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  • 8/16/2019 Lucky Lecture Yes Yes s

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    Asif Nawaz PMAS UAAR University Institute of Information Technology

    Lecture 0 ! Programming "un#amentals ! 0$%

    Lecture 0 ! Programming "un#amentals ! 0$%

    Lecture $&

    "unctions

    $

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    Lecture 0 ! Programming "un#amentals ! 0$%

    User 'e(ne# "unction

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    Asif Nawaz PMAS UAAR University Institute of Information Technology

    Lecture 0 ! Programming "un#amentals ! 0$%

    • A user)#e(ne# function consists ofthe following!

    – "unction 'eclaration may also *e calle# as"unction Prototy+e

    – "unction 'e(nition

    &

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    Lecture 0 ! Programming "un#amentals ! 0$%

    "unction'eclaration,Prototy+e

    "unction +rototy+e +rovi#esinformation to the com+iler a*out thestructure of the function to *e use#in a +rogram-

    Rules! – Usually placed at the beginning of source

    file just before the main() function. – Must be ends with a semicolon.

    %

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    Lecture 0 ! Programming "un#amentals ! 0$%

    "unction'eclaration,Prototy+e

    • "unction 'eclaration consists of thefollowing +arts-

    – "unction Name – "unction Return Ty+e- – Num*er an# Ty+es of Parameters-

    .here !Return Ty+e in#icate the ty+e of value that will *e returne#*y function-Parameters are the values that are +rovi#e# to a functionwhen the function is calle#-

    /

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    Lecture 0 ! Programming "un#amentals ! 0$%

    1am+le

    The following function show that thefunction show acce+t no +arameter an#no return ty+e-

    void show(void);

    The following function show that thefunction sum acce+t integer +arameter

    an# integer return ty+e-

    int sum(int);

    2

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    Lecture 0 ! Programming "un#amentals ! 0$%

    1am+le

    The following function show that thefunction a## acce+t three integer+arameter an# integer return ty+e-

    int add(int a, int b, int c);

    3

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    Lecture 0 ! Programming "un#amentals ! 0$%

    "unction 'e(nition

    • A set of statements that e1+lainswhat a function #oes is calle#function #e(nition-

    Rules! – Usually placed after the main() function.

    4

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    Lecture 0 ! Programming "un#amentals ! 0$%

    "unction '(nition

    • The function #e(nition consists of two+arts-

    • "unction 5ea#er! – "irst line of function #e(nition- – Similar to function +rototy+e *ut with no semicolon- – Num*er of +arameters an# return ty+e will *e same

    as +rototy+e-

    • "unction 6o#y! – The set of statements which are e1ecute# insi#e

    function- – The *o#y will always a++ear after function #eclarator

    an# statements are written in curly *races- 7

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    Lecture 0 ! Programming "un#amentals ! 0$%

    Synta1 "unction 'e(nition

    Return !ype "unction #ame($arameter)

    %

    &tatement ';

    &tatement ;

    .

    .

    .

    &tatement #;

    $0

    "unction5ea#er

    "unction6o#y

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    Lecture 0 ! Programming "un#amentals ! 0$%

    "unction 8all

    • The statement that activates afunction is 9nown as function call-

    • A function is calle# with its name an#+arameter list-

    • .hen "unction is calle# then! – The control moves to the function that is calle#- – All statements in the function *o#y are e1ecute#- – The control returns *ac9 to the calling function-

    $$

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    Lecture 0 ! Programming "un#amentals ! 0$%

    $

    main: ; <===-===-"un: ;>===-

    ===-"un: ;> ?

    voi# "un: ; <

    ==--==--

    ?

    8alling"unction

    "unction8alls

    8alle# "unction

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    Lecture 0 ! Programming "un#amentals ! 0$%

    .rite a +rogram that #is+lay amessage @Programming is anInteresting "iel# on screen *y usingfunction-

    $&

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    Lecture 0 ! Programming "un#amentals ! 0$%

    void show(void);

    main()

    %

    show();getch();

    void show(void)

    %

    cout**+ Programming is an interesting field” ;

    $%

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    Lecture 0 ! Programming "un#amentals ! 0$%

    1am+le

    .rite a +rogram that a## two integernum*ers- the num*ers shoul# to thefunction as argument-

    $/

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    Lecture 0 ! Programming "un#amentals ! 0$%

    $2

    void sum(int , int );

    main()

    %

    sum(' , '-);

    cout** /0 ;getch();

    void sum(int 1, int y)

    %

    int s 2 1 3 y;

    cout** &um is 2 **s**endl;

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    Lecture 0 ! Programming "un#amentals ! 0$%

    Passing Parameters to a"unction

    • Two ways to +ass values to functionBsParameter!

