Mark Scheme Summer 2008 - Higher Grade Maths · 4400 IGCSE Mathematics Summer 2008 Summer 2008...

46
Mark Scheme Summer 2008 IGCSE IGCSE Mathematics (4400) Edexcel Limited. Registered in England and Wales No. 4496750 Registered Office: One90 High Holborn, London WC1V 7BH

Transcript of Mark Scheme Summer 2008 - Higher Grade Maths · 4400 IGCSE Mathematics Summer 2008 Summer 2008...

Mark Scheme Summer 2008

IGCSE

IGCSE Mathematics (4400)

Edexcel Limited. Registered in England and Wales No. 4496750 Registered Office: One90 High Holborn, London WC1V 7BH

Edexcel is one of the leading examining and awarding bodies in the UK and throughout

the world. We provide a wide range of qualifications including academic, vocational,

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Through a network of UK and overseas offices, Edexcel’s centres receive the support

they need to help them deliver their education and training programmes to learners.

For further information please call our Customer Services on + 44 1204 770 696, or visit our website at www.edexcel-international.org.uk.

Summer 2008

Publications Code UG020267

All the material in this publication is copyright © Edexcel Ltd 2008

4400 IGCSE Mathematics Summer 2008

Contents

1. 4400/1F 5

2. 4400/2F 13

3. 4400/3H 21

4. 4400/4H 37

4400 IGCSE Mathematics Summer 2008

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

5

Sum

mer

2008 IG

CSE M

ath

s M

ark

Schem

e –

Paper

1F

Q

Work

ing

Answ

er

Mark

N

ote

s

1.

(a)

7006

1

B1

cao

(b

)

9000

1

B1

cao

(c

)

hundre

ds

1

B1

Accept

500,

100

(d

)

326

1

B1

cao

Tota

l 4 m

ark

s

2.

(a)(

i)

cuboid

1

B1

Accept

recta

ngula

r box

(i

i)

pri

sm

1

B1

Condone o

mis

sion o

f ‘p

enta

gonal’

(i

ii)

cone

1

B1

(b

)

8

1

B1

cao

Tota

l 4 m

ark

s

3.

(a)

Egypt

and M

ala

ysi

a

1

B1

(b

)(i)

20

3

B1

cao

(i

i)

100

20

M

1

for

100

20

""

51

A1

ft f

rom

“20”

(c

)

14

1

B1

Accept

13 o

r 14

(d

)(i)

Kenya

2

B1

(

ii)

0.4

3

B1

cao

(e

)(i)

35 <

bar<

40

2

B1

(

ii)

61

B1

cao

Tota

l 9 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

6

4.

(a)

1

B1

(b

) 10 ×

2 +

1

2

M1

21

A1

cao

(c

)

2

137−

2

M1

18

A1

cao

(d

) eg 6

0 is

even,

num

ber

of

stic

ks

is a

lways

odd,

firs

t num

ber

is o

dd a

nd 2

is

added e

ach t

ime,

mult

iply

ing b

y 2

and a

ddin

g 1

will alw

ays

giv

e a

n

odd n

um

ber

of

stic

ks

1

B1

May r

efe

r to

num

ber

sequence o

f st

ick p

att

ern

– n

eed n

ot

do b

oth

(e

)

n =

2p +

1

3

B3

for

n =

2p +

1 o

e

eg n

= p

2 +

1,

1 +

p ×

2 =

n

B2 f

or

2p +

1 o

e B

1 f

or

n =

lin

ear

functi

on o

f p e

g n

= p

+ 1

Tota

l 9 m

ark

s

5.

(a)

25 −

18

2

M1

for

25 −

18,

18-2

5,

18 t

o 2

5 e

tc

7

A1

cao

(b

) 18 1

9 2

1 2

2 2

3 2

4 2

4 2

5

or

22,

23 o

r 28

or

4 o

r 29

or

2

M1

Als

o a

ward

for

18 1

9 2

1 2

2 2

3 2

4 2

5

i.e.

wit

h o

ne 2

4 o

mit

ted

22.5

A1

cao

Tota

l 4 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

7

6.

(a)

24

2

B2

B2 f

or

23-2

5 inc B

1 f

or

22 o

r 26

(b

) 6 ×

2 +

(2

05

4.

) × 2

oe

2

M1

for

6 ×

2 +

(2

05

4.

) × 2

oe

20.6

-21.4

A1

for

20.6

-21.4

inc

SC if

M0,

aw

ard

B1 f

or

20

(c

)

0

1

B1

Accept

‘none’,

‘zero

(d

)

2

1

B1

cao

(e

)(i)

115°-1

19°

2

B1

(i

i)

obtu

se

B1

(f

)

4 ,

3

2

B2

B1 f

or

4 B

1 f

or

3

Tota

l 10 m

ark

s

7.

(a)

2p

1

B1

Accept

p2,

2 ×

p e

tc

(b

)

4xy

1

B1

Accept

xy4,

xy e

tc

(c

)

9g −

5h

2

B2

B1 f

or

9g B

1 f

or −

5h o

r + −

5h

Tota

l 4 m

ark

s

8.

(a)(

i)

27

1

B1

cao

(i

i)

20

1

B1

cao

(i

ii)

25

1

B1

cao

(i

v)

23

1

B1

cao

(b

)

95

2

M1

A1

fracti

on w

ith

denom

inato

r of

9

num

era

tor

of

5

or

B2 f

or

0.5

5,

0.5

6,

55%,

56% o

r bett

er

but

not

for

0.6

, 60%

B1 f

or

5 in 9

, 5 :

9

5 o

ut

of

9

Tota

l 6 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

8

9.

(a)

188

, 27

12

etc

1

B1

(b

) 65 ÷

5 o

r 13 o

r 4 ×

65 o

r 260

2

M1

52

A1

cao

(c

) 0.8

75

0.9

0.8

5

0.8

8

2

M1

2 f

racti

ons

convert

ed t

o d

ecim

als

or

perc

enta

ges

or

fracti

ons

wit

h t

he s

am

e d

enom

inato

r

109

25

22

87

20

17

A1

SC if

M0,

aw

ard

B1 f

or

3 f

racti

ons

in c

orr

ect

ord

er

Tota

l 5 m

ark

s

10.

