ME- 495 Mechanical and Thermal Systems Lab Fall 2011

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ME- 495 Mechanical and Thermal Systems Lab Fall 2011 Chapter 5: MEASURING SYSTEM RESPONSE Professor: Sam Kassegne, PhD, PE

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ME- 495 Mechanical and Thermal Systems Lab Fall 2011. Chapter 5: MEASURING SYSTEM RESPONSE Professor: Sam Kassegne, PhD, PE. Signal. Response of Measurand?. RESPONSE. - PowerPoint PPT Presentation

Transcript of ME- 495 Mechanical and Thermal Systems Lab Fall 2011

Page 1: ME- 495 Mechanical and Thermal Systems Lab Fall 2011

ME- 495Mechanical and Thermal

Systems LabFall 2011

Chapter 5: MEASURING SYSTEM RESPONSE

Professor: Sam Kassegne, PhD, PE

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Signal

Response of Measurand?

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RESPONSE• System Response: an evaluation of the systems

ability to faithfully sense, transmit and present all pertinent information included in the measurand and exclude all else:

• Key response characteristics/components are:– Amplitude response– Frequency response– Phase response– Slew Rate

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COMPONENTS OF SYSTEM RESPONSE

1) Amplitude response: • ability to treat all input

amplitudes uniformly– Overdriving – exceeding

an amplifiers ability to maintain consistent proportional output

– Gain = Amplification = So/Si

– Smin<Si<Smax

Overloaded in this range.

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2) Frequency Response

• ability to measure all frequency components proportionally

• Attenuation: loss of signal frequencies over a specific range

Attenuated in this range.

COMPONENTS OF SYSTEM RESPONSE

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3) Phase Response

• amplifiers ability to maintain the phase relationships in a complex wave.

• This is usually important for complex waves unlike amplitude and frequency responses which are important for all types of input wave forms. Why?

COMPONENTS OF SYSTEM RESPONSE

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• 4) Delay/Rise time: time delay between start of step but before proper output magnitude is reached.

• Slew rate: maximum rate of change that the system can handle (de/dt) (i.e. for example 25 volts/microsecond)

COMPONENTS OF SYSTEM RESPONSE

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Dynamic Characteristics of Simplified Mechanical Systems

• F(t) = general excitation force = fundamental circular forcing frequency

n

n

2n

2n

1nnn

o

2

2

c

A

Btan

BACn

)tncos(C2

A)t(F

Ksdt

ds

dt

sdm

g

1)t(F

Generalized Equation of Motion for a Spring Mass Damper System(1-axis)

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(I)FIRST ORDER SYSTEM(I.A) Step Forced

If mass = 0, we get a first-order system.

E.g. Temperature sensing systems

• F(t)=0 for t<0

• F(t) = F0 for t >= 0– t=time, k=deflection constant– s=displacement, =damping coefficient

– Fo=amplitude of input force

• This can be reduced to the general form:

(after integration over time and simplification)– P=magnitude of any first order system at time t

– P=limiting magnitude of the process as t

– PA=initial magnitude of process at t=0

= time constant = /k

ksdt

ds)t(F

t

A ePPPP

The above equation could be used to define processes such as a heated/cooled bulk or mass, such as temperature sensor subjected to a step-temperature change, simple capacitive-resistive or inductive-resistive circuits, and the decay of a radioactive source.

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Figure (a) depicts progressive process

Figure (b) depicts decaying process

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1f2_as_works__&0_and_1G_ideally

)f2(tan)f(_:becomes_response_phase

kttancons_time

T

1)Hz(frequencyf

k

FF_of_ntdisplaceme_staticP

process_dynamic_periodic_the_of_amplitude_imummaxP

)f2(1

1

P

P)f(G

1

os

d

2s

d

F(t) = Fo cost

(I)FIRST ORDER SYSTEM(I.B) Harmonically Excited

ksdt

ds)t(F

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PHASE LAG

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First Order System – Harmonically Excited – ExampleTemperature Probe Example

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TEMPERATURE PROBE EXAMPLE - Continued

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TEMPERATURE PROBE EXAMPLE - Continued

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• Step input– F=0 when t<0

– F=Fo when t>0

• Underdamped Eq:

(II) SECOND ORDER SYSTEM(II.A) Step Input

Ksdt

ds

dt

sdm

gtF

c

2

21)(

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OVERDAMPED SECOND ORDER SYSTEM

= / C >1

This represents both damped and under-damped cases.

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(II) SECOND ORDER SYSTEM(II.B) Harmonically Excited

F(t) = Fo cost

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MICROPHONE EXAMPLE

Second Order System – Harmonically Excited ExampleMicrophone Example

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MICROPHONE EXAMPLE