MB0040 Statistics for Management Sem 1 Aug Spring Assignment
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ASSIGNMENT – STATISTICS FOR MANAGEMENT – MB0040
ASSIGNMENT
STATISTICS FOR MANAGEMENT
REG NO :
NAME : MOHAMMED THOUFEEQ
COURSE : MBA
SEMESTER : FIRST SEMISTER
SUBJECT CODE : MB 0040
SUBJECT NAME : STATISTICS FOR MANAGEMENT
SET NO : 1&2
ASSIGNMENT SET - 1
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Q.1 (a) What is the difference between qualitative & quantitative
variable?
Qualitative variables are based on qualitative aspect or descriptive
characteristics of a phenomenon viz. sex, beauty, literacy, honesty, intelligence,
religion, eye-sight etc.
Such variables are usually dichotomous in nature in which the whole data
are divided into two groups viz. a group with presence of the attribute and a
group with absence of the attribute such as blind and not blind, deaf and not
deaf etc.
However in certain cases variables can also be made in manifold manner inwhich the data are grouped under more than two classes. This type of
classification is made when the qualitative aspect are defined by some grade or
performance. For instance, in the field of education, the classification can be
made in to different group viz. primary, secondary, higher secondary, and higher
education. Similarly on the basis of eye sight, the data may be grouped under
different grades of eye-sight viz. A, B, C, etc. Further, qualitative classifications
are made in made manner when more than on e attribute are taken into
consideration at a time, the classification will lead to a type of manifold
classification.
Quantitative variables are numerical in nature. In simple these variables can
be measured in quantitative terms. For example- mark, income, expenditure,
profit, loss, height, weight, age, price, production etc. which is capable of
quantitative expression and measurement. Quantitative variables may be
defined as a characteristic which varies in amount of magnitude under differenttime and place e.g. mark, age, and height etc. These variables can be of two
types viz. a) discrete variables, b) Continuous variables. A variable that assumes
only some specified values in a given range is known as discrete variable. A
variable that assumes all the values in the series is known as continuous
variables.
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ASSIGNMENT – STATISTICS FOR MANAGEMENT – MB0040
Q.1 (b) A town has 15 neighborhoods. If you interviewed everyone
living in one particular neighborhood, would you be interviewing a
population or a sample from the town? Would this be a random
sample? If you had a list of everyone living in the town, called a
frame, and you randomly selected 100 people from all
neighborhoods, would this a random sample?
Before answering this question we need to know what population is and
what a sample is. The totality of all individual in a survey is called population or
universe. If the number of objects in a population is finite then it is called finite
population otherwise it is known as infinite population.
A sample is a part or subset of the population. By studying the sample,
we can predict the characteristics of the entire population from where the sample
is taken. The data that describes the characteristics of sample is known as
statistics. Now if we interview only one particular neighborhood then it would be
a sample survey not a population survey. Because here we interviewed every
individuals of a particular group not the whole population. But by selecting 100
people from all neighborhoods for a survey would be called as a random sample.
Q.2. (a) Explain the steps involved in planning of statistical survey?
Stages in a statistical survey -
a). Nature of the problem to be investigated should be clearly defined in an
unambiguous manner.
b). Objectives of investigation should be stated at the outset. Objectives could be
Obtain certain estimates.
Establish a theory.
Verify an existing statement.
Find relationship between characteristics
c). The scope of investigation has to be made clear. The scope of the
investigation refers to the area to be covered, identification of units to be studied,
nature of characteristics to be observed, accuracy of measurement, analytical
method, time cost and other resources required.
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d). Whether to use data collected from primary sources or secondary sources
should be determined in advanced.
e). The organization of investigation is the final step. It encompasses the
determination of investigator required, training, supervision work, funds required.
Q.2(b) What are the merits & Demerits of Direct personal
observation and Indirect Oral Interview?
Direct personal observation: In the direct personal observation method,
the investigator collects data by direct contact with the units of investigation. The
accuracy of data depends upon ability, training, and attitude of the investigator.
Merits -
We get the original data which is more accurate and reliable.
Satisfactory information can be extracted through indirect questions.
Data is homogenous and comparable.
Additional information can be gathered.
Misinterpretation of question can be avoided.
Demerits -
This method consumes more cost.
This method costs more time.
This cannot be used when the scope of the investigation is wide.
