Matrična analiza konstrukcija
Transcript of Matrična analiza konstrukcija
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PRIMER:
Sraunati nepoznata pomeranja i sile u presecima sistema datog na slici, a zatim nacrtati
dijagrame presenih sila M, T i N. Sistem je izloen uticaju optereenja.
Napomena: promena krivine greda prema kvadratnoj paraboli.
7 23 10E kN m= , 51 10 1t C =
Proraunska ema konstrukcije:
Koordinate sistema:
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Lokalne koordinate elemenata:
Koordinate vorova:
vor x y
1 12,0 8,5
2 32,0 8,5
3 44,0 8,5
4 0,0 8,5
5 3,5 0,06 40,5 0,0
Geometrija tapova:
( ) ( )2 2
k i k il x x y y= + , ( ) ( )sin , cosk i k is y y l c x x l = = = =
Tabela 1
tapkraj tapa
xk-xi yk-yil
[m]
c
(cos)
s
(sin)i k
1 1 4 -12,0 0,0 12,0 -1 0
2 1 2 20,0 0,0 20,0 1 0
3 2 3 12,0 0,0 12,0 1 0
4 1 5 -8,5 -8,5 12,0208 -0,7071 -0,7071
5 2 6 8,5 -8,5 12,0208 0,7071 -0,7071
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- MATRICE KRUTOSTI TAPOVA U LOKALNIM KOORDINATAMA:
Matrica krutosti tapa i-k sa promenljivim poprenim presekom:
( ) ( )
( ) ( )
2 2
2 2
0 0 0 0
0 0
0 0
0 0 0 0
0 0
0 0
1 1
1 1
ik ik
ik ki ik ik ki ki
ik ik ik ik
ik ik
ik ki ik ik ki ki
ki ik ki ki
c c l c l c c l c l
c l a c l b
c c l c l c c l c l
c l b c l a
+ + =
+ +
k
Matrica krutosti tapa i-g sa promenljivim poprenim presekom :
2 2
2 2
1 0 0 1 0
0 0
0 01 0 0 1 0
0 0
ig ig
ig ig ig
ig ig ig g
ig ig
ig ig ig
d l d l d l
d l d d l
d l d l d l
=
k
Matrica krutosti tapa i-g sa konstantnim poprenim presekom :
3 2 3
2 2
3 2 3
0 0 0
0 3 3 0 3
0 3 3 0 3
0 0 0
0 3 3 0 3
ig ig ig ig
ig ig ig ig ig ig
ig ig ig ig ig ig ig
ig ig ig ig
ig ig ig ig ig ig
EF l EF l
EI l EI l EI l
EI l EI l EI l
EF l EF l
EI l EI l EI l
=
k
- Proraun matrica krutosti:
Matrica krutosti tapova 1 i 3:
Aksijalno naprezanje - reenje numerikom integracijom:
10
00 0 0
1 1 1 1 1,3
l l l
ig x m m
mx x x
dx dx dxEF bE h bE bE h=
= = = = =
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x hx =1/hx
0,0 0,600 1,666667 1 1,66667
1,2 0,609 1,642036 4 6,56814
2,4 0,636 1,572327 2 3,14465
3,6 0,681 1,468429 4 5,87372
4,8 0,744 1,344086 2 2,68817
6,0 0,825 1,212121 4 4,84848
7,2 0,924 1,082251 2 2,16450
8,4 1,041 0,960615 4 3,84246
9,6 1,176 0,85034 2 1,70068
10,8 1,329 0,752445 4 3,00978
12,0 1,500 0,666667 1 0,66667
= 36,17393
10
0
1 1 1,2 36,17393 36,173933 0,4 3
ig m
m
EbE E=
= = =
3
11 14 41 44
127,644220 10
36,17393ig
Ek k k k E
= = = = = =