180 −

2 ×

73 o

e

3

M2

for

180 −

2 ×

73 o

e

M1 f

or

unm

ark

ed b

ase

angle

identi

fied a

s 73° o

r 146° s

een

34

A1

cao

Tota

l 3 m

ark

s

11.

(a)(

i)

6859

2

B1

cao

(

ii)

6860

B1

cao

(b

)

4.2

28

.17

2

M1

for

17.2

8 o

r 2.4

or −

0.1

14..

. s

een

7.2

A1

for

7.2

oe inc

517

and

536

Tota

l 4 m

ark

s

12.

2 a

rcs,

radiu

s 6 c

m,

centr

es

A a

nd B

2

M1

tria

ngle

wit

hin

guid

elines

A1

Tota

l 2 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

9

13.

(a)

23500

1008

. o

r 1128

3

M1

23 5

00 +

“1128”

M1

(dep)

or

M2 f

or

23 5

00 ×

1.0

48 o

e

24 6

28

A1

cao

(b

) 29 8

32 −

28 2

50 o

r 1582

3

M1

Als

o a

ward

for

15.8

2

100

28250

1582

× o

r 100

29832

1582

×

M1

for

28250

1582

or

29832

1582

or

0.0

56

or

0.0

53…

or

M1 f

or

28250

29832

or

1.0

56

or

105.6

M

1 f

or

“1.0

56” −

1

or

“105.6

” −

100

or

M1 f

or

29832

28250

or

0.9

469..

. or

94.6

9..

. M

1 f

or

1 −

“0.9

469”

or

100 −

“94.6

9”

5.6

A1

cao (

Do N

OT a

ward

for

5.3

)

Tota

l 6 m

ark

s

14.

2

60

1.

2

M1

for

1 −

0.6

or

0.4

or

2x w

here

0 <

x <

1

0.2

oe

A1

for

0.2

oe

Tota

l 2 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

10

15.

(a)

Enla

rgem

ent

scale

facto

r 2 c

entr

e (

1,

3)

3

B3

B1 f

or

enla

rgem

ent,

enla

rge e

tc

B1 f

or

2,

× 2

, tw

o,

12,

1 :

2,

2 :

1

B1 f

or

(1,

3)

Condone o

mis

sion o

f

bra

ckets

but

do n

ot

accept

⎟⎟ ⎠⎞⎜⎜ ⎝⎛ 31

(b

) Refl

ecti

on in t

he lin

e y

= x

2

B2

B1 f

or

refl

ecti

on,

refl

ect

etc

B1 f

or

y =

x o

e

inc e

g ‘

in lin

e f

rom

(2,2

) to

(5,5

)’,

‘in

dott

ed lin

e s

how

n’

These

mark

s are

in

dependent

but

aw

ard

no

mark

s if

answ

er

is n

ot

a s

ingle

tr

ansf

orm

ati

on

Tota

l 5 m

ark

s

16.

3 +

1 o

r 4 s

een

2

M1

for

3 +

1 o

r 4 s

een

210

A1

for

210 c

ao

Tota

l 2 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

11

17.

(a)(

i)

1,

9,

17

2

B1

cao

(

ii)

1,

5,

9,

13,

17,

25,

33

B1

cao (

B0 if

1 o

r 9 o

r 17 r

epeate

d)

Bra

ckets

not

necess

ary

(b

) eg N

o m

em

bers

in c

om

mon.

The inte

rsecti

on is

em

pty

. N

one o

f th

e m

em

bers

of

A &

C a

re t

he s

am

e.

They d

on’t

have t

he s

am

e n

um

bers

. N

o n

um

bers

are

in b

oth

A a

nd C

.

1

B1

Tota

l 3 m

ark

s

18.

(a)

2

38×

oe

2

M1

for

2

38×

oe

12

A1

cao

(b

) 375

.0

83ta

n=

x

3

M1

A1

for

tan

for

83 o

r 0.3

75

or

M1 f

or

sin f

ollow

ing

corr

ect

Pyth

agora

s and

A1 f

or

0.3

511..

. or

M1 f

or

cos

follow

ing

corr

ect

Pyth

agora

s and

A1 f

or

0.9

363..

.

20.6

A1

for

20.6

or

bett

er

(A

ccept

20.5

5604…

rounded o

r tr

uncate

d t

o 4

sig

fig

s or

more

)

Tota

l 5 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

12

19.

(a)

7x −

7 =

5 −

2x

7x +

2x =

5 +

7 o

r 9x =

12

3

M1

M1

for

7x −

7 s

een

for

7x +

2x =

5 +

7 o

r 9x =

12

or

for

7x +

2x =

5 +

1 o

r 9x =

6 f

ollow

ing 7

x −

1 =

5 −

2x

31

1 o

e

A1

for

311

oe inc

34,

912

, 3.

1&,

1.3

3

(b

)(i)

16

4≤

x

4

M1

for

16

4≤

x

4

≤x

A1

for

4≤

x

(

ii)

1

2

3

4

B2

B1 f

or

3 c

orr

ect

and n

one w

rong

or

for

4 c

orr

ect

and 1

wro

ng

Tota

l 7 m

ark

s

20.

(i)

57.5

2

B1

Accept

94.

57

&,

57.4

99,

57.4

999 e

tc

(i

i)

56.5

B1

cao

Tota

l 2 m

ark

s

21.

4

M1

for

findin

g p

roducts

f ×

x c

onsi

stentl

y w

ithin

inte

rvals

(in

c e

nd p

oin

ts)

and s

um

min

g t

hem

55 ×

7 +

65 ×

21 +

75 ×

15 +

85 ×

14 +

95 ×

3

or

385 +

1365 +

1125 +

1190 +

285 o

r 4350

M

1

(dep)

for

use

of

half

way v

alu

es

(55,

65,

...

)

or

(55.5

, 65.5

, ..

.)

60

4350

""

M

1

for

60

4350

""

(dep o

n 1

st M

1)

for

div

isio

n b

y 6

0

or

for

60

"4380

"if

55.5

, 65.5

, ..

. use

d

72.5

A1

for

72.5

Accept

73 if

firs

t tw

o M

mark

s aw

ard

ed

Tota

l 4 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

13

Sum

mer

2008 IG

CSE M

ath

s M

ark

Schem

e –

Paper

2F

Q

W

ork

ing

Answ

er

Mark

N

ote

s

1.