Indirect oral interview: Indirect oral interview is used when the area to be
covered is large. The investigator collects the data from a third party or witness
or had of the institution. This method is generally used by police department in
cases related to enquiries on causes of fires, theft or murders.
Merits -
Economical in terms of time, cost and man power.
Confidential information can be collected.
Information is likely to be unbiased and reliable.
Demerits -
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The degree of accuracy of information is less.
Q.3. (a) Draw Ogives from the following data and measure the
median value. Verify it by actual calculations.
Central size 5 15 25 35 45Frequency 5 11 21 16 10
Central Value Limits Frequency Less than Greater than
5 0-10 5 10 5 0 63
15 10-20 11 20 16 10 58
25 20-30 21 30 37 20 47
35 30-40 16 40 53 30 26
45 40-50 10 50 63 40 10
Total 63
Now from the meeting points of these two ogives if we draw a perpendicular to
the X axis, the point where it meets X axis gives median of the series. So here
midpoint of 20-30 limit is 25. So median is 25.
By actual calculation
Here n=63, hence median is (N+1)/2th item which is (63+1)/2=32nd item =25.
So ogive median and actual median are same.
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Q.3. (b) Complete the following distribution, if its Median is 2,600 and
compute the value of Arithmetic Mean.
Size 1000-1500
1500-2000
2000-2500
2500-3000
3000-4000
4000-5000
5000-6000
Total
Frequency 120 ? 400 500 ? 50 20 1500
Size f cf
1000-1500 120 120
1500-2000 f1 120+f1
2000-2500 400 520+f1
2500-3000 500 1020+f1
3000-4000 410-f1* 1430
4000-5000 50 1480
5000-6000 20 1500
N=1500(given)
*N = 1500 - (120+400+500+50+20) - f 1Median = (N)th item , 1500/2=750th
item ,but median is 2600 (given)
This lies between 2500-3000 groups
Now M= L1 + L2-L1 (m-c)
F
2600= 2500+ 3000-2500/500 *(750-(520+f 1))
= >2600 = 2500+ 500/500* (750-520-f 1)
= >2600 = 2500- 230-f 1
= >2600-2500= 320-f 1
= > 100= 320- f 1
= > f 1 =130
Then f 2 = 410-130=280
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Ci f m fm
1000-1500 120 1250 150000
1500-2000 130 1750 227500
2000-2500 400 2250 900000
2500-3000 500 2750 1375000
3000-4000 280 3500 980000
4000-5000 50 4500 225000
5000-6000 20 5500 110000
1500 Σ fm = 3967500
X= Σ fm = 3967500
Σ f =3967500/1500 = 2645 (ans)
Q.4.(a) What is the main difference between correlation analysis and
regression analysis?
Correlation analysis: When two or more variables move in sympathy with
other, they are said to be correlated. If both variables move in the same direction
then they are said to be positively correlated. If the variables move in opposite
direction then they are said to be negatively correlated. If they move haphazardly
then there is no correlation between them.
Regression analysis: Regression analysis is used to estimate the values of the
dependent variables from the values of the independent variables. Regression
analysis is used to get measure of the error involved while using the regression
line as a basis for estimation. Regression coefficient is used to calculate
correlation coefficient.
The main difference between these two is: - correlation analysis attempts to
study the relationship between the variable ‘X’ and ‘Y’. Regression analysis
attempts to predict the average ‘X’ for a given ‘Y’. It is attempted to quantify the
dependence of one variable on the other.
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Difference between regression coefficient and correlation coefficient
Correlation coefficient Regression Coefficient
The correlation coefficients, rxy = ryx. The regression coefficients, byx = bxy
It indirectly helps in estimation. It is meant for estimation.
It has no units attached to it. It has units attached to it.
There exists nonsense correlation. There is no such nonsense correlation.
It is not based on cause and effect It is based on cause and effect
relationship. relationship.
Q.4.(b ) In Multiple regressions analysis is an extension of two
variable regression analyses. In this analysis, two or more
independent variables are used to estimate the values of a
dependent variable, instead of one independent variable.
In Multiple regressions analysis is an extension of two variable regressionanalyses. In this analysis, two or more independent variables are used toestimate the values of a dependent variable, instead of one independentvariable.
Objectives of multiple regression analysis are –
To derive an equation, this provides estimates of the dependent variablefrom values of the two or more independent variables?