Aksijalno naprezanje teoretsko reenje:12
2
0 0
1 1 1 1 1 20 6 6 36,173947arctan ,
0,4 0,00625 0,6 0,4 3 2 E
l
ig
x
dx dxbE h E x E
= = = = +
Popreno savijanje numerikom integracijom:
( )12
i x
x xM
l= =
( )
2 2
( ) ( )
( )3
( )0 0 0
2
( )
3
( )
12 12
12,
3
x
l l li x i x
ig x
x
ki x
ig m m
m i x
M Mdx dx dx
EI bE bEh
M
bE h=
= = = =
= =
x hx Mix = (Mix)2/( hx)3
0,0 0,600 0,00000 0,00000 1 0,000001,2 0,609 0,10000 0,04427 4 0,17710
2,4 0,636 0,20000 0,15549 2 0,31097
3,6 0,681 0,30000 0,28497 4 1,13989
4,8 0,744 0,40000 0,38851 2 0,77702
6,0 0,825 0,50000 0,44522 4 1,78089
7,2 0,924 0,60000 0,45634 2 0,91268
8,4 1,041 0,70000 0,43435 4 1,73742
9,6 1,176 0,80000 0,39351 2 0,78702
10,8 1,329 0,90000 0,34507 4 1,38029
12,0 1,500 1,00000 0,29630 1 0,29630
= 9,299565
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12 12 1,2 111,5947849,299565
3 0,4 3
k
ik m
m ibE E E =
= = =
318,960992 10ig
ig
d E= =
Popreno savijanje teoretsko reenje:
( )
2 2 12 2( ) ( )
3 2 3
( )0 0 0
12 12 ( 12)
0,4 (0,00625 0,6)x
l lg x g x
ig
x
M M xdx dx dx
EI bE h E x = = =
+
12 125 6 6 10 1arctan 111,594298
0,4 81 2 27ig
E E
= + =
318,961031 10ig
ig
d E= =
Sada su, prema Error! Reference source not found., matrice krutosti za tapove 1 i 3,
3
1 3 10 E
= =
k k
27,644220 0 0 -27,644220 0
0 0,062229 0,746749 0 -0,062229
0 0,746749 8,960992 0 -0,746749
-27,644220 0 0 27,644220 0
0 -0,062229 -0,746749 0 0,062229
Matrica krutosti tapa 2 :
Aksijalno naprezanje - reenje numerikom integracijom:
( )
( ) ( )0 0 0
1 1 1l l l
ik x
x x
dxdx dx
EF bE h bE = = =
( )
1 1,
3
k
ik m m
m i xbE h=
= =
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x hx =1/hx
0,0 1,500 0,66667 1 0,66667
2,0 1,320 0,75758 4 3,03030
4,0 1,180 0,84746 2 1,69492
6,0 1,080 0,92593 4 3,70370
8,0 1,020 0,98039 2 1,96078
10,0 1,000 1,00000 4 4,00000
12,0 1,020 0,98039 2 1,96078
14,0 1,080 0,92593 4 3,70370
16,0 1,180 0,84746 2 1,69492
18,0 1,320 0,75758 4 3,03030
20,0 1,500 0,66667 1 0,66667
= 26,112746
10
0
1 1 226,112746 43,5212433 0,4 3
ik m
mEbE E=
= = =
3
11 14 41 44
122,977285 10
43,521243ik
Ek k k k E
= = = = = =
Aksijalno naprezanje teoretsko reenje:20
2
0 0
1 1 1 1 1 2 43,52098820 2 arctan
0,4 0,005 0,1 1,5 0,4 2 E
l
ik
x
dx dxbE h E x x E
= = = = +
Popreno savijanje numerika integracija Simpsonovim pravilom:
( ) 120
i x
xM =
( )
20
k x
xM =
( )
2 2
( ) ( )
( )3
( )
12 12
x
i x i x
ik x
x
M Mdx dx dx
EI bE h bE = = =
( )
2
( )
3
12,
3x
ki x
ik m m
m i
M
bE h=
= =
Zbog simetrije tapa je ik = ki
