Md. Imrul Kaes - OEE Problem
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Transcript of Md. Imrul Kaes - OEE Problem
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8/22/2019 Md. Imrul Kaes - OEE Problem
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OEE Formulas:
Availability = Operating Time Planned Production Time
Performance = Ideal cycle Time Actual Cycle Time
Actual Cycle Time = Operating Time Total pieces produced
Ideal run time = 1 Ideal cycle time
Quality = Good pieces Total pieces produced
OEE = Availability x Performance x Quality x 100%
Example 1:
Shift length: 8 hours
Short breaks: 2 @ 15 minutes
Meal break: 1 @ 30 minutes
Downtime: 47 minutes
Ideal runtime: 60 pcs per minute
Total pcs produced: 19,271 pcs
Reject pcs: 423 pcs
Calculate OEE of that shift.
Solution:
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8/22/2019 Md. Imrul Kaes - OEE Problem
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Here, sift length = Plant operating time = 8 x 60 mins =
480 mins
Planned shut down time = 2 x 15 + 30 mins = 60 mins
Planned production time = plant operating time Planned shutdown time
= 480 60 mins = 420 mins
Down time loss = 47 mins
Operating time = Planned production time Down time loss
= 420 47 mins = 373 mins
Good pcs = Total pcs Rejected pcs
= 19271 423 pcs
= 18848 pcs
Availability = Operating Time Planned Production
Time
= 373 mins 420 mins = 0.88
Ideal cycle time = 1 Ideal run time
= 1 60 pcs per min = 0.0166 min per pcs
Actual Cycle Time = Operating Time Total pieces
produced
= 373 mins 19271 pcs = 0.0193 min per pc
Performance = Ideal cycle Time Actual Cycle Time
= 0.0166 0.0193 = 0.8576
Quality = Good pieces Total pieces produced
=18848 pcs 19271 pcs = 0.9780
OEE = Availability x Performance x Quality x 100%
=0.88 x 0.8576 x 0.9780 x 100%
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8/22/2019 Md. Imrul Kaes - OEE Problem
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=0.7381 x 100% =73.81% (ANS)
Example 2:
Shift length: 10 hours
Short breaks: 2 @ 10 minutes
Meal break: 1 @ 1 hour
Downtime: 69 minutes
Ideal runtime: 120 pcs per hour = 120 60 = 2 pcs per min
Total pcs produced: 771 pcs
Reject pcs: 70 pcs
Calculate OEE of that shift.
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8/22/2019 Md. Imrul Kaes - OEE Problem
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Solution:
Here, Sift length = Plant operating time = 10 x 60 mins =
600 mins
Planned shut down time = 2 x 10 + 60 mins = 80 mins
Planned production time = plant operating time Planned shut
down time
= 600 80 mins = 520 mins
Down time loss = 69 mins
Operating time = Planned production time Down time loss
= 520 69 mins = 451 mins
Good pcs = Total pcs Rejected pcs
= 771 70 pcs
= 701 pcs
Availability = Operating Time Planned Production
Time
= 451 mins 520 mins = 0.867
Ideal cycle time = 1 Ideal run time
= 1 2 pcs per min = 0.50 min per pcs
Actual Cycle Time = Operating Time Total pieces
produced
= 451 mins 771 pcs = 0.5849 min per pc
Performance = Ideal cycle Time Actual Cycle Time
= 0.50 0.5849 = 0.8548
Quality = Good pieces Total pieces produced
=701 pcs 771 pcs = 0.909
OEE = Availability x Performance x Quality x 100%
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8/22/2019 Md. Imrul Kaes - OEE Problem
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=0.867 x 0.8548 x 0.909 x 100%
=0.676 x 100% =67.62% (ANS)