(a)

800,

888,

1008,

1080,

1800

1

B1

This

ord

er

(b

)

-7

1

B1

(c

)

8,

14

2

B1B1

-B1 e

ach e

xtr

a

(d

)

1,

5,

7,

35

2

B2

B1 f

or

any t

wo,

wit

h n

o e

xtr

as.

Tota

l 6 m

ark

s

2.

(a)

12

1

B1

(b

)

7

1

B1

(c

)

Dave’s

Sport

s 1

B1

or

Sport

s or

Dave o

r th

e 4

th o

ne

(d

)

41/

4 c

ircle

s dra

wn

1

B1

Allow

if

inte

nti

on c

lear

Tota

l 4 m

ark

s

3.

(a)

5/8

1

B1

(b

)

3 s

ecto

rs s

haded

1

B1

Allow

if

inte

nti

on c

lear

Tota

l 2 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

14

4.

(a)(

i)

48,

96

2

B1B1f

Allow

wri

tten in t

he s

equence,

wit

h

noth

ing o

n lin

e o

r w

ith 1

92,

384 o

n lin

e

ft d

ep o

n f

irst

num

ber ≥

24

(a

)(ii)

x 2

oe

1

B1

or

doubling e

tc

(b

)(i)

8,

6

2

B1B1d

ep

(b

)(ii)

0

1

B1

(b

)(iii)

10 –

99x2 o

e

-188

2

M1

A1

Allow

10 –

100x2

or

-190

cao

Tota

l 8 m

ark

s

5.

(a)

Is

osc

ele

s 1

B1

Allow

any r

ecognis

able

spellin

g

(b

)

B &

D

1

B1

(c

)(i)

Enla

rgem

ent

1

B1

or

enla

rge o

r enla

rged o

r enla

rgin

g e

tc

Tota

l 3 m

ark

s

6.

(i)

Mark

A

A a

t 0.5

1

B1

(i

i)

Mark

B

B a

t 1

1

B1

(i

ii)

Mark

C

C 1

cm

– 3

cm

fro

m O

1

B1

If n

o c

ross

, m

ark

the p

oin

t on t

he lin

e

level w

ith t

he c

entr

e o

f th

e lett

er.

If

no

lett

ers

show

n,

no m

ark

s.

Tota

l 3 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

15

7.

(a)(

i)

m

or

cm

1

B1

(a

)(ii)

to

nnes

or

kg

1

B1

Not

ton

(a

)(iii)

m2,

are

, hecta

re

1

B1

or

metr

e s

quare

d o

r sq

uare

metr

e

(b

) 5.2

x 1

0 0

00

52 0

00

2

M1

A1

or

100 ×

100

Tota

l 5 m

ark

s

8.

(a)

12 –

(-4

) or

12 +

4 o

r -1

6

16

2

M

1

A1

Allow

wit

hout

bra

cket

(b

) -4

–3

-7

2

M

1

A1

Tota

l 4 m

ark

s

9.

(a)

1525

1

B1

Allow

wit

h a

ny p

unctu

ati

on o

r none

(b

) Att

em

pt

dif

fere

nce 3

:25 t

o 5

:10

1 h

our

+ 3

5 m

in +

10 m

in

1h 4

5m

ins

3

M1

M1

A1

Accept

1.8

5,

1hr

85m

in,

2.1

5,

2hr

15m

in

or

60 +

35 +

10,

120 –

15,

2hr

– 15m

in

cao

Tota

l 4 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

16

10.

(a)

70

1

B1

(b

) 180 –

(30 +

70)

80

2

M1

A1f

ft “

70” if

use

d.

(c

) 360 –

(70 +

130 +

85)

75

2

M1

A1

or

360 -

285

Tota

l 5 m

ark

s

11.

(a)

Measu

re a

ngle

s fo

r w

alk

& b

ike

“90”/ “

60” x

28 o

e

42 (

± 2

)

3

M1

M1

A1

Walk

60,

Bik

e 9

0,

allow

2o e

rror

Accept

“90”/”60”,

“60”/”90”,

“60”/”28”,

“2.1

4”,

“28”/”60”,

“0.4

66”

Inte

ger

requir

ed

(b

) 50/150 x

360

120

o

2

M1

A1

Accept

50/150,

150/50,

360/150,

150/360

cao

Tota

l 5 m

ark

s

12.

(a)

580 x

0.1

0 or

58(.

00)

+ 4

£62.(

00)

3

M1

M1

A1

dep

(b

) 78.6

0 –

4(.

00)

or

78.6

0/0.1

0

“74.6

0” /

0.1

0 o

e

746(.

00)

3

M1 M

1

A1

786 -

40

Tota

l 6 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

17

13.

(a)

3:5

1

B1

or

3 t

o 5

(b

) 15/40

3/

8

2

M1

A1

or

0.3

75

or

37.5

%

cao

Tota

l 3 m

ark

s

14.

(a)

6

1

B1

(b

) 8w

= 1

7 +

7

3

2

M1

A1

(c

) 6x –

2x =

7 –

13 o

r 2x –

6x =

13 -

7

4x =

-6 o

r –4

x =

6

x =

-1 ½

oe

3

M1

M1

A1

6x -

2x +

13 –

7 =

0 o

r 2x -

6x –

13 +

7 =

0

Accept

-6/4 o

r -3

/2 (

not

6/-4

or

3/-2

)

(d

) y –

2 x

5 =

4 x

5

or

y/5 =

4 +

2

y =

30

2

M1

A1

Tota

l 8 m

ark

s

15.

(a)

250±2

2

B2

B2 f

or

angle

248 t

o 2

52 inclu

sive.

B1 f

or

angle

190 t

o 2

60 inclu

sive

(b

)

305±3

2

B2

Aw

ard

B1 f

or

a b

eari

ng

270

o <

angle

< 3

60

o

Tota

l 4 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

18

16.

(a)

20/2 o

r (2

0 +

1)/

2

6

2

M1

A1

(b

)

Yes,

no o

r not

nec’y

w

ith c

onsi

stent

reaso

n

2

B2

Can’t

tell

B1

Tota

l 4 m

ark

s

17.

(a)

3 –

5 x

-2

13

2

M1

A1

(b

)

5y -

10

1

B1

(c

)

w

(w +

5)

2

B2

B1 f

or

two f

acto

rs t

hat

mult

iply

to g

ive a

t le

ast

one c

orr

ect

term

.