( )
( ) ( ) ( ) ( )
( )3
( )
12 12
x
i x k x i x k x
ik x
x
M M M Mdx dx dx
EI bE h bE = = =
( )
( ) ( )
3
12,3
x
ki x k x
ik ki m m
m i
M M
bE h=
= = =
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m x hm Mi Mk m m m
0 0,0 1,50 1,0 0,0 0,29630 0,00000 1
1 2,0 1,32 0,9 0,1 0,35218 0,03913 4
2 4,0 1,18 0,8 0,2 0,38952 0,09738 2
3 6,0 1,08 0,7 0,3 0,38898 0,16670 4
4 8,0 1,02 0,6 0,4 0,33924 0,22616 2
5 10,0 1,00 0,5 0,5 0,25000 0,25000 4
6 12,0 1,02 0,4 0,6 0,15077 0,22616 2
7 14,0 1,08 0,3 0,7 0,07144 0,16670 4
8 16,0 1,18 0,2 0,8 0,02435 0,09738 2
9 18,0 1,32 0,1 0,9 0,00435 0,03913 4
10 20,0 1,50 0,0 1,0 0,00000 0,00000 1
m =6,371847 3,940839
12 12 2 127, 4369426,371847
3 0, 4 3
k
ik ki m
m ibE E E =
= = = =
12 12 2 78,816784
3,9408393 0, 4 3
k
ik ki m
m ibE E E =
= = = =
( )2 2 2 22 21 1
127,436942 78,816784 10.028,088794ik ik
E E = = =
23127,436942 12,707999 10
10.028,088794
kiik ki
Ea a E
E
= = = =
2
378,816784 7,859602 1010.028,088794
ikik ki
Eb b E
E
= = = =
3 3 312, 707999 10 7, 859602 10 20, 567601 10ik ki ik ik c c a b E E E = = + = + =
Popreno savijanje teoretsko reenje:
( )
2 2 20 2( ) ( )
3 2 3
( )0 0 0
12 12 (1 0,05 )
0, 4 (0, 005 0,1 1,5)x
l li x i x
ik
x
M M xdx dx dx
EI bE h E x x
= = =
+
12 25 2 2 55 127, 435185arctan0, 4 8 2 36
ikE E
= + =
( )
8( ) ( ) ( ) ( )
3 2 3
( )0 0 0
12 12 (1 0,005 )(0, 005 )
0, 3 (0, 005 0,1 1, 5)x
l li x k x i x k x
ik
x
M M M M x xdx dx dx
EI bE h E x x
= = =
+
12 5 2 2 25 78,820370arctan
0,3 8 2 12ik
E E
= + =
312,709108 10ik kia a E= =
37,860754 10ik kib b E
= = 320,569861 10ikc E
=
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Sada je, prema Error! Reference source not found., matrica krutosti za tap 2,
2
=
k
022,977285 0 -22,977285 0 0
0 0,102838 1,028380 0 -0,102838 1,028380
0 1,028380 12,707999 0 -1,028380 7,859602
-22,977285 0 0 22,977285 0 0
0 -0,102838 -1,028380 0 0,102838 -1,0283800 1,028380 7,859602 0 -1,028380 12,707999
E
-310
Matrica krutosti tapova 4 i 5: 12,0208l m= , 20,24F m= , 40,0072I m=
4 5 E
= =
k k-3
19,965368 0 0 -19,965368 0
0 0,012435 0,149481 0 -0,012435
100 0,149481 1,796883 0 -0,149481
-19,965368 0 0 19,965368 0
0 -0,012435 -0,149481 0 0,012435
- MATRICE KRUTOSTI TAPOVA U GLOBALNIM KOORDINATAMA:
- Globalne koordinate tapova
- Matrice transformacije
Prema Error! Reference source not found.a, Error! Reference source not found.itabeli 1, imamo:
1
=
T
-1 0 0 0 0
0 -1 0 0 0
0 0 1 0 0
0 0 0 -1 0
0 0 0 0 -1
, 2
=
T
1 0 0 0 0 0
