Math

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TAKE THE CHALLEGE p. 62 1. If each of the fraction 3 a , 4 a , 5 a is in their lowest terms, which of the following could be the value of a ? a. 48 b. 49 c. 50 d. 51 Answer: The value of A is letter b. 49 2. A glass container has 120 marbles of different colors . There are 30 green marbles and 15 red marbles . The number of yellow marbles is three times as many as the red marbles and replaces them with yellow marbles. Answer: Original after answer Green = 30 12 a. _12 127 Red = 50 15 b. _70 127 Yellow = 45 70 c. _15 127 Others = 30 _30 TOTAL 127 3. We have learned proper and improper fractions . you are given 6 numbers : 2,3,5,7,11 and 13. Using 2 numbers each times , how many proper fractions can you form?

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Transcript of Math

TAKE THE CHALLEGE p. 621. If each of the fraction 3a, 4a,5a is in their lowest terms, which of the following col! "e the #ale of a $ a. %& ". %' c. () !. (1Answer*The #ale of A is letter ". %'2. A glass container has 12) mar"les of !i+erent colors . There are ,) green mar"les an! 1( re! mar"les . The nm"er of -ellow mar"les is three times as man- as the re! mar"les an! replaces them with -ellow mar"les.Answer* .riginal after answer Green/,) 12a.012 121 2e!/()1(".01) 121 3ellow / %(1)c.01(121 .thers / ,) 0,)T.TAL 121,. 4e ha#e learne! proper an! improper fractions . -o are gi#en 6 nm"ers * 2,,,(,1,11 an! 1,. 5sing 2 nm"ers each times , how man- proper fractions can -o form$6 6 7 (8 2 9 / 1( , therefore there are 1( proper fractions can form.Answer* 1( proper fractions. 23,25 ,27 , 211 , 213 ,35 ,37 , 311 , 313 ,57, 511, 513, 711 , 713 , 1113

%. Arrange the fractions "elow in or!er , from the smallest to the greatest .1999819999 1998919990 1999119992 1998819989 1999219993Answer*1998819989 ,1998919990 ,1999119992 ,1999219993 ,1999819999TAKE THE CHALLEGE p. &21. The height of the water in a container with a small pe""le in it is &14 cm. when a "igger pe""le is place! into the water , the water rises to 1)cm.in height. 4hen the small pe""le is ta:en ot , the water le#el !rops to &34 cm .4hat is the water le#el of the container when there is no pe""le$1) ; &34 / 1 34 &34 ;1 34 / 1Answer* 1 water le#el when there is no pe""le .2. Al"ert clim"e! a cocont tree. He clim"e!13 of the tree an! slippe! "ac: 14 of the total height . Then he clim"e!512 of the tree again . 4hat part of the tree is Al"ert locate! now$13 < 512 /912, 912 ; 14/ 612 or 12Answer* 12 part of the tree when Al"ert stoppe!.

TAKE THE CHALLEGE p. '21. A certain amont of mone- was !i#i!e! amongAnn , =o", an! Carol . Ann recei#e! 13 of the mone- pls >hp. 1).)) while =o" recei#e! 14 of the mone- pls >hp. 2).)) an! Carol recei#e! >hp. 2).)) . How mch !i! Ann an! =o" each recei#e! .?/ amont of mone-Ann/ 13 7 hp. 1).))=o"/ 147 < >hp. 2).))Carol / >hp. 2).))1 7/6 137< >hp. 1).))9 < 6 14 7 < >hp. 2).))9 hp. 2).)) 1 7 /13 7 ;14 7 / >hp 1).)) < >hp. 2).))< >hp 2).))12127 ; 4127;3127 / >hp. ().))126 512 7 / >hp. ().))9557 / 12 7 >hp. ().))?/Php600.005 ?/ 12)Ann/ 13 7 hp. 1).)) =o"/ 147 < >hp. 2).))/ 13 6 12)9 < >hp1).))/14 612)9 < php 2).)) / %) < php. 1).))/ ,) < >hp. 2).))/ >hp ().))/ >hp ().))Answer* >hp. ().)) each2. The sm of two nm"ers is (). The sm of14 of the @rst nm"er an!23 of the other nm"er is 2(. 4hat are the nm"ers$ a. 2) hp. &,()) more than >eter. If58 of >eterBs mone- was eCal to 27 of 2ogerBs mone- .a. How mch mone- !i! >eter ha!$>eter * 16 7 %() / >hp. 1, 2))". How mch mone- !i! the- ha#e altogether$>eter < 2oger / 6 16 hp %() / >hp 22, '()2.29 of Leonar!Bs stic:ers is eCal to 710 of Den-Bs stic:er s. If the- ha#e ,,2 stic:ers altogether ,LCE of 2 an! 1 / 1%a. How man- more stic:ers !oes Leonar! ha#e than Den- $Leonar!Bs 1463 / Den-Bs 1420Leonar!/ 6, "loc:s, Den-/ 2) "loc:s6,? % / 112". How man- stic:ers !oes Den- ha#e $2) 7 % / &) stic:ersE.FIGG T.4A2HA IGTE2GATI.GAL EATH C.GTEAT1. There are (% car!s in a set of pla-ing car!s. The @rst car! on top is the Ace ofApa!es .Threecar!s from the top are mo#e! to "ottom of the !ec: each time withot changing their or!er . How man- times !o -o nee! to !o this for the Ace of Apa!es to appear on top again$Answer* (%8, / 1& times2. 4hen fraction is !i#i!e! "- 59415 respecti#el-, the Cotients o"taine!in "oth cases are whole nm"ers . 4hat is the smallest possi"le #ale ifthis fraction$ Answer* 203 203 859=203 x 95=12203 415=203 x 154 / 2( ,. In badc= 11996 , "oth a an! " are 1 !igit nm"ers , "oth c an! ! are , !igit nm"ers, a is greater than ! , an! the !igit in the ones place of ! is %. Iin! the #ale of a, ", c an! !. Answer*a / %, " / ,, c/ %'' , !/ ,1%34374499=1,4971,4961996=11996%. 4hen ,)) sweets, 21) "iscits , an! 16, apples were share! eCall- among the ppils in a class , the ratio of the nm"er of remaining sweets to the nm"er of the remaining "iscits to nm"er of the remaining apple was 1*,*2. Iin! the nm"er of ppils in a class.Answer* 2, st!ents 1, r.1'r. , 1r. 223300 232102, 163 ; 2,; 2)1 ; 161 1), 2;6' 1(. There were 2 granaries, A an! = . The ratio of the mass of grain in granar- A tothe mass of granar- = was(*1 at @rst. After 6 tons of grain ha! "een transferre! from granar- = to granar- A. The ratio of themass of grain in granar- A to themass of grain in granar- = "ecame %* (. 4hat was the mass of grain in tons, each in granar- A an! granar- = at @rst$Answer* A/ ') an! = / 126(57 x 45) x 6 / 2( 76 /')2& 7 6 /16& ; %2 /1266. Atreet lamps are to "e installe! at eCal !istance apart along A=, a stretch of newl- constrcte! e7presse! wa-. There mst "e a street lamp each at point C, the mi!point of AC as well as the mi!point of =C. 4hat is the smallest possi"le nm"er of street lamps to "e installe! $ 12)cm &1)cmA = CAnswer* ,( street lampsA.&1)cm J 12)cm / ')cm=. ')cm J 2) cm / 1) cmC. 1) 8 2 / ,( PROJECT IN MATHEMATICSSubmitted by :RASBELLE MOICY FAYE A. DE VERASubmitted to : M. Ri!"do #ue$"do