Markowitz Model

8
Markowitz Model 3-stock portfolio, short selling allow 1 . . 2 2 2 ( * 2 2 2 2 2 2 C B A C C B B A A BC C B AC C A AB B A C C B B A A w w w R R w R w R w t s w w w w w w w w w Min Eg. R A = 20% R B = 10% R C = 8% 2 A =100 2 B =25 2 C =16 AB = 15 AC = 20 BC = 4

description

Markowitz Model. For 3-stock portfolio, short selling allowed. Eg. R A = 20% R B = 10% R C = 8%  2 A =100  2 B =25  2 C =16  AB = 15  AC = 20  BC = 4. Markowitz Model. Form the Lagrangian. Markowitz Model: Solution. For R* = 15% w A = 50.214% - PowerPoint PPT Presentation

Transcript of Markowitz Model

Page 1: Markowitz Model

Markowitz Model

For 3-stock portfolio, short selling allowed

1

..

22

2(

*

222222

CBA

CCBBAA

BCCBACCA

ABBACCBBAA

www

RRwRwRwts

wwww

wwwwwMin

Eg. RA= 20% RB= 10% RC= 8% 2

A=100 2B=25 2

C=16 AB= 15 AC= 20 BC= 4

Page 2: Markowitz Model

Markowitz Model

Form the Lagrangian

01

01581020

0832840

010805030

0204030200

sderivative partial Take

)1(

8102015840

301625100

2

1

21

21

21

2

1

222

CBA

CBA

CBAC

CbAB

CbAA

CBA

CBABABA

BAAAA

wwwL

wwwL

wwww

L

wwww

L

wwww

L

www

wwwwwww

wwwwwL

Page 3: Markowitz Model

Markowitz Model: Solution

For R* = 15%wA = 50.214%wB = 48.715%wC = 1.075%

Standard Dev = 6.22%

For R* = 20%wA = 91%wB = 56%wC = -47% (short sale)

Standard Dev = 9.47%

Page 4: Markowitz Model

Single Index ModelRt= A + BRmt + et

E(Rt) = A + BE(Rmt)

Cov(ei,ek)=0E(ei)=0Cov(ei,Rm)=0

2p=Pi[Ri - E(R)]2

by substitution2=Pi[A + BRmt +ei -A - BE(Rm)]2

2=Pi{B[Rmi-E(Rm)] + ei}2

2=Pi{B2[Rmi-E(Rm)]2 +ei2+2B[Rmi-E(Rm)] ei}

2p= B2

p 2m + 2

e

Page 5: Markowitz Model

Single Index Model (Cont’d)

2p= B2

p2m + 2

ep

We also know that

Bp= Cov(Rp, Rm)/ 2m

Bp=wjBj2

ep= wj2 2

ej

Hence, the portfolio variance is:

2p= (xjBj )22

m + xj2 2

ej

Page 6: Markowitz Model

Single Index Model (Cont’d)

For 3-stock portfolio, short selling allowed

1

..

)(

*

2222

2222

CBA

CCBBAA

CCBB

AAMCCBBAA

www

RRwRwRwts

ww

wwwwMin

Eg. RA= 20% RB= 10% RC= 8% 2

A=20 2B=15 2

C=9 A= 1.5 B= 0.75 C= 0.50

Page 7: Markowitz Model

Single Index Model (Cont’d)

Form the Lagrangian

081020

01

082(9)w

)36)(50.0)(50.075.05.1(2

0102(15)w

)36)(75.0)(50.075.05.1(2

0202(20)w

)36)(5.1)(50.075.05.1(2

sderivative partial Take

)81020(

)1(9

152036)50.075.05.1(

*

2

1

21C

21B

21A

*2

12

222

RwwwL

wwwL

wwww

L

wwww

L

wwww

L

Rwww

wwww

wwwwwL

CBA

CBA

CBAC

CBAB

CBAA

CBA

cBAC

BACBA

Page 8: Markowitz Model

Single Index Model Solution

When R* = 15%

wA = 0.57wB = 0.08wC = 0.35

Standard Deviation =