SC

w(w

+ 5

w)

B1

Tota

l 5 m

ark

s

18.

(a)

30 x

0.2

6

2

M1

A1

or

30 ÷

5

(b

) 0.2

+ 0

.1

0.3

oe

2

M1

A1

Tota

l 4 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

19

19.

8/12 o

r 3/12

8/

12,

3/

12

2

M1

A1

Accept

(4x2)/

(4x3)

or

(3x1)/

(4x3)

SC

Mult

iply

bs

by 1

2

B1

Decim

al m

eth

ods

M0 A

0

Tota

l 2 m

ark

s

For

oth

er

resp

onse

s not

covere

d b

y t

his

mark

schem

e b

ut

whic

h,

in y

our

opin

ion,

may b

e w

ort

hy o

f cre

dit

, se

nd t

o r

evie

w.

20.

(a)

3

14

1

B1

(b

)

73

1

B1

(c

)

3

72

5

55

=n

or

n

+ 3

– 7

= 2

n =

6

2

M1

A1

Accept

5n+3 =

59

Tota

l 4 m

ark

s

21.

½

x 3

x 4

3 x

15 a

nd 4

x 1

5 a

nd 5

x 1

5

192

4

M1

M2

A1

M1 f

or

any O

NE o

f th

ese

cao

Tota

l 4 m

ark

s

22.

8x =

12 o

r 8y =

-4

x =

1.5

o

e

y =

-0.5

oe

3

M1

A1

A1

Elim

inate

one v

ari

able

corr

ectl

y.

Accept

3x +

5x –

8 =

4 o

r 5(4

– y

)/3 –

y =

8 o

e

Tota

l 3 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

20

23.

(a)

4.8

1

B1

(b

) 5

2 -

“4.8

”2

or

1.9

6

\/(5

2 -

“4.8

”2)

1.4

3

M1

M1dep

A1

cao

Tota

l 4 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

21

Sum

mer

2008 IG

CSE M

ath

s M

ark

Schem

e –

Paper

3H

Q

W

ork

ing

Answ

er

Mark

N

ote

s

1.

4.2

28

.17

2

M1

for

17.2

8 o

r 2.4

or −

0.1

14..

. s

een

7.2

A1

for

7.2

oe inc

517

and

536

Tota

l 2 m

ark

s

2.

2

60

1.

2

M1

for

1 −

0.6

or

0.4

seen

or

2x w

here

0 <

x <

1

0.2

oe

A1

for

0.2

oe

Tota

l 2 m

ark

s

3.

(a)

Enla

rgem

ent

scale

facto

r 2 c

entr

e (

1,

3)

3

B3

B1 f

or

enla

rgem

ent,

enla

rge e

tc

B1 f

or

2,

× 2

, tw

o,

12,

1 :

2,

2 :

1

B1 f

or

(1,

3)

Condone o

mis

sion o

f

bra

ckets

but

do n

ot

accept

⎟⎟ ⎠⎞⎜⎜ ⎝⎛ 31

(b

) Refl

ecti

on in t

he lin

e y

= x

2

B2

B1 f

or

refl

ecti

on,

refl

ect

etc

B1 f

or

y =

x o

e

inc e

g ‘

in lin

e f

rom

(2,2

) to

(5,5

)’,

‘in

dott

ed lin

e s

how

n’

These

mark

s are

in

dependent

but

aw

ard

no

mark

s if

answ

er

is n

ot

a

single

tr

ansf

orm

ati

on

Tota

l 5 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

22

4.

3 +

1 o

r 4 s

een

2

M1

for

3 +

1 o

r 4 s

een

210

A1

for

210 c

ao

Tota

l 2 m

ark

s

5.

(a)(

i)

1,

9,

17

2

B1

cao

(

ii)

1,

5,

9,

13,

17,

25,

33

B1

cao

(B0 if

1,

9 o

r 17 r

epeate

d)

Bra

ckets

not

necess

ary

(b

) eg N

o m

em

bers

in c

om

mon.

The inte

rsecti

on is

em

pty

. N

one o

f th

e m

em

bers

of

A &

C a

re t

he s

am

e.

They d

on’t

have t

he s

am

e n

um

bers

. N

o n

um

bers

are

in b

oth

A a

nd C

.

1

B1

Tota

l 3 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

23

6.

375

.0

83ta

n=

x

3

M1

A1

for

tan

for

83 o

r 0.3

75

or

M1 f

or

sin a

nd

"73

"3fo

llow

ing

corr

ect

Pyth

agora

s and A

1 f

or

0.3

511..

. or

M1 f

or

cos

and

"73

"8fo

llow

ing

corr

ect

Pyth

agora

s and A

1 f

or

0.9

363..

.

20.6

A1

for

20.6

or

bett

er

(A

ccept

20.5

5604…

rounded o

r tr

uncate

d t

o 4

sig

fig

s or

more

)

Tota

l 3 m

ark

s

7.

π

× 7

.8 o

r 2π

× 3

.9

2

M1

for π

× 7

.8 o

r 2π

× 3

.9

24.5

A1

for

24.5

or

for

answ

er

whic

h r

ounds

to

24.4

9,

24.5

0 o

r 24.5

1

(π →

24.5

044…

3.1

4 →

24.4

92

3.1

42 →

24.5

076)

Tota

l 2 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

24

8.

(a)

n =

2p +

1 o

e

3

B3

for

n =

2p +

1 o

e

eg n

= p

2 +

1,

1 +

p ×

2 =

n,

n =

p +

p +

1

B2 f

or

2p +

1 o

e

B1 f

or

n =

lin

ear

functi

on o

f p e

g n

= p

+

1

(b

) 2p =

n −

1 o

r 21

2+

=p

n

2

M1

for

2p =

n −

1 o

r 21

2+

=p

n

2

1−n

oe

A1

for

2

1−n

oe inc

21

2−

n

Tota

l 5 m

ark

s

9.

(a)

7x −

7 =

5 −

2x

7x +

2x =

5 +

7 o

r 9x =

12

3

M1

M1

for

7x −

7 s

een

for

7x +

2x =

5 +

7 o

r 9x =

12

or

for

7x +

2x =

5 +

1 o

r 9x =

6 f

ollow

ing 7

x −

1 =

5 −

2x

31

1 o

e

A1

for

311

oe inc

34,

912

, 3.