    » Pass *y value-» Pass *y Reference-

    $3

    $

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    Lecture 0 ! Programming "un#amentals ! 0$%

    Pass *y Calue

    A +arameter +assing mechanism inwhich the value of actual +arameteris co+ie# to formal +arameter ofcalle# function is 9nown as +ass *yvalue-

    $4

    0 i l 0$%

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    Lecture 0 ! Programming "un#amentals ! 0$%

    1am+le

    $7

    .rite a +rogram that in+ut twointeger num*ers in main: ; functionD+asses these num*ers to function-

    The function #is+lays the ma1imumnum*er-

    L 0 ! P i " # l ! 0$%

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    Lecture 0 ! Programming "un#amentals ! 0$%

    void ma1(int a,int b );

    main()

    %

    int 1, y;cout**+4nter two numbers ;

    cin55155y;

    ma1(1,y);

    getch();

    void ma1(int a, intb)

    %if(a5b);

    % cout**+Ma1 number is **a**endl;

    else cout**+Ma1 number is **b**endl;

    0

    L 0 ! P i " # l ! 0$%

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    Lecture 0 ! Programming "un#amentals ! 0$%

    1am+le

    $

    .rite a +rogram that in+ut a num*erin main function an# +asses num*ersto a function- The function #is+laysta*le of that num*er-

    L t 0 ! P i " # t l ! 0$%

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    Lecture 0 ! Programming "un#amentals ! 0$%

    void table(int n);

    main()

    %int num;

    cout**+4nter number fortable ;

    cin55num;

    table(num);

    getch();

    void table(int n)

    %for(int c2 ; c*2' ; c33)

    %

    cout**n**+6+**c**+2+**n6c**endl;

    ?

    L t 0 ! P g i g " # t l ! 0$%

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    Lecture 0 ! Programming "un#amentals ! 0$%

    1am+le

    &

    .rite a +rogram that in+ut a num*erin main function an# +asses num*ersto a function- The function #is+laysfactorial of that num*er-

    Lect re 0 ! Programming " n#amentals ! 0$%

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    Lecture 0 ! Programming "un#amentals ! 0$%

    1am+le

    .rite a +rogram that in+ut twonum*ers an# one arithmetic o+erator+asses from main to function- Thefunction a++lies arithmetic o+erationon that two num*ers *ase# on theo+erator enter *y the user using

    switch statement-

    %

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming "un#amentals ! 0$%

    void operation(int a, int b, char ope)

    %

    switch(ope)

    %

    case 7389

    cout** a**+3:**b**a3b;

    brea0;

    case 7 89

    cout** a**+ :**b**a b;

    brea0;

    case 7689

    cout** a**+6:**b**a6b;

    brea0;

    .

    .

    .

    default9

    cout**+ nvalid /perator

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    Lecture 0 ! Programming un#amentals ! 0$%

    Pass *y Refrence

    2

    A +arameter +assing mechanism inwhich the value of actual +arameteris +asse# to the calle# function is9nown as +ass *y value- The formal+arameter is not create# se+aratelyin the main memory-

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming un#amentals ! 0$%

    1am+le

    Program to swa+ values using +ass *yreference-

    3

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming un#amentals ! 0$%

    4

    void swap(int =>, int =y);main()

    %

    int a,b;

    cout**+4nter values:;

    cin55a55b;cout**+?alues before swap9:;

    cout**+a 2+**a**endl;

    cout**+b 2+**b**endl;

    swap(a,b);

    getch();cout**+?alues after swap9:;

    cout**+a 2+**a**endl;

    cout**+b 2+**b**endl;

    getch();

    void swap(int =1, int =y)%int t;

    t 2 1;1 2 y;y 2 t;

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming un#amentals ! 0$%

    Returning Calue from a"unction

    .rite a +rogram that in+uts mar9s inmain function an# +asses these mar9sto a function- The function (n#s gra#eof a stu#ent on the *ases of followingcriteria-

    Era#e A 40 or A*ove mar9sEra#e 6 20 to 37 mar9sEra#e 8 %0 to /7 mar9sEra#e "*elow %0 mar9s

    7

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming un#amentals ! 0$%

    &0

    char grade(int m);

    main()

    %

    int mar0s;

    char g;

    cout**+4nter mar0s:;

    cin55mar0s;

    g 2 grade(mar0s);

    cout**+@our grade is:**g;

    getch();