0 1 0 0 0 0
0 0 1 0 0 0
0 0 0 1 0 0
0 0 0 0 1 0
0 0 0 0 0 1
, 3
=
T
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
0 0 0 0 1
,
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4
=
T
-0,70711 -0,70711 0 0 0
0,70711 -0,70711 0 0 0
0 0 1 0 0
0 0 0 -0,70711 -0,70711
0 0 0 0,70711 -0,70711
5
=
T
0,70711 -0,70711 0 0 0
0,70711 0,70711 0 0 0
0 0 1 0 0
0 0 0 0,70711 -0,70711
0 0 0 0,70711 0,70711
- Matrice krutosti u globalnom koordinatnom sistemu
* 3
1 1 1 1 10T E
= =
k T k T
2 5 7 1 10
2
5
7
1
10
27,644220 0 0 -27,644220 0
0 0,062229 -0,746749 0 -0,062229
0 -0,746749 8,960992 0 0,746749
-27,644220 0 0 27,644220 0
0 -0,062229 0,746749 0 0,062229
* 3
2 2 2 2 10T E
= =k T k T
2 5 7 3 6 8
22,977285 0 0 -22,977285 0 0
0 0,102838 1, 028380 0 -0,102838 1, 028380
0 1,028380 12,707999 0 -1,028380 7,859602
-22,977285 0 0 22,977285 0 0
0 -0,102838 -1,028380 0 0,102838 -1,0283800 1,028380 7,859602 0 -1,02 8
2
5
7
3
6
8380 12,707999
* 3
3 3 3 3 10T E
= =
k T k T
3 6 8 4 9
3
6
8
4
9
27,644220 0 0 -27,644220 0
0 0,062229 0,746749 0 -0,062229
0 0,746749 8,960992 0 -0,746749
-27,644220 0 0 27,644220 0
0 -0,062229 -0,746749 0 0,062229
* 3
4 4 4 4 10T
E= =k T k T
2 5 7 11 12
9,988902 9,976466 0,105699 -9,988902 -9,9764669,976466 9,988902 -0,105699 -9,976466 -9,988902
0,105699 -0,105699 1,796883 -0,105699 0,105699
-9,988902 -9,976466 -0,105699 9,988902 9,976466
-9,976
2
5
7
11
12466 -9,988902 0,105699 9,976466 9,988902
* 3
5 5 5 5 10T E
= =k T k T
3 6 8 13 14
9,988902 -9,976466 0,105699 -9,988902 9,976466
-9,976466 9,988902 0,105699 9,976466 -9,988902
0,105699 0,105699 1,796883 -0,105699 -0,105699
-9,988902 9,976466 -0,105699 9,988902 -9,976466
9,97646
3
6
8
13
146 -9,988902 -0,105699 -9,976466 9,988902
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- MATRICA KRUTOSTI SISTEMA:* *
*
* *
ss so
os oo
=
K KK
K K
*
ss E=K
1 2 3 4 5 6 7 8
-3
27,64422 -27,644220 0 0 0 0 0 0-27,64422 60,610407 -22,977285 0 9,976466 0 0,105699 0
0 -22,977285 60, 610407 -27,64422 0 -9,976466 0 0,105699
0 0 -27,644220 27,64422 0 0 0 010
0 9,976466 0 0 10,153969 -0,102838 0,175932 1,
6
7
8
1
2
3
4
5028380
0 0 -9, 976466 0 -0,102838 10,153969 -1,028380 -0,175932
0 0,105699 0 0 0,175932 -1,028380 23,465874 7,859602
0 0 0,105699 0 1,028380 -0,175932 7,859602 23,465874
*
0 0 0 0 00 0 0
0 0 0
0 0 0 0 0
0 0
0 0 0
0 0
0 0 0
so E
=
K
9 10 11 12 13 14
-3
00 -9,988902 -9,976466
0 -9,988902 9,976466
010
0 -0,062229 -9,976466 -9,988902
-0,062229 9,976466 -9,988902