1&,

1.3

3

(b

)(i)

16

4≤

x

4

M1

for

16

4≤

x

4

≤x

A1

for

4≤

x

(i

i)

1

2

3

4

B2

B1 f

or

3 c

orr

ect

and n

one w

rong

or

for

4 c

orr

ect

and 1

wro

ng

Tota

l 7 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

25

10.

(a)

29 8

32 −

28 2

50 o

r 1582 s

een

3

M1

M

1

for

28250

1582

or

29832

1582

or

0.0

56 o

r 0.0

53…

or

M1 f

or

28250

29832

or

1.0

56

or

105.6

M

1 f

or

“1.0

56” −

1

or

“105.6

” −

100

or

M1 f

or

29832

28250

or

0.9

469..

. or

94.6

9..

. M

1 f

or

1 −

“0.9

469”

or

100 −

“94.6

9”

5.6

A1

cao (

Do N

OT a

ward

for

5.3

)

(b

)

052

.128141

or

2.105

100

28141×

3

M2

for

052

.128141

or

2.105

100

28141×

M1 f

or

2.105

28141

, 105.2

%=28141

or

267.5

(0)

seen

26

750

A1

cao

Tota

l 6 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

26

11.

(a)

70

60

≤<

p

1

B1

Accept

60-7

0

(b

) 4

M1

for

findin

g a

t le

ast

four

pro

ducts

f ×

x c

onsi

stentl

y w

ithin

in

terv

als

(in

c e

nd p

oin

ts)

and s

um

min

g t

hem

55 ×

7 +

65 ×

21 +

75 ×

15 +

85 ×

14 +

95 ×

3

or

385 +

1365 +

1125 +

1190 +

285 o

r 4350

M

1

(dep)

for

use

of

half

way v

alu

es

(55,

65,

...

)

or

(55.5

, 65.5

, ..

.)

60

4350

""

M

1

60

4350

""

(dep o

n 1

st M

1)

for

div

isio

n b

y 6

0

or

for

60

"4380

"if

55.5

, 65.5

, ..

. use

d

72.5

A1

for

72.5

Aw

ard

4 m

ark

s fo

r 7

3 if

firs

t tw

o M

mark

s aw

ard

ed

(c

) 30 (

or

30½

) in

dic

ate

d o

n g

raph o

r st

ate

d

2

M1

for

30 (

or

30½

) in

dic

ate

d o

n g

raph o

r st

ate

d

124 o

r 125

A1

Accept

any v

alu

e in r

ange 1

24-1

25 inc

eg 1

24,

124.5

, 125

(d

) U

se o

f p =

131 o

n g

raph

2

M1

for

use

of

p =

131 s

how

n o

n g

raph o

r im

plied b

y 4

7,

48 o

r 49 s

tate

d

12

A1

Accept

any v

alu

e in r

ange 1

1-1

3 inc

Tota

l 9 m

ark

s

12.

3

2 o

r 9 o

r valu

e w

hic

h r

ounds

to

3.3

9 s

een

2

M1

for

32 o

r 9 o

r valu

e w

hic

h r

ounds

to 3

.39 s

een

36

A1

for

36 c

ao

Tota

l 2 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

27

13.

fi

nds

int

angle

of

hexagon

6

180

)2

6(×

finds

ext

angle

of

hexagon

6

360

5

M1

for

6

180

)26(

×−

or

6

360

120

60

A1

for

120 o

r 60

Aw

ard

M1 A

1 f

or

in

t angle

of

hexagon s

how

n a

s 120°

or

ext

angle

sh

ow

n a

s 60°

on

pri

nte

d d

iagra

m

or

on c

andid

ate

’s

ow

n d

iagra

m

If t

here

is

clear

evid

ence

the c

andid

ate

th

inks

the

inte

rior

angle

is

60° o

r th

e

exte

rior

angle

is

120°,

do n

ot

aw

ard

these

tw

o m

ark

s.

int

angle

of

poly

gon =

150

or

ext

angle

of

poly

gon =

30

B1

int

angle

of

poly

gon =

150

or

ext

angle

of

poly

gon =

30

Aw

ard

B1 f

or

int

angle

of

poly

gon

show

n a

s 150°

or

ext

angle

show

n

as

30° o

n p

rinte

d d

iagra

m o

r on

candid

ate

’s o

wn d

iagra

m

30

360

or

150

)2(

180

=−

nn o

e

M1

for

30

360

or

150

)2(

180

=−

nn o

e

12

A1

for

12 c

ao

Aw

ard

no m

ark

s fo

r an a

nsw

er

of

12 w

ith n

o w

ork

ing.

Aw

ard

5 m

ark

s fo

r an a

nsw

er

of

12 if

at

least

2 o

f th

e

pre

vio

us

4 m

ark

s sc

ore

d.

Tota

l 5 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

28

14.

(a)

5(2

y −

3)

1

B1

cao

(b

)

3pq(3

p +

4q)

2

B2

B1 f

or

3pq(…

) or

…(3

p +

4q)

or

3p(3

pq +

4q

2)

or

3q(3

p2 +

4pq)

or

pq(9

p +

12q)

or

3(3

p2q +

4pq

2)

ie

for

two f

acto

rs,

one o

f w

hic

h is

3pq o

r (3

p +

4q),

or

for

corr

ect,

but

incom

ple

te,

facto

risa

tion

(c

)(i)

(x −

2)(

x +

8)

3

B2

B1 f

or

one c

orr

ect

facto

r or

(x

+ 2

)(x −

8)

(

ii)

2,

−8

B1

ft f

rom

(i)

if

two lin

ear

facto

rs

Tota

l 6 m

ark

s

15.

(a)(

i)

57.5

2

B1

for

57.5

, 9

4.57

&,

57.4

99,

57.4

999 e

tc

but

NO

T f

or

57.4

9

(i

i)

56.5

B1

for

56.5

Als

o a

ccept

56.5

0

(b

) 62.5

− “

56.5

2

M1

for

62.5

− “

56.5

” A

ccept

94.

62

&,

62.4

99,

62.4

999 e

tc inst

ead

of

62.5

6

A1

for

6,

9.5&

, 5.9

99 e

tc

ft f

rom

“56.5

Tota

l 4 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

29

16.

