Algebra 1 Glencoe McGraw-Hill JoAnn Evans Math 8H 12-2 Counting Outcomes.
Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.
-
Upload
erin-rodgers -
Category
Documents
-
view
215 -
download
1
Transcript of Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.
![Page 1: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/1.jpg)
Math 8H
Algebra 1 Glencoe McGraw-Hill JoAnn Evans
8-4 (day 2)More Factoring Practice
![Page 2: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/2.jpg)
+●
-24
266 -4-4
24x2y + 6xy – 9y
3y(2x - 1)(4x + 3) is the factored
form.
Check your solution!
3y(8x2 + 2x – 3)
Start every factoring problem by checking for a greatest common monomial factor.
![Page 3: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/3.jpg)
+●
150
3166 2525
10y2 + 31y + 15
(2y + 5)(5y + 3) is the factored form.
Check your solution!
![Page 4: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/4.jpg)
+●
-24
232424 -1-1
23x - 6 + 4x2 Put the polynomial in standard form before you begin to
factor.
(x + 6)(4x - 1) is the factored form.
4x2 + 23x – 6
![Page 5: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/5.jpg)
Practice Problems
4 - 25n + 25n2 x4 - 10x2 + 25
+●
100
-25-5-5 +
●
25
-10
-5-5-20-20 -5-5
(5n - 1)(5n - 4) (x2 - 5)(x2 - 5)
25n2 - 25n + 4 Notice the power of the first term.
![Page 6: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/6.jpg)
Solve Equations by Factoring (find the roots)
x2 = -8x
x2 + 8x = 0
x(x + 8)= 0
x = 0 or x + 8 = 0
0 or 8x =
Set the equation equal to 0.
Factor the polynomial completely.
Set each of the factors equal to 0.
![Page 7: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/7.jpg)
Solve Equations by Factoring (find the roots)
9y2 = 12y - 4
9y2 – 12y + 4 = 0
+●
36
-12
-6-6 -6-6
(3y – 2)(3y - 2)= 0
3y - 2 = 02
y3
Set the equation equal to 0. Make sure it’s in standard form.
Factor the polynomial completely.
Set each of the factors equal to 0.
![Page 8: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/8.jpg)
Find two consecutive positive even integers whose product is 80.
Let x = the 1st integer Let x + 2 = the 2nd integer1st integer 2nd integer = 80
x(x + 2) = 80x2 + 2x = 80
x2 + 2x – 80 = 0+●
-80
21010 -8-8
(x + 10) (x – 8) = 0
x = -10 or 8 Remember the problem asked for positive
consecutive even integers. Only one of the roots will fit the context of this problem.
The 1st integer is 8 and the 2nd integer is
10.
x + 10 = 0 or x – 8 = 0
![Page 9: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/9.jpg)
The width of a rectangular poster is 7 in. less than its length. If the poster’s area is 78 in2,
find the dimensions.
Let x = length Let x - 7 = width
length width = areax(x - 7) = 78
x2 - 7x = 78
x2 - 7x – 78 = 0+●
-78
-766 -13-13
(x + 6) (x – 13) = 0
x = -6 or 13Only the positive root makes sense in this
context. Length can’t be negative. Discard
the negative root.Length is 13 and
width is 6.
x
x - 7
![Page 10: Math 8H Algebra 1 Glencoe McGraw-Hill JoAnn Evans 8-4 (day 2) More Factoring Practice.](https://reader036.fdocuments.in/reader036/viewer/2022082709/56649ceb5503460f949b6338/html5/thumbnails/10.jpg)
The sum of the squares of two negative consecutive integers is 145. Find the integers.
Let x = 1st integer
Let x + 1 = 2nd integer
square of 1st + square of 2nd = 145x2 + (x + 1)2 = 145
x2 + (x + 1)(x + 1) = 145x2 + x2 + x + x + 1 = 145
+●
-72
199 -8-8
2x2 + 2x + 1 = 145
2x2 + 2x – 144 = 0
2(x2 + x – 72) = 0
2(x + 9)(x – 8) = 0
x + 9 = 0 or x – 8 = 0
x = -9 or 8
Which answer doesn’t make sense in the
context of this problem?
The integers are -9 & -8.