0 0,746749 -0,105699 0,105699
-0,746749 -0,105699 -0,105699
6
7
8
1
2
3
4
5
*
os E
=
K
1 2 3 4 5 6 7 8
-3
0 0 0 0 0 -0,062229 0 -0,746749
0 0 0 0 -0,062229 0 0,746749 0
0 -9,988902 0 0 -9,976466 0 -0,105699 010
0 -9,976466 0 0 -9,988902 0 0,105699 0
0 0 -9,988902 0 0 9,976466 0 -0,105699
0 0 9,976466 0 0 -9,988902 0 -0,105699
9
10
11
12
13
14
*
oo E
=
K
9 10 11 12 13 14
9
10
11
12
13
14
-3
0,062229 0 0 0 0 0
0 0,062229 0 0 0 0
0 0 9,988902 9,976466 0 0
10 0 0 9,976466 9,988902 0 0
0 0 0 0 9,988902 -9,976466
0 0 0 0 -9,976466 9,988902
* 1
ssE
=K3
2,057554 2,021380 1,999633 1,999633 -1,974472 1,952773 0,068042 0,069374
2,021380 2,021380 1,999633 1,999633 -1,974472 1,952773 0,068042 0,069374
1,999633 1,999633 2,021380 2,021380 -1,952773 1,974472 0,069374 0,
10
068042
1,999633 1,999633 2,021380 2,057554 -1,952773 1,974472 0,069374 0,068042
-1,974472 -1,974472 -1,952773 -1,952773 2,027603 -1,905999 -0,065594 -0,072383
1,952773 1,952773 1,974472 1,974472 -1,905999 2,027603 0,072383 0
,065594
0,068042 0,068042 0,069374 0,069374 -0,065594 0,072383 0,050610 -0,013846
0,069374 0,069374 0,068042 0,068042 -0,072383 0,065594 -0,013846 0,050610
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A) UTICAJ ZADATOG OPTEREENJA:
- Vektori ekvivalentnog optereenja tapova:
Proraun momenata punog ukljetenja
tap 1:
( )
2
( )
1( )
( )
3,
160 5
,12
112
2
x
x
o x
xh
xM
M p x x
= +
=
=
2 212 12 101( ) 1( )
11 30( ) ( )0 0
2
1
3
12 12,
3
1,2
x x
m
mx x
mm
m
M ME dx dx
I b bh
Mm
h
=
= = =
= =
12 12 101( ) ( ) 1( ) ( )
10 30( ) ( )0 0
1
3
12 12
3
x o x x o x
m
mx x
m om
m
m
M M M ME dx dx p
I b bh
M M
h
=
= = =
=
m x hm M1 Mo m m m
0 0,00 0,600 0,0 0,00 0,00000 0,00000 1
1 1,20 0,609 0,1 6,48 0,04427 2,86895 42 2,40 0,636 0,2 11,52 0,15549 8,95594 2
3 3,60 0,681 0,3 15,12 0,28497 14,36256 4
4 4,80 0,744 0,4 17,28 0,38851 16,78359 2
5 6,00 0,825 0,5 18,00 0,44522 16,02805 4
6 7,20 0,924 0,6 17,28 0,45634 13,14253 2
7 8,40 1,041 0,7 15,12 0,43435 9,38205 4
8 9,60 1,176 0,8 11,52 0,39351 5,66657 2
9 10,80 1,329 0,9 6,48 0,34507 2,48452 4
10 12,00 1,500 1,0 0,00 0,29630 0,00000 1
m = 9,299565 269,601769
10
11
0
12 12 1,29,299565 111,594784
3 0, 4 3m
m
Eb
=
= = =
10
10
0
12 12 1,0269,601769 3.235,221228
3 0,4 3m
m
E p pb
=
= = =
2
1 14
3.235, 22122828,990793 1,6106 463,852681
111,594784 8
p plX M p kNm= = = = =
2 2
4 14
1 1 16 12463,852681 57,34561
2 12 2
plV M kN
l
= + = =
1 4 16 12 57,34561 134,65439V pl V kN = = =
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1