(a)

95

95×

2

M1

for

95

95×

81

25

A1

for

81

25

or

0.3

1 o

r bett

er

Sam

ple

space m

eth

od

– aw

ard

2 m

ark

s fo

r a

corr

ect

answ

er,

oth

erw

ise n

o m

ark

s

(b

) 91

91×

or

811

3

M1

for

91

91×

or

811

SC

M1 f

or

81

91×

or

721

91

91×

× 4

oe

M1

for

91

91×

× 4

oe

M1 f

or

81

91×

× 4

oe

814

A1

for

814or

0.0

5 o

r bett

er

Sam

ple

space m

eth

od

– aw

ard

3 m

ark

s fo

r a

corr

ect

answ

er,

oth

erw

ise n

o m

ark

s

Tota

l 5 m

ark

s

17.

(a)

hk

d=

3

M1

for

hk

d=

but

not

for

hd=

Als

o a

ward

for

d =

som

e n

um

eri

cal valu

e ×

h

54 =

15k

M1

for

54 =

15k

Als

o a

ward

for

225

54

k=

h

6.3

oe

A1

for

h6.

3 o

e

Aw

ard

3 m

ark

s if

answ

er

is

hk

d=

but

k is

evalu

ate

d a

s 3.6

oe in a

ny p

art

(b

)

28.8

1

B1

ft f

rom

“3.6

8 × e

xcept

for

k =

1,

if a

t le

ast

M1 s

core

d in

(a)

(1 d

.p.

accura

cy o

r bett

er

in f

ollow

thro

ugh)

(c

)

"6.

3"

2.61

=h

2

M1

for

"6.

3"

2.61

=h

except

for

k =

1

289

A1

cao

Tota

l 6 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

30

18.

°=

°64

sin

8.6

35

sina

3

M1

for

corr

ect

state

ment

of

Sin

e r

ule

°°

=64

sin

35

sin

8.6

a

M1

for

corr

ect

rearr

angem

ent

4.3

4

A1

for

4.3

4 o

r 4.3

395…

rounded o

r tr

uncate

d t

o 4

fig

ure

s or

more

Tota

l 3 m

ark

s

19.

2

B1

for

use

of

22

8=

or

16

28

for

mult

iplicati

on o

f num

era

tor

and d

enom

inato

r by

2 o

r

8

(in e

ither

ord

er)

eg

8

12

=2

212

=22

221

=4

212

8

12

=2

212

=22

26×

=2

26

8

12

=88

8

12×

=8

812

=2

22

8

12

=22

8

12×

=162

12

B1

SC B

1 f

or

16

312=

or

for

both

18

8

144

8

12

2

==

⎟ ⎠⎞⎜ ⎝⎛

and

18

29

)2

3(2

=

NB o

nly

tota

l of

1 m

ark

for

eit

her

of

these

appro

aches

Tota

l 2 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

31

20.

(a)(

i)

59

2

B1

cao

(i

i)

angle

at

the c

entr

e

= t

wic

e a

ngle

at

the c

ircum

fere

nce

or

angle

at

the c

ircum

fere

nce

= h

alf

the a

ngle

at

the c

entr

e

B1

Thre

e k

ey p

oin

ts m

ust

be m

enti

oned

1.

angle

at

centr

e/m

iddle

/O

/ori

gin

2.

twic

e/double

/2× o

r half

/21

as

appro

pri

ate

3.

angle

at

cir

cum

fere

nce/edge/peri

mete

r

(N

OT e

.g.

angle

R,

angle

PRQ

, angle

at

top,

angle

at

outs

ide)

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

32

for

180 −

(x +

36)

oe s

een,

eit

her

on its

ow

n o

r as

part

of

an

equati

on

(This

mark

may s

till b

e s

core

d,

even if

bra

ckets

are

late

r re

moved incorr

ectl

y.)

20.

(b)

180 −

(x +

36)

oe s

een (

poss

ibly

m

ark

ed o

n d

iagra

m a

s si

ze

of

ACB

∠)

5

B1

SC

(Max o

f 2 M

mark

s)

for

om

issi

on o

f bra

ckets

in −

(x +

36)

or

their

in

corr

ect

rem

oval

x =

2(1

80 −

(x +

36))

or

)36

180

(2−

−=

xx

or

2)

36

(180

xx

=+

or

180 −

x −

36 =

21

x

M1

x =

2(1

80 −

(x +

36))

or

x =

2(1

80 −

x +

36)

or

180 −

x +

36 =

21

x

or

180 −

36 +

x =

21

x

M

1

72

2360

−−

=x

x

or

x +

21

x =

180 −

36

M1

x =

360 −

2x +

72

or

x +

21

x =

180 +

36

(Note

– incorr

ect

sim

plifi

cati

on r

esu

lts

in

an a

nsw

er

of

x =

144)

M

1

72

360

3−

=x

or

3x =

288

or

23x =

180 −

36 o

r 23

x =

144

M1

96

A1

cao

Ple

ase

note

that

there

is

an a

ltern

ati

ve m

eth

od o

n t

he n

ext

page.

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

33

20.

(b)

OR

2x o

e s

een

(poss

ibly

mark

ed o

n d

iagra

m a

s si

ze

of

ACB

∠)

5

B1

180

236

=+

+x

x

M1

96

A1

cao

Tota

l 7 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

34

21.

(a)

tan d

raw

n a

t (3

, 6.5

)

3

M1

tan o

r ta

n p

roduced p

ass

es

betw

een p

oin

ts (

2,

0 <

y <

4)

and

(4,

9 <

y <

12)

dif

fere

nce

hori

zonta

ldif

fere

nce

vert

ical

M

1

finds

their

dif

fere

nce

hori

zonta

ldif

fere

nce

vert

ical

for

two p

oin

ts o

n t

an

or

finds

their

dif

fere

nce

hori

zonta

ldif

fere

nce

vert

ical

for

two p

oin

ts o

n c

urv

e,

where

one o

f th

e p

oin

ts h

as

an x

-coord

inate

betw

een 2

.5

and 3

inc a

nd t

he o

ther

poin

t has

an x

-coord

inate

betw

een 3

and 3

.5 inc

2.5

-6.5

in

c

A1

dep o

n b

oth

M m

ark

s

(b

)

−1.7

1

B1

Accept

answ

er

in r

ange −

1.7

- −

1.6

5

(c

)(i)

line j

oin

ing (−1

,11)

& (

1,1

3)

4

M1

12

A1

cao

(i

i)

pro

duces

line t

o c

ut

curv

e a

gain

M

1

4

A1

ft f

rom

lin

e

Tota

l 8 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

35

fi

rst

part

– f

inds

are

a o

f BCD

∆ a

nd/or

length

of

BD

22.

