn(x)| }) = 0.
Proposition 5.1. (Convergent Implies Cauchy). If the sequence{fn} isconvergent in measure, then it is Cauchy in measure. On complete measurespaces, this is an iff.
Theorem 5.11. (Convergence in Measure Results). Suppose f,g, {fn}, {gn}are measurable onE A.
(i) Fix a R. Iffn f, ({x: fn(x)> a}) ({x: f(x)> a})(ii) Iffn
f andgn g, then (fn+ gn) (f+ g)(iii) If in addition(E)< , then fngn f g.(iv) If(E)< ,fn f,gn pw g, andg= 0 ae onE, thenfn/gn f/g.(v) Suppose fn
f and let g : C C be a continuous function. Theng fn g f . For example:
fn f, (fn)p fp
Note that fngn fg = (fn f)(gn g) + f(gn g) + g(fn f), a usefulidentity for proving results about products.
Theorem 5.12. (Connection with Convergence Almost Everywhere).Statements of convergence are understood to be onE A.
(i) First note thatfnae f iff > 0,
limn
k=n
{x E: |f(x) fk(x)| }
= 0.
(ii) Iffnae f, thenfn f(as long as (E)< ).
(iii) If fn f, then there exists a subsequence {fnj}j=1 on E satisfying
fnjae f asj . Even more specifically, there is a subsequence{fnk}
satisfying
{x E: |fnk(x) fnk+1(x)| 2k} 2k
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Theorem 5.13. (Fatous Lemma for Convergence in Measure). Supposethat
{fn
}n=1
0 is a sequence of (complex-valued)
A-measurable functions such
thatfn fon . Then for each E A,E
f d limn
E
fnd.
Theorem 5.14. (DCT for Convergence in Measure). Suppose that {fn}n=10 is a sequence of (complex-valued)A-measurable functions such thatfn fon . Suppose further that for someg L1(, ), g 0, we have|fn| g aefor every n. Then
E
f d= limn
E
fnd.
Thus, the Dominated Convergence Theorem still holds even when almosteverywhere convergence is replaced by convergence in measure. (See Mcdonaldpg. 205 for proof)
6 Lp Spaces and Convergence
6.1 Definitions
Let (, A, ) be a measure space. For 0< p < andE A, the classLp(E, )denotes the collection of measurable (complex-valued) functions f :E C forwhich
E |f|p < . In particular
Lp(E, ) :=
f :
E
|f|p <
, 0< p < .
We write
fp,E :=
E
|f|p 1
p
,
or in the typical case whereE ,
fp :=
|f|p 1
p
.
For simplicity, we often omit reference to the region of integration, since theresults stated will typically hold whether the integral is taken over the entiredomain , or over some subsetE A. In this case, we will still use the simplernotation
fp := |f|p1p
when the region of integration is either understood or is not a primary concern.To define L spaces, we introduce the following:
ess supEf:= inf{ R :({x E: f(x)> }) = 0},
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if a finite exists, otherwise if({x E : f(x) > }) > 0 for all R, letess supEf :=
. Thus,
ess supEf= inf{M [, ] :f(x) Mae inE}.We now write
f= f,E:= ess supE|f|.WhenF 0.
(i) Then
iixi
i
i ii(xi)
i
i
(ii) In particular, ifk
i=1 i = 1, then
i
ixi
i
i(xi).
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Proof: see Wheeden and Zygmund pg. 119.
Theorem 6.3. (Jensens Integral Inequality). Letf, g (, A, ) be finiteae on a set E A. Suppose that f g and g are integrable on E, g 0 andE
gd >0. Suppose : R Ris convex over an interval containing the rangef(E) off.
(i) Then
EfgdEgd
E(f)gd
Egd
(ii) In particular, ifE
gd = 1,
E
fgd
E
(f)gd.
Corollary 6.4. (Useful Inequalities). Fix an integer k 1.(i) Let a1,...,ak Rand 1,...,k 0 such that
ki=1 i = 1. Then
ki=1
iexp{ai} exp
ki=1
iai
(ii) Letb1,...,bk 0 and 1,...,k 0 such thatk
i=1 i= 1. Then
ki=1
ibiki=1
bii ,
and in particular
1
k
ki=1
bi
ki=1
bi
1k
(iii) For anya, b R, and 1 p < ,|a + b|p 2p1(|a|p + |b|p)
Proof: Follow from Jensens Inequality.
Theorem 6.5. (Holders Inequality). Let 1 < p
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Corollary 6.6. (Holders Inequality: p= 1, q=). Letf L1(, ),andg
L(, ). Then since
|f g
| |f
|g
ae, we have
f g1 |fg|d f1g.
Corollary 6.7. (Discrete Holders Inequality). Letk N. Leta1,...,akR, b1,...,bk R and c1,...,ck 0. If 1 < p 0 we have
E
|f fn|p 0 as n andE
|fn|p M, thenE
|f|p M.
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Proposition 6.3. Letf , {fn} Lp(), for some p >0.
(i) fn Lp
f f fnp 0.(ii) Iff fnp 0, thenfnp fp (convergence in Lp implies conver-
gence of the norms).
(iii) Suppose 1 p < . Iffnp fp andfn fae, thenf fnp 0(sofn
Lp f).
Proposition 6.4. Fix any 1p 0.The sequence{fn} is said to converge weakly tof if
fngd
fgd for all
g Lp.Proposition 6.5. Letf , {fn} Lp(), for some 1< p < . Iffnp M forall n, then
fngd
fgd for all g Lq, with 1/p + 1/q= 1.
Proposition 6.6. Letf , {fn} Lp(), for some 1 p . Iffn Lp
f, thenfn fweakly to f.
6.6 Hilbert Spaces
Proposition 6.7. (Parallelogram law for L2).
f+ g2 + f g2 = 2f2 + 2g2
Theorem 6.10. (Cauchy-Schwarz Inequality). Letf , g L2(, ). Then |f g|d
|f|2d
12
|g|2d 1
2
,
that is
f g
1
f
2
g
2.
Proof: Follows from Holders inequality with p = q= 2.
Proposition 6.8. Letf , {fn} L2(). Iffn converges weakly to f inL2, thatis if
fngd
fgdfor all g L2, and iffn2 f2, thenfn L
2 f. (Soweak convergence plus convergence of the norms implies convergence in L2).
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7 Product Spaces and Iterated Integrals
Theorem 7.1. (Minkowskis Integral Inequality). Let 1 p
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(i) IfTis injective and continuous, then T is openT1 is continuous fromT(X) toX.
(ii)
Theorem 9.1. (The Open Mapping Theorem) IfX, Yare Banach spaces,andT L(X, Y), then T(X) is a closed subspace ofY T is open.
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