kN
kN
kNm
kN
kN
=
Q
0
134,65439
463,85268
0
57,34561
*
1 1 1
T
= =
Q T Q
2
5
7
1
10
0
-134,65439
463,85268
0
-57,34561
tap 2:
2
( )
1( )
2( )
3, 2,0
200 10 2
1 ,20
20
x
x
x
x xh m
x
M
xM
= + =
=
=
220 101( )
11 30( )0
12 12
3
x
m
mx
ME dx
b bh
=
= =
20 101( ) 2( )
12 30( )0
12 12
3
x x
m
mx
M ME dx
b bh
=
= =
220 102( )
22 3 0( )0
12 12
3
x
mmx
ME dx
b bh
=
= =
20 101( ) ( )
10 30( )0
12 12
3
x o x IV
m
mx
M ME dx
b bh
=
= =
20 102( ) ( )
20 30( )0
12 12
3
x o x V
m
mx
M ME dx
b bh
=
= =
m x hm M1 M2 Mo m m = m IV V
m m = m
0 0,0 1,50 0,0 1,0 0 0,00000 0,00000 0,00000 1
1 2,0 1,32 0,1 0,9 40 0,00435 0,03913 1,73915 4
2 4,0 1,18 0,2 0,8 80 0,02435 0,09738 9,73809 2
3 6,0 1,08 0,3 0,7 120 0,07144 0,16670 28,57796 4
4 8,0 1,02 0,4 0,6 160 0,15077 0,22616 60,30863 2
5 10,0 1,00 0,5 0,5 200 0,25000 0,25000 100,00000 4
6 12,0 1,02 0,6 0,4 160 0,33924 0,22616 90,46294 2
7 14,0 1,08 0,7 0,3 120 0,38898 0,16670 66,68191 4
8 16,0 1,18 0,8 0,2 80 0,38952 0,09738 38,95238 2
9 18,0 1,32 0,9 0,1 40 0,35218 0,03913 15,65239 4
10 20,0 1,50 1,0 0,0 0 0,29630 0,00000 0,00000 1
m = 6,371847 3,940839 1249,529748
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10
11 22
0
12 12 26,371847 127,436942
3 0, 4 3m
m
E Eb
=
= = = =
10
12
0
12 12 23,940839 78,816784
3 0, 4 3m
m
Eb
=
= = =
10
10 20
0
12 12 21249,529748 24.990,594953
3 0, 4 3
IV
m
m
E Eb
=
= = = =
1
2
127,436942 78,816784 24.990,5949530
78,816784 127,436942 24.990,594953
X
X
+ =
1 12 121,164332X M= =
2 21 121,164332X M= =
2
kN
kN
kNm
kN
kN
kNm
=
Q
0
-20,00000
-121,16433
0
-20,00000
121,16433
*
2 2 2
8
T
= =
Q T Q
2
5
7
3
6
0
-20,00000
-121,16433
0
-20,00000
121,16433
- Vektor ekvivalentnog optereenja sistema tapova:
* * *
*
* * *
0
s s s
o o
= = +
S Q RS
S Q R
Ovde je: - * 0s =R vektor sila zadatih u vorovima, u pravcima slobodnih koordinata sistema,
- *oR vektor sila u pravcima vezanih koordinata, odnosno reakcije oslonaca i ukljetenja
{ }* * *1 2 3 4 5 6 7 8
0 0 0 0 154,65439 20 342,68835 121,16433 T
s s s= + = S Q R
{ }*10 11 12
0 57,34561 0 0 0 0 T
o = Q
9 13 14
- Odreivanje pomeranja u pravcima slobodnih koordinata sistema:
Polazei od sistema uslovnih jednaina
* * *=K q S ,
odnosno* * * *
* * * *
ss so s s
os oo o o
=
K K q S
K K q S,
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dobijamo* * * * *
ss s so o s+ =K q K q S ,
odakle, uz uslov da su pomeranja u pravcima vezanih stepeni slobode jednaka nuli, tj. * 0o =q , imamo
* * *
ss s s=K q S .