To obtain the measure of the error involved in using the regressionequation as a basis of estimation.
To obtain a measure of the proportion of variance in the dependent
variable accounted for or explained by the independent variables.
In the given question N=12, hence degree of freedom will be v=n-1, where n is
the sample size. So the degree of freedom will be 12-1=11
Q.5 (a) Discuss what is meant by Quality control and improvement.
Quality control - is defined as the part of quality management focused on
fulfilling quality requirements. Ideally, prevention based controls should prevent
problems from occurring, but in reality, no system is foolproof and problems do
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occur. Accordingly, controls to detect quality problems must be established so
that customers receive only products that meet their requirements. ISO 9000
Lead Auditor Training Detection based controls are reactive – the problem and
cost have already occurred and the company is resorting to damage control. The
intent of detection is to evaluate output from processes and activities by
implementing controls to catch problems when they do occur. For example, final
inspection to catch defective product before it gets shipped.
Quality Improvement – is defined as the part of quality management focused
on increasing the ability to fulfill requirements. Continual improvement results
from ongoing actions taken to enhance product characteristics or increase
process effectiveness and efficiency. This is one of the key characteristics thatdifferentiate a quality management system from a quality assurance system, i.e.,
being able to improve the effectiveness and efficiency and of a process or
activity by setting measurable objectives and using performance data to manage
the achievement of these objectives.
Effectiveness is defined as the extent to which planned activities are realized
and planned results are achieved. In determining the effectiveness of quality
assurance and quality improvement activities, the following questions should be
asked:
–To what extent have problems in product or processes been prevented?
–To what extent have planned objectives for quality been met?
Efficiency is defined as the relationship between result achieved and resources
used. The measure of efficiency is determined by asking the following:
–Can we get the same output using fewer resources?
–Can we get more output without adding resources?
These questions may be applied to the output of any activity within the quality
management system of an organization.
It should be noted that ISO 9001 requires organizations to achieve QMS
effectiveness through quality assurance and continual improvement activities.
QMS efficiency is desirable, but not currently required by ISO 9001. ISO 9004
provides guidelines that consider both the effectiveness and efficiency of the
QMS.
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Quality improvement actions may include -
Measuring and analyzing situations
Establishing improvement objectives
Searching for possible solutions
Evaluating these solutions
Implementing the selected solution
Measuring, verifying, and analyzing results
Formalizing the changes
Q.5. (b) What are the limitations of a quality control charts?
Ans.: The quality control chart is based on the research of Villefredo Pareto. He
found that approximately 80 percent of all wealth of Italian cities he researched
was held by only 20 percent of the families. The Pareto principle has been found
to apply in other areas, from economics to quality control. Pareto charts have
several disadvantages, however.
Easy to Make but Difficult to Troubleshoot
Based on the Pareto principle, any process improvement should focus on
the 20 percent of issues that cause the majority of problems in order to
have the greatest impact. However, one of the disadvantages of Pareto
charts is that they provide no insight on the root causes. For example, a
Pareto chart will demonstrate that half of all problems occur in shipping
and receiving. Failure Modes Effect Analysis, Statistical Process Control
charts, run charts and cause-and-effect charts are needed to determine
the most basic reasons that the major issues identified by the Pareto chart
are occurring.
Multiple Pareto Charts May Be Needed
Pareto charts can show where the major problems are occurring.
However, one chart may not be enough. To trace the cause for the errorsto its source, lower levels of Pareto charts may be needed. If mistakes are
occurring in shipping and receiving, further analysis and more charts are
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needed to show that the biggest contributor is in order-taking or label-
printing. Another disadvantage of Pareto charts is that as more are
created with finer detail, it is also possible to lose sight of these causes in
comparison to each other. The top 20 percent of root causes in a Pareto
analysis two to three layers down from the original Pareto chart must also
be compared to each other so that targeted fix will have greatest impact.
Qualitative Data versus Quantitative Data
Pareto charts can only show qualitative data that can be observed. It
merely shows the frequency of an attribute or measurement. One
disadvantage of generating Pareto charts is that they cannot be used to
calculate the average of the data, its variability or changes in the
measured attribute over time. It cannot be used to calculate the mean, the
standard deviation or other statistics needed to translate data collected
from a sample and estimate the state of the real-world population. Without
quantitative data and the statistics calculated from that data, it isn't
possible to mathematically test the values. Qualitative statistics are
needed to whether or not a process can stay within a specification limit.
While a Pareto chart may show which problem is the greatest, it cannot
be used to calculate how bad the problem is or how far changes would
bring a process back into specification.
Q.6. (a) Suggest more suitable average in each of following cases:
(i) Average size of ready-made garments.
(ii) Average marks of a student.
Average size of readymade garments: Arithmetic mean will be used because
it is continuous and additive in nature.
Average marks of a student: Arithmetic mean will be used because the data re
in the interval and the distribution is symmetrical.
Q.6. (b) State the nature of symmetry in the following cases:
(i) When median is greater than mean, and
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(ii) When Mean is greater than median.
When median is greater than mean, the series is said to have negative
skewness. The following characteristics can be seen
• Mode > Median > Mean
• The left tail of the curve is longer than the right tail, when the data are
plotted through a histogram, or a frequency polygon.
• The formula of skewness and its coefficients give negative figures.
When mean is greater than median, the series is said to have positive skewness.
the following characteristics can be seen
• Mean > Median > Mode
• The right tail of the curve is longer than its left tail, when the data are
plotted through a histogram, or a polygon.
• The formula of skewness and its coefficients give positive figures.
Following example show the above distributions and respective characteristics:
Value (X) Positively Skewed Negatively Skewed
F FX CF F FX CF
10 5 50 5 5 50 5
20 15 300 20 7 140 12
30 13 390 33 9 270 21
40 11 440 44 11 440 32
50 9 450 53 13 650 45
60 7 420 60 15 900 60
70 5 350 65 5 350 65
Total 65 2400 - 65 2800 -
Mean= 2400/65= 37 Mean= 2800/65= 43
Median=(65+1)/2=33th Median= 33th item =50 Item =30
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Assignment Set - 2
Q.1. (a) What are characteristics of good measure of central
tendency?
The statistics, mean median and mode are known to be the most
common measures of central tendency. A measure of central tendency is a sort
of average or a typical value of the item in the series or some characteristic of
members in a group. Each of these measures of central tendency provides a
single value o represent the characteristic of the whole group in its own way.
According to Tete measure of central tendency is: "A sort of average or typical
value of the items in the series and its function is to summarize the series in
terms of this average value."
Mean represents the average for an ungrouped data; the sum of the scores
divide by the total number of the scores gives the value of the mean.
Median is the score or value of that central item which divides the series in
exactly two equal halves.
Mode is defined as the size of the variable that occurs most frequently in the
series.
1). Characteristics of the mean include –
Every score influences the mean.
Changing a score changes the mean.
Adding or subtracting score changes mean (unless score equals mean).
If a constant value is added to every score, the same constant will be
added to the mean. If a constant value is subtracted from every score, the
same constant will be subtracted from the mean.
If every score is multiplied or divided by a constant, the mean will change
in the same way.
It is inappropriate to use the mean to summarize nominal and ordinal
data; it is appropriate to use mean to summarize interval and ratio data.
If the distribution is skewed or has some outliers, the mean will be
distorted.
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2). Characteristics of the Median include –
It is inappropriate to use the median to summarize nominal data; it isappropriate to use median to summarize ordinal, interval, and ratio data.
The median depends on the frequency of the scores, not on the actual
values.
The median is not distorted by outliers or extreme scores.
The median is the preferred measure of central tendency when the
distribution is skewed or distorted by outliers.
3). Characteristics of the Mode include –
This may be used to summarize nominal, ordinal, interval, and ratio data.
There may be more than one mode.
The mode may not exist.
Q.1. (b) What are the uses of averages?
Ans.: Below are the usages of various Averages –
1). Arithmetic mean is used when –
In depth study of the variable is needed
The variable is continuous and additive in nature
The data are in the interval or ratio scale
When the distribution is symmetrical
2). Median is used when –
The variable is discrete
There exists abnormal values
The distribution is skewed
The extreme values are missing
The characteristics studied are qualitative
The data are on the ordinal scale
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3). Mode is used when –
The variable is discrete
There exists abnormal values
The distribution is skewed
The extreme values are missing
The characteristics studied are qualitative
4). Geometric mean is used when –
The rate of growth, ratios and percentages are to be studies
The variable is of multiplicative nature
5). Harmonic mean is used when –
The study is related to speed, time
Average of rates which produce equal effects has to be found
Q.2.For each one of the following null hypothesis, determine it is a
left tailed a right-tailed, or a two-tailed test.
a. μ ≥ 10. b. P ≤ 0.5. c. μ is at least 100. d. μ ≤ -20. e. p is exactly 0.22.
The hypothesis that contains an = is the null, implied by the question.
a) Ho:μ ≥ 10, Ha:μ <10 so left tailed.
b) Ha: P>0.5, so right tailed
c) at least 100 means μ ≥ 100 so Ha:μ < 100 and left-tailedd) Ha:μ >-20, right-tailed
e) Could be left, right or two tailed.
Q.3. What is test statistic? Why do we have to know the distribution
of a test statistic?
In statistical hypothesis testing, a test statistic is a numerical summary of a set of data that reduces the data to one or a small number of values that can
be used to perform a hypothesis test. Given a null hypothesis and a test
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statistic T, we can specify a "null value" T0 such that values of T close to T0
present the strongest evidence in favor of the null hypothesis, whereas values
of T far from T0 present the strongest evidence against the null hypothesis. An
important property of a test statistic is that we must be able to determine
sampling distribution under null hypothesis, which allows to calculate p-values.
For example, suppose we wish to test whether a coin is fair (i.e. has equal
probabilities of producing a head or a tail). If we flip the coin 100 times and
record the results, the raw data can be represented as a sequence of 100
Head's and Tail's. If our interest is in the marginal probability of obtaining a head,
we only need to record the number T out of the 100 flips that produced a head,
and use T0 = 50 as our null value. The exact sampling distribution of T isthe binomial distribution, but for larger sample sizes the normal approximation
can be used. Using one of these sampling distributions, it is possible to compute
either a one-tailed or two-tailed p-value for the null hypothesis that the coin is
fair. Note that the test statistic in this case reduces a set of 100 numbers to a
single numerical summary that can be used for testing.
A test statistic shares some of the same qualities of a descriptive statistic, and
many statistics can be used as both test statistics and descriptive statistics.
However a test statistic is specifically intended for use in statistical testing,
whereas the main quality of a descriptive statistic is that it is easily interpretable.
Some informative descriptive statistics, such as the sample range, do not make
good test statistics since it is difficult to determine their sampling distribution.
After deciding what level of significance to use, our next task in hypothesis
testing is to determine the appropriate probability distribution. We have a choice
between the normal distribution and the ‘t’ distribution.
Q 4. Suppose you are sampling from population with mean μ= 1,065
and standard deviation σ = 500. The sample size is n=100. What are
the expected value and the variance of a sample mean ? ̅
If sample mean is xbar, E(xbar)=μ=1065
Var(xbar) = (population variance)/n==100^2/100=500
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ASSIGNMENT – STATISTICS FOR MANAGEMENT – MB0040
E[Xbar] = μ = 1,065
Var(Xbar) = σ^2/n = 500^2/100 = 2500
Q.5 The time it takes an international telephone operator to place an
overseas phone call is normally distributed with mean 45 seconds
and standard deviation 10 seconds.
a) What is probability that my call will go through in less than 1 minute?
b) What is the probability that I will get through in less than 40 seconds?
a. First thing is, let be the time it takes to the telephone operator to place an
overseas phone call. The probability we are looking for is Pr(X<60)
In order to compute this probability, we need to normalize in the following
way. We know that has standard normal distribution, so we
compute
(Since the mean is given in seconds, we have to write 1 minute as 60 seconds)
b. Same as before, let be the time it takes to the telephone operator to place
an overseas phone calls. The probability we are looking for is Pr(X<60)
In order to compute this probability, we need to normalize in the same way
we did before. We know that has standard normal distribution, so we
compute
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Q.6. The following data are the number of tons shipped weekly across the pacific by a shipping company.
398, 412, 560, 476, 544, 690, 587, 600, 613, 457, 504, 477,530, 641, 359, 566, 452, 633, 474, 499, 580, 606, 344, 455,505, 396, 347, 441, 390, 632, 400, 582
Assume these data represent an entire population. Find the population mean and the population standard deviation.
Population Mean
= Sum of X values / N(Number of values)
= 16150 / 32
= 504.7
Standard Deviation is given by
Population Standard Deviation is given by
S = 94.54
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