Are

a o

fBCD

∆ =

2

6

B1

for

are

a o

f tr

iangle

BCD

22

22

2+

=)(B

D o

r 2

22

22

2=

⎟ ⎠⎞⎜ ⎝⎛

+⎟ ⎠⎞

⎜ ⎝⎛BD

BD

or

°=

45

cos

2

2/

BD

or

sin45°

or

°=

45

cos

22BD

or

2 s

in45°

M1

for

corr

ect

start

to P

yth

agora

s or

trig

for

findin

g B

D o

r ⎟ ⎠⎞

⎜ ⎝⎛2BD

8)

(=

BD

or

22

or

2.8

3 o

r bett

er

(2.8

284..

.)

or

22

= ⎟ ⎠⎞⎜ ⎝⎛B

D o

r 28

or

1.4

1 o

r bett

er

(1.4

142..

.)

A1

for

length

s BD

or

⎟ ⎠⎞⎜ ⎝⎛

2BD

corr

ect

se

cond p

art

m

eth

od 1

– u

ses

Pyth

agora

s to

fin

d A

M,

where

M is

mid

poin

t of

BD

22

2

210

⎟ ⎠⎞⎜ ⎝⎛

−=

BD

AM

M

1

98

=A

Mor

27

or

9.9

0 o

r bett

er

(9.8

994..

.)

A1

for

98

or

27

9.9

0 o

r bett

er

16

A1

for

16 o

r answ

er

roundin

g t

o 1

6.0

Tota

l 6 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

36

se

cond p

art

m

eth

od 2

– f

inds

angle

A e

ither

usi

ng C

osi

ne R

ule

or

by f

irst

fin

din

g 2A

usi

ng t

rig

10

10

2

10

10

cos

22

2

××

−+

=BD

A o

r 200

192

or

0.9

6

or

10

2/

2si

nBD

A=

or

208

or

0.1

41 o

r bett

er

(0.1

4142..

.)

M1

(A =

) 16.3

or

bett

er

(16.2

602..

.)

A1

for

angle

A c

orr

ect

16

A1

for

16 o

r answ

er

roundin

g t

o 1

6.0

Tota

l 6 m

ark

s

se

cond p

art

m

eth

od 3

– f

inds

angle

ABD

(or

angle

AD

B)

usi

ng t

rig o

r Cosi

ne R

ule

10

2/

)(c

os

BD

ABD=

∠ o

r BD

BD

ABD

××

−+

=∠

10

2

10

10

)(c

os

22

2

or

=∠

ABD

cos

208

or

0.1

41 o

r bett

er

(0.1

4142..

.)

M1

°=

∠9.

81

)(

ABD

or

bett

er

(81.8

698..

.)

A1

16

A1

for

16 o

r answ

er

roundin

g t

o 1

6.0

Tota

l 6 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

37

Sum

mer

2008 IG

CSE M

ath

s M

ark

Schem

e –

Paper

4H

Q

W

ork

ing

Answ

er

Mark

N

ote

s

1.

(a)

6x –

2x =

7 –

13 o

r 2x –

6x =

13 -

7

4x =

-6 o

r –4

x =

6

x =

-1 ½

oe

3

M1

M1

A1

6x -

2x +

13 –

7 =

0 o

r 2x -

6x –

13 +

7 =

0

Accept

-6/4 o

r -3

/2 (

not

6/-4

or

3/-2

)

(b

) y –

2 x

5 =

4 x

5

or

y/5 =

4 +

2

y =

30

2

M1

A1

Tota

l 5 m

ark

s

2.

(a)

250±2

2

B2

B2 f

or

angle

248 t

o 2

52 inclu

sive.

B1 f

or

angle

190 t

o 2

60 inclu

sive

(b

)

305±3

2

B2

Aw

ard

B1 f

or

a b

eari

ng

270

o <

angle

< 3

60

o

Tota

l 4 m

ark

s

3.

(a)

20/2 o

r (2

0 +

1)/

2

6

2

M1

A1

(b

)

Yes,

no o

r not

nec’y

w

ith c

onsi

stent

reaso

n

2

B2

Can’t

tell

B1

Tota

l 4 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

38

4

(a)

3 –

5 x

-2

13

2

M1

A1

(b

)

5y -

10

1

B1

(c

)

w(w

+ 5

)

2

B2

B1

fo

r tw

o f

acto

rs th

at

mu

ltip

ly to

giv

e a

t le

ast o

ne

co

rre

ct te

rm.

SC

w(w

+ 5

w)

B1

Tota

l 5 m

ark

s

5.

(a)

30 x

0.2

6

2

M1

A1

or

30 ÷

5

(b

) 0.2

+ 0

.1

0.3

oe

2

M1

A1

Tota

l 4 m

ark

s

6.

8/12 o

r 3/12

8/

12,

3/

12

2

M1

A1

Accept

(4x2)/

(4x3)

or

(3x1)/

(4x3)

SC

Mult

iply

bs

by 1

2

B1

Decim

al m

eth

ods

M0 A

0

Tota

l 2 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

39

7.

(a)

3

14

1

B1

(b

)

73

1

B1

(c

)

3

72

5

55

=n

or

n

+ 3

– 7

= 2

n =

6

2

M1

A1

Accept

5n+3 =

59

(d

) Pro

duct

of

posi

tive inte

ger

pow

ers

of

both

2 a

nd 3

only

24 o

r 2

3 x

3

2

M1

A1

Pow

ers

and/or

pro

ducts

may b

e

evalu

ate

d.

Tota

l 6 m

ark

s

8.

½

x 3

x 4

3 x

15 a

nd 4

x 1

5 a

nd 5

x 1

5

192

4

M1

M2

A1

M1 f

or

any O

NE o

f th

ese

. cao

Tota

l 4 m

ark

s

9.

8x =

12 o

r 8y =

-4

x =

1.5

o

e

y =

-0.5

oe

3

M1

A1

A1

Elim

inate

one v

ari

able

corr

ectl

y.