Sada je vektor pomeranja u pravcima slobodnih koordinata sistema
* * 1 *
s ss s
=q K S ,
odnosno,
*
sE
=q3
2,057554 2,021380 1,999633 1,999633 -1,974472 1,952773 0,068042 0,069374
2,021380 2,021380 1,999633 1,999633 -1,974472 1,952773 0,068042 0,069374
1,999633 1,999633 2,021380 2,021380 -1,952773 1,974472 0,069374 0,068
10
042
1,999633 1,999633 2,021380 2,057554 -1,952773 1,974472 0,069374 0,068042
-1,974472 -1,974472 -1,952773 -1,952773 2,027603 -1,905999 -0,065594 -0,072383
1,952773 1,952773 1,974472 1,974472 -1,905999 2,027603 0,072383 0,06
0
0
0
0
154,65439
20,00000
342,68835
121,16
5594
0,068042 0,068042 0,069374 0,069374 -0,065594 0,072383 0,050610 -0,013846
0,069374 0,069374 0,068042 0,068042 -0,072383 0,065594 -0,013846 0,050610 433
3* 10s
E
= =
q
1
2
3
4
298, 02802 9, 934 mm
298, 02802 9, 934 mm
294,53343 9,818 mm
294,53343 9,818 mm
-306,70618 -10,224 mm
286,97138 9,566 mm
24,36251 0,00081 rad
11,26959 0,00038 rad
6
7
8
5
- Odreivanje reakcija oslonaca i oslonakih ukljetenja *oR :
Iz sistema uslovnih jednaina imamo, * * * * * * *0os s oo o o o+ = = +K q K q S Q R ,
Odakle je, za * 0o =q ,* * * *
o os s o= R K q Q
*
o
E
=
R 3
0 0 0 0 0 -0,062229 0 -0,746749
0 0 0 0 -0,062229 0 0,746749 0
0 -9,988902 0 0 -9,976466 0 -0,105699 0
0 -9,976466 0 0 -9,988902 0 0,105699 010
0 0 -9,988902 0 0 9,976466 0 -0,105699
0 0 9,976466 0 0 -9,988902 0 -0,105699
310
E
298,02802
298,02802 0
294,53343 -57,346
294,53343 0
-306, 70618 0
286,97138 0
24,36251 0
11,26959
*
o
= = =
= =
=
=
R
9
10
11
12
13
14
3
4
5
5
6
6
V -26,2735 kN
V 94,6243 kN
H 80,2963 kN
V 92,9664 kN
H -80,2963 kN
V 70,6828 kN
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- Vektori generalisanih pomeranja tapova u lokalnom koordinatnom sistemu:
3 3*
1 1 1
10 10
E E
= = =
q T q
-1 0 0 0 0 298,02802 -298,02802
0 -1 0 0 0 -306,70618 306,70618
0 0 1 0 0 24,36251 24,36251
0 0 0 -1 0 298,02802 -298,028020 0 0 0 -1 0 0
2
5
7
1
10
3 3*
2 2 2
8
10 10
E E
= = =
q T q
1 0 0 0 0 0 298,02802 298,02802
0 1 0 0 0 0 -306,70618 -306,70618
0 0 1 0 0 0 24,36251 24,36251
0 0 0 1 0 0 294,53343 294,53343
0 0 0 0 1 0 286,97138 286,9713
0 0 0 0 0 1 11,26959
2
5
7
3
6
8
11,26959
3 3*