    Ahar grade(int m)

    %

    if(m5B )return 7C8;

    else if (m5D )return 7E8;

    else if (m5F )

    return 7A8;else

    return 7"8;

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming un#amentals ! 0$%

    .rite a +rogram that in+uts *ase an#height in main function an# +assesthem to a function- The function (n#sthe area of a triangle an# return it toa main functionD where it #is+lay onscreen-

    Crea is 2 G (Ease 6 height)

    &$

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming un#amentals ! 0$%

    &

    float triangle(int b, int h);

    main()

    %

    int base, height;

    float area;

    cout**+4nter base:;

    cin55base;

    cout**+4nter height:;

    cin55height;

    area 2 triangle(base, height);

    cout**+Crea is:**area;

    getch();

    float area(int b, int h)%

    float a;a 2 .- 6 b 6 h;return a;

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming un#amentals ! 0$%

    &&

    .rite a +rogram that in+uts twointeger- It +asses one integer to thefunction that calculate an# return itssFuare- It +asses secon# integer toanother function that calculate an#return its cu*e- The main function

    a## *oth values an# return its result-

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming un#amentals ! 0$%

    &%

    int sHuare(int n);

    int cube(int n);

    main()

    %

    int a, b, sum;

    cout**+4nter first nteger:;

    cin55a;

    cout**+4nter &econd nteger:;

    cin55b;

    sum 2 sHr(a) 3 cube(b);

    cout**+Result is:**sum;

    getch();

    int sHuare(int n)%

    return n 6 n;

    int cube(int n)

    %return n 6 n 6 n;

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Lecture 0 ! Programming un#amentals ! 0$%

    Sco+e of Caria*le

    • The varia*les can *e #eclare# insi#ethe main functionD insi#e user#e(ne# function-

    • The eGect of the varia*les #eclare#in these +laces is #iGerent-

    • 6ase# u+on their eGectsD varia*lesare #ivi#e# into two classes!

    • Local Caria*le• Elo*al Caria*le

    &/

    Lecture 0 ! Programming "un#amentals ! 0$%

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    ectu e 0 ! og a g u a e ta s ! 0$%

    Local Caria*le

    • The varia*le #eclare# insi#e the mainfunction or insi#e user #e(ne#function is calle# Local Caria*le-

    These varia*les may also *e calle#as Automatic Caria*les-

    &2

    Lecture 0 ! Programming "un#amentals ! 0$%

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    g g $

    &3

    void sum(int , int );

    main()

    %

    int a 2 - ;

    int b 2 D ;s 2 sum(' , '-);

    cout**+&um is 2+**sum;

    cout** /0 ;

    getch();

    void sum(int 1, int y)%int s 2 1 3 y;return s;

    Lecture 0 ! Programming "un#amentals ! 0$%

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    g g

    Elo*al Caria*le

    &4

    • The varia*le #eclare# outsi#e themain function or any other user#e(ne# function is calle# glo*alCaria*le- These varia*les can *eaccesse# in any function at any time#uring the e1ecution of +rogram-

    Lecture 0 ! Programming "un#amentals ! 0$%

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    g g

    1am+le

    &7

    int g;

    void fun(void);

    main()

    %

    cout**+ 4nter a number +;cin55g;

    cout**+?alue of g before function:**g;

    fun();

    cout**+?alue of g after function:**g;

    getch();

    void fun()%

    g 2 g 6 ;

    Lecture 0 ! Programming "un#amentals ! 0$%

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    g g

    'efault Parameter

    • The +arameter that initialize #uringfunction #eclaration is calle# #efault+arameter-

    %0

    Lecture 0 ! Programming "un#amentals ! 0$%

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    g g

    %$

    void !est(int n 2 ' );

    main()

    %

    !est();

    !est( );!est(I-);

    getch();

    void !est(int n)

    %

    cout**+n2 **n**endl;

    Output:

    1002

    75

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Asif Nawaz PMAS UAAR University Institute of Information Technology %

    void add(int v'2-, int v 2 ' );main()

    %

    int vJ 2 v' 3 v ;

    cout**+!he sum of two num 2+**vJ;getch();

    void !est(int n)

    %

    add();add(', );

    add(');

    Output:

    !he sum of two num 2 '-

    !he sum of two num 2 J!he sum of two num 2 ''

    Lecture 0 ! Programming "un#amentals ! 0$%

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    "unctions an# Arrays

    • An array can *e +asse# to a functionas a +arameter-

    • .hen an array is +asse# as a+arameter to a functionD only thea##ress of (rst element of the arrayis +asse#-

    • An array is +asse# *y reference not*y value-

    void display(int arrayKL); %&

    Lecture 0 ! Programming "un#amentals ! 0$%

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    1am+le

    .rite a +rogram that in+uts (veinteger in an array an# +asses thearray to a function- The function#is+lay the value of the array-

    %%

    Lecture 0 ! Programming "un#amentals ! 0$%

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    Asif Nawaz PMAS UAAR University Institute of Information Technology %/

    void show(int arrayKL);

    main()

    %int numK-L, i;

    cout**+4nter five nteger ;for(int i2 ; i*2-; i33)

    %

    cin55numKiL;

    show(num);getch();

    void show(int arrayKL)

    %

    int j;for(int j2 ; j*2-; j33)

    %

    cout**arrayKjL**endl;

    ?

    Lecture 0 ! Programming "un#amentals ! 0$%

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    1am+le

    %2

    .rite a +rogram that in+uts (veinteger in an array an# +asses thearray to a function- The functioncounts the even num*ers in thearray- An# return the result to mainfunction where the result is

    #is+laye#-

    Lecture 0 ! Programming "un#amentals ! 0$%

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    int even(int arrayKL);main()

    %int numK-L, i, n;

    cout**+4nter five nteger ;

    for(int i2 ; i*2-; i33)%

    cin55numKiL;

    n 2 even(num);Aout**+!he array

    contain**n**+even number:;

    getch();

    int even(int arrayKL)

    %

    int j, e;

    e 2 ;for(int j2 ; j*2-; j33)

    %if(arrayKjL 22 )

    %

    e33;

    ?

    Lecture 0 ! Programming "un#amentals ! 0$%

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    "unction an# Structure

    • The structures can also *e use# withfunction-

    • A function can acce+t structure as+arameter-

    • A function can also return a structurevaria*le-

    %4

    Lecture 0 ! Programming "un#amentals ! 0$%

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    1am+le

    .rite a +rogram that #eclares astructure to store mar9s an# gra#e- It#e(nes structure varia*le an# in+utvalues- It +asses the varia*le to afunction that show its contents-

    %7

    Lecture 0 ! Programming "un#amentals ! 0$%

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    void show(!est p);

    main()

    %

    struct !est

    %

    int mar0s;

    char grade;

    ;

    !est t;

    cout**+4nter mar0s:;

    cin55t.mar0s;

    cout**+4nter grade:;

    cin55t.grade;

    show(t);

    getch();

    void show(!est p)%cout**+Mar0s:**p.mar0s**endl;cout**+Nrade:**p.grade**endl;

    Lecture 0 ! Programming "un#amentals ! 0$%

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    .rite a +rogram that #eclares astructure to store country name an#+o+ulation in million- It #e(nes twostructure varia*le an# in+uts values-It +asses *oth varia*les to a functionthat show the recor# of a country

    with more +o+ulation-

    Lecture 0 ! Programming "un#amentals ! 0$%

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    void fun(pop 1, pop y);

    main()

    %struct pop

    %

    char name;

    float people;

    ;pop a,b;cout**+4nter Aountry #ame

    = population:;

    cin55a.name55a.people;

    cout**+4nter Aountry #ame= population:;

    cin55b.name55b.people;

    fun(a,b);

    getch();

    void fun(pop 1, pop y)%cout**+!he country withmore population 9:;%

    if(1.pp5y.pp)%cout**+#ame:**1.name**endl;cout**+$opulation:**p.population;else

    cout**+#ame:**y.name**endl;cout**+$opulation:**y.population;

    Lecture 0 ! Programming "un#amentals ! 0$%

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    "unction Hverloa#ing

    • "unction with same name *ut with#iGerent +arameters value is calle#function overloa#ing-

    • The function with same name may*e #iGerent with one of the followingways-

    » Num*er of +arameters» Ty+e of +arameter» SeFuence of +arameter

    /&

    Lecture 0 ! Programming "un#amentals ! 0$%

  • 8/16/2019 Lucky Lecture Yes Yes s

    54/54

    void line();

    void line(int n);

    void line(int n, c ar c);

    main()

    !struct "est!

    line()line(#);

    line(5, $ @ %);getc ();&

    void line();!

    int i;

    for(i'1; i '10; i )

    !cout * + * endl;

    &

    void line(n);

    %

    int i;

    for(i2n; i*2' ; i33)

    %

    cout**+ 6 +**endl;

    void line(int n, char c);

    %

    int ;

    for(i2'; i*2n; i33)%

    cout**c**endl;