Accept

3x +

5x –

8 =

4 o

r 5(4

– y

)/3 –

y =

8 o

e

No w

ork

ing M

0 A

0 A

0

Tota

l 3 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

40

10.

(a)

4.8

1

B1

(b

) 5

2 -

“4.8

”2

or

1.9

6

\/(5

2 -

“4.8

”2)

1.4

3

M1

M1dep

A1

cao

Tota

l 4 m

ark

s

11.

123.4

7 &

123.5

3

2

B2

B1 f

or

123.3

7 &

123.4

3

(e

qual to

1dp)

o

r 1

23.5

7 &

123.6

3

Tota

l 2 m

ark

s

12.

(a)

6

3

1

B1

cao

(b

) 4 x

5/8

oe

2.5

2

M1

A1

or

8 ÷

2 =

4 s

o 5

÷ 2

= …

, or

4 ÷

1.6

or

(62 +

52 –

2 x

6 x

5 c

os

20

o)

or

(5 x

sin

20

o)

/ s

in 6

3o

2.1

5

1.9

2

M1 f

or

com

ple

te t

rig m

eth

od.

A1 f

or

answ

er

to 3

SF.

(c

) 6 x

8/5

oe

9.6

2

M1

A1

or

(42 +

82 –

2 x

4 x

8 c

os

‘97

o’)

or

(8 x

sin

‘97

o’)

/si

n 6

3o

or

(4 x

sin

‘97

o’)

/si

n 2

0o

9.3

7

8.9

1

11.6

M1 f

or

com

ple

te t

rig m

eth

od.

A1 f

or

answ

er

to 3

SF.

Tota

l 5 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

41

13.

(a)

2/

3 c

orr

ectl

y p

laced

once

Corr

ect

stru

ctu

re

All c

orr

ect

3

B1

B1

B1

corr

ect

4 n

ew

lin

es,

ignore

la

bels

/pro

bs

inclu

din

g labels

/pro

bs

(b

) 2/

3 x

2/

3

1-2

/3 x

2/

3 o

r 1/

3 +

2/

3 x

1/

3 or

1/

3 x

2/

3 +

2/

3 x

1/

3 +

1/

3 x

1/

3

5/

9

oe

3

M1

M1

A1

1/

3 x

2/

3 o

r 2

/3 x

1/

3 or

1/

3 x

1/

3

Tota

l 6 m

ark

s

14.

(a)(

i)

vert

dif

f/hori

z dif

f fo

r any 2

poin

ts o

n L

0.5

o

e

2

M1

A1

(a

)(ii)

y =

“0.5

”x +

const

ant

Y =

“0.5

”x +

1 o

e

2

M1f

A1f

SC “

0.5

”x +

1 o

r L =

“0.5

”x +

1 B

1

(b

)

x <

4

y >

-1

Y <

0.5

x +

1

oe

3

B1

B1

B1

Allow

<

SC

All inequaliti

es

Allow

>

w

rong w

ay r

ound B

1

Allow

<

To

tal 7

ma

rk

s

15.

3.1

2 +

3.9

2 –

2 x

3.1

x 3

.9 x

cos8

0o

9.6

+ 1

5.2

– 4

.2

4.5

4

3

M1

M1

A1

3.1

2 +

3.9

2 –

24.2

x c

os8

0o

or

20.6

Tota

l 3 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

42

16.

(a)

5 ±

\/((

-5)2

– 4

x3)

2

5 ±

\/13

2

4.3

0 a

nd 0

.697

3

M1

M

1

A1

allow

4.3

and 0

.697

(b

) y <

3 o

r y >

-3

-3 <

y <

3

2

M1

A1

Allow

y <

3 o

r y

≥ -

3

Tota

l 5 m

ark

s

17.

(a)

Try

to f

ind a

rea o

f 2-4

blo

ck.

Try

to f

ind t

ota

l are

a.

40%

3

M1

M

1

A1

or

8

M0 f

or

2/8 o

r 9 -

1

Wit

h c

onsi

stent

scale

.

(b

) H

alf

tota

l are

a

or

try t

o f

ind m

iddle

of

dis

trib

uti

on

4

2

M1f

A1

ft d

ep o

n M

1 f

or

tota

l are

a in (

a)

Cao

Tota

l 5 m

ark

s

18.

x

x 4

= 3

x 1

4

oe

x =

10.5

o

e

2

M1

A1

x/ 1

4 =

¾,

3/ (

3 +

4) =

x/ (

x +

14),

4/ (

3 +

4) =

14/ (

x +

14

)

Tota

l 2 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

43

19.

(a)

2t

- 6

2

B1B1

(b

) 2 x

5 -

6

4

2

M1f

A1

Su

b t

= 5

in

“ds/dt”

de

p o

n lin

ea

r f(

t)

M0 f

or

(2 x

5 -

6)/

5

Cao

(c

) d(“

2t

– 6”)/

dt

2

2

M1

A1

Atte

mp

t d

iff

“ds/dt”

de

p o

n lin

ea

r f(

t)

Cao

Tota

l 6 m

ark

s

20.

(a)

14 x

10

12 o

e

1.4

x 1

013

2

M1

A1

or

1.4

e13

(b

)(i)

16

1

B1

cao

(b

)(ii)

(p +

q)

x 1

015 =

r x

10

n

(p

+ q

)/10 o

e

2

M1

A1

may b

e s

een in (

i)

0.1

(p +

q),

(p +

q)

x 1

0-1,

16

15

15 10

10

10

×+

×q

p

Tota

l 5 m

ark

s

21.

(a)(

i)

a +

b

oe

1

B1

(a

)(ii)

-a

oe

1

B1

(a

)(iii)

b –

a

oe

1

B1

(b

)

5

1

B1

Tota

l 4 m

ark

s

4400 IG

CSE M

ath

em

ati

cs

Sum

mer

2008

44

22.

1/

2 x

6 x

8 x

sin

xo =

12

sinx

o =

0.5

30

x =

150

4

M1

M1

A1

A1

allow

x =

30

Tota

l 4 m

ark

s

23.

(a)

(x –

3)(

x +

3)

x(x

+ 3

)

x

x3

3

M1

M1

A1

x31−

(b

)

2

2

1

31

x

x−

or

2131

x

1 –

3x

2

2

M

1

A1

ft

x

x3

+ o

nly

cao

Tota

l 5 m

ark

s

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