3 3 3
10 10
E E
= = =
q T q
1 0 0 0 0 294,53343 294,53343
0 1 0 0 0 286,97138 286,971380 0 1 0 0 11,26959 11,26959
0 0 0 1 0 294,53343 294,53343
0 0 0 0 1 0 0
3
6
8
4
9
3 3*
4 4 4
10 10
E E
= = =
q T q
-0,7071 -0,7071 0 0 0 298,02802 6,13639
0,7071 -0,7071 0 0 0 -306,70618 427,61165
0 0 1 0 0 24,36251 24,36251
0 0 0 -0,7071 -0,7071 0 0
0 0 0 0,7071 -0,7071 0 0
2
5
7
11
12
3 3*
5 5 5
10 10
E E
= = =
q T q
0,7071 -0,7071 0 0 0 294,53343 5,34717
0,7071 0,7071 0 0 0 286,97138 411,18599
0 0 1 0 0 11,26959 11,26959
0 0 0 0,7071 -0,7071 0 0
0 0 0 0,7071 0,7071 0 0
3
6
8
13
14
- Vektori generalisanih sila na krajevima tapova u lokalnom koordinatnom sistemu:
Za tap j , j j j j= R k q Q
3
1 3
10
10
EI
EI
=
R
27,6442 0 0 -27,6442 0 -298,02802 00 0, 0622 0, 7467 0 -0, 0622 306, 70618 134,6544
0 0,7467 8,9610 0 -0,7467 24,36251 463,8
-27,6442 0 0 27,6442 0 -298,02802
0 -0,0622 -0,7467 0 0,0622 0
=
0-97,376
527 -16,508
0 0
57,3456 -94,624
3
2 3
10
10
EI
EI
=
R
022,9773 0 -22,9773 0 0 298,02802
0 0,1028 1,0284 0 -0,1028 1,0284 -306,706
0 1, 0284 12, 7080 0 -1, 0284 7, 8596
-22,9773 0 0 22,9773 0 0
0 -0,1028 -1, 0284 0 0,1028 -1, 0284
0 1, 0284 7, 8596 0 -1, 0284 12, 7080
=
0 80,296
18 -20,0000 -4, 409
24,36251 -121,1643 -91,189
294,53343 0 -80,296
286,97138 -20,0000 44,409
11,26959 121,1643 -396,997
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3
3 3
10
10
EI
EI
= =
R
27,6442 0 0 -27,6442 0 294,53343 0
0 0,0622 0,746749 0 -0,0622 286,97138 26,274
0 0,7467 8,9610 0 -0,7467 11,26959 315,282
-27,6442 0 0 27,6442 0 294,53343
0 -0,0622 -0,7467 0 0,0622 0
0
-26,274
3
4 3
10
10
EI
EI
= =
R
19,9654 0 0 -19,9654 0 6,13639 122,515
0 0,0124 0,1495 0 -0,0124 427,61165 8,959
0 0,1495 1,7969 0 -0,1495 24,36251 107,696
-19,9654 0 0 19,9654 0 0 -122,51
0 -0,0124 -0,1495 0 0,0124 0
5
-8,959
3
5 3
10
10
EI
EI
= =
R
19,9654 0 0 -19,9654 0 5,34717 106,758
0 0,0124 0,1495 0 -0,0124 411,18599 6,798
0 0,1495 1,7969 0 -0,1495 11,26959 81,715
-19,9654 0 0 19,9654 0 0 -106,758
0 -0,0124 -0,1495 0 0,0124 0
-6,798
Sile na krajevima tapova:
- Pomeranja vorova, reakcije oslonaca:
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- Dijagrami presenih sila: